In SQL, for the same set of ID, I want to create the column Action with New where the Contract Number is the largest and Old for the smaller values.
For example, for ID = 123, the largest value in Contract Number is 10, so that row will be marked as New and the others as Old. The only columns in the SQL database are ID and Contract Number, so I'm assuming I should use a CASE WHEN statement to create the Action column, but not sure how to formulate it
Sample table:
ID
Contract Number
123
10
123
5
123
3
456
3
456
2
Expected output:
ID
Contract Number
Action
123
10
Keep
123
5
Old
123
3
Old
456
3
Keep
456
2
Old
You could use a case expression together with a windowed aggregate:
select *,
case when
contractnumber = Max(ContractNumber) over(partition by Id) then 'Keep'
else 'Old' end Action
from sampledata;
I like using Common Table Expressions (CTEs) for this
--get the max value
;with CN as (select max(ContractNumber) as MaxContractNumber, ID
FROM [SampleDb].[dbo].[SampleDataforSO]
group by ID,ContractNumber)
--loop through and assign the relevant action item for the max value
select s.ID, s.ContractNumber,
case
when ContractNumber < max(MaxContractNumber) then 'Old'
when ContractNumber = max(MaxContractNumber) then 'Keep'
end as 'Action'
from CN
join [SampleDb].[dbo].[SampleDataforSO] s
on s.ID = cn.ID
group by s.id, ContractNumber
output:
Related
I am trying to design a database of customer details. Where customers can have up to two different phone numbers.
When I run the Select * command to bring out the customers that match criteria, I get this:
Name | Number
James | 12344532
James | 23232422
I would like it to display all customers with two numbers this way:
Name | Number | Number
James 12344532 23232422
John 32443322
Jude 12121212 23232422
I am using Postgresql server on Azure Data studio.
Please assist.
I tried using this command:
Select * FROM name.name,
min(details.number) AS number1,
max(details.number) AS number2
FROM name
JOIN details
ON name.id=details.id
GROUP BY name.name
I got this:
Name | Number | Number
James 12344532 23232422
John 32443322 32443322
Jude 12121212 23232422
Customers with just 1 phone number gets duplicated in the table. How do I go about this?
I would aggregate the numbers into an array, then extract the array elements:
select n.name,
d.numbers[1] as number_1,
d.numbers[2] as number_2
from name n
join (
select id, array_agg(number) as numbers
from details
group by id
) d on d.id = n.id
order by name;
This is also easy to extend if you have more than two numbers.
Try using the following query:
SELECT
Name,
MIN(CASE WHEN rn = 1 THEN Number END) AS Number1,
MIN(CASE WHEN rn = 2 THEN Number END) AS Number2
FROM
(SELECT
Name, Number,
ROW_NUMBER() OVER (PARTITION BY Name ORDER BY Number) AS rn
FROM name) t
GROUP BY Name
This query will use the ROW_NUMBER() function to assign a unique row number to each phone number for each customer. The ROW_NUMBER() function is ordered by the Number column, so the lowest number will have a row number of 1, and the second lowest number will have a row number of 2, etc.
Then we use the outer query to group customer by name and use MIN() function to get the first and second number based on the row number.
This query will return the desired output, with two columns, one showing the customer's first phone number and the other showing their second phone number.
Note: The query above assumes that the phone number is unique for each customer. If a customer has duplicate phone numbers, the query will return the first one it encounters.
I have a table as follows
groupCode
ProductIdentifier
1
dental
1
membership
2
dental
2
vision
2
health
3
dental
3
vision
I need to find out if a specific groupCode have "dental", "vision" and "health" (all three simultaneously)
The expected result is code 2
What I need to identify is if groupCode 2 has the three products (or two, or whatever the user enters). This is part of a huge kitchen sink query I'm building.
I'm doing
SELECT groupCode
FROM dbo.table
WHERE (productIdentifier = N'dental')
AND (productIdentifier = N'vision')
AND (productIdentifier = N'health')
AND (groupCode = 2)
But clearly is wrong because it's not working.
I tried to do something like its described here but it didn't return a result for me:
Select rows with same id but different value in another column
Thanks.
If each of 'dental','vision' and 'health' occur only once per group identifier, you can group by group identifier and filter by the groups having count(*) = 3:
WITH
-- your input ..
indata(groupCode,ProductIdentifier) AS (
SELECT 1,'dental'
UNION ALL SELECT 1,'membership'
UNION ALL SELECT 2,'dental'
UNION ALL SELECT 2,'vision'
UNION ALL SELECT 2,'health'
UNION ALL SELECT 3,'dental'
UNION ALL SELECT 3,'vision'
)
-- real query starts here ...
SELECT
groupcode
FROM indata
WHERE productidentifier IN ('dental','vision','health')
GROUP BY
groupcode
HAVING COUNT(*) = 3;
-- out groupcode
-- out -----------
-- out 2
As per Marcothesane answer, if you know the groupCode (2) and the number of products (vision, dental and health), 3 in this case, and you need to confirm if that code has those three specific products, this will work for you:
SELECT COUNT(groupCode) AS totalRecords
FROM dbo.table
WHERE (groupCode = 2) AND (productIdentifier IN ('dental', 'vision', 'health'))
HAVING (COUNT(groupCode) = 3)
This will return 3 (number of records = number of products).
Its basically's Marcothesane answer in a way you can "copy/paste" to your code by just changing the table name. You should accept Marcothesane answer.
I have a requirement in which I have two main fields Amount CR and Amount DR.
