This question already has answers here:
How to split comma-separated values?
(5 answers)
Split values in parts with sqlite
(2 answers)
Closed 12 months ago.
I have been trying to convert split_string syntax to SQLite from SQL Server. I couldn't find any alternative to do that. can anyone please help me to do that.
SELECT row_number () over (order by (select 0)) rn, value
FROM string_split(Nav_Path,''/'')
This is the SQL query that needs to write in SQLite. There is syntax error saying
Transaction ERROR: sqlite3_prepare_v2 failure: no such table: string_split
Thank you
Related
This question already has answers here:
Simple Postgresql Statement - column name does not exists
(2 answers)
cannot get simple PostgreSQL insert to work
(4 answers)
PostgreSQL error: Column "MANAGER" does not exist [duplicate]
(1 answer)
What is the difference between single quotes and double quotes in PostgreSQL?
(3 answers)
Closed 3 years ago.
My simple WHERE query is not working. It says column "Exception" does not exist, but the column it type, that is only a value.
SQL Query:
select * from logs
where type = "Exception"
As S-Man commented the answer is:
" characters are for column names. You have to use ' characters.
Try this one:
SELECT *
FROM
logs
WHERE
type = 'Exception'
This question already has answers here:
ListAGG in SQLSERVER
(4 answers)
Simulating group_concat MySQL function in Microsoft SQL Server 2005?
(12 answers)
Closed 6 years ago.
I would like to convert this construction from oracle syntaxis to mssql.
SELECT
cs.id,
LISTAGG(w.WonderNumber, '|')
WITHIN GROUP (
ORDER BY w.WonderNumber) AS Wonder
FROM
CasaS cs
I have tried approaches with FOR XML PATH but didn't completely understand this. Could you please show solution with explanations. Thanks in advance!
This question already has answers here:
Concatenate results from a SQL query in Oracle
(7 answers)
Closed 6 years ago.
Lets say, I have following table(i.e: Reference Table). I want to display my results as 'Expected Table'. How may I get this result? Any help will be highly appreciated. I am using Oracle 10g.
Expected:
SELECT Collateral_Id,
LISTAGG(Commitment_Id, ',')
WITHIN GROUP (ORDER BY Commitment_Id) "Commitment_Id"
FROM yourTable
GROUP BY Collateral_Id
This question already has answers here:
How to get Oracle create table statement in SQL*Plus
(3 answers)
Closed 7 years ago.
I'm new to sql and I have created table using create table table_name.
And now I want to get this table definition or let's say source code, I know command desc table_name but that's not what I want. Could you help me figure it out?
Check the function: DBMS_METADATA.GET_DDL
http://psoug.org/reference/dbms_metadata.html
This question already has answers here:
Missing Expression when selecting all columns and one more
(2 answers)
Closed 9 years ago.
When a test with SQL Navigator(it's work fine):
select userid,* from user_ ;
but with sql developer, it get an error: ORA-00936: missing expression
Please explain me why SQL Navigator can but SQL Developer can not, and explain me why what is wrong here.
This question may be similar to sql-Missi.... question, but not true.
Thank for your suggestion !
try this,
select userid, user_.* from user_
SQLFiddle Demo