Value need from range, based on Priority in SQL , - sql

Question

There is 3 cases: (In all cases value needs to be picked up based on priority)
case 1 : zip exist between range
case 2: zip does not exist between range
case 3 : overlap range
Table
Temp1
state
zip_start
zip_end
Priority
Value
NY
100
200
1
A
NY
150
250
3
c
NY
null
null
2
B
Data
state
zip
NY
201
NY
400
OUTPUT :
state
zip_start
zip_end
Priority
Value
zip
NY
null
null
2
B
201
NY
null
null
2
B
400
I am trying with below code , but It's not picking the data based on priority:
SELECT ZIP,ZIP_START,ZIP_END,VALUE,PRIORITY,STATE,IX FROM
(
SELECT TMP1.*,
ROW_NUMBER () OVER (PARTITION BY STATE,ZIP ORDER BY PRIORITY ) IX
FROM
(
WITH CASE_1 AS
( SELECT
temp1.*
,DATA.ZIP
FROM TEMP1
LEFT JOIN
"DATA" ON DATA.STATE = temp1.STATE
WHERE DATA.ZIP BETWEEN TEMP1.ZIP_START AND TEMP1 .ZIP_END
),
CASE_2 AS
(
SELECT
temp1.*
,DATA.ZIP
FROM "DATA"
LEFT JOIN
TEMP1 ON DATA.STATE = temp1.STATE
WHERE (ZIP_START IS NULL OR ZIP_START = '')
AND (ZIP_END IS NULL OR ZIP_END = '')
AND Not EXISTS
(SELECT 1 FROM CASE_1 WHERE CASE_1.zip=DATA.zip
AND CASE_1.STATE=DATA.STATE)
)
SELECT * FROM CASE_1
UNION
SELECT * FROM CASE_2
)TMP1
) TMP2
WHERE TMP2.IX = 1;

Answer 1

From Oracle 12, you can use a LATERAL join and filter when the zip is within range or when one-or-other end of the range is NULL the ORDER BY priority and FETCH the FIRST matched ROW ONLY:
SELECT t.*, d.zip
FROM data d
CROSS JOIN LATERAL (
SELECT *
FROM temp1 t
WHERE d.state = t.state
AND (t.zip_start <= d.zip OR t.zip_start IS NULL)
AND (t.zip_end >= d.zip OR t.zip_end IS NULL)
ORDER BY priority
FETCH FIRST ROW ONLY
) t
In earlier versions, you can join the two tables and then use the ROW_NUMBER analytic function to find the best match:
SELECT state, zip_start, zip_end, priority, value, zip
FROM (
SELECT t.*,
d.zip,
ROW_NUMBER() OVER (PARTITION BY d.ROWID ORDER BY t.priority) AS rn
FROM data d
INNER JOIN temp1 t
ON ( d.state = t.state
AND (t.zip_start <= d.zip OR t.zip_start IS NULL)
AND (t.zip_end >= d.zip OR t.zip_end IS NULL))
)
WHERE rn = 1;
Which, for the sample data:
CREATE TABLE Temp1 (state, zip_start, zip_end, Priority, Value) AS
SELECT 'NY', 100, 200, 1, 'A' FROM DUAL UNION ALL
SELECT 'NY', 150, 250, 3, 'c' FROM DUAL UNION ALL
SELECT 'NY', null, null, 2, 'B' FROM DUAL;
CREATE TABLE Data (state, zip) AS
SELECT 'NY', 201 FROM DUAL UNION ALL
SELECT 'NY', 400 FROM DUAL;
Both output:
STATE
ZIP_START
ZIP_END
PRIORITY
VALUE
ZIP
NY
null
null
2
B
201
NY
null
null
2
B
400
db<>fiddle here

Answer 2

CREATE TABLE TEMP1 (
STATE VARCHAR(10),
ZIP_START NUMBER,
ZIP_END NUMBER,
PRIORITY NUMBER,
VAL VARCHAR(10));
INSERT INTO TEMP1 VALUES ('NY', 100,200,1,'A');
INSERT INTO TEMP1 VALUES ('NY', 150,250,3,'C');
INSERT INTO TEMP1 VALUES ('NY', null,null,2,'B');
CREATE TABLE DATATABLE (
STATE VARCHAR(10),
ZIP NUMBER
);
INSERT INTO DATATABLE VALUES ('NY', 201);
INSERT INTO DATATABLE VALUES ('NY', 400);
The main idea is to figure out first how many times your condition (zip in range between zip_start and end) is met. This is why we use count_match variable.
Once you get if your data is priority 1,2 or 3, you match your data table with the temp table to get the value associated with that priority.
SELECT
t0.STATE,
t0.ZIP_START,
t0.ZIP_END,
CASE WHEN t0.COUNT_MATCH > 1 THEN 3
WHEN t0.COUNT_MATCH = 1 THEN 1
WHEN t0.COUNT_MATCH = 0 THEN 2 END AS PRIORITY,
t.VAL,
t0.ZIP
FROM
(
SELECT
t1.STATE,
MIN(t2.ZIP_START) AS ZIP_START,
MAX(t2.ZIP_END) AS ZIP_END,
COUNT(t2.STATE) AS COUNT_MATCH,
t1.ZIP
FROM DATATABLE t1
LEFT JOIN TEMP1 t2 ON (t1.STATE = t2.STATE AND t1.ZIP>=t2.ZIP_START AND t1.ZIP <= t2.ZIP_END)
GROUP BY
t1.STATE, t1.ZIP) t0
LEFT JOIN TEMP1 t ON (t0.STATE = t.STATE AND CASE WHEN t0.COUNT_MATCH > 1 THEN 3
WHEN t0.COUNT_MATCH = 1 THEN 1
WHEN t0.COUNT_MATCH = 0 THEN 2 END = t.PRIORITY)
;