Issue in forming node structure when multiple identical keys found in a nodeset - xslt-1.0

Question

Scenario 1: L node having child node SL
Scenario 2: L node with no child node SL
Scenario 3: L node having child node SL and having multiple pit elements having attribute ref identical.
I need to form multiple L nodes if text "L1" () is found at other nodes like and . Id attribute of SL node(i.e ) is formed using "L1" in . Also ref attribute of pit node(i.e ) is formed using "L1" in , I need to check whether "L1" is present in either id attribute of SL or ref attribute of pit and form the desired output.
Input xml as below
<root>
<L Id="L1">
<test>ed</test>
<SL id="L1S1">
<check>
<AId>1</AId>
</check>
<MD>
<UnitNumber>1</UnitNumber>
</MD>
</SL>
<SL id="L1S2">
<check>
<AId>2</AId>
</check>
<MD>
<UnitNumber>2</UnitNumber>
</MD>
</SL>
</L>
<cp>
<current>
<Amt>20154.00</Amt>
</current>
<pi>
<pit ref="L1S1">
<value>123</value>
</pit>
<pit ref="L1S2">
<value>1232</value>
</pit>
</pi>
</cp>
</root>
Expected output should be:
<root>
<L Id="L1">
<SL id="L1S1">
<check>
<AId>1</AId>
</check>
<MD>
<UnitNumber>1</UnitNumber>
</MD>
</SL>
<pit ref="L1S1">
<value>123</value>
</pit>
</L>
<L Id="L1">
<SL id="L1S2">
<check>
<AId>2</AId>
</check>
<MD>
<UnitNumber>2</UnitNumber>
</MD>
</SL>
<pit ref="L1S2">
<value>1232</value>
</pit>
</L>
</root>
<root>
<L Id="L1">
<test>ed</test>
</L>
<cp>
<current>
<Amt>20154.00</Amt>
</current>
<pi>
<pit ref="L1S1">
<value>123</value>
</pit>
<pit ref="L1S2">
<value>1232</value>
</pit>
</pi>
</cp>
</root>
Expected output should be:
<root>
<L Id="L1">
<pit ref="L1S1">
<value>123</value>
</pit>
</L>
<L Id="L1">
<pit ref="L1S2">
<value>1232</value>
</pit>
</L>
</root>
Scenario 3:
Input xml as below
<root>
<L Id="L1">
<test>ed</test>
<SL id="L1S1">
<check>
<AId>1</AId>
</check>
<MD>
<UnitNumber>1</UnitNumber>
</MD>
</SL>
<SL id="L1S2">
<check>
<AId>2</AId>
</check>
<MD>
<UnitNumber>2</UnitNumber>
</MD>
</SL>
</L>
<cp>
<current>
<Amt>20154.00</Amt>
</current>
<pi>
<pit ref="L1S1">
<value>123</value>
</pit>
<pit ref="L1S1">
<value>234</value>
</pit>
<pit ref="L1S2">
<value>1232</value>
</pit>
<pit ref="L1S2">
<value>1</value>
</pit>
</pi>
</cp>
</root>
Expected output should be:
<root>
<L Id="L1">
<SL id="L1S1">
<check>
<AId>1</AId>
</check>
<MD>
<UnitNumber>1</UnitNumber>
</MD>
</SL>
<pit ref="L1S1">
<value>123</value>
</pit>
</L>
<L Id="L1">
<SL id="L1S1">
<check>
<AId>1</AId>
</check>
<MD>
<UnitNumber>1</UnitNumber>
</MD>
</SL>
<pit ref="L1S1">
<value>234</value>
</pit>
</L>
<L Id="L1">
<SL id="L1S2">
<check>
<AId>2</AId>
</check>
<MD>
<UnitNumber>2</UnitNumber>
</MD>
</SL>
<pit ref="L1S2">
<value>1232</value>
</pit>
</L>
<L Id="L1">
<SL id="L1S2">
<check>
<AId>2</AId>
</check>
<MD>
<UnitNumber>2</UnitNumber>
</MD>
</SL>
<pit ref="L1S2">
<value>1</value>
</pit>
</L>
</root>
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:key name="pit-SL" match="pit" use="#ref" />
<xsl:key name="pit-L" match="pit" use="substring(#ref,1,2)" />
<xsl:strip-space elements="*"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="L[SL]">
<xsl:apply-templates select="SL"/>
</xsl:template>
<xsl:template match="SL">
<L>
<xsl:copy-of select="parent::L/#Id"/>
<xsl:copy>
<xsl:copy-of select="#id"/>
<xsl:apply-templates select="node()"/>
<xsl:copy-of select="key('pit-SL',#id)"/>
</xsl:copy>
</L>
</xsl:template>
<xsl:template match="L[not(SL)]">
<xsl:apply-templates select="key('pit-L',#Id)">
<xsl:with-param name="L" select="."/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="pit">
<xsl:param name="L"/>
<L>
<xsl:copy-of select="$L/#Id"/>
<xsl:copy-of select="."/>
</L>
</xsl:template>
<xsl:template match="cp"/>
</xsl:stylesheet>
Iam facing issue in 3rd scenario, when there are multiple identical pit ref keys.

Answer 1

Here is an approach.
<xsl:key name="SLkey" match="SL" use="#id"/>
<xsl:key name="pitKey" match="pit" use="generate-id()"/>
<xsl:template match="root">
<xsl:copy>
<xsl:apply-templates select="#*|.//pit"/>
</xsl:copy>
</xsl:template>
<xsl:template match="pit">
<xsl:choose>
<!-- Is there an SL node match? -->
<xsl:when test="key('SLkey', #ref)[1]">
<xsl:apply-templates select="key('SLkey', #ref)[1]/.." mode="Loutput">
<xsl:with-param name="ref" select="#ref"/>
<xsl:with-param name="pitID" select="generate-id(.)"/>
</xsl:apply-templates>
</xsl:when>
<!-- Use the first L in the document. -->
<xsl:otherwise>
<xsl:apply-templates select="//L[1]" mode="Loutput">
<xsl:with-param name="ref" select="#ref"/>
<xsl:with-param name="pitID" select="generate-id(.)"/>
</xsl:apply-templates>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<!-- ********************** -->
<!-- Loutput mode templates -->
<!-- ********************** -->
<xsl:template match="node()|#*" mode="Loutput">
<xsl:copy>
<xsl:apply-templates select="node()|#*" mode="Loutput"/>
</xsl:copy>
</xsl:template>
<xsl:template match="L" mode="Loutput">
<xsl:param name="ref"/>
<xsl:param name="pitID"/>
<xsl:copy>
<xsl:apply-templates select="#*|SL[#id = $ref]" mode="Loutput"/>
<xsl:apply-templates select="key('pitKey', $pitID)" mode="Loutput"/>
</xsl:copy>
</xsl:template>