Pyspark: Parquet tables visible in SQL? - sql

I am fairly new to PySpark/Hive and I have a problem:
I have a dataframe and want to write it as a paritioned table to HDFS. So far, I've done that via:
df = spark.sql('''
CREATE EXTERNAL TABLE database.df(
ID STRING
)
PARTITIONED BY (
DATA_DATE_PART STRING
)
STORED AS PARQUET
LOCATION 'hdfs://path/file'
''')
df.createOrReplaceTempView("df")
df = spark.sql('''
INSERT INTO database.df PARTITION(DATA_DATE_PART = '{}')
SELECT ID
FROM df
'''.format(date))
But as with growing dataframes, instead of having to define all columns, I thought there is a better solution to this:
df.write.mode('overwrite').partitionBy('DATA_DATE_PART').parquet("/path/file")
However, a table like this I cannot access via spark.sql nor see it in my HUE browser. I can see it though via PySpark shell: hdfs dfs -ls /path/
So my question, why is that? I've read that parquet files can be special when reading with SQL but my first script does well and the tables are visible everywhere.

You just need to use saveAsTable function for that (doc). By default it stores data in the default location, but you can use the path option to redefine it & make a table "unmanaged" (see this doc for more details). Just use following code:
df.write.mode('overwrite').partitionBy('DATA_DATE_PART') \
.format("parquet") \
.option("path", "/path/file") \
.saveAsTable("database.df")

Related

How to load large csv files with lots of columns into a database at Postgresql using command shell? [duplicate]

