Consider following dataset:
id
name
mgr_id
salary
bonus
1
Paul
1
68000
10000
2
Lucas
2
29000
null
3
Max
1
50000
20000
4
Zack
2
30000
null
I now want to find the manager who pays his subordinates the highest average salary plus bonus. A manager is someone who is present in of the mgr_id cells. So in this example Paul and Lucas are managers because their id is present in the mgr_id column of themselves and Max for Paul and Zack for Lucas.
Basically I want MAX(AVG(salary + bonus)) and then grouped by the mgr_id. How can I do that?
I am using SQLite.
My expected output in this example would be simply the employee name 'Paul' because he has 2 subordinates (himself and Max) and pays them more than the other manager Lucas.
SELECT
mrg_id
, pay_avg
FROM
(
SELECT mrg_id
, AVG(salary + COALESCE(bonus,0)) pay_avg
FROM <table>
GROUP
BY mrg_id
) q
ORDER
BY pay_avg
desc
LIMIT 1
select top 1 t1.mgr_id,AVG((t1.salary)+(t1.bonus)) as tot_sal
from #tbl_emps as t1
group by t1.mgr_id
order by AVG((t1.salary)+(t1.bonus)) desc
Related
This question already has answers here:
Select second most minimum value in Oracle
(3 answers)
Closed 4 years ago.
EMPID NAME DEPTID SALARY
---------- ------------------------------------------ --
101 surendra 201 1000
102 narendra 202 2000
103 rajesh 203 3000
104 ramesh 203 2000
105 hanumanth 202 10000
a) Write a Query to find least 5th (Least salary in 5th position from
least salary in the order) salaried employee?
b) Query to find the highest earning employee in each department
a) Write a Query to find least 5th (Least salary in 5th position from least salary in the order) salaried employee?
SELECT EMPID,NAME,DEPTID,SALARY
FROM
(
SELECT EMPID,NAME,DEPTID,SALARY, DENSE_RANK() OVER (ORDER BY SALARY) AS RN
FROM Table1
)
WHERE RN=5
b) Query to find the highest earning employee in each department
SELECT EMPID,NAME,DEPTID,SALARY
FROM
(
SELECT EMPID,NAME,DEPTID,SALARY,
DENSE_RANK() OVER (PARTITION BY DEPTID ORDER BY SALARY DESC) AS RN
FROM Table1
)
WHERE RN=1
Demo
http://sqlfiddle.com/#!4/63ce0/12
Let's assume we have a table named EmployeeSalary which has 3 columns:
Id
Name
Salary
Salary might be same for multiple employee according to the following table data
Id Name Salary
----------
6 Belalo 74
1 Karim 100
5 dIPU 100
4 Satter 102
9 Kiron 120
10 Rash 120
11 Harun 130
13 Baki 130
12 Munshi 132
2 Rahim 500
7 Kaif 987
8 Sony 987
3 Belal 4000
Now the query will be
SELECT A.Salary
FROM
(
SELECT DISTINCT Salary,
DENSE_RANK() OVER (ORDER BY Salary) AS Ranks
FROM [dbo].[EmployeeSalary]
) A
WHERE A.Ranks=5
EmployeeID EmployeeName Department Salary
----------- --------------- --------------- ---------
1 Nisha Finance 40000.00
2 John Finance 25000.00
3 NEo Finance 25000.00
4 Dan Finance 15000.00
5 Jstin IT 80000.00
6 Amy IT 50000.00
I want to get the second highest Salary which is 50000.00 without using subquery?
Try below query, it will work.
select max(e1.salary) from Employee e1,Employee e2 where e1.salary<e2.salary;
Using limit and offset (to skip highest salary)
In MySQL
select * from table order by Salary desc limit 1 offset 1
In SQL server
select * from table order by Salary desc offset 1 rows fetch next 1 row only
You can try with another Database here
http://sqlfiddle.com/#!9/15c32/1/0
Couldn't you just use LIMIT 1,1 (grab first result after first row). I come from the MySql side of things so the sql might have to be adjusted slightly for Sql Server.
SELECT Salary FROM table ORDER BY Salary DESC LIMIT 1,1
SELECT DISTINCT Salary
FROM TABLE
ORDER BY Salary DESC OFFSET 1 ROWS
FETCH NEXT 1 ROW ONLY
Test this query after adding your table name and column names
select MAX(country) as country from users where country < ( select MAX(country) as country from users where country < (SELECT MAX(country) from users ) );
You can use TOP keyword to fetch number of records from the database tables. for example
SELECT TOP 1 * FROM TABLE NAME
I want to calculate highest nth salary in Oracle. I've already done with my solution but on google I found one query doing the same thing.
