while True:
string = input('Enter some text to print. \nType "done" to quit>')
if string == 'done':
break
print(string)
print('Done!')
SyntaxError: invalid syntax
image of issue
Image after idz's suggestion
I think your problem is that you wrote:
while true:
instead of
while True:
However, if you are using Python 2 you should be aware that input will attempt to evaluate what you type in as Python. Depending on what your aim is, you may want to use raw_input instead. This is not an issue if your are using Python 3.
Related
I attach a screenshot of the code
I am new to Python and am currently studying artificial intelligence, working in Spyder(python 3.9)
After executing the code, I expected this output
Binarized data:
[[1.о.1.]
[о.1.о.]
[1.о.о.]
[1.о.о.]]
In Python it is important to write one command in one line:
data_binarized = preprocessing.Binarizer(your_code)
If you want to write it in two lines, you can use implicit line continuation (Possible only inside parentheses, brackets and braces):
data_binarized = preprocessing.Binarizer(
your_code)
As an second possible option you can use the backslash (explicit line continuation):
data_binarized =\
preprocessing.Binarizer(your_code)
For more information about this look at this answer:
https://stackoverflow.com/a/4172465/21187993
I am new to PyCharm and I have 'Process finished with exit code 0' instead of getting (683, 11) as a result (please see attachment), could you guys help me out please? Much appreciate it!
That is good news! It means that there is no error with your code. You have run it right through and there is nothing wrong with it. Pycharm returns 0 when it has found no errors (plus any output you give it) and returns 1 as well as an error message when it encounters errors.
Editors and scripts do not behave like the interactive terminal, when you run a function it does not automatically show the the result. You need to actually tell it to do it yourself.
Generally you just print the results.
If you use print(data.shape) it should return what you expect with the success message Process finished with exit code 0.
exit code 0 means you code run with no error.
Let's give a error code for example(clearly in the below image): in below code, the variable lst is an empty list,
but we get the 5 member in it(which not exists), so the program throws IndexError, and exit 1 which means there is error with the code.
You can also define exit code for analysis, for example:
ERROR_USERNAME, ERROR_PASSWORD, RIGHT_CODE = 683, 11, 0
right_name, right_password = 'xy', 'xy'
name, password = 'xy', 'wrong_password'
if name != right_name:
exit(ERROR_USERNAME)
if password != right_password:
exit(ERROR_PASSWORD)
exit(RIGHT_CODE)
I would recommend you to read up onexit codes.
exit 0 means no error.
exit 1 means there is some error in your code.
This is not pyCharm or python specific. This is a very common practice in most of the programming languages. Where exit 0 means the successful execution of the program and a non zero exit code indicates an error.
Almost all the program(C++/python/java..) return 0 if it runs successful.That isn't specific to pycharm or python.
In program there is no need to invoke exit function explicitly when it runs success it invoke exit(0) by default, invoke exit(not_zero_num) when runs failed.
You can also invoke exit function with different code(num) for analysis.
You can also see https://en.wikipedia.org/wiki/Exit_(system_call) for more details.
What worked for me when this happened was to go to
Run --> Edit Configurations --> Execution --> check the box Run with
Python Console (which was unchecked).
This means that the compilation was successful (no errors). PyCharm and command prompt (Windows OS), terminal (Ubuntu) don't work the same way. PyCharm is an editor and if you want to print something, you explicitly have to write the print statement:
print(whatever_you_want_to_print)
In your case,
print(data.shape)
I think there's no problem in your code and you could find your print results (and other outputs) in the tab 5: Debug rather than 4: Run.
I just ran into this, but couldn't even run a simple print('hello world') function.
Turns out Comodo's Firewall was stopping the script from printing. This is a pretty easy fix by deleting Python out of the Settings > Advanced > Script Analysis portion of Comodo.
Good Luck
I had same problem with yours. And I finally solve it
I see you are trying to run code "Kaggle - BreastCancer.py"
but your pycharm try to run "Breast.py" instead of your code.
(I think Breast.py only contains functions so pycharm can run without showing any result)
Check on tab [Run] which code you are trying to run.
