I have 3 tables.First table is student.Second is student_detail and last one special_codes.
student table
studentname | invoiceno |tax |invoiceamount
Paul 10 500 1950
Georghe 20 1000 6850
Mary 30 1500 1900
Messy 40 2000 7050
studentdetail
invoiceno | code | product | amount
10 101 pencil 100
10 102 rubber 350
10 103 bag 1500
20 108 wheel 5000
20 109 tv 1500
20 110 ps 300
20 111 mouse 50
30 103 bag 1500
30 105 keyboard 400
40 111 mouse 50
40 112 car 7000
I can join these two table like this and get result table
select s.studentname,s.tax,s.invoiceamount,st.product,sum(st.amount) from student s, studentdetail st
where s.invoiceno = st.invoiceno
group by
s.studentname,
s.tax,
s.invoiceamount,
st.product
result table
studentname tax invoiceamount product amount
Paul 500 1950 bag 1500
Paul 500 1950 pencil 100
Paul 500 1950 rubber 350
Messy 2000 7050 car 7000
Messy 2000 7050 mouse 50
Mary 1500 1900 bag 1500
Mary 1500 1900 keyboard 400
Georghe 1000 6850 mouse 50
Georghe 1000 6850 ps 300
Georghe 1000 6850 tv 1500
Georghe 1000 6850 wheel 5000
Last table is special codes.It contains only one column which is called code
specialcodes table
code
101
102
113
104
105
110
111
What i want to do is to look up studentdetail table and to find codes that are same in specialcodes.Then to sum amount values and write sum to result table as another column.Result table
should be like that
result table(final)
studentname tax invoiceamount product amount taxexclude
Paul 500 1950 bag 1500 450
Paul 500 1950 pencil 100 450
Paul 500 1950 rubber 350 450
Messy 2000 7050 car 7000 50
Messy 2000 7050 mouse 50 50
Mary 1500 1900 bag 1500 400
Mary 1500 1900 keyboard 400 400
Georghe 1000 6850 mouse 50 350
Georghe 1000 6850 ps 300 350
Georghe 1000 6850 tv 1500 350
Georghe 1000 6850 wheel 5000 350
You can use analytic functions rather than GROUP BY and aggregating:
select s.studentname,
s.tax,
invoiceamount,
SUM(d.amount) OVER (PARTITION BY s.invoiceno) AS inv_amt_calc,
d.product,
d.amount,
SUM(CASE WHEN c.code IS NOT NULL THEN d.amount END)
OVER (PARTITION BY s.invoiceno) AS taxexclude
from student s
INNER JOIN studentdetail d
ON s.invoiceno = d.invoiceno
LEFT OUTER JOIN specialcodes c
ON (c.code = d.code)
Note: You can (and should) calculate the invoice amount from the studentdetails table rather than duplicating the data in the student table and violating Third-Normal Form.
Which, for your sample data, outputs:
STUDENTNAME
TAX
INVOICEAMOUNT
INV_AMT_CALC
PRODUCT
AMOUNT
TAXEXCLUDE
Paul
500
1950
1950
rubber
350
450
Paul
500
1950
1950
pencil
100
450
Paul
500
1950
1950
bag
1500
450
Georghe
1000
6850
6850
tv
1500
350
Georghe
1000
6850
6850
wheel
5000
350
Georghe
1000
6850
6850
ps
300
350
Georghe
1000
6850
6850
mouse
50
350
Mary
1500
1900
1900
bag
1500
400
Mary
1500
1900
1900
keyboard
400
400
Messy
2000
7050
7050
mouse
50
50
Messy
2000
7050
7050
car
7000
50
If you really want a version using GROUP BY then:
SELECT s.studentname,
s.tax,
s.invoiceamount,
SUM(d.amount) OVER (PARTITION BY s.invoiceno) AS inv_amt_calc,
d.product,
d.amount,
t.taxexclude
FROM student s
INNER JOIN studentdetail d
ON s.invoiceno = d.invoiceno
LEFT OUTER JOIN (
SELECT invoiceno,
SUM(amount) AS taxexclude
FROM studentdetail
WHERE code IN (SELECT code FROM specialcodes)
GROUP BY
invoiceno
) t
ON s.invoiceno = t.invoiceno;
db<>fiddle here
Related
I have two tables:
Employees:
employee_id field max_amount
3 a 3000
4 a 3000
1 a 1600
2 a 500
4 b 4000
2 b 4000
3 b 1700
ordered by employee, field, amount desc.
Amounts (pol, premia,field):
pol premia field **assign_to_employee**
11 900 a 3
44 1000 a 3
55 1400 a 4
77 500 a 3
88 1300 a 1
22 800 b 4
33 3900 b 2
66 1300 b 4
Assign Stats Table:
employee_id field max_amount true_amount remain
3 a 3000 2400 600
4 a 3000 1400 1600
1 a 1600 1300 300
2 a 500 0 500
4 b 4000 2100 1900
2 b 4000 3900 100
3 b 1700 0 1700
The output : assign_to_employee field (merged to amounts table).
