Assume i have a table called MyTable and this table have a JSON type column called myjson and this column have next value as a json array hold multiple objects, for example like next:
[
{
"budgetType": "CF",
"financeNumber": 1236547,
"budget": 1000000
},
{
"budgetType": "ENVELOPE",
"financeNumber": 1236888,
"budget": 2000000
}
]
So how i can search if the record has any JSON objects inside its JSON array with financeNumber=1236547
Something like this:
SELECT
t.*
FROM
"MyTable",
LATERAL json_to_recordset(myjson) AS t ("budgetType" varchar,
"financeNumber" int,
budget varchar)
WHERE
"financeNumber" = 1236547;
Obviously not tested on your data, but it should provide a starting point.
with a as(
SELECT json_array_elements(myjson)->'financeNumber' as col FROM mytable)
select exists(select from a where col::text = '1236547'::text );
https://www.postgresql.org/docs/current/functions-json.html
json_array_elements return setof json, so you need cast.
Check if a row exists: Fastest check if row exists in PostgreSQL
Related
I have a JSON file (array of objects) which I have to convert into a table format using a PostgreSQL query.
Follow Sample Data.
"b", "c", "d", "e" are to be extracted as separate tables as they are arrays and in these arrays, there are objects
I have tried using json_populate_recordset() but it only works if I have a single array.
[{a:"1",b:"2"},{a:"10",b:"20"}]
I have referred to some links and codes.
jsonb_array_element example
postgreSQL functions
Expected Output
Sample Data:
{
"b":[
{columnB1:value, columnB2:value},
{columnB1:value, columnB2:value},
],
"c":[
{columnC1:value, columnC2:value, columnC3:value},
{columnC1:value, columnC2:value, columnC3:value},
{columnC1:value, columnC2:value, columnC3:value}
],
"d":[
{columnD1:value, columnD2:value},
{columnD1:value, columnD2:value},
],
"e":[
{columnE1:value, columnE2:value},
]
}
expected output
b should be one table in which columnA1 and columnA2 are displayed with their values.
Similarly table c, d, e with their respective columns and values.
Expected Output
You can use jsonb_to_recordset() but you need to unnest your JSON. You need to do this inline as this is a JSON Processing Function which cannot used derived values.
I am using validated JSON as simplified and formatted at end of this answer
To unnest your JSON use below notation which extracts JSON object field with the given key.
--one level
select '{"a":1}'::json->'a'
result : 1
--two levels
select '{"a":{"b":[2]}}'::json->'a'->'b'
result : [2]
We now expand this to include json_to_recordset()
select * from
json_to_recordset(
'{"a":{"b":[{"f1":2,"f2":4},{"f1":3,"f2":6}]}}'::json->'a'->'b' --inner table b
)
as x("f1" int, "f2" int); --fields from table b
or using json_array_elements. Either way we need to list our fields. With second solution type will be json not int so you cant sum etc
with b as (select json_array_elements('{"a":{"b":[{"f1":2,"f2":4},{"f1":3,"f2":6}]}}'::json->'a'->'b') as jx)
select jx->'f1' as f1, jx->'f2' as f2 from b;
Output
f1 f2
2 4
3 6
We now use your data structure in jsonb_to_recordset()
select * from jsonb_to_recordset( '{"a":{"b":[{"columnname1b":"value1b","columnname2b":"value2b"},{"columnname1b":"value","columnname2b":"value"}],"c":[{"columnname1":"value","columnname2":"value"},{"columnname1":"value","columnname2":"value"},{"columnname1":"value","columnname2":"value"}]}}'::jsonb->'a'->'b') as x(columnname1b text, columnname2b text);
Output:
columnname1b columnname2b
value1b value2b
value value
For table c
select * from jsonb_to_recordset( '{"a":{"b":[{"columnname1b":"value1b","columnname2b":"value2b"},{"columnname1b":"value","columnname2b":"value"}],"c":[{"columnname1":"value","columnname2":"value"},{"columnname1":"value","columnname2":"value"},{"columnname1":"value","columnname2":"value"}]}}'::jsonb->'a'->'c') as x(columnname1 text, columnname2 text);
Output
columnname1 columnname2
value value
value value
value value
Sample JSON
{
"a": {
"b": [
{
"columnname1b": "value1b",
"columnname2b": "value2b"
},
{
"columnname1b": "value",
"columnname2b": "value"
}
],
"c": [
{
"columnname1": "value",
"columnname2": "value"
},
{
"columnname1": "value",
"columnname2": "value"
},
{
"columnname1": "value",
"columnname2": "value"
}
]
}
}
Well, I came up with some ideas, here is one that worked. I was able to get one table at a time.
https://www.postgresql.org/docs/9.5/functions-json.html
I am using json_populate_recordset.
