I have this query but it is only showing the last 5 rows instead of limiting the amount of rows the group by gets
I only want the last 50 rows for each person to be sum and in the group.
SELECT playerid, SUM(gamesplayed) AS totalgames, SUM(playtimes) AS playtimeTotal, SUM(Kills) AS totalkills
FROM plugin_game
WHERE gamesplayed=1
GROUP BY playerid
ORDER BY totalkills DESC
LIMIT 50
playerid totalgames playtimeTotal totalkills
797749 8 3076 678
53854 8 5982 635
24398 8 3277 575
464657 4 1325 387
65748 4 3390 368
651532 4 3219 354
287378 6 3893 350
753808 4 2565 323
731631 4 1733 256
665338 4 1971 255
569648 2 2041 244
56488 4 2636 157
006985 3 785 93
58640 1 432 72
If i change the LIMIT to 5 it only shows
playerid totalgames playtimeTotal totalkills
797749 8 3076 678
53854 8 5982 635
24398 8 3277 575
464657 4 1325 387
65748 4 3390 368
so if we use 5 games as an example, i only want to get the SUM for the past 5 games for the group
This should work in postgre sql!
SELECT playerid,
SUM(gamesplayed) over w AS totalgames,
SUM(playtimes) over w AS playtimetotal,
SUM(kills) over w AS totalkills,
ROW_NUMBER() over w AS row
FROM plugin_game
window w AS (PARTITION BY playerid ORDER BY totalkills DESC)
WHERE gamesplayed=1 and row <=50
Related
I have a table in DB2 as below :
Key ID SubID
Abc123 576 10
Abc123 576 12
Abc124 576 13
Abc125 577 14
Abc126 578 15
Abc127 578 16
Abc128 578 17
Want to create a additional count column where it counts number of unique occurrences of key value for each ID and the output should be as below
Key ID SubID Count
Abc123 576 10 2
Abc123 576 12 2
Abc124 576 13 2
Abc125 577 14 1
Abc126 578 15 3
Abc127 578 16 3
Abc128 578 17 3
I tried below
select Key, ID, SubId ,
count(Key) over (partition by Key) as count
from table
Appreciate any help!
You cannot use a window function with the DISTINCT qualifier. You can use a scalar subquery to count the rows you want.
For example:
select *,
(select count(distinct key) from t x where x.id = t.id) as cnt
from t
Result:
KEY ID SUBID CNT
------- ---- ------ ---
Abc123 576 10 2
Abc123 576 12 2
Abc124 576 13 2
Abc125 577 14 1
Abc126 578 15 3
Abc127 578 16 3
Abc128 578 17 3
See running example at db<>fiddle.
so i have a Dataframe that has a repeating Number Series that i want to group like this:
Number Pattern
Value
Desired Group
Value.1
1
723
1
Max of Group
2
400
1
Max of Group
8
235
1
Max of Group
5
387
2
Max of Group
7
911
2
Max of Group
3
365
3
Max of Group
4
270
3
Max of Group
5
194
3
Max of Group
7
452
3
Max of Group
100
716
4
Max of Group
104
69
4
Max of Group
2
846
5
Max of Group
3
474
5
Max of Group
4
524
5
Max of Group
So essentially the number pattern is always monotonly increasing.
Any Ideas?
You can compare Number Pattern by 1 with cumulative sum by Series.cumsum and then is used GroupBy.transform with max:
df['Desired Group'] = df['Number Pattern'].eq(1).cumsum()
df['Value.1'] = df.groupby('Desired Group')['Value'].transform('max')
print (df)
Number Pattern Value Desired Group Value.1
0 1 723 1 723
1 2 400 1 723
2 3 235 1 723
3 1 387 2 911
4 2 911 2 911
5 1 365 3 452
6 2 270 3 452
7 3 194 3 452
8 4 452 3 452
9 1 716 4 716
10 2 69 4 716
11 1 846 5 846
12 2 474 5 846
13 3 524 5 846
For monotically increasing use:
df['Desired Group'] = (~df['Number Pattern'].diff().gt(0)).cumsum()
I am trying to join 3 different tables to get how many Home Runs a player has in his career along with how many Awards they have recieved. However, I'm getting incorrect results:
Peoples
PlayerId
Battings
PlayerId, HomeRuns
AwardsPlayers
PlayerId, AwardName
Current Attempt
SELECT TOP 25 Peoples.PlayerId, SUM(Battings.HomeRuns) as HomeRuns, COUNT(AwardsPlayers.PlayerId)
FROM Peoples
JOIN Battings ON Battings.PlayerId = Peoples.PlayerId
JOIN AwardsPlayers ON AwardsPlayers.PlayerId = Battings.PlayerId
GROUP BY Peoples.PlayerId
ORDER BY SUM(HomeRuns) desc
Result
PlayerID HomeRuns AwardCount
bondsba01 35814 1034
ruthba01 23562 726
rodrial01 21576 682
mayswi01 21120 736
willite01 20319 741
griffke02 18270 667
schmimi01 18084 594
musiast01 16150 748
pujolal01 14559 414
dimagjo01 12996 468
