When navigating between screens using the StackNavigator with a fade transition, a user is able to click during the transition animation and possibly hit a TouchableOpacity on the screen that is being navigated away from. The TouchableOpacity registers the hit and thus the app responds accordingly. This is causing issues for "fast clicking" users where they click a button to navigate to a new screen and immediately click where they think a new button will be, but in reality is clicking a button on the previous screen.
Is there a way to prevent any user interaction during these transition animations? I have tried setting the transition duration to 0 like so:
transitionConfig: () => ({
transitionSpec: {
duration: 0
}
})
but the issue still occurs.
I do not want to disable the animation completely, because it is quick enough for most users and they like the animation.
So in your case you can do several things
You can use React Native Activity Indicator -> View
You can use Overlay Library -> react-native-loading-spinner-overlay -> View GitHub
If you like to make loading like facebook / instagram -> then use react-native-easy-content-loader -> View GitHub
you need to flag screen before navigating away; disabling all touchs.
an easy way would be to have a reusable hook that return a transparent absolute positioned View that cover entier page and a callback to enable it;
so you flow will be; enable this which will overlap whole screen and capture any clicks basically disabling them;
something more like:
function useOverlay(){
const [isVisible, toggle] = React.useState(false);
const Component = React.memo(()=><View style={styles.transparentAbsolute} />,[])
return [toggle, isVisible ? Component : null];
}
then inside your Screen before you call navigate just call toggle
and include Component at top of you screen;
export default function TabOneScreen({ navigation }: RootTabScreenProps<'TabOne'>) {
const [ toggle, component ] = useOverlay();
return (
<View style={styles.container}>
{component}
<Button onPress={()=>{toggle(true); navigation.navigate('Home');} title="go home" />
</View>
);
}
Related
I have a react native app which uses react navigation (V6.x for sure). My app has a main navigator which is a bottom-tabs navigator and contains three screens (tabs). Every one of these screens are stack navigators themselves. Let's say one of my tabs is named Wallet (others are Settings and Transactions). Inside this Wallet screen (which is a stack navigator), i have a HomePage screen, a Receive screen and a Send screen. I want to achieve the following behavior (like below screenshot from designs):
Whenever the user goes to one of Send or Receive screens, i want all the tab bar buttons become unfocused (tab bar is still visibe though). And whenever the user gets back to HomePage screen (or going to Settings or Transactions tab by pressing the corresponding tab button), I want the relevant tab button to get focused again. How can i achieve that with react navigation itself?
(My project is managed by redux, but i prefer not to use state management tools and use react navigation itself)
You can do that, but checking child navigation state inside your TabNavigator's screenOptions.
screenOptions={({ route, navigation }) => {
// get wallet stack route
const walletStack = navigation.getState().routes.find((route) => route.name === 'Wallet');
// get current wallet stack focused screen
const walletRouteName = getFocusedRouteNameFromRoute(walletStack);
const shouldBeUnfocused =
walletRouteName === 'Send' || walletRouteName === 'Receive';
{...}
}
Based on shouldBeUnfocused you can render proper icons and colors. Here is the snack with example code. You can red here about customizing tab bar's appearance.
I am using react navigation ("#react-navigation/native": "^5.1.3") and I have the following setup:
BottomNavigation
-stack1
-stack2
It looks like goBack() is local to the stack. What that means is that if I navigate from a page in stack1 to a page in stack2, I am unable to go the the page I came up from.
Solutions (or rather hacks) that didn't work for me:
pass the source screen as param and then navigate. That isn't a real back button and does not play well with android back button.
Put all pages in bottom navigation. Bottom navigation does not have animations it seems, so I can not achieve the right transitions
Put all pages in stack navigation. In this case I lose the fixed bottom navigation. I can add it to each page, but when transitioning it will go away with the old screen and come again with the new one, which is undesirable.
So I am wondering if I am missing something big here, like a globalBack() that I overlooked?!
And also, I am looking for a solution to this problem which remains.
Naturally if you have bottoms tabs with each tab having its own stack navigator, calling navigation.goBack() will go back from one screen inside stack navigator to previous screen inside that same stack navigator. That's how navigation works in pretty much every app. Pressing back button or swiping back does not change tab for you, tabs are more like separate small apps by itself. If you want to specifically jump from one tab to another instead of going back in stack, use navigation.dispatch(TabActions.jumpTo('Profile')). If pressing something inside tab#1 makes you go to to tab#2 then this screen most likely also belongs to tab#1
also, take a look at backBehavior prop of Tab.Navigator, it might be doing what you want depending on what exactly it is you want https://reactnavigation.org/docs/bottom-tab-navigator/#backbehavior
I'm using bottom tab navigator with 2 stacks as well. I faced similar issue and agree with #Max explanation. Due to my Notification screen is in Stack 1, I have to goBack to Notification after navigating away to Detail screen. After searching for the fix, I'm using this workaround (for v6).
