C++ has string functions like find_first_of(), find_first_not_of(), find_last_of(),
find_last_not_of(). e.g. if I write
string s {"abcdefghi"};
s.find_last_of("eaio") returns the index of i
s.find_first_of("eaio") returns the index of a
s.find_first_not_of("eaio") returns the index of b
Does Kotlin has any equivalent.
Kotlin doesn't have these exact functions, but they are all special cases of indexOfFirst and indexOfLast:
fun CharSequence.findFirstOf(chars: CharSequence) = indexOfFirst { it in chars }
fun CharSequence.findLastOf(chars: CharSequence) = indexOfLast { it in chars }
fun CharSequence.findFirstNotOf(chars: CharSequence) = indexOfFirst { it !in chars }
fun CharSequence.findLastNotOf(chars: CharSequence) = indexOfLast { it !in chars }
These will return -1 if nothing is found.
Usage:
val s = "abcdefghi"
val chars = "aeiou"
println(s.findFirstOf(chars))
println(s.findFirstNotOf(chars))
println(s.findLastOf(chars))
println(s.findLastNotOf(chars))
Output:
0
1
8
7
I have this function to convert string sentence to list words. I created this function in Java and converted to Kotlin using default Kotlin conversion in Android Studio, but I believe there can be many ways to shorten this code in Awesome Kotlin. I will be good if you can share your piece of code and help me(and all) to improve our knowledge in Kotlin.
private fun stringToWords(mnemonic: String): List<String> {
val words = ArrayList<String>()
for (word in mnemonic.trim { it <= ' ' }.split(" ".toRegex()).dropLastWhile { it.isEmpty() }.toTypedArray()) {
if (word.isNotEmpty()) {
words.add(word)
}
}
return words
}
I would go for the following:
fun stringToWords(s : String) = s.trim().splitToSequence(' ')
.filter { it.isNotEmpty() } // or: .filter { it.isNotBlank() }
.toList()
Note that you probably want to adjust that filter, e.g. to filter out blank entries too... I put that variant in the comment... (if you use that one, you do not require an initial trim() though)
If you rather want to work with the Sequence you can do so by just omitting the .toList() at the end.
And as also Abdul-Aziz-Niazi said: same is also possible via extension function, if you require it more often:
fun String.toWords() = trim().splitToSequence(' ').filter { it.isNotEmpty() }.toList()
You can do it like this.. Just make a function of return type list.
val s = "This is a sample sentence."
val words:Array<String> = s.split("\\s+".toRegex()).dropLastWhile { it.isEmpty() }.toTypedArray()
for (i in words.indices) {
// You may want to check for a non-word character before blindly
// performing a replacement
// It may also be necessary to adjust the character class
words[i] = words[i].replace("[^\\w]".toRegex(), "")
}
May this will help you :-)
It's easier than you think:
fun stringToWords(mnemonic: String) = mnemonic.replace("\\s+".toRegex(), " ").trim().split(" ")
Remove multiple spaces, trim start and the end, split.
Like an extention:
fun String.toWords() = replace("\\s+".toRegex(), " ").trim().split(" ")
After Roland's suggestion:
fun String.toWords() = trim().split("\\s+".toRegex())
You don't need scopes, the redundant "".toRegex() and the last expression.
You can do something like this:
private fun stringToWords(mnemonic: String): List<String> {
val words = ArrayList<String>()
for (w in mnemonic.trim(' ').split(" ")) {
if (w.isNotEmpty()) {
words.add(w)
}
}
return words
}
Additionally,
If you use this method a lot in this project, you can make it an extension in string class. Paste this method in a separate file(outside a classes or add it in classless .kt file) so it has a global access.
and then you can use it with any string like
myString.toWords() anywhere in the project
The method will look like this
inline fun String.toWords(): List<String> {
val words = ArrayList<String>()
for (w in this.trim(' ').split(" ")) {
if (w.isNotEmpty()) {
words.add(w)
}
}
return words
}
I can generate a random sequence of numbers in a certain range like the following:
fun ClosedRange<Int>.random() = Random().nextInt(endInclusive - start) + start
fun generateRandomNumberList(len: Int, low: Int = 0, high: Int = 255): List<Int> {
(0..len-1).map {
(low..high).random()
}.toList()
}
Then I'll have to extend List with:
fun List<Char>.random() = this[Random().nextInt(this.size)]
Then I can do:
fun generateRandomString(len: Int = 15): String{
val alphanumerics = CharArray(26) { it -> (it + 97).toChar() }.toSet()
.union(CharArray(9) { it -> (it + 48).toChar() }.toSet())
return (0..len-1).map {
alphanumerics.toList().random()
}.joinToString("")
}
But maybe there's a better way?
Since Kotlin 1.3 you can do this:
fun getRandomString(length: Int) : String {
val allowedChars = ('A'..'Z') + ('a'..'z') + ('0'..'9')
return (1..length)
.map { allowedChars.random() }
.joinToString("")
}
Lazy folks would just do
java.util.UUID.randomUUID().toString()
You can not restrict the character range here, but I guess it's fine in many situations anyway.
