I need to select a distinct row based on a value from a joined table in SQL Server.
Table Orderlines:
| order_id | product_id|
|------------|------------|
| 1234 | 11 |
| 1234 | 22 |
| 1234 | 33 |
| 1234 | 44 |
| 1234 | 55 |
| 2222 | 66 |
| 2222 | 77 |
Table Products:
| product_id | deliverytime|
|------------|--------------|
| 11 | 2 |
| 22 | 3 |
| 33 | 5 |
| 44 | 2 |
| 55 | 1 |
| 66 | 4 |
| 77 | 1 |
Result I am looking for:
| order_id | product_id| deliverytime|
|------------|------------|--------------|
| 1234 | 33 | 5 |
| 2222 | 66 | 4 |
Thanks in advance
We can RANK by deliverytime DESC in a CTE and then only take RANK 1 which is the highest value.
WITH CTE AS
(SELECT
o.product_id,
o.order_id
p.deliverytime,
RANK() OVER (PARTITION BY order_id
ORDER BY deliverytime DESC) rn
FROM Orderline o
JOIN Products p
ON o.product_id = p.product_id )
SELECT
order_id,
product_id,
deliverytime
FROM CTE
WHERE rn = 1;
ORDER BY order_id
Maybe it should work for you, but if there are two or more products with the same highest value, you'd get more than 1 row per order:
select v.order_id
, p2.product_id
, p2.deliverytime
from (
select o.order_id
, max(p.deliverytime) as max_deliverytime
from Orderlines o
join Products p
on o.product_id = p.product_id
group by o.order_id
) v
join Products p2
on v.max_deliverytime = p2.deliverytime;
it is better to use row_number to get highest delivery_time row. we can also order it based on highest product_id if there is more than 1 highest delivery time
SELECT ol.order_id,
ol.product_id,
p.deliverytime
FROM (
SELECT ol.order_id,
ol.product_id,
p.deliverytime,
row_number() over(partition by ol.order_id
order by p.deliverytime desc, ol.product_id desc) rn
FROM orderline ol
JOIN products p
ON ol.product_id = p.product_id
)RPR
WHERE rn = 1
Related
I have tables like this:
TABLE 1 - PERSON:
m_id | name |
-------------
22 | jo |
-------------
77 | john |
--------------
TABLE 2 - AMT_DATA
m_id | amt | activity |
-------------------------
22 | 100 | - |
-------------------------
77 | 300 | n |
-------------------------
TABLE 3 - STATUS_DATA:
m_id | status | s_date |
22 | - | 01.01.2000 |
22 | n | 01.01.2001 |
22 | - | 01.01.2002 |
77 | - | 01.01.2001 |
77 | n | 01.01.2002 |
How can i write a query or procedure that will return me all m_ids which biggest status_data.s_date for that m_id also have status_data.status = '-'?
I need to get result like this:
person.m_id | person.name | amt_data.amt | status | s_date
------------------------------------------------------------------
22 | jo | 100 | - | 01.01.2002
I don't see what amt really has to do with the question. You can just join that in.
One method is:
select p.*, status_date, status
from person p join
(select m_id, max(s_date) as status_date,
max(status) keep (dense_rank first order by s_date desc) as status
from status_data
group by m_id
) s
using (m_id)
where status = '-';
The keep syntax is Oracle's (rather verbose) way of implementing a "first" aggregation function.
You can use the analytical function as follows:
Select * from
(Select p.m_id,
P.name,
A.amt,
S.status,
S.s_date,
Row_number() over (partition by p.m_id order by s.s_date desc) as rn
From person p
join amt_data a on p.m_id = a.m_id
Join status_data s on p.m_id = s.m_id
Where s.status = '-')
Where rn = 1;
I have two tables cars and usage. I create a record in usage once a month for some of cars.
Now I want to get distinct list of cars with their latest usage that I saved.
first of all look at the tables please
cars:
| id | model | reseller_id |
|----|-------------|-------------|
| 1 | Samand Sall | 324228 |
| 2 | Saba 141 | 92933 |
usages:
| id | car_id | year | month | gas |
|----|--------|------|-------|-----|
| 1 | 2 | 2020 | 2 | 68 |
| 2 | 2 | 2020 | 3 | 94 |
| 3 | 2 | 2020 | 4 | 33 |
| 4 | 2 | 2020 | 5 | 12 |
The problem is here
I need only the latest usage of year and month
I tried a lot of ways but none of them is good enough. because sometimes this query gets me one ofnot latest records of usages.
SELECT * FROM cars AS c
LEFT JOIN
(select *
from usages
) u on (c.id = u.car_id)
order by u.gas desc
You can do this with a DISTINCT ON in the derived table:
SELECT *
FROM cars AS c
LEFT JOIN (
select distinct on (u.car_id) *
from usages u
order by u.car_id, u.year desc, u.month desc
) lu on c.id = lu.car_id
order by u.gas desc;
I think you need window function row_number. Here is the demo.
select
id,
model,
reseller_id
from
(
select
c.id,
model,
reseller_id,
row_number() over (partition by u.car_id order by u.id desc) as rn
from cars c
left join usages u
on c.id = u.car_id
) subq
where rn = 1
I have an issue with an SQL query that I am trying to write. I am trying to retrieve the row that has the minimal create_dt for each inst (see table) and amount (which isn't unique).
Unfortunately I can't use group by as the amount column isn't unique.