Here is the query
SELECT *
FROM Employee Emp1
WHERE (N - 1) = (SELECT COUNT(DISTINCT(Emp2.orig_salary))
FROM Employee Emp2
WHERE emp2.orig_salary > emp1.orig_salary)
Data
ID Name Birth Orig_Salary
2 John 15-JUL-97 2341
3 Joe 25-JAN-86 4321
4 Tom 13-SEP-06 2413
5 Jane 17-APR-05 7654
6 James 18-JUL-04 5679
7 Jodd 20-JUL-03 5438
8 Joke 01-JAN-02 8765
9 Jack 29-AUG-01 7896
I'm not not able to understand this query.
After running inner query it will always gives me count of 8 after doing this it will go to where clause where it will pick salary which is higher than the outer query salary. How equal operator is working here in between inner and outer query and how comparison is happening.
Could any help me to understand how this query is working technically in back-end..?
SELECT *
FROM Employee Emp1
WHERE (N - 1) = (SELECT COUNT(DISTINCT(Emp2.orig_salary))
FROM Employee Emp2 <--- cartesian product with same table
WHERE emp2.orig_salary > emp1.orig_salary) <---- but do the cartesian product only if line of salary of emp 2 is greater than the current line of Emp1 'salary
e.g assume there are only 3 lines in the table:
ID Name Birth Orig_Salary
2 John 15-JUL-97 2341
3 Joe 25-JAN-86 4321
4 Tom 13-SEP-06 5413
the main query will look at the first line --> 2 John 15-JUL-97 2341 <---, and subquery will return 2 because the salaries 4321 (emp2.orig_salary) and 5413 (emp2.orig_salary) are greater than 2341 (emp1.orig_salary)
the main query will then look at the second line --> 3 Joe 25-JAN-86 4321 <---, and subquery will return 1 because the salaries 5413 (emp2.orig_salary) is greater than 2341 (emp1.orig_salary)
when i say subquery, it is the
=(SELECT COUNT(DISTINCT(Emp2.orig_salary))
FROM Employee Emp2 <--- cartesian product with same table
WHERE emp2.orig_salary > emp1.orig_salary)
and the main query is
SELECT *
FROM Employee Emp1
WHERE
the returned value from the subquery is then compare to the where condition n-1, if the condition is satisfied, then it retrieves the line.
There is no need to understand that query. The correct formulation is:
SELECT Emp1.*
FROM (SELECT Emp1.*, DENSE_RANK() OVER (ORDER BY Emp2.orig_salary) as seqnum
FROM Employee Emp1
) Emp1
WHERE seqnum = <n>;
This gives the details for the employees. If you just want the salary:
SELECT orig_salary
FROM (SELECT Emp1.*, DENSE_RANK() OVER (ORDER BY Emp2.orig_salary) as seqnum
FROM Employee Emp1
) Emp1
WHERE seqnum = <n> AND rownum = 1;
I should note that a simpler version of this is:
select distinct orig_salary
from employees
order by orig_salary desc
offset <n - 1>
fetch first 1 row only;
The use of a correlated subquery for this is a pleasant anachronism from the days when relational databases were not as powerful as they are now. It is of historical interest.
I am new to Oracle.
I want to find the name who got the second maximum salary from a table?
Here the example table:
R.no name employee_id salary
201 Sanjay 78781 1000
202 Mohan 78782 2500
203 Viji 78783 5000
204 Vinay 78784 3000
205 Ishanth 78785 8000
select *
from (
select name,
salary,
dense_rank() over (order by salary desc) as rnk
from table_name
) t
where rnk = 2
SQLFiddle example: http://sqlfiddle.com/#!4/e93c3/1
How can retrieve that data:
Name Title Profit
Peter CEO 2
Robert A.D 3
Michael Vice 5
Peter CEO 4
Robert Admin 5
Robert CEO 13
Adrin Promotion 8
Michael Vice 21
Peter CEO 3
Robert Admin 15
to get this:
Peter........4
Robert.......15
Michael......21
Adrin........8
I want to get the highest profit value from each name.
If there are multiple equal names always take the highest value.
select name,max(profit) from table group by name
Since this type of request almost always follows with "now can I include the title?" - here is a query that gets the highest profit for each name but can include all the other columns without grouping or applying arbitrary aggregates to those other columns:
;WITH x AS
(
SELECT Name, Title, Profit, rn = ROW_NUMBER()
OVER (PARTITION BY Name ORDER BY Profit DESC)
FROM dbo.table
)
SELECT Name, Title, Profit
FROM x
WHERE rn = 1;