Assuming you have a specific set of source characters (source in this snippet), you could do this:
val source = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
java.util.Random().ints(outputStrLength, 0, source.length)
.asSequence()
.map(source::get)
.joinToString("")
Which gives strings like "LYANFGNPNI" for outputStrLength = 10.
The two important bits are
Random().ints(length, minValue, maxValue) which produces a stream of length random numbers each from minValue to maxValue-1, and
asSequence() which converts the not-massively-useful IntStream into a much-more-useful Sequence<Int>.
Using Collection.random() from Kotlin 1.3:
// Descriptive alphabet using three CharRange objects, concatenated
val alphabet: List<Char> = ('a'..'z') + ('A'..'Z') + ('0'..'9')
// Build list from 20 random samples from the alphabet,
// and convert it to a string using "" as element separator
val randomString: String = List(20) { alphabet.random() }.joinToString("")
Without JDK8:
fun ClosedRange<Char>.randomString(length: Int) =
(1..length)
.map { (Random().nextInt(endInclusive.toInt() - start.toInt()) + start.toInt()).toChar() }
.joinToString("")
usage:
('a'..'z').randomString(6)
To define it for a defined length:
val randomString = UUID.randomUUID().toString().substring(0,15)
where 15 is the number of characters
('A'..'z').map { it }.shuffled().subList(0, 4).joinToString("")
Using Kotlin 1.3:
This method uses an input of your desired string length desiredStrLength as an Integer and returns a random alphanumeric String of your desired string length.
fun randomAlphaNumericString(desiredStrLength: Int): String {
val charPool: List<Char> = ('a'..'z') + ('A'..'Z') + ('0'..'9')
return (1..desiredStrLength)
.map{ kotlin.random.Random.nextInt(0, charPool.size) }
.map(charPool::get)
.joinToString("")
}
If you prefer unknown length of alphanumeric (or at least a decently long string length like 36 in my example below), this method can be used:
fun randomAlphanumericString(): String {
val charPool: List<Char> = ('a'..'z') + ('A'..'Z') + ('0'..'9')
val outputStrLength = (1..36).shuffled().first()
return (1..outputStrLength)
.map{ kotlin.random.Random.nextInt(0, charPool.size) }
.map(charPool::get)
.joinToString("")
}
Or use coroutine API for the true Kotlin spirit:
buildSequence { val r = Random(); while(true) yield(r.nextInt(24)) }
.take(10)
.map{(it+ 65).toChar()}
.joinToString("")
Building off the answer from Paul Hicks, I wanted a custom string as input. In my case, upper and lower-case alphanumeric characters. Random().ints(...) also wasn't working for me, as it required an API level of 24 on Android to use it.
This is how I'm doing it with Kotlin's Random abstract class:
import kotlin.random.Random
object IdHelper {
private val ALPHA_NUMERIC = ('0'..'9') + ('A'..'Z') + ('a'..'z')
private const val LENGTH = 20
fun generateId(): String {
return List(LENGTH) { Random.nextInt(0, ALPHA_NUMERIC.size) }
.map { ALPHA_NUMERIC[it] }
.joinToString(separator = "")
}
}
The process and how this works is similar to a lot of the other answers already posted here:
Generate a list of numbers of length LENGTH that correspond to the index values of the source string, which in this case is ALPHA_NUMERIC
Map those numbers to the source string, converting each numeric index to the character value
Convert the resulting list of characters to a string, joining them with the empty string as the separator character.
Return the resulting string.
Usage is easy, just call it like a static function: IdHelper.generateId()
I use the following code to generate random words and sentences.
val alphabet: List<Char> = ('a'..'z') + ('A'..'Z') + ('0'..'9')
val randomWord: String = List((1..10).random()) { alphabet.random() }.joinToString("")
val randomSentence: String = (1..(1..10).random()).joinToString(" ") { List((1..10).random()) { alphabet.random() }.joinToString("") }
the question is old already, but I think another great solution (should work since Kotlin 1.3) would be the following:
// Just a simpler way to create a List of characters, as seen in other answers
// You can achieve the same effect by declaring it as a String "ABCDEFG...56789"
val alphanumeric = ('A'..'Z') + ('a'..'z') + ('0'..'9')
fun generateAlphanumericString(length: Int) : String {
// The buildString function will create a StringBuilder
return buildString {
// We will repeat length times and will append a random character each time
// This roughly matches how you would do it in plain Java
repeat(length) { append(alphanumeric.random()) }
}
}
fun randomAlphaNumericString(#IntRange(from = 1, to = 62) lenght: Int): String {
val alphaNumeric = ('a'..'z') + ('A'..'Z') + ('0'..'9')
return alphaNumeric.shuffled().take(lenght).joinToString("")
}
Building on Fabb111's answer:
fun randomString(length: Int): String =
buildString {
repeat(length) {
append((0 until 36).random().toString(36))
}
}
Numbers can be converted to a different base using the Int.toString(Int).
