I have the below Query. My Expected output would be as below. Please help me make changes to the Query
select
ID,TERM,
case
when TERM like '____1_' then
function_toget_hrs(ID, TERM,sysdate) else null
end fall_hours,
case
when TERM like '____2_' then
function_toget_hrs(ID, TERM,sysdate) else null
end winter_hours
from TABLE_TERM
where ID='12087762'
Expecting one row for each ID. Please help me the ways
Pivoting is what you need:
WITH TABLE_TERM AS
(
SELECT 12087762 AS ID, '202110____1_' AS term, 12 AS func FROM dual UNION ALL
SELECT 12087762 AS ID, '202120____2_' AS term, 16 FROM dual UNION ALL
SELECT 12087762 AS ID, '202140____1_' AS term, 0 FROM dual
)
SELECT *
FROM (SELECT ID
, DECODE(SUBSTR(term,-6),'____1_','fall_hours','winter_hours') AS hrs
, func --function_toget_hrs(ID, TERM,sysdate) for test purposes
FROM TABLE_TERM
WHERE ID = '12087762'
)
PIVOT (SUM(func) FOR hrs IN ('fall_hours','winter_hours'));
Related
Why "else" part is not working I don't understand. Normally it should returns reverse of numbers if case statement not provided.
Here is my code;
select Id,
case
when mod(Id,10)<(Id/10)
then (cast((Id/10) as number(5))*10)+(mod(Id,10))
else
mod(Id,10)*10+(Id/10)
end Col
from digits
Sample data;
CREATE TABLE Test
(
Id INT
);
insert into test
select 21 from dual
UNION ALL
select 12 from dual
UNION ALL
select 34 from dual
UNION ALL
select 43 from dual
UNION ALL
select 29 from dual
UNION ALL
select 92 from dual;
Thanks in advance..
For reversing the integers with two digits the case should look like(notice the trunc function):
select
Id,
case
when mod(Id,10)<(Id/10)
then trunc(Id/10)*10+mod(Id,10) --this is the number itself, Id
else
mod(Id,10)*10+trunc(Id/10) --reverse :)
end Col
#aprkturk you mentioned T-SQL; here is Florin's answer translated:
select
Id,
case
when Id % 10 < Id / 10
then Id / 10 * 10 + Id % 10 -- this is the number itself, Id
else
Id % 10 * 10 + Id / 10 -- reverse :)
end Col
from #i
order by Id
What is this for? It seems an odd sort of thing to want to do...
I have a script that extracts transactions and their details from a database. But my users complain that the file size being generated is too large, and so they asked for certain transactions to be just summed up/consolidated instead if they are of a certain classification, say Checking Accounts. That means there should only be one line in the result set named "Checking" which contains the sum of all transactions under Checking Accounts. Is there a way for an SQL script to go like:
CASE
WHEN Acct_class = 'Checking'
then sum(tran_amount)
ELSE tran_amount
END
I already have the proper GROUP BY and ORDER BY statements, but I can't seem to get my desired output. There is still more than one "Checking" line in the result set. Any ideas would be very much appreciated.