Algoritem wise : The method is to assign pol's to employees until the premia needs to be added to the cumulative_sum is bigger then the max amount per employee listed in the employees table. You always start with the employess with most max amount until you cannot add any other pols to the employee.
I start with the employees with the grater max_amount per field.
I keep doing this until no pols remains to be assign.
Can you help me solve this?
Thank you.
select
om.orderno,
od.product,
od.preorderqty,
(od.preorderqty * od.nto) as preordernet
from OrderMaster om
join OrderDetail od on od.orderid = om.id
and ((od.prodcode like '100-%') or (od.prodcode like '200-%'))
order by om.orderno,sod.prodcode
Current result:
ORDERNO PRODUCT PREORDERQTY PREORDERNET
1000 100-A 2 200
1000 100-B 2 300
1000 100-C 1 450
2000 100-A 3 300
2000 100-B 1 150
2000 200-A 2 900
3000 200-A 1 450
I would need help getting a script that:
Sums the orders based on specific content
Orders can contain products beginning with 300- etc.
Expected result:
ORDERNO PRODUCT PREORDERQTY PREORDERNET ORDERNET
1000 100-A 2 200 950
1000 100-B 2 300 950
1000 100-C 1 450 950
2000 100-A 3 300 1350
2000 100-B 1 150 1350
2000 200-A 2 900 1350
3000 200-A 1 450 450
As I understood from the expected output ,use sum as window function to get it,
select om.orderno
,od.product
,od.preorderqty
,(od.preorderqty * od.nto) as preordernet
,sum(od.preorderqty * od.nto) over (partition by om.orderno) as ordernet
from OrderMaster om
join OrderDetail od
on od.orderid = om.id
and ((od.prodcode like '100-%')
or (od.prodcode like '200-%'))
order by om.orderno,sod.prodcode
I have a table that looks like this
TIMECODE UNIT_CODE Department Account AMOUNT
20194 10 1000 1000 100
20194 10 2354 1100 150
20194 10 1000 1000 200
20194 10 2354 1000 100
20194 20 500 1000 250
20194 20 500 1100 200
How I need the results to be is like this
TIMECODE UNIT_CODE Department 1000 1100
20194 10 1000 300 NULL
20194 10 2354 100 150
20194 20 500 250 200
hopefully that gives you a better image, but basically I would need to do a SUM depending on the distinct value of the other columns. The accounts that were previously in rows would be changed into columns.
any ideas or help with this would be greatly appreciated
Try the following, here is the demo.
select
TIMECODE,
UNIT_CODE,
Department,
sum(case when Account = 1000 then AMOUNT end) as "1000",
sum(case when Account = 1100 then AMOUNT end) as "1100"
from myTable
group by
TIMECODE,
UNIT_CODE,
Department
Output:
---------------------------------------------------
| TIMECODE UNIT_CODE DEPARTMENT 1000 1100 |
---------------------------------------------------
| 20194 20 500 250 200 |
| 20194 10 1000 300 null|
| 20194 10 2354 100 150 |
---------------------------------------------------
I have 3 SQL tables. StudentTable, FeeAssociationTable and InvoiceTable.
StudentTable has primary key of AdmissionNumber, FeeAssociationTable has primary key of FeeAssociationID and InvioceTable has primary key InvoiceID.
The FeeAssociationTable takes AdmissionNumber and assign a fee to it, then while depositing fee the InvoiceTable takes AdmissionNumber and calculate all his fee and subtract from paid and the inserts in the dues.
The problem is; same AdmissionNumbercan have multiple row in InvoiceTable, "How can I can select and sum all recent dues of each AdmissionNumber(not repeating)."
Here is some data;
37 1 3000 January-2018 3000 0 2018-08-17
38 2 3000 January-2018 3000 0 2018-08-17
39 3 3000 January-2018 3000 0 2018-08-17
40 4 3000 January-2018 3000 0 2018-08-17
41 5 3000 January-2018 3000 0 2018-08-17
42 6 3000 January-2018 3000 0 2018-08-17
43 7 3000 January-2018 3000 0 2018-08-17
44 8 3000 January-2018 3000 0 2018-08-17
45 9 3000 January-2018 3000 0 2018-08-17
46 10 3000 January-2018 3000 0 2018-08-17
47 1 3200 June-2018 2500 700 2018-08-17
48 2 3200 June-2018 2500 700 2018-08-17
49 3 3200 June-2018 2500 700 2018-08-17
50 4 3200 June-2018 2500 700 2018-08-17
51 5 3200 June-2018 2500 700 2018-08-17
52 6 3200 June-2018 2500 700 2018-08-17
53 7 3200 June-2018 2500 700 2018-08-17
54 8 3200 June-2018 2500 700 2018-08-17
55 9 3200 June-2018 2500 700 2018-08-17
56 10 3200 June-2018 2500 700 2018-08-17
57 10 3700 July-2018 2500 1200 2018-08-17
58 9 3700 July-2018 2400 1300 2018-08-17
59 8 3700 July-2018 200 3500 2018-08-17
60 7 3700 July-2018 2000 1700 2018-08-17
61 1 3700 July-2018 1500 2200 2018-08-17
62 2 3700 July-2018 3100 600 2018-08-17
Expectation:
I want the most recent dues of each student without adding in the previous one.