How can I write a stored procedure that imports data from a CSV file and populates the table?
Take a look at this short article.
The solution is paraphrased here:
Create your table:
CREATE TABLE zip_codes
(ZIP char(5), LATITUDE double precision, LONGITUDE double precision,
CITY varchar, STATE char(2), COUNTY varchar, ZIP_CLASS varchar);
Copy data from your CSV file to the table:
COPY zip_codes FROM '/path/to/csv/ZIP_CODES.txt' WITH (FORMAT csv);
If you don't have permission to use COPY (which work on the db server), you can use \copy instead (which works in the db client). Using the same example as Bozhidar Batsov:
Create your table:
CREATE TABLE zip_codes
(ZIP char(5), LATITUDE double precision, LONGITUDE double precision,
CITY varchar, STATE char(2), COUNTY varchar, ZIP_CLASS varchar);
Copy data from your CSV file to the table:
\copy zip_codes FROM '/path/to/csv/ZIP_CODES.txt' DELIMITER ',' CSV
Mind that \copy ... must be written in one line and without a ; at the end!
You can also specify the columns to read:
\copy zip_codes(ZIP,CITY,STATE) FROM '/path/to/csv/ZIP_CODES.txt' DELIMITER ',' CSV
See the documentation for COPY:
Do not confuse COPY with the psql instruction \copy. \copy invokes COPY FROM STDIN or COPY TO STDOUT, and then fetches/stores the data in a file accessible to the psql client. Thus, file accessibility and access rights depend on the client rather than the server when \copy is used.
And note:
For identity columns, the COPY FROM command will always write the column values provided in the input data, like the INSERT option OVERRIDING SYSTEM VALUE.
One quick way of doing this is with the Python Pandas library (version 0.15 or above works best). This will handle creating the columns for you - although obviously the choices it makes for data types might not be what you want. If it doesn't quite do what you want you can always use the 'create table' code generated as a template.
Here's a simple example:
import pandas as pd
df = pd.read_csv('mypath.csv')
df.columns = [c.lower() for c in df.columns] # PostgreSQL doesn't like capitals or spaces
from sqlalchemy import create_engine
engine = create_engine('postgresql://username:password#localhost:5432/dbname')
df.to_sql("my_table_name", engine)
And here's some code that shows you how to set various options:
# Set it so the raw SQL output is logged
import logging
logging.basicConfig()
logging.getLogger('sqlalchemy.engine').setLevel(logging.INFO)
df.to_sql("my_table_name2",
engine,
if_exists="append", # Options are ‘fail’, ‘replace’, ‘append’, default ‘fail’
index = False, # Do not output the index of the dataframe
dtype = {'col1': sqlalchemy.types.NUMERIC,
'col2': sqlalchemy.types.String}) # Datatypes should be SQLAlchemy types
Most other solutions here require that you create the table in advance/manually. This may not be practical in some cases (e.g., if you have a lot of columns in the destination table). So, the approach below may come handy.
Providing the path and column count of your CSV file, you can use the following function to load your table to a temp table that will be named as target_table:
The top row is assumed to have the column names.
create or replace function data.load_csv_file
(
target_table text,
csv_path text,
col_count integer
)
returns void as $$
declare
iter integer; -- dummy integer to iterate columns with
col text; -- variable to keep the column name at each iteration
col_first text; -- first column name, e.g., top left corner on a csv file or spreadsheet
begin
create table temp_table ();
-- add just enough number of columns
for iter in 1..col_count
loop
execute format('alter table temp_table add column col_%s text;', iter);
end loop;
-- copy the data from csv file
execute format('copy temp_table from %L with delimiter '','' quote ''"'' csv ', csv_path);
iter := 1;
col_first := (select col_1 from temp_table limit 1);
-- update the column names based on the first row which has the column names
for col in execute format('select unnest(string_to_array(trim(temp_table::text, ''()''), '','')) from temp_table where col_1 = %L', col_first)
loop
execute format('alter table temp_table rename column col_%s to %s', iter, col);
iter := iter + 1;
end loop;
-- delete the columns row
execute format('delete from temp_table where %s = %L', col_first, col_first);
-- change the temp table name to the name given as parameter, if not blank
if length(target_table) > 0 then
execute format('alter table temp_table rename to %I', target_table);
end if;
end;
$$ language plpgsql;
You could also use pgAdmin, which offers a GUI to do the import. That's shown in this SO thread. The advantage of using pgAdmin is that it also works for remote databases.
