I have a table with 5 rows representing two different products. The columns include the product, sales, discount. I'm trying to calculate the percentage of sales per product that included a discount. The table looks like this:
product
sales
discount
1
10
0
1
10
5
2
20
10
2
20
0
2
20
10
My results should look like the below (which I know because I've calculated this in Excel):
product
perc_discount
1
50.00
2
66.67
For each of the two products we are calculating the count of sales with discount divided by the total count of sales, so for product 1 it would be (1/2)*100 = 50.
My SQL code looks like the below:
SELECT
product,
(SELECT COUNT(*) FROM sales WHERE discount >0)/COUNT(*)*100 AS perc_discount
FROM sales
GROUP BY product
However, the result I'm getting is:
product
perc_discount
1
150.0
2
100.0
It seems to be calculating the total count of discounted sales in the table and diving it by the count of each product and I can't seem to figure out how to change it. Any ideas on how I can improve this?
Thanks.
How about conditional sum?
SQL> select product,
2 round(sum(case when discount > 0 then 1 else 0 end) / count(*) * 100, 2) perc_discount
3 from sales
4 group by product;
PRODUCT PERC_DISCOUNT
---------- -------------
1 50
2 66,67
SQL>
So: add 1 for every discount row per product. Divide that sum with total number of rows per product (that's count). Round the result to 2 decimals (so that it looks prettier).
You can use conditional aggregation. For example:
select
product,
100.0 * count(case when discount <> 0 then 'x' end) / count(*) as perc_discount
from sales
group by product
Related
I'm very new to SQL and VB.NET. I have an existing table called STOCK with the columns shown here, and I want to sum buy and sell to display current quantity.
Existing table:
ID
Date
BUY
SELL
Current quantity
1
01/01/22
88
0
2
03/01/22
22
0
94669
05/02/22
0
30
I want to display in Current quantity like this
(the current quantity amount in the row above + BUY - SELL)
I add result in Current quantity manually, but I want to do this in automatic way it is possible in SQL code
ID
Date
BUY
SELL
Current quantity
1
01/01/22
88
0
88
2
03/01/22
22
0
110
3
05/02/22
0
30
80
You can try this:
select a.*,
sum(net_sell) over (order by Curr_date ) as Current_quantity
from
(select s.*,
buy-sell as net_sell
from stock s) a ;
Dbfiddle link : https://dbfiddle.uk/?rdbms=postgres_11&fiddle=196a41a578d1e699ccaa3e878e261019
What if I have table like this and I want to select the best selling product_id.
id
transaction_id
product_id
qty_sold
1
21
2
5
2
22
3
2
3
23
4
2
3
24
2
1
3
25
2
4
I want the best selling product_id with the highest qty_sold
Using SQLS, you can group by the productID, add up the number of sold, and order by the total descending. If we also take the minimum transaction ID per product, if two products come out to have the same total qty, we can take the minimum tran ID to split the tie
SELECT TOP 1 product_id, SUM(qty_sold) as sellcount, MIN(transaction_id) as firsttran
FROM t
GROUP BY product_id
ORDER BY SUM(qty_sold) DESC, MIN(transaction_id)
Once you're happy the sums are right etc, you can remove the , SUM(qty_sold) as sellcount, MIN(transaction_id) from the SELECT if you want/if you only need the prod ID
product
quantity
price
milk
3
10
bread
7
3
bread
5
2
And my output table should be
product
total_price
milk
30
bread
31
I can't seem to get my code to work. Here is my code
SELECT product, (SELECT (quantity*unit_price)
FROM shopping_history AS sh ) AS total_price
FROM shopping_history
GROUP BY product
You are looking for the aggregate function SUM (which doesn't require a sub-query) e.g.
SELECT product, SUM(quantity*unit_price) AS Total_Price
FROM shopping_history
GROUP BY product
suppose i have a product is and sales column
product id sales
1 1000
2 10000
3 50000
4 12000
5 8000
write an sql query to get all product ids that contribute to top 80 % of sales?
For this, you want a cumulative sum. Presumably, you want the top selling such products, so:
select p.*
from (select p.*,
sum(sales) over (order by sales desc) as running_sales,
sum(sales) over () as total_sales,
from products
) p
where running_sales - sales < 0.8 * total_sales;
This returns the product that reaches or first exceeds 80% of the total sales.
I have a table, sales, which is ordered by descending TotalSales
user_id | TotalSales
----------------------
4 10
2 1.5
5 0.99
3 0.5
1 0.33
What I would like to do is find the percentage of the sum of all sales that the xx% most important sales represent.
For example if I wanted to do it for top 40% sales, here I would get (10+1.5)/(10+1.5+0.99+0.5+0.33)= 86%
But right now I haven't been able to select "top xx% rows".
Edit: DB management system can be MySQL or Vertica or Hive
select Sum(a) as s from sales where a in (Select TotalSales from sales where TotalSales>=x)
GROUP BY a
select Sum(TotalSales) as b from sales group by b
your result is s/b
and x= the percentage you set each time