Your starting the program's run from a different file than you have open there. In Run (alt+shift+F10), set the python file you would like to run or debug.
I am using HCatalog's WebHCat API to run Pig jobs, such as documented here:
https://cwiki.apache.org/confluence/display/Hive/WebHCat+Reference+Pig
I have no problem running a simple job but I would like to attach a parameters file to the job, such as one can do using pig command line's parameter: --param_file .
I assume this is possible through arg request's parameter, so I tried multiple things, such as passing:
'arg': '-param_file /path/to/param.file'
or:
'arg': {'param_file': '/path/to/param.file'}
None seems to work, and error stacks don't say much.
I would love to know if this is possible, and if so, how to correctly achieve this.
Many thanks
Correct usage:
'arg': ['-param_file', '/path/to/param.file']
Explanation:
By passing the value in arg,
'arg': {'-param_file': '/path/to/param.file'}
webhcat generates "-param_file" for the command prompt.
Pig throws the following error
ERROR org.apache.pig.Main - ERROR 2999: Unexpected internal error. Can not create a Path from a null string
Using a comma instead of the colon operator passes the path to file as a second argument.
webhcat will generate "-param_file" "/path/to/param.file"
P.S: I am using Requests library on python to make the REST calls
Am trying to use NEOS to solve a linear program using MPS input.
The MPS file is fine, but apparently you need a "paramaters file" as well to tell the solver what to do (min/max etc.). However I can't find any information on this online anywhere.
So far I have got NEOS to solve a maximization problem and display the objective function. However I cannot get it to display the variables.
Does anyone know what code I should add to the paramters file to tell NEOS/CBC to display the resulting variables?
The parameter file consists of a list of Cbc (standalone) commands in a file (one per line). The format of the commands is (quoting the documentation):
One command per line (and no -)
abcd? gives list of possibilities, if only one + explanation
abcd?? adds explanation, if only one fuller help(LATER)
abcd without value (where expected) gives current value
abcd value or abcd = value sets value
The commands are the following:
? dualT(olerance) primalT(olerance) inf(easibilityWeight)
integerT(olerance) inc(rement) allow(ableGap) ratio(Gap)
fix(OnDj) tighten(Factor) log(Level) slog(Level)
maxN(odes) strong(Branching) direction error(sAllowed)
gomory(Cuts) probing(Cuts) knapsack(Cuts) oddhole(Cuts)
clique(Cuts) round(ingHeuristic) cost(Strategy) keepN(ames)
scaling directory solver import
export save(Model) restore(Model) presolve
initialS(olve) branch(AndBound) sol(ution) max(imize)
min(imize) time(Limit) exit stop
quit - stdin unitTest
miplib ver(sion)
To see the solution values, you should include the line sol - after the min or max line of your parameter file.
If this doesn't work you can submit the problem to NEOS in AMPL format via this page. In addition to model and data files, it accepts a commands file where you can use statements to solve the problem and display the solution, for example:
solve;
display _varname, _var;
This post describes how to convert MPS to AMPL.
Just started learning Python as beginner and I found it fun. But it gave me strange errors mentioned below. I'm learning from a book and the code there is written as:
fish="basss"
if fish=="bass":
print('super')
else:
print('bla')
It gave me a syntax error and I couldn't understood the reason. I have written my code as same as written in book. I've searched in google, but couldn't find anything. I'm using the latest version of python and I typed this in Python shell.
Python is sensitive to indentation. Your code should be indented like this:
fish="basss"
if fish=="bass":
print('super')
else:
print('bla')
because your else block isn't aligned with your if block, try un-indenting the else.
fish = "basss"
if fish == "bass":
print('super')
else:
print('bla')
Python differentiates between code blocks by indentation. It is very important to have correct indentation in your code.
if fish=="bass":
print('super')
else:
print('bla')
if and else have to be at the same level of indentation. All statements to be executed within each of those conditionals have to be indented again.
There is an indentation error , you have to do like this,
fish="basss"
if fish=="bass":
print('super')
else:
print('bla')
Always else block should be under the same indentation level of if or elif statements.
You have to type it on multiple lines. The if and else statements cannot be on the same line. This causes an error, and so they must be typed in separate lines.