Much like the previous solutions though, you would need to have your table on the database already. Each person has his own solution, but I usually open the CSV file in Excel, copy the headers, paste special with transposition on a different worksheet, place the corresponding data type on the next column, and then just copy and paste that to a text editor together with the appropriate SQL table creation query like so:
CREATE TABLE my_table (
/* Paste data from Excel here for example ... */
col_1 bigint,
col_2 bigint,
/* ... */
col_n bigint
)
COPY table_name FROM 'path/to/data.csv' DELIMITER ',' CSV HEADER;
Create a table first
Then use the copy command to copy the table details:
copy table_name (C1,C2,C3....)
from 'path to your CSV file' delimiter ',' csv header;
NOTE:
columns and order are specified by C1,C2,C3.. in SQL
The header option just skips one line from the input, not according to columns' name.
As Paul mentioned, import works in pgAdmin:
Right-click on table → Import
Select a local file, format and coding.
Here is a German pgAdmin GUI screenshot:
A similar thing you can do with DbVisualizer (I have a license and am not sure about free version).
Right-click on a table → Import Table Data...
Use this SQL code:
copy table_name(atribute1,attribute2,attribute3...)
from 'E:\test.csv' delimiter ',' csv header
The header keyword lets the DBMS know that the CSV file have a header with attributes.
For more, visit Import CSV File Into PostgreSQL Table.
This is a personal experience with PostgreSQL, and I am still waiting for a faster way.
Create a table skeleton first if the file is stored locally:
drop table if exists ur_table;
CREATE TABLE ur_table
(
id serial NOT NULL,
log_id numeric,
proc_code numeric,
date timestamp,
qty int,
name varchar,
price money
);
COPY
ur_table(id, log_id, proc_code, date, qty, name, price)
FROM '\path\xxx.csv' DELIMITER ',' CSV HEADER;
When the \path\xxx.csv file is on the server, PostgreSQL doesn't have the
permission to access the server. You will have to import the .csv file through the pgAdmin built in functionality.
Right click the table name and choose import.
If you still have the problem, please refer this tutorial: Import CSV File Into PostgreSQL Table
How to import CSV file data into a PostgreSQL table
Steps:
Need to connect a PostgreSQL database in the terminal
psql -U postgres -h localhost
Need to create a database
create database mydb;
Need to create a user
create user siva with password 'mypass';
Connect with the database
\c mydb;
Need to create a schema
create schema trip;
Need to create a table
create table trip.test(VendorID int,passenger_count int,trip_distance decimal,RatecodeID int,store_and_fwd_flag varchar,PULocationID int,DOLocationID int,payment_type decimal,fare_amount decimal,extra decimal,mta_tax decimal,tip_amount decimal,tolls_amount int,improvement_surcharge decimal,total_amount
);
Import csv file data to postgresql
COPY trip.test(VendorID int,passenger_count int,trip_distance decimal,RatecodeID int,store_and_fwd_flag varchar,PULocationID int,DOLocationID int,payment_type decimal,fare_amount decimal,extra decimal,mta_tax decimal,tip_amount decimal,tolls_amount int,improvement_surcharge decimal,total_amount) FROM '/home/Documents/trip.csv' DELIMITER ',' CSV HEADER;
Find the given table data
select * from trip.test;
You can also use pgfutter, or, even better, pgcsv.
These tools create the table columns from you, based on the CSV header.
pgfutter is quite buggy, and I'd recommend pgcsv.
Here's how to do it with pgcsv:
sudo pip install pgcsv
pgcsv --db 'postgresql://localhost/postgres?user=postgres&password=...' my_table my_file.csv
In Python, you can use this code for automatic PostgreSQL table creation with column names:
import pandas, csv
from io import StringIO
from sqlalchemy import create_engine
def psql_insert_copy(table, conn, keys, data_iter):
dbapi_conn = conn.connection
with dbapi_conn.cursor() as cur:
s_buf = StringIO()
writer = csv.writer(s_buf)
writer.writerows(data_iter)
s_buf.seek(0)
columns = ', '.join('"{}"'.format(k) for k in keys)
if table.schema:
table_name = '{}.{}'.format(table.schema, table.name)
else:
table_name = table.name
sql = 'COPY {} ({}) FROM STDIN WITH CSV'.format(table_name, columns)
cur.copy_expert(sql=sql, file=s_buf)
engine = create_engine('postgresql://user:password#localhost:5432/my_db')
df = pandas.read_csv("my.csv")
df.to_sql('my_table', engine, schema='my_schema', method=psql_insert_copy)
It's also relatively fast. I can import more than 3.3 million rows in about 4 minutes.
You can create a Bash file as import.sh (that your CSV format is a tab delimiter):
#!/usr/bin/env bash
USER="test"
DB="postgres"
TBALE_NAME="user"
CSV_DIR="$(pwd)/csv"
FILE_NAME="user.txt"
echo $(psql -d $DB -U $USER -c "\copy $TBALE_NAME from '$CSV_DIR/$FILE_NAME' DELIMITER E'\t' csv" 2>&1 |tee /dev/tty)
And then run this script.
You can use the Pandas library if the file is not very large.
Be careful when using iter over Pandas dataframes. I am doing this here to demonstrate the possibility. One could also consider the pd.Dataframe.to_sql() function when copying from a dataframe to an SQL table.
