how to update array data in jsonb column on database postgresql?
for example on table table1 i have column attribute that have value like this:
id
attribute
1
[{"task_customs": ["a", "b", "c"]}]
2
[{"task_customs": ["d", "e", "f"]}]
for example if i want to delete b from id 1, so it will be like this on attribute column
id
attribute
1
[{"task_customs": ["a", "c"]}]
2
[{"task_customs": ["d", "e", "f"]}]
already do some research but didn't get what i need..
try this :
(a) Delete 'b' acccording to its position in the array :
UPDATE table1
SET attribute = attribute #- array['0', 'task_customs', '1'] :: text[]
WHERE id = 1
(b) Delete 'b' without knowing its position in the array :
WITH list AS
( SELECT id, to_jsonb(array[jsonb_build_object('task_customs', jsonb_agg(i.item ORDER BY item_id))]) AS new_attribute
FROM table1
CROSS JOIN LATERAL jsonb_array_elements_text(attribute#>'{0,task_customs}') WITH ORDINALITY AS i(item,item_id)
WHERE id = 1
AND i.item <> 'b'
GROUP BY id
)
UPDATE table1 AS t
SET attribute = l.new_attribute
FROM list AS l
WHERE t.id = l.id
see the test result in dbfiddle.
One option is to start splitting the JSONB value by using jsonb_to_recordset such as
UPDATE table1 AS t
SET attribute =
(
SELECT json_build_array(
jsonb_build_object('task_customs',task_customs::JSONB - 'b')
)
FROM table1,
LATERAL jsonb_to_recordset(attribute) AS (task_customs TEXT)
WHERE id = t.id
)
WHERE id = 1
Demo
Edit : If you need more elements as expressed within the comment then you can rather prefer using
UPDATE table1 AS t
SET attribute =
(
SELECT jsonb_agg(
jsonb_build_object(key,je.value::JSONB - 'b')
)
FROM table1,
LATERAL jsonb_array_elements_text(attribute) AS atr,
LATERAL jsonb_each_text(atr::JSONB) AS je
WHERE id = t.id
)
WHERE id = 1
Demo
i solve this issue by combining both answer from Edouard and Barbaros
this is my final query
UPDATE table1 AS t
SET attribute =
jsonb_set(
attribute,
'{0,task_customs}',
(
SELECT task_customs::JSONB - 'b'
FROM table1
CROSS JOIN LATERAL jsonb_to_recordset(attribute) AS (task_customs TEXT)
WHERE id = t.id
)
)
WHERE id = 1
see the test result in dbfiddle
Related
Let's say I have a table events with structure:
id
value_array
XXXX
[a,b,c,d]
...
...
I have a second table values_of_interest with structure:
value
x
y
z
a
I want to find id's that have any of the values found in values_of_interest. All else equal, what would be the most performant SQL to make this happen? (I am using BigQuery, but feel free to answer more generally)
My current thought is:
SELECT
DISTINCT e.id
FROM
events e, values_of_interest vi
WHERE
EXISTS(
SELECT
value
FROM
UNNEST(e.value_array) value
JOIN
vi ON vi.value = e.value
)
Few quick options for BigQuery Standard SQL
Option 1
select id
from `project.dataset.events`
where exists (
select 1
from `project.dataset.values_of_interest`
where value in unnest(value_array)
)
Option 2
select id
from `project.dataset.events` t
where (
select count(1)
from t.value_array as value
join `project.dataset.values_of_interest`
using(value)
) > 0
I would write this using exists and a join:
select e.id
from `project.dataset.events` e
where exists (select 1
from unnest(e.value_array) val join
`project.dataset.values_of_interest` voi
on val = voi.value
);
I have tables:
Result containing 5 columns: result_id, num_1, num_2, num_3, num_4
Ref containing 4 columns: num_1, num_2, num_3, num_4
Columns num contain random int in range of 1-9
Aim of exercise is to display all result_id from Result table which have num values combination present in Ref table and to display result_id which have not met combination criteria.
I've been trying left joining ref to result, but unfortunately no success. Could you please share some light how to deal with it?
