Below are two tables. An item is being sold at different values during different periods. I need to calculate average sale of the item. I need to come to an optimal working query. I think the trick would be to map each sales date with their start_date and end_date and multiply the quatity with their respective price for that period and then derive the avergae using the formula total sales amount/ total quatity.
CREATE TABLE sales(
item_id varchar(255) ,
start_date date ,
end_date date,
price int
) ;
insert into sales values
('mobile','2021-01-01','2021-01-05',500),
('mobile','2021-01-06','2021-01-09',400),
('mobile','2021-01-10','2021-01-15',900) ;
CREATE TABLE item(
sales_id int,
item_id varchar(255) ,
sales_date date ,
quatity int
) ;
insert into item values
(101,'mobile','2021-01-01',10),
(102,'mobile','2021-01-06',20),
(103,'mobile','2021-01-15',30) ;
select item_id, sum(total_amount)/sum(quatity) avg_price from
(
select s.item_id, s.price, i.quatity, s.price * i.quatity as total_amount
from sales s, item i where i.item_id = s.item_id
and i.sales_date between s.start_date and s.end_date
) as A
group by item_id;
Please try this,
SELECT
i.item_id,avg(s.price*i.quatity) FROM
item I
LEFT JOIN
sales S
on
I.item_id=S.item_id
AND I.sales_date >=S.start_date AND I.sales_date<=S.end_date
group by i.item_id;
Related
I'm having trouble with a simple problem for fifo sql query (to calculate profit for each sales day).
There are two tables Production and Invoice. For each day of sales, I have to output total sales profit by using FIFO method.
Example, for second day profit , I have to use leftover item from previous day with their respecting price.
Here is the tables and desired output result
CREATE TABLE Production
(
id int identity(1,1) primary key,
Productid varchar(10),
pdate date,
Qty int,
Price decimal(18, 2),
);
INSERT INTO Production (Productid,pDate, Qty ,Price) VALUES ('PD1', '01/01/2017', 8, 200);
INSERT INTO Production (Productid,pDate ,Qty ,Price) VALUES ('PD2', '02/01/2017', 14, 300);
INSERT INTO Production (Productid,pDate ,Qty ,Price) VALUES ('PD3', '03/01/2017', 15, 150);
CREATE TABLE Sales
(
id int identity(1,1) primary key,
Sid varchar(10),
sDate date,
Productid varchar(10),
Qty int,
);
INSERT INTO Sales (Sid,sDate ,Productid ,Qty) VALUES ('S001', '04/01/2017', 'PD1', 5);
INSERT INTO Sales (Sid,sDate ,Productid ,Qty) VALUES ('S002', '05/01/2019', 'PD2', 4);
INSERT INTO Sales (Sid,sDate ,Productid ,Qty) VALUES ('S003', '06/01/2019', 'PD3', 6);
Manual calculation for leftover formula for each day
( existing - sales qty ) + purchase qty = leftover
I think a simple check on sales.qty < purchase.qty won't work. Since even if you have sales.qty < purchase.qty but have leftovers from last day then you will be using those leftovers first.
You should use try this:
with cte as(
select s.id,s.Sid,sDate,s.Productid,s.qty AS Qty,s.qty as saleqty,p.qty as productqty,p.price
,sum(p.qty-s.qty) over (order by sdate) as leftover
from purchase P
inner join sales S
on p.productid=s.productid
and p.pdate=s.sdate
)
select id, Sid,sDate,Productid,Qty,
case when lag(leftover) over (order by sdate)>0 then lag(leftover *price) over( order by sdate)
+( saleqty-lag(leftover) over (order by sdate)) * price
else saleqty * price end as profit
from cte;
Hope this would help.
SELECT
s.sid,
s.sdate,
p.productid,
s.qty,
CASE
WHEN s.qty <= p.qty
THEN s.qty*p.price
ELSE p.qty*p.price + (s.qty-p.qty) * (SELECT price FROM purchase WHERE pdate IN (SELECT MAX(pdate) FROM purchase WHERE pdate < s.sdate))
END AS PROFIT
FROM purchase p
JOIN sales s
ON p.productid = s.productid
AND p.pdate = s.sdate
I have a table that stores the VIN numbers and delivery dates of vehicles based on a code. I want to be able to get one row with three columns of data.
