Start new fragment from dialogfragment - kotlin

Question

I want to show DialogFragment in my project if database size is less then 5 (I check it in QuizFragment) and move to another fragment (ListFragment) by clicking button "OK" on dialogFragment. Both fragments are in navigation if it matters. How can I do it?
This database size check in quizFragment
viewModel.getRandomTranslations().observe(viewLifecycleOwner, { translations ->
binding.apply {
if (translations.size < 5){
DatabaseSizeDialogFragment(translations.size).show(parentFragmentManager, "DatabaseSizeDialogFragment")
}
}
This is my dialog fragment
class DatabaseSizeDialogFragment(
private val databaseSize: Int
): DialogFragment() {
override fun onCreateDialog(savedInstanceState: Bundle?): Dialog {
return activity?.let {
val builder = AlertDialog.Builder(it)
builder.setTitle("Result Dialog")
builder.setTitle("Your learning list size is $databaseSize. \nYou need at least 5 words to start the quiz!")
builder.setPositiveButton("Ok") { _, _ ->
dismiss()
}
builder.create()
} ?: throw IllegalStateException("Activity cannot be null")
}
}

Answer 1

You can use lambda
viewModel.getRandomTranslations().observe(viewLifecycleOwner, { translations ->
binding.apply {
if (translations.size < 5){
DatabaseSizeDialogFragment(
{id->
//move to another fragment
},
translations.size)
.show(parentFragmentManager, "DatabaseSizeDialogFragment")
}
}
and in dialog :
class DatabaseSizeDialogFragment(
var block: (id: Int) -> Unit,private val databaseSize: Int
): DialogFragment() {
override fun onCreateDialog(savedInstanceState: Bundle?): Dialog {
...
builder.setPositiveButton("Ok") { _, _ ->
dismiss()
block.invoke(yourId)
}
...
}
}