Base 36 is the numeral system that contains all alphanumeric characters
You can use RandomStringUtils.randomAlphanumeric(min: Int, max: Int) -> String from apache-commons-lang3
Here's a cryptographically secure version of it, or so I believe:
fun randomString(len: Int): String {
val random = SecureRandom()
val chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789".toCharArray()
return (1..len).map { chars[random.nextInt(chars.size)] }.joinToString("")
}
I used the most voted answer, but after using it for a while I discovered a big problem, since the random strings weren't that random.
I had to modify the generation of the random character, since if I only left allowedChars.random() it always generated the same strings, and I couldn't find why. I was reading that because random() was called very quickly, but I don't know how it works when calling it on the list of numbers.
fun getRandomString(): String {
val allowedChars = ('A'..'Z') + ('a'..'z') + ('0'..'9')
var string = ""
for (i in (1..20)) {
string += allowedChars[(Math.random() * (allowedChars.size - 1)).roundToInt()]
}
return string
}
// initialise at top
companion object {
private const val allowedCharacters = "0123456789QWERTYUIOPASDFGHJKLZXCVBNM"
}
//pass size and get Random String Captcha
fun getRandomCaptcha(sizeOfRandomCaptcha: Int): String {
val random = Random()
val sb = StringBuilder(sizeOfRandomCaptcha)
for (i in 0 until sizeOfRandomCaptcha)
sb.append(allowedCharacters[random.nextInt(allowedCharacters.length)])
return sb.toString()
}
Here's a simple function that uses newer Kotlin stdlib functions:
fun randomString(length: Int): String =
CharArray(length) { validChars.random() }.concatToString()
val validChars: List<Char> = ('a'..'z') + ('A'..'Z') + ('0'..'9'),
This uses:
a collection constructor with a initializer function
CharArray(length) { i -> /* provide a value for element i */ }
This is a one-liner for creating a CharArray and initializing each value using a lambda, It accepts a length, so the CharArray will be initialized with the correct size.
The Collection<>.random() extension function, that will pick a random character. This can be seeded if desired.
validChars.random()
The initialized CharArray is converted to a string using concatToString(), which was released in version 1.4.
The best way I think:
fun generateID(size: Int): String {
val source = "A1BCDEF4G0H8IJKLM7NOPQ3RST9UVWX52YZab1cd60ef2ghij3klmn49opq5rst6uvw7xyz8"
return (source).map { it }.shuffled().subList(0, size).joinToString("")
}
How to replace a part of a string with something else in Kotlin?
For example, changing "good morning" to "good night" by replacing "morning" with "night"
fun main(args: Array<String>) {
var a = 1
// simple name in template:
val s1 = "a is $a"
a = 2
// arbitrary expression in template:
val s2 = "${s1.replace("is", "was")}, but now is $a"
println(s2)
}
OUPUT: a was 1, but now is 2
"Good Morning".replace("Morning", "Night")
It's always useful to search for functions in the Kotlin standard library API reference. In this case, you find the replace function in Kotlin.text:
/**
* Returns a new string with all occurrences of [oldChar] replaced with [newChar].
*/
public fun String.replace(oldChar: Char, newChar: Char, ignoreCase: Boolean = false): String {
if (!ignoreCase)
return (this as java.lang.String).replace(oldChar, newChar)
else
return splitToSequence(oldChar, ignoreCase ignoreCase).joinToString(separator = newChar.toString())
}
How in Kotlin can I prepend a Char to a String?
e.g.
fun main(args: Array<String>) {
val char = 'H'
val string = "ello World"
val appendingWorks = string + char //but not what I want...
//val prependingFails = char + string //no .plus(str:String) version
val prependingWorkaround1 = char.toString() + string
val prependingWorkaround2 = "" + char + string
val prependingWorkaround3 = String(charArray(char)) + string
}
When trying to call + (e.g. plus) on Char, there is no version that accepts a String on the right, so therefore 'H' + "ello World" doesn't compile
The first workaround might be good enough but it's a regression for me from what works in Java: String test = 'H' + "ello World"; (compiles fine...)
I also don't like the last workaround, at least in the java.lang.String I have a constructor that accepts a single char, or I can use java.lang.Character.toString(char c). Is there an elegant way in Kotlin to do so?
Was this discussed before (adding a plus(str:String) overload to the Char object?)
What about using string templates, like this:
val prepended = "$char$string"
As of kotlin 1.5, there is an extension plus operator function defined on Char, which can be used to concatenate a Char with given String. So you can do
val char = 'H'
val string = "ello World"
// Use the function call syntax
val result1 = char.plus(string)
// or use the operator syntax
val result2 = char + string
If you want to truly prepend a string using just a method call on that string, you can do the following:
val str = "ello World!"
println(str.let { 'H' + it })
This way can be useful if str was instead a large complicated chain of method calls:
val squares = ... // 10x10 array of square numbers
println(squares.joinToString("\n") {
it.joinToString(" ") { "%03d".format(it) }
}.let { "Squares:\n" + it })