I have tried the following
SELECT DISTINCT VIN, MAX(TRANSACTION_DATE) AS DELIVERY_DATE
FROM "TABLE"
WHERE DELIVERY_TYPE ='025'
AND VIN IN ('XYZ')
GROUP BY VIN
UNION ALL
SELECT VIN, MAX(TRANSACTION_DATE) AS OTHER_DELIVERY_DATE
FROM "TABLE"
WHERE DELIVERY_TYPE !='025'
AND VIN IN ('XYZ')
GROUP BY VIN;
When I run this I get
VIN DELIVERY_DATE
XYZ 26-dec-18
XYZ 01-MAY-19
current data format in table:
VIN TRANSACTION_DATE
XYZ 26-DEC-18
XYZ 01-MAY-19
Required format:
VIN DELIVERY_DATE OTHER_DELIVERY DATE
XYZ 26-DEC-18 01-MAY-19
use conditional aggregation
SELECT VIN,
MAX (CASE WHEN DELIVERY_TYPE ='025' AND
VIN IN ('XYZ') then TRANSACTION_DATE end) AS DELIVERY_DATE
MAX(CASE WHEN DELIVERY_TYPE !='025' AND
VIN IN ('XYZ') then TRANSACTION_DATE end) AS OTHER_DELIVERY
FROM "TABLE"
GROUP BY VIN
Just use conditional aggregation:
SELECT VIN,
MAX(CASE WHEN DELIVERY_TYPE = 25 THEN TRANSACTION_DATE END) AS DELIVERY_DATE,
MAX(CASE WHEN DELIVERY_TYPE <> 25 THEN TRANSACTION_DATE END) AS TRANSACTION_DATE
FROM TABLE
WHERE VIN IN ('XYZ')
GROUP BY VIN;
Note that SELECT DISTINCT is almost never used with GROUP BY.
You can use CROSS APPLY
DECLARE #Cars TABLE (VIN VARCHAR(100), DELIVERY_TYPE VARCHAR(3), TRANSACTION_DATE DATE)
INSERT INTO #Cars
(VIN, DELIVERY_TYPE , TRANSACTION_DATE)
VALUES
('XYZ', '025', '20181226'), ('XYZ', '030', '20190319')
I needed above code to be able to run without a table and data, all you need is this:
SELECT DISTINCT C.VIN, DD.DELIVERY_DATE, TD.TRANSACTION_DATE
FROM #Cars C
CROSS APPLY (SELECT MAX(TRANSACTION_DATE) DELIVERY_DATE FROM #Cars D WHERE D.DELIVERY_TYPE = '025' AND D.VIN = C.VIN) DD
CROSS APPLY (SELECT MAX(TRANSACTION_DATE) TRANSACTION_DATE FROM #Cars D WHERE D.DELIVERY_TYPE = '025' AND D.VIN = C.VIN) TD
If you need to transpond not two but a lot more columns, I'd suggest using PIVOT TABLE as more appropriate, but for two columns either CROSS APPLY or conditional aggregation will do the trick.
I'm trying to sum a certain column over a certain date range. The kicker is that I want this to be a CTE, because I'll have to use it multiple times as part of a larger query. Since it's a CTE, it has to have the date column as well as the sum and ID columns, meaning I have to group by date AND ID. That will cause my results to be grouped by ID and date, giving me not a single sum over the date range, but a bunch of sums, one for each day.
To make it simple, say we have:
create table orders (
id int primary key,
itemID int foreign key references items.id,
datePlaced datetime,
salesRep int foreign key references salesReps.id,
price int,
amountShipped int);
Now, we want to get the total money a given sales rep made during a fiscal year, broken down by item. That is, ignoring the fiscal year bit:
select itemName, sum(price) as totalSales, sum(totalShipped) as totalShipped
from orders
join items on items.id = orders.itemID
where orders.salesRep = '1234'
group by itemName
Simple enough. But when you add anything else, even the price, the query spits out way more rows than you wanted.