Assuming you have created the table you want, you could:
import psycopg2
import pandas as pd
data=pd.read_csv(r'path\to\file.csv', delimiter=' ')
#prepare your data and keep only relevant columns
data.drop(['col2', 'col4','col5'], axis=1, inplace=True)
data.dropna(inplace=True)
print(data.iloc[:3])
conn=psycopg2.connect("dbname=db user=postgres password=password")
cur=conn.cursor()
for index,row in data.iterrows():
cur.execute('''insert into table (col1,col3,col6)
VALUES (%s,%s,%s)''', (row['col1'], row['col3'], row['col6'])
cur.close()
conn.commit()
conn.close()
print('\n db connection closed.')
DBeaver Community Edition (dbeaver.io) makes it trivial to connect to a database, then import a CSV file for upload to a PostgreSQL database. It also makes it easy to issue queries, retrieve data, and download result sets to CSV, JSON, SQL, or other common data formats.
It is a FOSS multi-platform database tool for SQL programmers, DBAs and analysts that supports all popular databases: MySQL, PostgreSQL, SQLite, Oracle, DB2, SQL Server, Sybase, MS Access, Teradata, Firebird, Hive, Presto, etc. It's a viable FOSS competitor to TOAD for Postgres, TOAD for SQL Server, or Toad for Oracle.
I have no affiliation with DBeaver. I love the price (FREE!) and full functionality, but I wish they would open up this DBeaver/Eclipse application more and make it easy to add analytics widgets to DBeaver / Eclipse, rather than requiring users to pay for the $199 annual subscription just to create graphs and charts directly within the application. My Java coding skills are rusty and I don't feel like taking weeks to relearn how to build Eclipse widgets, (only to find that DBeaver has probably disabled the ability to add third-party widgets to the DBeaver Community Edition.)
You have 3 options to import CSV files to PostgreSQL:
First, using the COPY command through the command line.
Second, using the pgAdmin tool’s import/export.
Third, using a cloud solution like Skyvia which gets the CSV file from an online location like an FTP source or a cloud storage like Google Drive.
You can check out the article that explains all of these from here.
Create a table and have the required columns that are used for creating a table in the CSV file.
Open postgres and right click on the target table which you want to load. Select import and Update the following steps in the file options section
Now browse your file for the filename
Select CSV in format
Encoding as ISO_8859_5
Now go to Misc. options. Check header and click on import.
If you need a simple mechanism to import from text/parse multiline CSV content, you could use:
CREATE TABLE t -- OR INSERT INTO tab(col_names)
AS
SELECT
t.f[1] AS col1
,t.f[2]::int AS col2
,t.f[3]::date AS col3
,t.f[4] AS col4
FROM (
SELECT regexp_split_to_array(l, ',') AS f
FROM regexp_split_to_table(
$$a,1,2016-01-01,bbb
c,2,2018-01-01,ddd
e,3,2019-01-01,eee$$, '\n') AS l) t;
DBFiddle Demo
I created a small tool that imports csv file into PostgreSQL super easy. It is just a command and it will create and populate the tables, but unfortunately, at the moment, all fields automatically created uses the type TEXT:
csv2pg users.csv -d ";" -H 192.168.99.100 -U postgres -B mydatabase
The tool can be found on https://github.com/eduardonunesp/csv2pg
These are some great answers but over complicated for me. I just need to load in a CSV file into postgreSQL without creating a table first.
Here is my way:
libraries
import pandas as pd
import os
import psycopg2 as pg
from sqlalchemy import create_engine
Use environmental Variable to get your password
password = os.environ.get('PSW')
create our engine
engine = create_engine(f"postgresql+psycopg2://postgres:{password}#localhost:5432/postgres")
The break down of engine requirements:
engine = create_engine(dialect+driver://username:password#host:port/database)
Break Down
postgresql+psycopg2 = dialect+driver
postgres = username
password = password from my environmental variable. You can type in password if needed but not recommended
localhost = host
5432 = port
postgres = database
Get your CSV file path, I had to use an encoding aspect. reason why can be found Here
data = pd.read_csv(r"path, encoding= 'unicode_escape')
Send data to Postgress SQL:
data.to_sql('test', engine, if_exists='replace')
Break Down
test = table name you want table to be
engine = engine created above. AKA our connection
if_exsists = will replace old table if there. Use this with caution.
All Together:
import pandas as pd
import os
import psycopg2 as pg
from sqlalchemy import create_engine
password = os.environ.get('PSW')
engine = create_engine(f"postgresql+psycopg2://postgres:{password}#localhost:5432/postgres")
data = pd.read_csv(r"path, encoding= 'unicode_escape')
data.to_sql('test', engine, if_exists='replace')