+--------------+--------+------+-------------+
| Company_Name | Amount | inst | Create Date |
+--------------+--------+------+-------------+
| Company A | 1000 | 4545 | 01/10/2018 |
| Company A | 400 | 4545 | 01/11/2018 |
| Company A | 200 | 4545 | 31/10/2018 |
| Company B | 2000 | 4893 | 01/10/2016 |
| Company B | 212 | 4893 | 04/10/2016 |
| Company B | 100 | 4893 | 10/10/2017 |
| Company B | 20 | 4893 | 04/10/2018 |
+--------------+--------+------+-------------+
In the above example I expect to see:
+--------------+--------+------+-------------+
| Company_Name | Amount | inst | Create Date |
+--------------+--------+------+-------------+
| Company A | 1000 | 4545 | 01/10/2018 |
| Company B | 2000 | 4893 | 01/10/2016 |
+--------------+--------+------+-------------+
Code:
SELECT
bill_company, bill_name, account_no
FROM
dbo.customer_information;
SELECT
balance_id, balance_id2, minus_balance,new_balance,
create_date, account_no
FROM
dbo.btr
SELECT
balance_id, balance_id2, expired_Date, amount, balance_type, account_no
FROM
dbo.btr_balance
SELECT
balance_ist, expired_date, account_no, balance_type
FROM
dbo.BALANCE_inst
Retrieve the minimal create data for a balance instance with the lowest balance for a balance inst.
(SELECT
bill_company,
bill_name,
account_no,
balance_ist,
amount,
MIN(create_date)
FROM
dbo.mtr btr
LEFT JOIN
btr_balance btrb ON btr.balance_id = btrb.balance_id
AND btr.balance_id2 = btrb.balance_id2
LEFT JOIN
balance_inst bali ON btr.account_no = bali.account_no
AND btrb.expired_date = bali.expired_date
GROUP BY
bill_company, bill_name, account_no,amount, balance_ist)
I have seen some solutions about using correlated query but can't see to get my head around it.
Common Table Expression (CTE) will help you.
;with cte as (
select *, row_number() over(partition by company_name order by create_date) rn
from dbo.myTable
)
select * from cte
where rn = 1;
use row_number() i assumed bill_company is your company name
select * from
( SELECT bill_company,
bill_name,
account_no,
balance_ist,
amount,
create_date,
row_number() over(partition by bill_company order by create_date) rn
FROM dbo.mtr btr left join btr_balance btrb
on btr.balance_id = btrb.balance_id and btr.balance_id2 = btrb.balance_id2
left join balance_inst bali
on btr.account_no = bali.account_no and btrb.expired_date = bali.expired_date
) t where t.rn=1
I have two tables , A and B
Table A contains:
OrderNo | StyleNo | Qty
O-20 | S-15 | 20
O-20 | S-18 | 40
O-25 | S-19 | 50
Table B contains:
OrderNo | StyleNo | Ship Qty
O-20 | S-15 | 5
O-20 | S-18 | 30
O-20 | S-15 | 12
O-20 | S-18 | 6
Result Requires
OrderNo | StyleNo | Qty | Ship Qty
O-20 | S-15 | 20 | 17
O-20 | S-18 | 40 | 36
O-25 | S-19 | 50 | 0
The following query is not working
select
B.Orderno, B.StyleNo, sum(A.Qty), sum(B.QtyShip)
from
A
inner join
B on A.OrderNo = B.OrderNo and A.StyleNo = B.StyleNo
group by
B.OrderNo, B.StyleNo
The issue you're having is that it's summing the qty field multiple times. Move the sums to subqueries and use a join on those:
select a.orderno, a.styleno, a.qty, b.qtyship
from (
select orderno, styleno, sum(qty) qty
from a
group by orderno, styleno
) a
join (
select orderno, styleno, sum(qtyship) qtyship
from b
group by orderno, styleno
) b on a.orderno = b.orderno and a.styleno = b.styleno
SQL Fiddle Demo
Here's a sample database table :
| ID | ProductID | DateChanged | Price
| 1 | 12 | 2011-11-11 | 93
| 2 | 2 | 2011-11-12 | 12
| 3 | 3 | 2011-11-13 | 25
| 4 | 4 | 2011-11-14 | 17
| 5 | 12 | 2011-11-15 | 97
Basically, what I want to happen is get the latest price of grouped by ProductID.
The result should be like this :
| ID | ProductID | Price
| 2 | 2 | 12
| 3 | 3 | 25
| 4 | 4 | 17
| 5 | 12 | 97
If you notice, the first row is not there because there is a new price for ProductID 12 which is the row of ID 5.
Basically, it should be something like get ID,ProductID and Price grouped by productID where DateChanged is the latest.
SELECT ID, ProductId, Price
FROM
(
SELECT ID, ProductId, Price
, ROW_NUMBER() OVER (PARTITION BY ProductID ORDER BY DateChanged DESC) AS rowNumber
FROM yourTable
) AS t
WHERE t.rowNumber = 1
SELECT ID, ProductID,DateChanged, Price
FROM myTable
WHERE ID IN
(
SELECT MAX(ID)
FROM myTable
GROUP BY ProductID
)
select a.id, a.productid, a.price
from mytable a,
(select productid, max(datechanged) as maxdatechanged
from mytable
group by productid) as b
where a.productid = b.productid and a.datechanged = b.maxdatechanged
SELECT ID, ProductId, Price
from myTable A
where DateChanged >= all
(select DateChanged
from myTable B
where B.ID = A.ID);