If you want the result_id for which combination exists in the ref table then use following JOIN query:
select distinct r.result_id
from results r
join ref on r.num_1 = ref.num_1 and r.num_2 = ref.num_2
and r.num_3 = ref.num_3 and r.num_4 = ref.num_4
If you want the result_id for which combination do not exists in REF table then use the LEFT JOIN as follows:
select r.result_id
from results r
left join ref on r.num_1 = ref.num_1 and r.num_2 = ref.num_2
and r.num_3 = ref.num_3 and r.num_4 = ref.num_4
where ref.num_1 is null -- or use PK / Not nullable column of REF table here
Assuming you want the columns to "line up" and you want to add a flag to the result_id in the first table, then use exists:
select t1.*,
(case when exists (select 1
from table2 t2
where t2.n1 = t1.n1 and t2.n2 = t1.n2 and t2.n3 = t1.n3 and t2.n4
)
then 'present' else 'not present'
end) as flag
from t2;
I have a table that looks like this:
ref key val
--------------------------
1 Include Yes
1 Color Green
1 Shape Square
2 Include No
2 Color Red
2 Shape Circle
If an Include key exists with value Yes, I'd like to get all the values with the same ref.
So for the above example the result should be:
ref key val
--------------------------
1 Include Yes
1 Color Green
1 Shape Square
This is what I have so far:
select *
from ref_table
where ref in
(
select ref
from ref_table
where key = 'Include' and val = 'Yes'
)
This also seems to work:
with included
as
(
select ref
from ref_table
where key = 'Include' and val = 'Yes'
)
select *
from ref_table
where ref in
(
select * from included
)
Just wondering if there is a better (simpler) way to do this.
You can use EXISTS() :
SELECT * FROM ref_table t
WHERE EXISTS(SELECT 1 FROM ref_table s
WHERE t.ref = s.ref and s.key = 'Include' and s.val = 'Yes')
I always prefer this method over IN() , most of the time it performs better (exists wait for the first record to return) , it is also more clear for that purpose. IN() can also have problems when it can return NULL values.
Another way is an INNER JOIN :
SELECT t.* FROM ref_table t
INNER JOIN ref_table s
ON(t.ref = s.ref and s.key = 'Include' and s.val = 'Yes')
One more way with OUTER APPLY, but I guess it is not much simpler:
SELECT r.*
FROM ref_table r
OUTER APPLY (
SELECT DISTINCT ref
FROM ref_table
WHERE [key] = 'Include' and val = 'Yes') p
WHERE p.ref = r.ref
I have two tables as follows:
CREATE List (
id INTEGER,
type INTEGER REFERENCES Types(id),
data TEXT,
PRIMARY_KEY(id, type)
);
CREATE Types (
id INTEGER PRIMARY KEY,
name TEXT
);
Now I want to create a query that determines all ids of List which has given type strings.
For example,
List:
1 0 "Some text"
1 1 "Moar text"
2 0 "Foo"
3 1 "Bar"
3 2 "BarBaz"
4 0 "Baz"
4 1 "FooBar"
4 2 "FooBarBaz"
Types:
0 "Key1"
1 "Key2"
2 "Key3"
Given the input "Key1", "Key2", the query should return 1, 4.
Given the input "Key2", "Key3", the query should return 3, 4.
Given the input "Key2", the query should return 1, 3, 4.
Thanks!
select distinct l.id
from list l
inner join types t on t.id = l.type
where t.name in ('key1', 'key2')
group by l.id
having count(distinct t.id) = 2
You have to adjust the having clause to the number of keys you are putting in your where clause. Example for just one key:
select distinct l.id
from list l
inner join types t on t.id = l.type
where t.name in ('key2')
group by l.id
having count(distinct t.id) = 1
SQlFiddle example
You can use the following trick to extend Jurgen's idea:
with keys as (
select distinct t.id
from types t
where t.name in ('key1', 'key2')
)
select l.id
from list l join
keys k
on l.type = keys.id cross join
(select count(*) as keycnt from keys) k
group by l.id
having count(t.id) = max(k.keycnt)
That is, calculate the matching keys in a subquery, and then use this for the counts. This way, you only have to change one line to put in key values, and you can have as many keys as you would like. (Just as a note, I haven't tested this SQL so I apologize for any syntax errors.)