The column used in the first select statement comes from a table whose column is a JSON type which we are trying to extract into a table.
The 'tablename from column' in the json_populate_recordset function, is the table we are trying to extract followed with b its columns and datatypes.
WITH input AS(
SELECT cast(column as json) as a
FROM tablename
)
SELECT b.*
FROM input c,
json_populate_recordset(NULL::record,c.a->'tablename from column') as b(columnname1 datatype, columnname2 datatype)
I have a table mytable and a JSONB column employees that contains data like this:
[ {
"name":"Raj",
"email":"raj#gmail.com",
"age":32
},
{
"name":"Mohan",
"email":"Mohan#yahoo.com",
"age":21
}
]
I would like to extract only the names and save them in a list format, so the resulting cell would look like this:
['Raj','Mohan']
I have tried
select l1.obj ->> 'name' names
from mytable t
cross join jsonb_array_elements(t.employees) as l1(obj)
but this only returns the name of the first array element.
How do I get the name of all array elements?
Thanks!
PostgreSQL 11.8
In Postgres 12, you can use jsonb_path_query_array():
select jsonb_path_query_array(employees, '$[*].name') as names
from mytable
In earlier versions you need to unnest then aggregate back:
select (select jsonb_agg(e -> 'name')
from jsonb_array_elements(employees) as t(e)) as names
from mytable
I have the following JSON stored in a PostgreSQL JSON column
{
"status": "Success",
"message": "",
"data": {
"serverIp": "XXXX",
"ruleId": 32321,
"results": [
{
"versionId": 555555,
"PriceID": "8abf35ec-3e0e-466b-a4e5-2af568e90eec",
"price": 550,
"Convert": 0.8922953080331764,
"Cost": 10
}
]
}
}
I would like to search for a specific priceID across the entire JSON column (name info) and select the entire results element by the PriceID.
How do i do that in postgresql JSON?
One option uses exists and json(b)_array_elements(). Assuming that your table is called mytable and that the jsonb column is mycol, this would look like:
select t.*
from mytable t
where exists (
select 1
from jsonb_array_elements(t.mycol -> 'data' -> 'results') x(elt)
where x.elt ->> 'PriceID' = '8abf35ec-3e0e-466b-a4e5-2af568e90eec'
)
In the subquery, jsonb_array_elements() unnest the json array located at the given path. Then, the where clause ensures that at least one elment in the array has the given PriceID.
If your data is of json datatype rather than jsonb, you need to use json_array_elements() instead of jsonb_array_elements().
If you want to display some information coming from the matching array element, then it is different. You can use a lateral join instead of exists. Keep in mind, though, that this will duplicate the rows if more than one array element matches:
select t.*, x.elt ->> 'price' price
from mytable t
cross join lateral jsonb_array_elements(t.mycol -> 'data' -> 'results') x(elt)
where x.elt ->> 'PriceID' = '8abf35ec-3e0e-466b-a4e5-2af568e90eec'
I have the below sample JSON:
{
"Id1": {
"name": "Item1.jpg",
"Status": "Approved"
},
"Id2": {
"name": "Item2.jpg",
"Status": "Approved"
}
}
and I am trying to get the following output:
_key name Status
Id1 Item1.jpg Approved
Id2 Item2.jpg Approved
Is there any way I can achieve this in Snowflake using SQL?
You should use Snowflake's VARIANT data type in any column holding JSON data. Let's break this down step by step:
create temporary table FOO(v variant); -- Temp table to hold the JSON. Often you'll see a variant column simply called "V"
-- Insert into the variant column. Parse the JSON because variants don't hold string types. They hold semi-structured types.
insert into FOO select parse_json('{"Id1": {"name": "Item1.jpg", "Status": "Approved"}, "Id2": {"name": "Item2.jpg", "Status": "Approved"}}');
-- See how it looks in its raw state
select * from FOO;
-- Flatten the top-level JSON. The flatten function breaks down the JSON into several usable columns
select * from foo, lateral flatten(input => (foo.v)) ;
-- Now traverse the JSON using the column name and : to get to the property you want. Cast to string using ::string.