For example:-
InvoiceId AdmissionNumber TotalFee Month Paid Dues Date
37 1 3000 January-2018 3000 0 2018-08-17
47 1 3200 June-2018 2500 700 2018-08-17
61 1 3700 July-2018 1500 2200 2018-08-17
There are 3 entries of AdmissionNumber 1 in the InvoiceTable. In the first one there are no due, but in the second entry there are Dues of 700, and in the third the dues of 2200 on AdmissionNumber 1.
The thing I want to do is select last one which can be done by this code given below:
SELECT Dues FROM InvoiceTable AS IT
WHERE IT.InvoiceID = (SELECT MAX(InvoiceID)
FROM InvoiceTable WHERE AdmissionNumber = 1)
This is for single I want list of recent dues of every student.
Thanks in Advance
Based on your follow up information, I believe the following will give you what you are looking for:
SELECT invoiceId, AdmissionNumber, Dues
FROM InvoiceTable AS IT
WHERE IT.invoiceId IN (SELECT MAX(invoiceId)
FROM InvoiceTable
GROUP BY AdmissionNumber)
ORDER BY AdmissionNumber ASC
They query you tried in your example was close, it just had to be adapted to work for the whole table and not a single AdmissionNumber.
Here is a demo of this working: SQL Fiddle
I have three tables in my database Sales, SalesPeople and Appliances.
Sales
SaleDate EmployeeID AppID Qty
---------- ---------- ----- -----------
2010-01-01 1412 150 1
2010-01-05 3231 110 1
2010-01-03 2920 110 2
2010-01-13 1412 100 1
2010-01-25 1235 150 2
2010-01-22 1235 100 2
2010-01-12 2920 150 3
2010-01-14 3231 100 1
2010-01-15 1235 300 1
2010-01-03 2920 200 2
2010-01-31 2920 310 1
2010-01-05 1412 420 1
2010-01-15 3231 400 2
SalesPeople
EmployeeID EmployeeName CommRate BaseSalary SupervisorID
---------- ------------------------------ ----------- ----------- ------------
1235 Linda Smith 15 1200 1412
1412 Anne Green 12 1800 NULL
2920 Charles Brown 10 1150 1412
3231 Harry Purple 18 1700 1412
Appliances
ID AppType StoreID Cost Price
---- -------------------- ------- ------------- -------------
100 Refrigerator 22 150 250
110 Refrigerator 20 175 300
150 Television 27 225 340
200 Microwave Oven 22 120 180
300 Washer 27 200 325
310 Washer 22 280 400
400 Dryer 20 150 220
420 Dryer 22 240 360
How can I obtain this result? (That displays the profitability of each of the salespeople ordered from the most profitable to the least. Gross is simply the sum of the quantity of items sold multiplied by the price. Commission is calculated from the gross minus the cost of those items (i.e. from
qty*(price-cost)). Net profit is the total profit minus commission.)
Name Gross Commission Net Profit
------------- ----- ---------- ---------
Charles Brown 2380 83.5 751.5
Linda Smith 1505 83.25 471.75
Harry Purple 990 65.7 299.3
Anne Green 950 40.2 294.8
My attempt:
CREATE PROC Profitability AS
SELECT
sp.EmployeeName, (sum(s.Qty) * a.Price) as [Gross],
[Gross] - a.Cost, as [Commision],
SOMETHING as [Net Profit]
FROM
Salespeople sp, Appliances a, Sales s
WHERE
s.AppID = a.ID
AND sp.EmployeeID = s.EmployeeID
GROUP BY
sp.EmployeeName
GO
EXEC Profitability
Simple rule: Never use commas in the FROM clause. Always use explicit JOIN syntax.
In addition to fixing the JOIN syntax, your query needs a few other enhancements for the aggregation functions:
SELECT sp.EmployeeName, sum(s.Qty * a.Price) as Gross,
SUM(s.Qty * (a.Price - a.Cost)) * sp.CommRate / 100.0 as Commission,
SUM(s.Qty * (a.Price - a.Cost)) * (1 - sp.CommRate / 100.0) as NetProfit
FROM Sales s JOIN
Salespeople sp
ON sp.EmployeeID = s.EmployeeID JOIN
Appliances a
ON s.AppID = a.ID
GROUP BY sp.EmployeeName sp.CommRate
ORDER BY NetProfit DESC;