If you can dynamically produce the SQL, this may be one of the most efficent ways, in many DBMS:
SELECT l.id
FROM List l
JOIN Types t1 ON t1.id = l.type
JOIN Types t2 ON t2.id = l.type
WHERE t1.name = 'Key1'
AND t2.name = 'Key2' ;
See this similar question, with more than 10 ways to get the same result, plus some benchmarks (for Postgres): How to filter SQL results in a has-many-through relation
I'm trying to solve the below problem.
I feel like it is possible, but I can't seem to get it.
Here's the scenario:
Table 1 (Assets)
1 Asset-A
2 Asset-B
3 Asset-C
4 Asset-D
Table 2 (Attributes)
1 Asset-A Red
2 Asset-A Hard
3 Asset-B Red
4 Asset-B Hard
5 Asset-B Heavy
6 Asset-C Blue
7 Asset-C Hard
If I am looking for something having the same attributes as Asset-A, then it should identify Asset-B since Asset-B has all the same attributes as Asset-A (it should discard heavy, since Asset-A didn't specify anything different or the similar). Also, if I wanted the attributes for only Asset-A AND Asset-B that were common, how would I get that?
Seems simple, but I can't nail it...
The actual table I am using, is almost precisely Table2, simply an association of an AssetId, and an AttributeId so:
PK: Id
int: AssetId
int: AttributeId
I only included the idea of the asset table to simplify the question.
SELECT ato.id, ato.value
FROM (
SELECT id
FROM assets a
WHERE NOT EXISTS
(
SELECT NULL
FROM attributes ata
LEFT JOIN
attributes ato
ON ato.id = ata.id
AND ato.value = ata.value
WHERE ata.id = 1
AND ato.id IS NULL
)
) ao
JOIN attributes ato
ON ato.id = ao.id
JOIN attributes ata
ON ata.id = 1
AND ata.value = ato.value
, or in SQL Server 2005 (with sample data to check):
WITH assets AS
(
SELECT 1 AS id, 'A' AS name
UNION ALL
SELECT 2 AS id, 'B' AS name
UNION ALL
SELECT 3 AS id, 'C' AS name
UNION ALL
SELECT 4 AS id, 'D' AS name
),
attributes AS
(
SELECT 1 AS id, 'Red' AS value
UNION ALL
SELECT 1 AS id, 'Hard' AS value
UNION ALL
SELECT 2 AS id, 'Red' AS value
UNION ALL
SELECT 2 AS id, 'Hard' AS value
UNION ALL
SELECT 2 AS id, 'Heavy' AS value
UNION ALL
SELECT 3 AS id, 'Blue' AS value
UNION ALL
SELECT 3 AS id, 'Hard' AS value
)
SELECT ato.id, ato.value
FROM (
SELECT id
FROM assets a
WHERE a.id <> 1
AND NOT EXISTS
(
SELECT ata.value
FROM attributes ata
WHERE ata.id = 1
EXCEPT
SELECT ato.value
FROM attributes ato
WHERE ato.id = a.id
)
) ao
JOIN attributes ato
ON ato.id = ao.id
JOIN attributes ata
ON ata.id = 1
AND ata.value = ato.value
I don't completely understand the first part of your question, identifying assets based on their attributes.
Making some assumptions about column names, the following query would yield the common attributes between Asset-A and Asset-B:
SELECT [Table 2].Name
FROM [Table 2]
JOIN [Table 1] a ON a.ID = [Table 2].AssetID AND a.Name = 'Asset-A'
JOIN [Table 1] b ON b.ID = [Table 2].AssetID AND b.Name = 'Asset-B'
GROUP BY [Table 2].Name
Select * From Assets A
Where Exists
(Select * From Assets
Where AssetId <> A.AssetID
And (Select Count(*)
From Attributes At1 Join Attributes At2
On At1.AssetId <> At2.AssetId
And At1.attribute <> At2.Attribute
Where At1.AssetId = A.AssetId Asset) = 0 )
And AssetId = 'Asset-A'
select at2.asset, count(*)
from attribute at1
inner join attribute at2 on at1.value = at2.value
where at1.asset = "Asset-A"
and at2.asset != "Asset-A"
group by at2.asset
having count(*) = (select count(*) from attribute where asset = "Asset-A");
Find all assets who have every attribute that "A" has (but also may have additional attributes):
SELECT Other.ID
FROM Assets Other
WHERE
Other.AssetID <> 'Asset-A' -- do not return Asset A as a match to itself
AND NOT EXISTS (SELECT NULL FROM Attributes AttA WHERE
AttA.AssetID='Asset-A'
AND NOT EXISTS (SELECT NULL FROM Attributes AttOther WHERE
AttOther.AssetID=Other.ID AND AttOther.AttributeID = AttA.AttributeID
)
)
I.e., "find any asset where there is no attribute of A that is not also an attribute of this asset".