select itemName, price, sum(price) as totalSales, sum(totalShipped) as totalShipped
from orders
join items on items.id = orders.itemID
where orders.salesRep = '1234'
group by itemName, price
Now, each group is (name, price) instead of just (name). This is kind of sudocode, but in my database, just this change causes my result set to jump from 13 to 32 rows. Add to that the date range, and you really have a problem:
select itemName, price, sum(price) as totalSales, sum(totalShipped) as totalShipped
from orders
join items on items.id = orders.itemID
where orders.salesRep = '1234'
and orderDate between 150101 and 151231
group by itemName, price
This is identical to the last example. The trouble is making it a CTE:
with totals as (
select itemName, price, sum(price) as totalSales, sum(totalShipped) as totalShipped, orderDate as startDate, orderDate as endDate
from orders
join items on items.id = orders.itemID
where orders.salesRep = '1234'
and orderDate between startDate and endDate
group by itemName, price, startDate, endDate
)
select totals_2015.itemName as itemName_2015, totals_2015.price as price_2015, ...
totals_2016.itemName as itemName_2016, ...
from (
select * from totals
where startDate = 150101 and endDate = 151231
) totals_2015
join (
select *
from totals
where startDate = 160101 and endDate = 160412
) totals_2016
on totals_2015.itemName = totals_2016.itemName
Now the grouping in the CTE is way off, more than adding the price made it. I've thought about breaking the price query into its own subquery inside the CTE, but I can't escape needing to group by the dates in order to get the date range. Can anyone see a way around this? I hope I've made things clear enough. This is running against an IBM iSeries machine. Thank you!
Depending on what you are looking for, this might be a better approach:
select 'by sales rep' breakdown
, salesRep
, '' year
, sum(price * amountShipped) amount
from etc
group by salesRep
union
select 'by sales rep and year' breakdown
, salesRep
, convert(char(4),orderDate, 120) year
, sum(price * amountShipped) amount
from etc
group by salesRep, convert(char(4),orderDate, 120)
etc
When possible group by the id columns or foreign keys because the columns are indexed already you'll get faster results. This applies to any database.
with cte as (
select id,rep, sum(sales) sls, count(distinct itemid) did, count(*) cnt from sommewhere
where date between x and y
group by id,rep
) select * from cte order by rep
or more fancy
with cte as (
select id,rep, sum(sales) sls, count(distinct itemid) did, count(*) cnt from sommewhere
where date between x and y
group by id,rep
) select * from cte join reps on cte.rep = reps.rep order by sls desc
I eventually found a solution, and it doesn't need a CTE at all. I wanted the CTE to avoid code duplication, but this works almost as well. Here's a thread explaining summing conditionally that does exactly what I was looking for.
I have the following select, whose goal is to select all customers who had no sales since the day X, and also bringing the date of the last sale and the number of the sale:
select s.customerId, s.saleId, max (s.date) from sales s
group by s.customerId, s.saleId
having max(s.date) <= '05-16-2013'
This way it brings me the following:
19 | 300 | 26/09/2005
19 | 356 | 29/09/2005
27 | 842 | 10/05/2012
In another words, the first 2 lines are from the same customer (id 19), I wish to get only one record for each client, which would be the record with the max date, in the case, the second record from this list.
By that logic, I should take off s.saleId from the "group by" clause, but if I do, of course, I get the error:
Invalid expression in the select list (not contained in either an
aggregate function or the GROUP BY clause)
I'm using Firebird 1.5
How can I do this?
GROUP BY summarizes data by aggregating a group of rows, returning one row per group. You're using the aggregate function max(), which will return the maximum value from one column for a group of rows.
Let's look at some data. I renamed the column you called "date".
create table sales (
customerId integer not null,
saleId integer not null,
saledate date not null
);
insert into sales values
(1, 10, '2013-05-13'),
(1, 11, '2013-05-14'),
(1, 12, '2013-05-14'),
(1, 13, '2013-05-17'),
(2, 20, '2013-05-11'),
(2, 21, '2013-05-16'),
(2, 31, '2013-05-17'),
(2, 32, '2013-03-01'),
(3, 33, '2013-05-14'),
(3, 35, '2013-05-14');
You said
In another words, the first 2 lines are from the same customer(id 19), i wish he'd get only one record for each client, which would be the record with the max date, in the case, the second record from this list.
select s.customerId, max (s.saledate)
from sales s
where s.saledate <= '2013-05-16'
group by s.customerId
order by customerId;
customerId max
--
1 2013-05-14
2 2013-05-16
3 2013-05-14
What does that table mean? It means that the latest date on or before May 16 on which customer "1" bought something was May 14; the latest date on or before May 16 on which customer "2" bought something was May 16. If you use this derived table in joins, it will return predictable results with consistent meaning.
