I have to make this SPARQL query on protege:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX owl: <http://www.w3.org/2002/07/owl#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>
PREFIX sw:<http://www.semanticweb.org/lorep/ontologies/2022/0/untitled-ontology-16#>
SELECT ?Name ?Surname ?test ?written ?oral ?Course
WHERE {
?Candidates sw:take_parts ?Course;
sw:Name ?Name;
sw:Surname ?Surname;
sw:test ?test;
sw:written ?written;
sw:oral ?oral;
}
Now I have some candidates that took only the test without taking written and oral so when I execute the query they does not show. How can I make everyone visible?
And then how could i sum the values from written and oral? I tried with BIND(?written+?oral AS ?total) but it doesn't seem to work
Related
I have a query made like this:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX owl: <http://www.w3.org/2002/07/owl#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>
PREFIX sw: <http://www.semanticweb.org/lorep/ontologies/2021/7/untitled-ontology-3#>
SELECT ?Name ?Surname ?Birth ?y
WHERE {
?x sw:is_in ?y ;
sw:Name ?Name;
sw:Surname ?Cognome;
sw:Birth ?Birth;
}
Is there any way to filter from a specific value of the resource y?
I'm quite new to query so any help would be appreciated
I am trying to retrieve information based on Data Property Assertions in Protege (SPARQL Query), however, my code is not working. I am trying to get all individuals that were born after 1960.
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX owl: <http://www.w3.org/2002/07/owl#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>
SELECT ?person ?birthYear
WHERE {
?a rdfs:label ?person .
?person xsd:hasBirthYear ?birthYear .
FILTER(?birthYear>=1960)
}
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX owl: <http://www.w3.org/2002/07/owl#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>
PREFIX base: <http://www.cs7is1.com/ireland-school-county#>
SELECT ((COUNT(?school))/?a AS ?density)
WHERE {
?school base:inCounty base:DUBLIN.
base:area ?a
}
GROUP BY ?a
I run this query, query is fine but I am getting a result like this
"0.47776812"^^<http://www.w3.org/2001/XMLSchema#float>
I want to remove the XML content, I tried to bind it didn't work
I am a novice in Semantic Web and I would like to retrieve all property-value pairs of "apple" from DBPedia using SPARQL query. Below I have written the query in http://dbpedia.org/sparql editor, but it returns no any results.Could you tell me where I make a mistake, please?
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
prefix dbo: <http://dbpedia.org/ontology/>
prefix owl: <http://www.w3.org/2002/07/owl#>
prefix prov: <http://www.w3.org/ns/prov#>
prefix foaf: <http://xmlns.com/foaf/0.1/>
prefix dbp: <http://dbpedia.org/property/>
prefix dct: <http://purl.org/dc/terms/>
select * where {<http://http://dbpedia.org/page/Apple> ?property ?value}
You wrote http:// twice. Also, the correct URI for the query is /resource/, not /page/.
Working query:
select * where {<http://dbpedia.org/resource/Apple> ?property ?value}
Keep in mind this will give you information about the fruit, not the company.
I am giving you the query which will give you information about Apple Company rather than apple Fruit.
PREFIX dbprop: <http://dbpedia.org/property/>
PREFIX db: <http://dbpedia.org/resource/>
SELECT ?property, ?value WHERE {db:Apple_Inc ?property ?value}
Please help to list all Mealcourse from the wine Ontology or happy to receive useful links like this one :Sparql query on restriction list (Equivalent To) in protégé
MealCourse
and (hasFood value Pizza)
and(hasDrink value Wine)
Thank you
This is a bit complicated, but if you look into the ontology everything that is defined as a :MealCourse is an owl:equivalentClass, so you need to first find all owl:equivalentClass and then if you look into the result you will see that they are made of owl:intersectionOf parts. Then you need to break this intersection and filter so that you will only get objects that have :MealCourse as part of the intersection.
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX owl: <http://www.w3.org/2002/07/owl#>
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX : <http://www.w3.org/TR/2003/PR-owl-guide-20031209/food#>
SELECT distinct *
WHERE { ?subject owl:equivalentClass ?object.
?object (owl:intersectionOf | owl:unionOf) ?node.
?node rdf:rest*/rdf:first ?eq.
Filter ( ?eq in (:MealCourse ) )
}
orderBy ?subject