how to split a string which is having comma and colon - sql

Question

I have a following query like this
SELECT REGEXP_SUBSTR('SARAH;10,JOE;1D,KANE;1A,SDF:1a', '[^,;]+', 1, level)
FROM dual
CONNECT BY REGEXP_SUBSTR('SARAH;10,JOE;1D,KANE;1A,SDF:1a',
'[^,;]+',
1,
level) IS NOT NULL;
I am trying to get o/p as SARAH,JOE,KANE,SDF

Answer 1

If there's only one row of data, then you can use
WITH t(str) AS
(
SELECT 'SARAH;10,JOE;1D,KANE;1A,SDF:1a' FROM dual
), t2 AS
(
SELECT level AS lvl, REGEXP_SUBSTR(str, '[^,;:]+', 1, level) AS str
FROM t
CONNECT BY REGEXP_SUBSTR(str,
'[^,;]+',
1,
level) IS NOT NULL
)
SELECT LISTAGG(str,',') WITHIN GROUP (ORDER BY lvl) AS result
FROM t2
WHERE NOT REGEXP_LIKE(str,'^(\d)')
in order to filter the extracted substrings which don't start with an integer through use of REGEXP_LIKE() like above

Answer 2

Don't split the string and re-aggregate. Just replace the string from each ; or : until the next , or then end-of-the-string:
SELECT REGEXP_REPLACE(
'SARAH;10,JOE;1D,KANE;1A,SDF:1a',
'[;:].*?(,|$)',
'\1'
) AS replaced_value
FROM DUAL;
Which outputs:
REPLACED_VALUE
SARAH,JOE,KANE,SDF
db<>fiddle here
Update
If your delimiter can be any one of the ;:, characters until the next ;:, character or the end-of-the-string then:
SELECT value,
RTRIM(REGEXP_REPLACE(value, '[;:,].*?([;:,]|$)', ','), ',')
AS replaced_value
FROM table_name;
Which, for the sample data:
CREATE TABLE table_name (value) AS
SELECT 'SARAH;10,JOE;1D,KANE;1A,SDF:1a' FROM DUAL UNION ALL
SELECT 'SARAH,10;JOE,1D;KANE,1A;SDF:1a' FROM DUAL;
Outputs:
VALUE
REPLACED_VALUE
SARAH;10,JOE;1D,KANE;1A,SDF:1a
SARAH,JOE,KANE,SDF
SARAH,10;JOE,1D;KANE,1A;SDF:1a
SARAH,JOE,KANE,SDF
db<>fiddle here