Now let's look at a slightly different query. MySQL permits this syntax, and returns the result set below.
select s.customerId, s.saleId, max(s.saledate) max_sale
from sales s
where s.saledate <= '2013-05-16'
group by s.customerId
order by customerId;
customerId saleId max_sale
--
1 10 2013-05-14
2 20 2013-05-16
3 33 2013-05-14
The sale with ID "10" didn't happen on May 14; it happened on May 13. This query has produced a falsehood. Joining this derived table with the table of sales transactions will compound the error.
That's why Firebird correctly raises an error. The solution is to drop saleId from the SELECT clause.
Now, having said all that, you can find the customers who have had no sales since May 16 like this.
select distinct customerId from sales
where customerID not in
(select customerId
from sales
where saledate >= '2013-05-16')
And you can get the right customerId and the "right" saleId like this. (I say "right" saleId, because there could be more than one on the day in question. I just chose the max.)
select sales.customerId, sales.saledate, max(saleId)
from sales
inner join (select customerId, max(saledate) max_date
from sales
where saledate < '2013-05-16'
group by customerId) max_dates
on sales.customerId = max_dates.customerId
and sales.saledate = max_dates.max_date
inner join (select distinct customerId
from sales
where customerID not in
(select customerId
from sales
where saledate >= '2013-05-16')) no_sales
on sales.customerId = no_sales.customerId
group by sales.customerId, sales.saledate
Personally, I find common table expressions make it easier for me to read SQL statements like that without getting lost in the SELECTs.
with no_sales as (
select distinct customerId
from sales
where customerID not in
(select customerId
from sales
where saledate >= '2013-05-16')
),
max_dates as (
select customerId, max(saledate) max_date
from sales
where saledate < '2013-05-16'
group by customerId
)
select sales.customerId, sales.saledate, max(saleId)
from sales
inner join max_dates
on sales.customerId = max_dates.customerId
and sales.saledate = max_dates.max_date
inner join no_sales
on sales.customerId = no_sales.customerId
group by sales.customerId, sales.saledate
then you can use following query ..
EDIT changes made after comment by likeitlikeit for only one row per CustomerID even when we will have one case where we have multiple saleID for customer with certain condition -
select x.customerID, max(x.saleID), max(x.x_date) from (
select s.customerId, s.saleId, max (s.date) x_date from sales s
group by s.customerId, s.saleId
having max(s.date) <= '05-16-2013'
and max(s.date) = ( select max(s1.date)
from sales s1
where s1.customeId = s.customerId))x
group by x.customerID
You can Try Maxing the s.saleId (Max(s.saleId)) and removing it from the Group By clause
A subquery should do the job, I can't test it right now but it seems ok:
SELECT s.customerId, s.saleId, subq.maxdate
FROM sales AS s
INNER JOIN (SELECT customerId, MAX(date) AS maxdate
FROM sales
GROUP BY customerId, saleId
HAVING MAX(s.date) <= '05-16-2013'
) AS subq
ON s.customerId = subq.customerId AND s.date = subq.maxdate
I have a table with purchased orders data.
Each row contails the amount of certain item purchased, cost per item and the order number group. Each different item purchased is a new row with same order number.
I basically want to return the total cost for that order. I have tried the following but am getting nowhere:
SELECT order_number, SUM( sub_total ) AS `total`
FROM
SELECT order_number, SUM( SUM( amount ) * SUM( cost_per_item ) ) AS `sub_total`
FROM `ecom_orders`
WHERE member_id = '4'
GROUP BY order_number
ORDER BY purchase_date DESC
Pretty much any SQL-92 compliant RDBMS will take this:
SELECT
order_number
,SUM(amount * cost_per_item) AS total
,purchase_date
FROM
ecom_orders
WHERE member_id = '4'
GROUP BY order_number,purchase_date
ORDER BY purchase_date DESC