Find all assets who have exactly the same attributes as "A":
SELECT Other.ID
FROM Assets Other
WHERE
Other.AssetID <> 'Asset-A' -- do not return Asset A as a match to itself
AND NOT EXISTS (SELECT NULL FROM Attributes AttA WHERE
AttA.AssetID='Asset-A'
AND NOT EXISTS (SELECT NULL FROM Attributes AttOther WHERE
AttOther.AssetID=Other.ID
AND AttOther.AttributeID = AttA.AttributeID
)
)
AND NOT EXISTS (SELECT NULL FROM Attributes AttaOther WHERE
AttaOther.AssetID=Other.ID
AND NOT EXISTS (SELECT NULL FROM Attributes AttaA WHERE
AttaA.AssetID='Asset-A'
AND AttaA.AttributeID = AttaOther.AttributeID
)
)
I.e., "find any asset where there is no attribute of A that is not also an attribute of this asset, and where there is no attribute of this asset that is not also an attribute of A."
This solution works as prescribed, thanks for the input.
WITH Atts AS
(
SELECT
DISTINCT
at1.[Attribute]
FROM
Attribute at1
WHERE
at1.[Asset] = 'Asset-A'
)
SELECT
DISTINCT
Asset,
(
SELECT
COUNT(ta2.[Attribute])
FROM
Attribute ta2
INNER JOIN
Atts b
ON
b.[Attribute] = ta2.[attribute]
WHERE
ta2.[Asset] = ta.Asset
)
AS [Count]
FROM
Atts a
INNER JOIN
Attribute ta
ON
a.[Attribute] = ta.[Attribute]
Find all assets that have all the same attributes as asset-a:
select att2.Asset from attribute att1
inner join attribute att2 on att2.Attribute = att1.Attribute and att1.Asset <> att2.Asset
where att1.Asset = 'Asset-A'
group by att2.Asset, att1.Asset
having COUNT(*) = (select COUNT(*) from attribute where Asset=att1.Asset)
I thought maybe I can do this with LINQ and then work my way backwards with:
var result = from productsNotA in DevProducts
where productsNotA.Product != "A" &&
(
from productsA in DevProducts
where productsA.Product == "A"
select productsA.Attribute
).Except
(
from productOther in DevProducts
where productOther.Product == productsNotA.Product
select productOther.Attribute
).Single() == null
select new {productsNotA.Product};
result.Distinct()
I thought that translating this back to SQL with LinqPad would result into a pretty SQL query. However it didn't :). DevProducts is my testtable with a column Product and Attribute. I thought I'd post the LINQ query anyways, might be useful to people who are playing around with LINQ.
If you can optimize the LINQ query above, please let me know (it might result in better SQL ;))
I'm using following DDL
CREATE TABLE Attributes (
Asset VARCHAR(100)
, Name VARCHAR(100)
, UNIQUE(Asset, Name)
)
Second question is easy
SELECT Name
FROM Attributes
WHERE Name IN (SELECT Name FROM Attributes WHERE Asset = 'A')
AND Asset = 'B'
First question is not more difficult
SELECT Asset
FROM Attributes
WHERE Name IN (SELECT Name FROM Attributes WHERE Asset = 'A')
GROUP BY Asset
HAVING COUNT(*) = (SELECT COUNT(*) FROM FROM Attributes WHERE Asset = 'A')
Edit:
I left AND Asset != 'A' out of the WHERE clause of the second snippet for brevity