I have two columns A, B in oracle where A value has values like that xx-target-xx
xx any data but target is exists
A
--------
xx-target-xx
xx-target
i neet to return only 'target' from text
i tired this
select TRIM(substr(A, 0, instr(A, '-') - 1)) from mytable
but the result returns xx not target
Use REGEXP_SUBSTR. You want the second string of any characters except the minus sign:
select a, regexp_substr(a, '[^-]+', 1, 2) from mytable;
Using INSTR and SUBSTR instead is a tad more complicated, but possible of course:
select a, substr(a,
instr(a, '-') + 1,
instr(a || '-', '-', 1, 2) - instr(a, '-') - 1
) as value
from mytable;
Demo: https://dbfiddle.uk/?rdbms=oracle_18&fiddle=e75b878bbd6300e9207cd698bb3029ec
Related
I am struggle with regex to split spring into columns in Oracle database.
select (REGEXP_SUBSTR(replace('1:::9999', ' ',''), '[^: ]+', 1, 4)) from dual;
I need to obtain 4th value from that string as a column value, sometimes values at position 2,3 are empty and my query doesn't work. I am trying to figure out what regex will work
You can use
select (REGEXP_SUBSTR(replace('1:::9999', ' ',''), '([^: ]*)(:|$)', 1, 4, 'i', 1)) from dual;
Here, the ([^: ]*)(:|$) matches
([^: ]*) - Group 1: any zero or more chars other than : and space
(:|$) - Group 2, either : or end of string.
You do not need a (slower) regex for this task, use simple substr/instr functions:
with input_(val) as (
select '1:::9999' from dual
union all
select '1:2::' from dual
union all
select '1:2::3:5' from dual
)
, replaced as (
select input_.*, replace(val, ' ', '') as val_replaced
from input_
)
select
val,
substr(
val_replaced,
/*Locate the first occurrence of a colon and get a substring ...*/
instr(val_replaced, ':', 1, 3) + 1,
/*.. until the end, if the next colon is absent, or until the next colon*/
nvl(nullif(instr(val_replaced, ':', 1, 4), 0), length(val_replaced) + 1) - instr(val_replaced, ':', 1, 3) - 1
) as col
from replaced
VAL
COL
1:::9999
9999
1:2::
null
1:2::3:5
3
fiddle with performance difference.
Example
123\.456.578.910.ABC
123\.456.578.910
Expected result
123\.456.578
123\.456.578
For the both the inputs I should get only the first 3
I tried the regexp and substring and instr but I’m not getting the results
We can use REGEXP_SUBSTR here with a capture group:
SELECT REGEXP_SUBSTR(col, '^(\d+(\.\d+)*)', 1, 1, NULL, 1)
FROM yourTable;
Demo
Traditional, substr + instr combination is another option:
Sample data:
SQL> with test (col) as
2 (select '123\.456.578.910.ABC' from dual union all
3 select '123\.456.578.910' from dual
4 )
Query begins here:
5 select col,
6 substr(col, 1, instr(col, '.', 1, 3) - 1) result
7 from test;
COL RESULT
-------------------- --------------------
123\.456.578.910.ABC 123\.456.578
123\.456.578.910 123\.456.578
SQL>
If you value will always have at least 3 . characters then you can use:
SELECT value,
SUBSTR(value, 1, INSTR(value, '.', 1, 3) - 1) AS expected
FROM table_name;
If it may have fewer and you want the entire string in those cases then:
SELECT value,
CASE INSTR(value, '.', 1, 3)
WHEN 0
THEN value
ELSE SUBSTR(value, 1, INSTR(value, '.', 1, 3) - 1)
END AS expected
FROM table_name;
Which, for your sample data:
CREATE TABLE table_name (value) AS
SELECT '123\.456.578.910.ABC' FROM DUAL UNION ALL
SELECT '123\.456.578.910' FROM DUAL;
Both outputs:
VALUE
EXPECTED
123.456.578.910.ABC
123.456.578
123.456.578.910
123.456.578
db<>fiddle here
In the table code_subject there is a row with a following format string1#string2#integer#string3. How to extract a number (integer) from it?
IS IT LIKE THAT?:
SELECT REGEXP_SUBSTR('integer') "REGEXPR_SUBSTR" FROM code_subject
One way could be using regexp_replace:
select regexp_replace('stringA#stringB#1234#stringC', '[^0-9]', '')
from dual;
Another possibility is:
select substr('string1#string2#1234#string3', instr('string1#string2#1234#string3', '#', 1, 2) + 1,
instr('string1#string2#1234#string3', '#', 1, 3) - instr('string1#string2#1234#string3', '#', 1, 2) - 1)
from dual;
I have some filename like 'abc-type-bank-20200112-1578796204118.csv'
i want to get the value 'bank' from above which is 3rd value if I cut the string by '-'.
If my filename is like abc-type-XYZ-20200112-1578796204118.csv, I should get 'XYZ' from 3rd position.
I was trying to get by below code, but it giving wrong value.
select substr(v_FILE_NAME,1,instr(v_FILE_NAME, '-') + 3) as name from (
select 'abc-type-bank-20200112-1578796204118.csv' as v_FILE_NAME from dual);
To use SUBSTR and INSTR to extract your desired substring you'd do something like
WITH cteData AS (SELECT 'abc-type-bank-20200112-1578796204118.csv' AS FILENAME FROM DUAL),
ctePos AS (SELECT FILENAME,
INSTR(FILENAME, '-', 1, 2) AS DASH_2_POS,
INSTR(FILENAME, '-', 1, 3) AS DASH_3_POS
FROM cteData)
SELECT SUBSTR(FILENAME, DASH_2_POS + 1, DASH_3_POS - DASH_2_POS - 1) AS SUBSTR_3
FROM ctePos
The above will extract the substring 'bank' from the sample data.
db<>fiddle here
The use of dual suggests Oracle. In that database you can use regexp_substr():
select regexp_substr(filename, '[^-]+', 1, 3)
from (select 'abc-type-XYZ-20200112-1578796204118.csv' as filename from dual) x;
i've a string like 'aabbcczx' and i need to split that string by 2 char.
The result expected is something like:
aabbcczx aa
aabbcczx bb
aabbcczx cc
aabbcczx zx
How can I do this?
consider also that the length of the string change row by row.
Thanks
If it's always 2 chars:
SELECT A.Val,
CA1.N,
SUBSTRING(A.Val,n,2)
FROM (
VALUES ('aabbcczx')
) AS A(Val)
CROSS
APPLY dbo.GetNums(1,LEN(A.Val)) AS CA1
WHERE CA1.n % 2 = 1;
GetNums is a number table/tally table generator you can find some several sources online.
It will provide the position of each character and we can use that in the substring start position. The where clause uses MOD to so we only show every other starting position
You can use a recursive query:
with cte as (
select convert(varchar(max), left(str, 2)) as val2, convert(varchar(max), stuff(str, 1, 2, '')) as rest, str
from (values ( 'aabbcczx' )) v(str)
union all
select left(rest, 2) as val2, stuff(rest, 1, 2, '') as rest, str
from cte
where rest <> ''
)
select str, val2
from cte;
You can use a recursive query to extract pairs of characters:
with instring as
( select 'aabbcczx' as s )
, splitter as
(
select s, substring(s, 1, 2) as rslt, 3 as next -- first two chars
from instring
union all
select s, substring(s, next, 2), next + 2 -- next two chars
from splitter
where len(s) >= next
)
select *
from splitter
See dbfiddle