-- If you must have exact case on your column names, you need to double quote them.
select KEY as "_key",
VALUE:name::string as "name",
VALUE:Status::string as "Status"
from FOO, lateral flatten(input => (FOO.V)) ;
I have searched extensively (in Postgres docs and on Google and SO) to find examples of JSON functions being used on actual JSON columns in a table.
Here's my problem: I am trying to extract key values from an array of JSON objects in a column, using jsonb_to_recordset(), but get syntax errors. When I pass the object literally to the function, it works fine:
Passing JSON literally:
select *
from jsonb_to_recordset('[
{ "id": 0, "name": "400MB-PDF.pdf", "extension": ".pdf",
"transferId": "ap31fcoqcajjuqml6rng"},
{ "id": 0, "name": "1000MB-PDF.pdf", "extension": ".pdf",
"transferId": "ap31fcoqcajjuqml6rng"}
]') as f(name text);`
results in:
400MB-PDF.pdf
1000MB-PDF.pdf
It extracts the value of the key "name".
Here's the JSON in the column, being extracted using:
select journal.data::jsonb#>>'{context,data,files}'
from journal
where id = 'ap32bbofopvo7pjgo07g';
resulting in:
[ { "id": 0, "name": "400MB-PDF.pdf", "extension": ".pdf",
"transferId": "ap31fcoqcajjuqml6rng"},
{ "id": 0, "name": "1000MB-PDF.pdf", "extension": ".pdf",
"transferId": "ap31fcoqcajjuqml6rng"}
]
But when I try to pass jsonb#>>'{context,data,files}' to jsonb_to_recordset() like this:
select id,
journal.data::jsonb#>>::jsonb_to_recordset('{context,data,files}') as f(name text)
from journal
where id = 'ap32bbofopvo7pjgo07g';
I get a syntax error. I have tried different ways but each time it complains about a syntax error:
Version:
PostgreSQL 9.4.10 on x86_64-unknown-linux-gnu, compiled by gcc (Ubuntu 4.8.2-19ubuntu1) 4.8.2, 64-bit
The expressions after select must evaluate to a single value. Since jsonb_to_recordset returns a set of rows and columns, you can't use it there.
The solution is a cross join lateral, which allows you to expand one row into multiple rows using a function. That gives you single rows that select can act on. For example:
select *
from journal j
cross join lateral
jsonb_to_recordset(j.data#>'{context, data, files}') as d(id int, name text)
where j.id = 'ap32bbofopvo7pjgo07g'
Note that the #>> operator returns type text, and the #> operator returns type jsonb. As jsonb_to_recordset expects jsonb as its first parameter I'm using #>.
See it working at rextester.com
jsonb_to_recordset is a set-valued function and can only be invoked in specific places. The FROM clause is one such place, which is why your first example works, but the SELECT clause is not.
In order to turn your JSON array into a "table" that you can query, you need to use a lateral join. The effect is rather like a foreach loop on the source recordset, and that's where you apply the jsonb_to_recordset function. Here's a sample dataset:
create table jstuff (id int, val jsonb);
insert into jstuff
values
(1, '[{"outer": {"inner": "a"}}, {"outer": {"inner": "b"}}]'),
(2, '[{"outer": {"inner": "c"}}]');
A simple lateral join query:
select id, r.*
from jstuff
join lateral jsonb_to_recordset(val) as r("outer" jsonb) on true;
id | outer
----+----------------
1 | {"inner": "a"}
1 | {"inner": "b"}
2 | {"inner": "c"}
(3 rows)
That's the hard part. Note that you have to define what your new recordset looks like in the AS clause -- since each element in our val array is a JSON object with a single field named "outer", that's what we give it. If your array elements contain multiple fields you're interested in, you declare those in a similar manner. Be aware also that your JSON schema needs to be consistent: if an array element doesn't contain a key named "outer", the resulting value will be null.
From here, you just need to pull the specific value you need out of each JSON object using the traversal operator as you were. If I wanted only the "inner" value from the sample dataset, I would specify select id, r.outer->>'inner'. Since it's already JSONB, it doesn't require casting.