Tab 1 - Stack 1 (Home > Notification screen)
Tab 2 - Stack 2 (Reward Home > Reward Detail screen)
I passed a param when navigating from Notification to RewardDetail. Then I override the headerLeft and use BackHandler to handle Android back function.
Notification.js
navigation.navigate('RewardStack', {
screen: 'RewardDetail',
initial: false,
params:{notification: notification_data_source}
})
RewardDetail.js
const payload = route.params.notification
//1. override headerLeft button
useLayoutEffect(() => {
if(payload)
navigation.setOptions({
headerLeft: () => (
<Button
TouchableComponent={TouchableOpacity}
buttonStyle={{paddingTop:4, paddingLeft:0}}
type='clear'
icon={<Icon name={'chevron-left'} size={30} style={{color:'#FFF'}} />}
onPress={()=>{
navigation.goBack()
navigation.navigate('Notification') //can use this only
}}
/>
)
})
}, [navigation]);
//2. Add BackHandler
useEffect(() => {
const onBackPress = () => {
if (payload) {
navigation.goBack()
navigation.navigate('Notification') //can use this only
return true
} else {
return false
}
}
BackHandler.addEventListener('hardwareBackPress', onBackPress)
return () => BackHandler.removeEventListener('hardwareBackPress', onBackPress)
}, [navigation]);
I can just use navigation.navigate('Notification') to return to Notification but this will cause Detail screen to stay mounted in Stack 2. I want the Stack 2 to return to RewardHome after go back to Notification. Hence I used:
navigation.goBack() //pop screen to RewardHome
navigation.navigate('Notification') //jump to Notification
I am making an react native android app in which componentWillUnmount() does not works.Suppose user enters a text value in a text input in particular screen and goes to next screen.After that when user presses back button then i want that text value written in text input to be removed.I tries by adding this line in my code.
componentWillUnmount(){
this.setState({text:""})
}
Basically i was removing the state value which i put in TextInput.But this does not works.Same this is happening in case of activity indicator.When activity indicator start to fetch data then first i check if connected to internet or not.If not then by navigation i navigate to no network screen.But from there when i presses back button then activity indicator does not go away ? So how can i remove all the value of state in a component after navigating to different screen?
React Navigation allows you to add listeners so you track actions that are happening to the screen.
There are four listeners that you can add:
willFocus - the screen will focus
didFocus - the screen focused (if there was a transition, the transition completed)
willBlur - the screen will be unfocused
didBlur - the screen unfocused (if there was a transition, the transition completed)
https://reactnavigation.org/docs/en/navigation-prop.html#addlistener-subscribe-to-updates-to-navigation-lifecycle
Here is an example of calling the willBlur, the others follow the same pattern you just change the value that is passed to the function.
componentDidMount () {
this.didBlurSubscription = this.props.navigation.addListener(
'didBlur',
payload => {
// you can perform actions here when the screen `willBlur`
this.setState({text: ''});
}
);
}
componentWillUnmount () {
// remember to unsubscribe
if (this.didBlurSubscription) {
this.didBlurSubscription.remove();
}
}
The reason your current solution is not working is that the screen isn't being unmounted it is going in and out of focus/blur. So the componentWillUnmount will not be called. Also if the component is being unmounted then you should not be trying to setState as that is an anitpattern and can lead to memory leaks.
I have a component that locks the screen to landscape before rendering.
When I click on the next button, I go to the next screen which unlocks the orientation.
When I click on the previous button, I go back to the first screen.
(The navigation is done by this.props.navigation.navigate('ScreenName') from react-native-navigation).
The screen now gets locked in the componentDidMount method, is there a similar method that gets called when you go back to an already rendered component?
One way you can do this in react-native-navigation is to pass parameters backwards. When you navigate back to your component pass a parameter that indicates that it went back. After that in your file where you want to have the function, have it listening for the wentBack prop.
Navigating backwards with a parameter:
this.props.navigation.navigate('ScreenName', {
wentBack: true,
});
Listening for the parameter:
const { navigation } = this.props,
wentBack = navigation.getParam('wentBack', 'whatever default value - should be false');
Then in your render method you can render conditionally for whatever you want to show:
render() {
return (
<View>
{wentBack ? 'do something it went back!' : 'it didn't go back'}
</View>
);
}
i am getting struggling with this issue that how to stop the navigation bar pop swiping, if possible can any one give me suggestions that how to resolve it
as shown in the above image, when i was in the Property page,when i swipe from that page it goes to the previous page, this is at the time of swipe, it shows that when i swipe from Property it goes to results screen.I wanted to stop it, any help much appreciated
You can prevent all gestures by adding this to your Navigator
configureScene={(route) => ({
...Navigator.SceneConfigs.HorizontalSwipeJump,
gestures: false
})}
you can also disable this per route by adding this when you push the route
sceneConfig: {
...Navigator.SceneConfigs.HorizontalSwipeJump,
gestures: {} //or null
}