ripkeca01 12499 609
gehrilo01 12325 425
aaronha01 12080 368
foxxji01 11748 462
ramirma02 10545 399
benchjo01 10114 442
sosasa01 9744 304
ortizda01 9738 360
piazzmi01 9394 396
winfida01 9300 460
rodriiv01 9019 667
robinfr02 8790 330
dawsoan01 8760 420
robinbr01 8576 736
hornsro01 8127 648
I am pretty confident it's my second join Do I need to do some sort of subquery or should this work? Barry Bonds definitely does not have 35,814 Home Runs nor does he have 1,034 Awards
If I just do a single join, I get the correct output:
SELECT TOP 25 Peoples.PlayerId, SUM(Battings.HomeRuns) as HomeRuns
FROM Peoples
JOIN Battings ON Battings.PlayerId = Peoples.PlayerId
GROUP BY Peoples.PlayerId
ORDER BY SUM(HomeRuns) desc
bondsba01 762
aaronha01 755
ruthba01 714
rodrial01 696
mayswi01 660
pujolal01 633
griffke02 630
thomeji01 612
sosasa01 609
robinfr02 586
mcgwima01 583
killeha01 573
palmera01 569
jacksre01 563
ramirma02 555
schmimi01 548
ortizda01 541
mantlmi01 536
foxxji01 534
mccovwi01 521
thomafr04 521
willite01 521
bankser01 512
matheed01 512
ottme01 511
What am I doing wrong? I'm sure it's how I'm joining my second table (AwardsPlayers)
I think you have two independent dimensions. The best approach is to aggregate before joining:
SELECT TOP 25 p.PlayerId, b.HomeRuns, ap.cnt
FROM Peoples p LEFT JOIN
(SELECT b.PlayerId, SUM(b.HomeRuns) as HomeRuns
FROM Battings b
GROUP BY b.PlayerId
) b
ON b.PlayerId = p.PlayerId LEFT JOIN
(SELECT ap.PlayerId, COUNT(*) as cnt
FROM AwardsPlayers ap
GROUP BY ap.PlayerId
) ap
ON ap.PlayerId = p.PlayerId
ORDER BY b.HomeRuns desc;
Result
bondsba01 762 47
aaronha01 755 16
ruthba01 714 33
rodrial01 696 31
mayswi01 660 32
pujolal01 633 23
griffke02 630 29
thomeji01 612 6
sosasa01 609 16
robinfr02 586 15
mcgwima01 583 9
killeha01 573 8
palmera01 569 8
jacksre01 563 13
ramirma02 555 19
schmimi01 548 33
ortizda01 541 18
mantlmi01 536 15
foxxji01 534 22
mccovwi01 521 10
thomafr04 521 10
willite01 521 39
bankser01 512 10
matheed01 512 4
ottme01 511 11
I have a table as below. I want to do a group by in such a way that 1-4 weeknums are joined together and 5-8 weeknums are joined together. Or in other words i want to get the monthly total from below fields
table1
weeknum amount
1 1000
2 1100
3 1200
4 1300
5 1400
6 1500
7 1600
8 1700
The output i need is as below
output
max(weeknum) sum(amount)
4 4600
8 6200
The below answer did not work exactly for my actual values as below. I want to start with 4 weeks grouping. The formula (weeknum-1)/4 returns 3 groups as in the expected is only 2
weeknum Group Expr Expected Group Expr
1855 463 463
1856 463 463
1857 464 463
1858 464 463
1859 464 464
1860 464 464
1861 465 464
1862 465 464
Need to execute the query in oracle
Try using FLOOR that rounds the number down in the group by clause:
SELECT MAX(t.weeknum),sum(amount)
FROM table1 t
GROUP BY FLOOR((t.weeknum-1)/4)
This will make sure every 4 weeks are treated as a group :
(1-1)/4 -> 0
(2-1)/4 -> 0
...
(5-1)/4 -> 1
Given two tables:
1st Table Name: FACETS_Business_NPI_Provider
Buss_ID NPI Bussiness_Desc
11 222 Eleven 222
12 223 Twelve 223
13 224 Thirteen 224
14 225 Fourteen 225
11 226 Eleven 226
12 227 Tweleve 227
12 228 Tweleve 228
2nd Table : FACETS_PROVIDERs_Practitioners
NPI PRAC_NO PROV_NAME PRAC_NAME
222 943 P222 PR943
222 942 P222 PR942
223 931 P223 PR931
224 932 P224 PR932
224 933 P224 PR933
226 950 P226 PR950
227 951 P227 PR951
228 952 P228 PR952
228 953 P228 PR953
With below query I'm getting following results whereas it is expected to have the provider counts from table FACETS_Business_NPI_Provider (i.e. 3 instead of 4 for Buss_Id 12 and 2 instead of 3 for Buss_Id 11, etc).
SELECT BP.Buss_ID,
COUNT(BP.NPI) PROVIDER_COUNT,
COUNT(PP.PRAC_NO)PRACTITIONER_COUNT
FROM FACETS_Business_NPI_Provider BP
LEFT JOIN FACETS_PROVIDERs_Practitioners PP
ON PP.NOI=BP.NPI
group by BP.Buss_ID
Buss_ID PROVIDER_COUNT PRACTITIONER_COUNT
11 3 3
12 4 4
13 2 2
14 1 0
If I understood it correctly, you might want to add a DISTINCT clause to the columns.
Here is an SQL Fiddle, which we can probably use to discuss further.
http://sqlfiddle.com/#!2/d9a0e6/3