Getting datetime count range in SQL Server - sql

Question

I try to get the date range between the data changes in SQL Server
my query is
select count(1) as qty, Info, convert(char,dFError,100) dErr
from TableData
group by Info, convert(char,dFError,100)
order by dErr asc
I have this
qty has the number of reques to a server, info are the servers ip and the date it's when a request it's sended to another server.
qty
Info
dErr
1
1.97
Aug 11 2021 9:01AM
1
1.97
Aug 11 2021 9:06AM
88
1.33
Dec 21 2021 2:04PM
1
1.95
Dec 22 2021 9:44PM
9
1.95
Dec 22 2021 9:45PM
1
1.33
Dec 22 2021 9:51PM
19
1.33
Dec 22 2021 9:52PM
3
1.33
Dec 22 2021 9:53PM
6
1.33
Dec 27 2021 7:10PM
17
1.33
Dec 27 2021 7:11PM
15
1.95
Dec 27 2021 7:17PM
8
1.95
Dec 27 2021 7:18PM
and I want this, in Aug 11 at 9:06AM all are going to 1.97, at Dec 21 at 2:04PM all are going to 1.33, that means the date and the info
qty
Info
dErr
2
1.97
Aug 11 2021 9:06AM
88
1.33
Dec 21 2021 2:04PM
10
1.95
Dec 22 2021 9:45PM
46
1.33
Dec 27 2021 7:11PM
23
1.95
Dec 27 2021 7:18PM
in the same day can be the same group of numbers on distinct hour
qty
Info
dErr
1
1.97
Jan 24 2022 9:39AM
1
1.97
Jan 24 2022 9:51AM
1
1.97
Jan 24 2022 9:58AM
4
1.97
Jan 24 2022 10:08AM
1
1.97
Jan 24 2022 10:12AM
8
1.95
Jan 24 2022 10:24AM
2
1.95
Jan 24 2022 10:32AM
10
1.33
Jan 24 2022 10:33AM
1
1.33
Jan 24 2022 11:37AM
8
1.95
Jan 24 2022 11:59AM
1
1.95
Jan 24 2022 12:00PM
2
1.95
Jan 24 2022 12:08PM
and need to be displayed like
qty
Info
dErr
8
1.97
Jan 24 2022 10:12AM
10
1.95
Jan 24 2022 10:32AM
11
1.33
Jan 24 2022 11:37AM
11
1.95
Jan 24 2022 12:08PM

Answer 1

A double row_number can be used to calculate a ranking.
Then the ranking can be used in the aggregation to solve this Gaps-And-Islands type of problem.
select sum(qty) as qty, Info, max(dFError) as dErr
from (
select Info, dFError, qty
, convert(date, dFError) as dErrorDate
, Rnk = row_number() over (order by dFError)
+ row_number() over (partition by Info order by dFError desc)
from TableData
) q
group by Info, Rnk
order by dErr;
qty
Info
dErr
2
1.97
2021-08-11 09:06:00.000
88
1.33
2021-12-21 14:04:00.000
10
1.95
2021-12-22 21:45:00.000
46
1.33
2021-12-27 19:11:00.000
23
1.95
2021-12-27 19:18:00.000
8
1.97
2022-01-24 10:12:00.000
10
1.95
2022-01-24 10:32:00.000
11
1.33
2022-01-24 11:37:00.000
11
1.95
2022-01-24 12:08:00.000
Demo on db<>fiddle here

Answer 2

select
SUM(P_COUNT) as "COUNT",
P_DATA as "DATA",
MAX(FECHA) as "FECHA"
from
TABLEA
GROUP BY
P_DATA, CONVERT(DATE, FECHA)
ORDER BY "FECHA"

Answer 3

Your expected results don't match the given data - in the first set you have rows for 12/22 with both 1.33 and 1.95, but not included in your expected results.
It seems to me you want to either group by the date - or the date\hour. Here is an example of both:
Declare #testTable table (qty int, Info numeric(3,2), dErr datetime);
Insert Into #testTable (qty, Info, dErr)
Values ( 1, 1.97, 'Aug 11 2021 9:01AM')
, ( 1, 1.97, 'Aug 11 2021 9:06AM')
, (88, 1.33, 'Dec 21 2021 2:04PM')
, ( 1, 1.95, 'Dec 22 2021 9:44PM')
, ( 9, 1.95, 'Dec 22 2021 9:45PM')
, ( 1, 1.33, 'Dec 22 2021 9:51PM')
, (19, 1.33, 'Dec 22 2021 9:52PM')
, ( 3, 1.33, 'Dec 22 2021 9:53PM')
, ( 6, 1.33, 'Dec 27 2021 7:10PM')
, (17, 1.33, 'Dec 27 2021 7:11PM')
, (15, 1.95, 'Dec 27 2021 7:17PM')
, ( 8, 1.95, 'Dec 27 2021 7:18PM')
, ( 1, 1.97, 'Jan 24 2022 9:39AM')
, ( 1, 1.97, 'Jan 24 2022 9:51AM')
, ( 1, 1.97, 'Jan 24 2022 9:58AM')
, ( 4, 1.97, 'Jan 24 2022 10:08AM')
, ( 1, 1.97, 'Jan 24 2022 10:12AM')
, ( 8, 1.95, 'Jan 24 2022 10:24AM')
, ( 2, 1.95, 'Jan 24 2022 10:32AM')
, (10, 1.33, 'Jan 24 2022 10:33AM')
, ( 1, 1.33, 'Jan 24 2022 11:37AM')
, ( 8, 1.95, 'Jan 24 2022 11:59AM')
, ( 1, 1.95, 'Jan 24 2022 12:00PM')
, ( 2, 1.95, 'Jan 24 2022 12:08PM');
--==== Grouped by date
Select total_qty = sum(tt.qty)
, tt.Info
, latest_date = max(tt.dErr)
From #testTable tt
Group By
tt.Info
, cast(tt.dErr As date)
Order By
cast(tt.dErr As date);
--==== Grouped by date\hour
Select total_qty = sum(tt.qty)
, tt.Info
, latest_date = max(tt.dErr)
From #testTable tt
Group By
tt.Info
, cast(tt.dErr As date)
, datepart(Hour, tt.dErr)
Order By
cast(tt.dErr As date)
, datepart(Hour, tt.dErr);