I have never worked with JSON in SQL Server before that's why need some help.
I have written a simple snippet of code:
DECLARE #json NVARCHAR(4000)
SET #json =
N'{
"id":"40476",
"tags":[
{
"id":"5f5883",
},
{
"id":"5fc8",
}
],
"type":"student",
"external_id":"40614476"
}'
SELECT
JSON_value(#json, '$.tags[0].id') as tags
In sample above I write code how get first "id" from "tags".
But how looks like script if in "tags" not 2 "id", but an unknown number this "id" and result should be in column like this:
1 5f5883
2 5fc8
You may use OPENJSON() with explicit schema to parse the $.tags JSON array:
DECLARE #json NVARCHAR(4000)
SET #json =
N'{
"id":"40476",
"tags":[
{
"id":"5f5883"
},
{
"id":"5fc8"
}
],
"type":"student",
"external_id":"40614476"
}'
SELECT id
FROM OPENJSON(#json, '$.tags') WITH (id varchar(10) '$.id')
Result:
id
------
5f5883
5fc8
If you want to get the index of each id in the $.tags JSON array, then you need a combination of OPENJSON() with default schema and JSON_VALUE():
SELECT CONVERT(int, [key]) AS rn, JSON_VALUE([value], '$.id') AS id
FROM OPENJSON(#json, '$.tags')
Result:
rn id
----------
0 5f5883
1 5fc8
Related
Is it possible to output a nested array into a table?
I intend to loop over the orders array and capture the line_item id's for the current iteration.
SQL
DECLARE #json NVARCHAR(4000) = N'
{
"orders":[
{
"id":123,
"line_items":[
{
"id":1
},
{
"id":2
}
]
}
]
};'
SELECT
[LineId]
FROM OPENJSON (#json, '$.orders.line_items') WITH (
[LineId] BIGINT '$.id'
);
Desired output
id
1
2
Here is a working option using a CROSS APPLY to extract the array.
SELECT id = JSON_VALUE(B.Value,'$.id')
FROM OPENJSON(#json, '$.orders') A
CROSS APPLY OPENJSON (A.value, '$.line_items') as B
Results
id
1
2
See sample below. How would I use JSON_MODIFY or other way to modify all the "disc" values to "100" without having to update each array item in a loop?
create table #temp_data (json_text nvarchar(max))
insert into #temp_data select
'
"curr":"USD",
"items":[
{
"line":1,
"disc":10,
},
{
"line":2,
"disc":11
},
{
"line":3,
"disc":12,
}
]
}'
select * from #temp_data
We don't actually need to parse the rest of the JSON, we only need the $.items part. So we can APPLY that property with OPENJSON, then reassemble it with JSON_MODIFY:
UPDATE t
SET json_text = JSON_MODIFY(t.json_text, '$.items', v.items)
FROM temp_data t
CROSS APPLY (
SELECT line, disc = 100
FROM OPENJSON(t.json_text, '$.items') WITH (line int) AS items
FOR JSON PATH
) v(items);
In the WITH block, we need to add all properties we are not modifying, then in the inner SELECT we add any columns we want to change.
One way would be to use the traditional SQL DML UPDATE to replace the json_text with a new piece of JSON derived from the existing. Something like this
JSON_MODIFY could be added if that's a requirement.
drop table if exists #temp_data;
go
create table #temp_data (json_text nvarchar(max));
insert into #temp_data(json_text) values(
N'{
"curr":"USD",
"items":[
{
"line":1,
"disc":10
},
{
"line":2,
"disc":11
},
{
"line":3,
"disc":12
}
]
}');
update #temp_data
set json_text=( select json_value(d.json_text, N'strict $.curr') curr,
(select j2.line, j2.disc+100 as disc
from #temp_data td
cross apply openjson(td.json_text)
with(curr nvarchar(20),
items nvarchar(max) as json) j1
cross apply openjson(j1.items)
with(line int,
disc int) j2
for json path) items
from #temp_data d
for json path, without_array_wrapper);
select * from #temp_data;
{
"curr": "USD",
"items": [
{
"line": 1,
"disc": 210
},
{
"line": 2,
"disc": 211
},
{
"line": 3,
"disc": 212
}
]
}
It's not possible to use a wildcard in a JSON_MODIFY() call, so one possible approach are the following steps:
Parse the $.items array from the stored JSON using OPENJSON() and explicit schema including the line key.
Set the new value for the disc key for each item of this array.
Generate the JSON again using FOR JSON PATH.
Update the table with JSON_MODIFY().
Table:
create table #temp_data (json_text nvarchar(max))
insert into #temp_data (json_text)
VALUES (N'
{
"curr":"USD",
"items":[
{"line":1, "disc":10},
{"line":2, "disc":11},
{"line":3, "disc":12}
]
}')
Statement:
UPDATE #temp_data
SET json_text = JSON_MODIFY(
json_text,
'$.items',
(
SELECT line, 100 AS disc
FROM OPENJSON(json_text, '$.items') WITH (line int '$.line')
FOR JSON PATH
)
)
Result:
json_text
{
"curr":"USD",
"items":[{"line":1,"disc":100},{"line":2,"disc":100},{"line":3,"disc":100}]
}
I have the below JSON object. I need to write a select query to get the index values of Object JSON array. Kind of getting the sequence value.