Try This,
Select sum(tran_amount) From tran_amount Where Acct_class = 'Checking'
You can try to achieve this using UNION ALL
SELECT tran_amount, .... FROM table WHERE NOT Acct_class = 'Checking'
UNION ALL
SELECT SUM(tran_amount), .... FROM table WHERE Acct_class = 'Checking' GROUP BY Acct_class, ...;
hi you can try below sql
select account_class,
case when account_class = 'saving' then listagg(trans_detail, ',') within group (order by emp_name) -- will give you all details transactions
when account_class = 'checking' then to_char(sum(trans_detail)) -- will give you only sum of transactions
end as trans_det from emp group by account_class;
Or, if your desired output is getting either the sum, either the actual column value based on another column value, the solution would be to use an analytical function to get the sum together with the actual value:
select
decode(acct_class, 'Checking', tran_amount_sum, tran_amount)
from (
select
sum(tran_amount) over (partition by acct_class) as tran_amount_sum,
tran_amount,
acct_class
from
YOUR_TABLE
)
You can try something like the following, by keeping single rows for some classes, and aggregating for some others:
with test (id, class, amount) as
(
select 1, 'a' , 100 from dual union all
select 2, 'a' , 100 from dual union all
select 3, 'Checking', 100 from dual union all
select 4, 'Checking', 100 from dual union all
select 5, 'c' , 100 from dual union all
select 6, 'c' , 100 from dual union all
select 7, 'c' , 100 from dual union all
select 8, 'd' , 100 from dual
)
select sum(amount), class
from test
group by case
when class = 'Checking' then null /* aggregates elements of class 'b' */
else id /* keeps elements of other classes not aggregated */
end,
class
I have the below code to show what I am "trying" to accomplish in a stored procedure:
select * from
(
select to_char(sum(aa.amount))
from additional_amount aa, status st
where aa.int_tran_id = st.int_tran_id
and st.stage in ('ACHPayment_Confirmed')
and aa.entry_timestamp > (
select to_date(trunc(last_day(add_months(sysdate,-1))+1), 'DD-MON-RR') AS "day 1"
from dual
)
)
UNION ALL
(
select distinct it.debit_acct as "debit_accounts"
from internal_transactions it
where it.debit_acct IN ( select texe_cnasupro
from service.kndtexe, service.kndtctc
where texe_cncclipu = tctc_cncclipu
and tctc_cntipcli = 'C'
)
)
union all
(select distinct it.credit_acct as "credit_account"
from internal_transactions it
where it.credit_acct IN (select texe_cnasupro
from service.kndtexe, service.kndtctc
where texe_cncclipu = tctc_cncclipu
and tctc_cntipcli = 'C'
)
)
;
Output:
TO_CHAR(SUM(AA.AMOUNT))
----------------------------------------
130250292.22
6710654504
0000050334
2535814905
0007049560
5 rows selected
The top row of the output is what I need in the SP as output based on the below two queries which I am guessing needs to be sub-queried against the top select statement.
The top select is to select the sum of the amount a table with a join against another table for filtering (output:130250292.22).
The second and third selects is actually to check that the accounts in the internal_transactions table are signed up for the corresponding two tables in the service db which is a different db on the same server(owned by the same application).
The tables in the "service" db do not have the same common primary keys as in the first select which is against the same database.
Thank you for your help!
I don't understand your question, but I do know you can simplify this bit:
to_date(trunc(last_day(add_months(sysdate,-1))+1), 'DD-MON-RR') AS "day 1"
to this
trunc (sysdate, 'mm')
and you don't need a SELECT from DUAL to do that either.
and aa.entry_timestamp > trunc (sysdate, 'mm')
Is it possible to keep order from a 'IN' conditional clause?
I found this question on SO but in his example the OP have already a sorted 'IN' clause.
My case is different, 'IN' clause is in random order
Something like this :
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField IN (45,2,445,12,789)
I would like to retrieve results in (45,2,445,12,789) order. I'm using an Oracle database. Maybe there is an attribute in SQL I can use with the conditional clause to specify to keep order of the clause.
There will be no reliable ordering unless you use an ORDER BY clause ..
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField IN (45,2,445,12,789)
order by case TestResult.SomeField
when 45 then 1
when 2 then 2
when 445 then 3
...
end
You could split the query into 5 queries union all'd together though ...
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField = 4
union all
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField = 2
union all
...
I'd trust the former method more, and it would probably perform much better.
Decode function comes handy in this case instead of case expressions:
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField IN (45,2,445,12,789)
ORDER BY DECODE(SomeField, 45,1, 2,2, 445,3, 12,4, 789,5)
Note that value,position pairs (e.g. 445,3) are kept together for readability reasons.