How to create a table from a dataframe in SparkR

I am trying to find a way to convert a dataframe into a table to be used in another Databricks notebook. I cannot find any documentation regarding doing this in R.
First, convert R dataframe to SparkR dataframe using SparkR::createDataFrame(R_dataframe). Then use saveAsTable function to save as a permanent table - which can be accessed through other notebooks. SparkR::createOrReplaceTempView will not help if you try to access it from different notebook.
require(SparkR)
data1 <- createDataFrame(output)
saveAsTable(data1, tableName = "default.sample_table", source="parquet", mode="overwrite")
In the above code, default is some existing database name, under which a new table will get created having name as sample_table.

Extract BigQuery partitioned table

Is there a way to extract the complete BigQuery partitioned table with one command so that data of each partition is extracted into a separate folder of the format part_col=date_yyyy-mm-dd
Since Bigquery partitioned table can read files from the hive type partitioned directories, is there a way to extract the data in a similar way. I can extract each partition separately, however that is very cumbersome when i an extracting a lot of partitions
You could do this programmatically. For instance, you can export partitioned data by using the partition decorator such as table$20190801. And then on the bq extract command you can use URI Patterns (look the example of the workers pattern) for the GCS objects.
Since all objects will be within the same bucket, the folders are just an hierarchical illusion, so you can specify URI patterns on the folders as well, but not on the bucket.
So you would do a script where you loop over the DATE value, with something like:
bq extract
--destination_format [CSV, NEWLINE_DELIMITED_JSON, AVRO]
--compression [GZIP, AVRO supports DEFLATE and SNAPPY]
--field_delimiter [DELIMITER]
--print_header [true, false]
[PROJECT_ID]:[DATASET].[TABLE]$[DATE]
gs://[BUCKET]/part_col=[DATE]/[FILENAME]-*.[csv, json, avro]
You can't do it automatically with just a bq command. For this it would be better to raise a feature request as suggested by Felipe.
Set the project as test_dataset using gcloud init before running the below command.
bq extract --destination_format=CSV 'test_partitiontime$20210716' gs://testbucket/20210716/test*.csv
This will create a folder with the name 20210716 inside testbucket and write the file there.

Can I issue a query rather than specify a table when using the BigQuery connector for Spark?

I have used the Use the BigQuery connector with Spark to extract data from a table in BigQuery by running the code on Google Dataproc. As far as I'm aware the code shared there:
conf = {
# Input Parameters.
'mapred.bq.project.id': project,
'mapred.bq.gcs.bucket': bucket,
'mapred.bq.temp.gcs.path': input_directory,
'mapred.bq.input.project.id': 'publicdata',
'mapred.bq.input.dataset.id': 'samples',
'mapred.bq.input.table.id': 'shakespeare',
}
# Output Parameters.
output_dataset = 'wordcount_dataset'
output_table = 'wordcount_output'
# Load data in from BigQuery.
table_data = sc.newAPIHadoopRDD(
'com.google.cloud.hadoop.io.bigquery.JsonTextBigQueryInputFormat',
'org.apache.hadoop.io.LongWritable',
'com.google.gson.JsonObject',
conf=conf)
copies the entirety of the named table into input_directory. The table I need to extract data from contains >500m rows and I don't need all of those rows. Is there a way to instead issue a query (as opposed to specifying a table) so that I can copy a subset of the data from a table?
Doesn't look like BigQuery supports any kind of filtering/querying for tables export at the moment:
https://cloud.google.com/bigquery/docs/exporting-data
https://cloud.google.com/bigquery/docs/reference/rest/v2/jobs#configuration.extract

Rename whitespace in column name in Parquet file using spark sql

I want to show the content of the parquet file using Spark Sql but since the column names in parquet file contains space I am getting error -
Attribute name "First Name" contains invalid character(s) among " ,;{}()\n\t=". Please use alias to rename it.;
I have written below code -
val r1 = spark.read.parquet("filepath")
val r2 = r1.toDF()
r2.select(r2("First Name").alias("FirstName")).show()
but still getting same error
Try and rename the column first instead of aliasing it:
r2 = r2.withColumnRenamed("First Name", "FirstName")
r2.show()
For anyone still looking for an answer,
There is no optimised way to remove spaces from column names while dealing with parquet data.
What can be done is:
Change the column names at the source itself, i.e, while creating the parquet data itself.
OR
(NOT THE OPTIMISED WAY - won't WORK FOR HUGE DATASETS) read the parquet file using pandas and rename the column for the pandas dataframe. If required, write back the dataframe to a parquet using pandas itself and then progress using spark if required.
PS: With the new Pandas API for PySpark scheduled to be present from PySpark 3.2, implementing pandas with spark might be much faster and optimised when dealing with huge datasets.
For anybody struggling with this, the only thing that worked for me was:
for c in df.columns:
df = df.withColumnRenamed(c, c.replace(" ", ""))
df = spark.read.schema(base_df.schema).parquet(filename)
This is from this thread: Spark Dataframe validating column names for parquet writes (scala)
Alias, withColumnRenamed, and "as" sql select statements wouldn't work. Pyspark would still use the old name whenever trying to .show() the dataframe.