{
"Model": [
{
"ModelName": "Test Model",
"Object": [
{
"ID": 1,
"Name": "ABC",
},
{
"ID": 11,
"Name": "ABCD",
},
{
"ID": 15,
"Name": "ABCDE",
},
]
}]}
Expected Output:
Index_Value
1
2
3
If I understand the question correctly and you want to get the index of the items in the Object JSON array, you need to use OPENJSON() with default schema. The result is a table with columns key, value and type and in case of JSON array, the key column holds the index of each item in the array (0-based):
JSON:
DECLARE #json nvarchar(max) = N'{
"Model":[
{
"ModelName":"Test Model",
"Object":[
{
"ID":1,
"Name":"ABC"
},
{
"ID":11,
"Name":"ABCD"
},
{
"ID":15,
"Name":"ABCDE"
}
]
}
]
}'
Statement:
SELECT CONVERT(int, j2.[key]) + 1 AS item_id
FROM OPENJSON (#json, '$.Model') j1
CROSS APPLY OPENJSON(j1.[value], '$.Object') j2
But if you want to get the values of the ID keys in the Object JSON array, the statement is different:
SELECT j2.ID
FROM OPENJSON (#json, '$.Model') j1
CROSS APPLY OPENJSON(j1.[value], '$.Object') WITH (
ID int '$.ID'
) j2
Note, that you need two OPENJSON() calls, because the input JSON has nested array structure. Of course, if Model JSON array has always one item, you may simplify the statement using an appropriate path:
SELECT CONVERT(int, [key]) + 1 AS item_id
FROM OPENJSON (#json, '$.Model[0].Object')
Finally, to get index, ID and Name, you should use the following statement, which assumes, that $.Model JSON array has more than one item and defines ID and Name columns with the appropraite data types:
SELECT
CONVERT(int, j2.[key]) + 1 AS ItemID,
j3.ID, j3.Name
FROM OPENJSON (#json, '$.Model') j1
CROSS APPLY OPENJSON(j1.[value], '$.Object') j2
CROSS APPLY OPENJSON(j2.[value], '$') WITH (
ID int '$.ID',
Name varchar(50) '$.Name'
) j3
DECLARE #json nvarchar(max) = N'{
"Model":[
{
"ModelName":"Test Model",
"Object":[
{
"ID":1,
"Name":"ABC"
},
{
"ID":11,
"Name":"ABCD"
},
{
"ID":15,
"Name":"ABCDE"
}
]
}
]
}'
declare #i int=0;
SELECT
j2.ID, j2.Name
FROM OPENJSON (#json, '$.Model') j1
CROSS APPLY OPENJSON(j1.[value],concat('$.Object[',#i,']')) WITH (
ID i`enter code here`nt '$.ID', Name varchar(100) '$.Name'
) j2
Results:-
ID
Name
11
ABCD
you can select the key columns in select clause no need to mention in with of crossjoin.
SELECT
distinct t.id,
JSON_VALUE(AttsData.[value], '$.address') as address,
JSON_VALUE(AttsData.[value], '$.name') as name,
JSON_VALUE(AttsData.[value], '$.owner_name') as owner_name,
JSON_VALUE(AttsData.[value], '$.project') as project
,CONVERT(int, AttsData.[key]) index_id
FROM mytablewithjsonfeild t
CROSS APPLY OPENJSON (t."jsonfeild",N'$.parentkey') as AttsData
Above query, from the table I have cross joined the JSON field. and in select statement i have taken the specific keys.
and CONVERT(int, AttsData.[key]) to get the index of the elements
I am trying to make a table out of the [key] row values from a
select * from openjson(#json) statement. The openjson(#json) statement gives me results that contains 53 [key] row values, here's a small snippet:
[key] [value] [type]
_id 5b05390c5d222f0059209918 1
ean 65485555 1
name NULL 0
holder {"_id":"5b0538355d222f00585db6f1","name":"***... 5
root {"_id":"5b05390c5d222f005920990a","holder":{"_id":"5b0538885... 5
assigner {"_id":"5b0538885d222f00570aca19","name":"***... 5
created 2018-05-23T09:49:00+0000 1
children [] 4
address 1
timezone Etc/GMT-1 1
I want a table that look something like this:
table1
[_id] [ean] [name] [holder] [etc...]
5b05390c5d222f0059209918 65485555 NULL {"_id":"5b0538355d222...}
I also want to be able to insert values from another JSON into the same table
insert into table1 ()
select [value] from openjson(#json2)
Thank you!
Just add a WITH clause to your OPENJSON query.
See OPENJSON, eg:
DECLARE #json NVARCHAR(MAX) = N'[
{
"Order": {
"Number":"SO43659",
"Date":"2011-05-31T00:00:00"
},
"AccountNumber":"AW29825",
"Item": {
"Price":2024.9940,
"Quantity":1
}
},
{
"Order": {
"Number":"SO43661",
"Date":"2011-06-01T00:00:00"
},
"AccountNumber":"AW73565",
"Item": {
"Price":2024.9940,
"Quantity":3
}
}
]'
SELECT *
FROM OPENJSON ( #json )
WITH (
Number varchar(200) '$.Order.Number',
Date datetime '$.Order.Date',
Customer varchar(200) '$.AccountNumber',
Quantity int '$.Item.Quantity',
[Order] nvarchar(MAX) AS JSON
)
Is there a way to return json and non json data together? For example:
Column1 | Column2
1 | {["something":"value", "column2": "value2"]}
Try use AS JSON
DECLARE #json NVARCHAR(MAX) = N'
{
"Other":[{
"something": "value",
"column2": "value2"}],
"Id": 1
}'
SELECT *
FROM OPENJSON ( #json )
WITH (
[Id] int '$.Id',
[Other] nvarchar(MAX) AS JSON
)