SQL Comma separated values comparisons - sql

Question

I am having a challenge comparing values in Available column with values in Required column. They are both comma separated.
Available
Required
Match
One, Two, Three
One, Three
1
One, Three
Three, Five
0
One, Two, Three
Two
1
What I want to achieve is, if values in the Required column are all found in the Available column then it gives me a match of 1 and 0 if one or more values that are in the Required column is missing in the Available column
I want to achieve this in SQL.

Answer 1

If I understand the question correctly, an approach based on STRING_SPLIT() and an appropriate JOIN is an option:
Sample data:
SELECT *
INTO Data
FROM (VALUES
('One, Two, Three', 'One, Three'),
('One, Three', 'Three, Five'),
('One, Two, Three', 'Two')
) v (Available, Required)
Statement:
SELECT
Available, Required,
CASE
WHEN EXISTS (
SELECT 1
FROM STRING_SPLIT(Required, ',') s1
LEFT JOIN STRING_SPLIT(Available, ',') s2 ON TRIM(s1.[value]) = TRIM(s2.[value])
WHERE s2.[value] IS NULL
) THEN 0
ELSE 1
END AS Match
FROM Data
Result:
Available
Required
Match
One, Two, Three
One, Three
1
One, Three
Three, Five
0
One, Two, Three
Two
1

Answer 2

A variation of Zhorov's solution.
It is using a set based operator EXCEPT.
SQL
-- DDL and sample data population, start
DECLARE #tbl TABLE (Available VARCHAR(100), Required VARCHAR(100));
INSERT INTO #tbl (Available, Required) VALUES
('One, Two, Three', 'One, Three'),
('One, Three', 'Three, Five'),
('One, Two, Three', 'Two');
-- DDL and sample data population, end
SELECT t.*
, [Match] = CASE
WHEN EXISTS (
SELECT TRIM([value]) FROM STRING_SPLIT(Required, ',')
EXCEPT
SELECT TRIM([value]) FROM STRING_SPLIT(Available, ',')
) THEN 0
ELSE 1
END
FROM #tbl AS t;
Output
+-----------------+-------------+-------+
| Available | Required | Match |
+-----------------+-------------+-------+
| One, Two, Three | One, Three | 1 |
| One, Three | Three, Five | 0 |
| One, Two, Three | Two | 1 |
+-----------------+-------------+-------+

Answer 3

You need to do a cross join to look in all available values, your query would be :
SELECT t.*
,case when SUM(CASE
WHEN t1.Available LIKE '%' + t.Required + '%'
THEN 1
ELSE 0
END) > 0 THEN 1 ELSE 0 END AS [Match_Calculated]
FROM YOUR_TABLE t
CROSS JOIN YOUR_TABLE t1
GROUP BY t.Available
,t.Required
,t.Match
Here's a dbfiddle

Answer 4

You can use "STRING_SPLIT" to achieve your request
;with Source as
(
select 1 id,'One,Two,Three' Available,'One,Three' Required
union all
select 2 id,'One,Three' Available,'Three,Five' Required
union all
select 3 id,'One,Two,Three' Available,'Two' Required
)
,AvailableTmp as
(
SELECT t.id,
x.value
FROM Source t
CROSS APPLY (SELECT trim(value) value
FROM string_split(t.Available, ',')) x
)
,RequiredTmp as
(
SELECT t.id,
x.value
FROM Source t
CROSS APPLY (SELECT trim(value) value
FROM string_split(t.Required, ',')) x
)
,AllMatchTmp as
(
select a.id
,1 Match
From RequiredTmp a
left join AvailableTmp b on a.id=b.id and a.value = b.value
group by a.id
having max(case when b.value is null then 1 else 0 end ) = 0
)
select a.id
,a.Available
,a.Required
,ISNULL(b.Match,0) Match
from Source a
left join AllMatchTmp b on a.id = b.id

Answer 5

Another way using STRING_SPLIT
DECLARE #data TABLE (Available VARCHAR(100), [Required] VARCHAR(100),
INDEX IX_data(Available,[Required]));
INSERT #data
VALUES ('One, Two, Three', 'One, Three'),('One, Three', 'Three, Five'),
('One, Two, Three', 'Two');
SELECT
Available = d.Available,
[Required] = d.[Required],
[Match] = MIN(f.X)
FROM #data AS d
CROSS APPLY STRING_SPLIT(REPLACE(d.[Required],' ',''),',') AS split
CROSS APPLY (VALUES(REPLACE(d.[Available],' ',''))) AS cleaned(String)
CROSS APPLY (VALUES(IIF(split.[value] NOT IN
(SELECT s.[value] FROM STRING_SPLIT(cleaned.String,',') AS s),0,1))) AS f(X)
GROUP BY d.Available, d.[Required];