CONSECUTIVE DAYS QUERY [closed] - sql

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I have an Oracle DB Connection that has data (SELECT * FROM SALES) as in the picture, i want a query that gives me which 3 consecutive days are those who have the sum of PREMIUM_TOTAL > 100.
I have tried with the method lead, lag , DATADIFF but failed. Also i'm new at this, if you can give me hints please.

Answer 1

If you want 3 rows from successive days then you can use a recursive query:
WITH successive_days (day, products, total, depth) AS (
SELECT entry_date,
TO_CHAR(product_id),
premium_total,
1
FROM table_name
UNION ALL
SELECT s.day + 1,
s.products || ',' || t.product_id,
s.total + t.premium_total,
s.depth + 1
FROM successive_days s
INNER JOIN table_name t
ON (s.day + 1 = t.entry_date)
WHERE s.depth < 3
)
SELECT day AS final_day, products, total
FROM successive_days
WHERE depth = 3
AND total >= 100;
Which, for the sample data:
CREATE TABLE table_name (product_id, entry_date, premium_total) AS
SELECT 1, DATE '2022-03-01', 1 FROM DUAL UNION ALL
SELECT 2, DATE '2022-03-01', 20 FROM DUAL UNION ALL
SELECT 4, DATE '2022-03-02', 30 FROM DUAL UNION ALL
SELECT 5, DATE '2022-03-03', 30 FROM DUAL UNION ALL
SELECT 10, DATE '2022-03-21', 12 FROM DUAL UNION ALL
SELECT 11, DATE '2022-03-31', 40.5 FROM DUAL UNION ALL
SELECT 13, DATE '2022-03-05', 70 FROM DUAL UNION ALL
SELECT 12, DATE '2022-03-05', 80 FROM DUAL UNION ALL
SELECT 14, DATE '2022-03-05', 10 FROM DUAL UNION ALL
SELECT 20, DATE '2022-03-06', 20 FROM DUAL UNION ALL
SELECT 21, DATE '2022-03-07', 30 FROM DUAL UNION ALL
SELECT 22, DATE '2022-03-07', 40 FROM DUAL UNION ALL
SELECT 30, DATE '2022-03-08', 20 FROM DUAL UNION ALL
SELECT 31, DATE '2022-03-09', 50 FROM DUAL UNION ALL
SELECT 40, DATE '2022-03-10', 2 FROM DUAL;
Outputs:
FINAL_DAY
PRODUCTS
TOTAL
2022-03-07 00:00:00
13,20,21
120
2022-03-07 00:00:00
13,20,22
130
2022-03-07 00:00:00
12,20,21
130
2022-03-07 00:00:00
12,20,22
140
2022-03-09 00:00:00
21,30,31
100
2022-03-09 00:00:00
22,30,31
110
If you want all the rows (at least 3) that are all within 3 successive days then you can use MATCH_RECOGNIZE:
SELECT MIN(entry_date) AS start_day,
MAX(entry_date) AS final_day,
LISTAGG(product_id, ',') WITHIN GROUP (ORDER BY entry_date) AS products,
SUM(premium_total) AS total
FROM table_name
MATCH_RECOGNIZE(
ORDER BY entry_date
MEASURES
MATCH_NUMBER() AS mno
ALL ROWS PER MATCH
AFTER MATCH SKIP TO NEXT ROW
PATTERN (first_day+ second_day+ third_day* final_day)
DEFINE
first_day AS FIRST(entry_date) = entry_date,
second_day AS FIRST(entry_date) + 1 = entry_date,
third_day AS FIRST(entry_date) + 2 = entry_date,
final_day AS FIRST(entry_date) + 2 = entry_date
AND SUM(premium_total) >= 100
)
GROUP BY mno;
Which, for the sample data, outputs:
START_DAY
FINAL_DAY
PRODUCTS
TOTAL
2022-03-05 00:00:00
2022-03-07 00:00:00
12,13,14,20,21,22
250
2022-03-05 00:00:00
2022-03-07 00:00:00
13,14,20,21,22
170
2022-03-05 00:00:00
2022-03-07 00:00:00
13,20,21,22
160
2022-03-06 00:00:00
2022-03-08 00:00:00
20,21,22,30
110
2022-03-07 00:00:00
2022-03-09 00:00:00
21,22,30,31
140
2022-03-07 00:00:00
2022-03-09 00:00:00
22,30,31
110
db<>fiddle here