Now the requirement is that this both amounts have different values like Trx Number, Bank Name ETC but have a common Reference Number.
There is only one record for every Refrence Number with a CR Amount, DR Amount respectivly.
For detaila see the table below:
Transaction Number
Bank Name
Reference Number
CR Amount
DR Amount
1
XYZ
1234
1000
2
ABC
1234
1000
3
DEF
1111
1000
4
TEST
1111
2300
So basically I want to compare CR and DR Amount based on the Reference Number. In the example Reference Number 1234 is ok and Reference Number 1111 should be listed.
How can I achieve this by an Oracle query?
Knowing that there is exactly one record with dr and one with cr amount you can make a self join over the reference number.
The 2 Trransactions for a Reference Number will be listed in one row:
select * from table t1
inner join table t2 on t1.referencenumber = t2.referencenumber
and t1.cr_amount is not null
and t2.dr_amount is not null
where t1.cr_amount <> t2.dr_amount
Add two analytical aggregated functions calculating the sum of CRand DB per the reference_number and compare them
case when
sum(cr_amount) over (partition by reference_number) =
sum(dr_amount) over (partition by reference_number) then 'Y' else 'N' end is_equ
This identifies the rows with reference_number where the sum is not equal.
In an additional query simple filter only the rows where the not equal sum.
with test as (
select a.*,
case when
sum(cr_amount) over (partition by reference_number) =
sum(dr_amount) over (partition by reference_number) then 'Y' else 'N' end is_equ
from tab a)
select
TRANSACTION_NUMBER, BANK_NAME, REFERENCE_NUMBER, CR_AMOUNT, DR_AMOUNT
from test
where is_equ = 'N'
TRANSACTION_NUMBER BANK REFERENCE_NUMBER CR_AMOUNT DR_AMOUNT
------------------ ---- ---------------- ---------- ----------
3 DEF 1111 1000
4 TEST 1111 2300
You can aggregate and use a case expression:
select reference_number,
sum(cr_amount), sum(db_amount),
(case when sum(cr_amount) = sum(db_amount)
then 'same' else 'different'
end)
from t
group by reference_number;
I am writing a query which fetches details from different tables. In one column I want to print count value of a column. If the count value of the column is greater than 1, I want to print the count of the column else I want to print value in the field.
I want to build a query which will give me count of user_id from table 1 & 2. if the count user_id is greater than 1, then print count (user_id) else print value of user_id
Table:1
| user_id |
| John |
| Bob |
| Kris |
| Tom |
Table:2
| user_id |
| Rob |
query result should list count of table1 as it greater than 1. Table2 should list Rob as it is lesser than 2
You want to select user IDs (names actually) from a table. If it's just one row then show that name, otherwise show the number of entries instead. So, just use a CASE expression to check whether count is 1 or greater than 1.
You probably need CAST or CONVERT to turn the count number into a string, so the CASE expression always returns the same type (this is how CASE works).
select
case when count(*) > 1
then cast(count(*) as varchar(100))
else max(user_id)
end as name_or_count
from mytable
Window Functions come to mind but since your user_ids are not numbers, you'll run into an issue where you can't have two different data types in the same column. See how this works for you. Make sure to cast the varchar numbers back to integer if this script is part of a larger process.
with cte as
(select 'John' as user_id union all
select 'Bob' as user_id union all
select 'Kris' as user_id union all
select 'Tom' as user_id)
select distinct case when count(*) over() > 1
then cast(count(*) over() as varchar) else user_id end
from cte
with cte as
(select 'Rob' as user_id)
select distinct case when count(*) over() > 1
then cast(count(*) over() as varchar) else user_id end
from cte
I've been stuck for quite a while now trying to get this query to work.
Here's the setup:
I have a [Notes] table that contains a nonunique (Number) column and a nonunique (Result) column. I'm looking to create a SELECT statement that will display each distinct (Number) value where the count of the {(Number), (Result)} tuple where Result = 'NA' is > 25.
Number | Result
100 | 'NA'
100 | 'TT'
101 | 'NA'
102 | 'AM'
100 | 'TT'
200 | 'NA'
200 | 'NA'
201 | 'NA'
Basically, have an autodialer that calls a number and returns a code depending on the results of the call. We want to ignore numbers that have had an 'NA'(no answer) code returned more than 25 times.
My basic attempts so far have been similar to:
SELECT DISTINCT n1.Number
FROM Notes n1
WHERE (SELECT COUNT(*) FROM Notes n2
WHERE n1.Number = n2.Number and n1.Result = 'NA') > 25
I know this query isn't correct, but in general I'm not sure how to relate the DISTINCT n1.Number from the initial select to the Number used in the subquery COUNT. Most examples I see aren't actually doing this by adding a condition to the COUNT returned. I haven't had to touch too much SQL in the past half decade, so I'm quite rusty.
you can do it like this :
SELECT Number
FROM Notes
WHERE Result = 'NA'
GROUP BY Number
HAVING COUNT(Result) > 25
Try this:
SELECT Number
FROM (
SELECT Number, Count(Result) as CountNA
FROM Notes
WHERE Result = 'NA'
GROUP BY Number
)
WHERE CountNA > 25
EDIT: depending on SQL product, you may need to give the derived table a table correlation name e.g.
SELECT DT1.Number
FROM (
SELECT Number, Count(Result) as CountNA
FROM Notes
WHERE Result = 'NA'
GROUP
BY Number
) AS DT1 (Number, CountNA)
WHERE DT1.CountNA > 25;