Try this:
SELECT T.SomeField,T.OtherField
FROM TestResult T
JOIN
(
SELECT 1 as Id, 45 as Val FROM dual UNION ALL
SELECT 2, 2 FROM dual UNION ALL
SELECT 3, 445 FROM dual UNION ALL
SELECT 4, 12 FROM dual UNION ALL
SELECT 5, 789 FROM dual
) I
ON T.SomeField = I.Val
ORDER BY I.Id
There is an alternative that uses string functions:
with const as (select ',45,2,445,12,789,' as vals)
select tr.*
from TestResult tr cross join const
where instr(const.vals, ','||cast(tr.somefield as varchar(255))||',') > 0
order by instr(const.vals, ','||cast(tr.somefield as varchar(255))||',')
I offer this because you might find it easier to maintain a string of values rather than an intermediate table.
I was able to do this in my application using (using SQL Server 2016)
select ItemID, iName
from Items
where ItemID in (13,11,12,1)
order by CHARINDEX(' ' + Convert("varchar",ItemID) + ' ',' 13 , 11 , 12 , 1 ')
I used a code-side regex to replace \b (word boundary) with a space. Something like...
var mylist = "13,11,12,1";
var spacedlist = replace(mylist,/\b/," ");
Importantly, because I can in my scenario, I cache the result until the next time the related items are updated, so that the query is only run at item creation/modification, rather than with each item viewing, helping to minimize any performance hit.
Pass the values in via a collection (SYS.ODCINUMBERLIST is an example of a built-in collection) and then order the rows by the collection's order:
SELECT t.SomeField,
t.OtherField
FROM TestResult t
INNER JOIN (
SELECT ROWNUM AS rn,
COLUMN_VALUE AS value
FROM TABLE(SYS.ODCINUMBERLIST(45,2,445,12,789))
) i
ON t.somefield = i.value
ORDER BY rn
Then, for the sample data:
CREATE TABLE TestResult ( somefield, otherfield ) AS
SELECT 2, 'A' FROM DUAL UNION ALL
SELECT 5, 'B' FROM DUAL UNION ALL
SELECT 12, 'C' FROM DUAL UNION ALL
SELECT 37, 'D' FROM DUAL UNION ALL
SELECT 45, 'E' FROM DUAL UNION ALL
SELECT 100, 'F' FROM DUAL UNION ALL
SELECT 445, 'G' FROM DUAL UNION ALL
SELECT 789, 'H' FROM DUAL UNION ALL
SELECT 999, 'I' FROM DUAL;
The output is:
SOMEFIELD
OTHERFIELD
45
E
2
A
445
G
12
C
789
H
fiddle
I am using the following query :
select 8 Union Select 0 Union Select 15
to populate the these 3 number in a column. The result I get is:
0
8
15
But I want 8 to come first and then 0 and then 15, e.g.
8
0
15
How do I do this?
Use UNION ALL
E.g.
select 8 UNION ALL Select 0 UNION ALL Select 15
#SimonMartin's answer works for the exact data set you give, but be aware that if your data set contains duplicate values, the UNION ALL will produce different results than UNION.
The UNION operator removes duplicates, whereas the UNION ALL will preserve them (as well as their order, as noted in #SimonMartin's answer).
If you want to combine the functionality of your UNION operator with the ordering capabilities provided by UNION ALL, then you need to start with UNION ALL then filter out the duplicate values yourself:
-- baseline query + 1 duplicate record at the end
with query as
(
select 8 as Val
UNION ALL
Select 0 as Val
UNION ALL
Select 15 as Val
UNION ALL
Select 0 as Val
)
-- now add row numbers
, queryWithRowNumbers as
(
select row_number() over (order by (select 0)) as rn, Val
from query
)
-- finally, get rid of the duplicates
select Val from (
select Val, min(rn) as minRn
from querywithrownumbers
group by val
) q
order by minRn
This will give results of
8
0
15
whereas if you ONLY use UNION ALL you will end up with
8
0
15
0