I’m using the this query to connect with amazon redshift.
And I have the following query:
Select b.*, c."releasedate",
DENSE_RANK() OVER(PARTITION BY b.originboardid ORDER BY TO_DATE(SUBSTRING(b.sprintenddate,0,9), 'DD/Mon/YY') DESC) AS "rank_sprint",
DENSE_RANK() OVER(PARTITION BY b.originboardid ORDER BY TO_DATE(c.releasedate, 'YYYY-MM-DD') DESC) AS "rank_release",
RANK() OVER (ORDER BY b.issueid, b.sprintid DESC) as "rank_issue",
MAX(IF (b.issueorigin='completed') AND (b.changeto='In Progress') and (b.changefield='status')
max(TO_DATE(SUBSTRING(b.changecreation,0,10),'YYYY-MM-DD')) OVER(b.issueid,b.sprintid)
) OVER (b.issueid,b.sprintid) as "lastinprogress"
from digitalplatforms.issues_braze b
Left join jira.releases c
On b.version_id=c.versionid
and its outputing the following error:
[Amazon](500310) Invalid operation: syntax error at or near "max"
Position: 459;
Also if I query just:
Select b.*, c.“releasedate”,
DENSE_RANK() OVER(PARTITION BY b.originboardid ORDER BY TO_DATE(SUBSTRING(b.sprintenddate,0,9), ‘DD/Mon/YY’) DESC) AS “rank_sprint”,
DENSE_RANK() OVER(PARTITION BY b.originboardid ORDER BY TO_DATE(c.releasedate, ‘YYYY-MM-DD’) DESC) AS “rank_release”,
RANK() OVER (ORDER BY b.issueid, b.sprintid DESC) as “rank_issue”
from digitalplatforms.issues_braze b
Left join jira.releases c
On b.version_id=c.versionid
it works.
Can someone help?
Thank you
There is no "IF" statement in SQL. SQL is not procedural. You need to rewrite you query using "CASE" or "DECODE" statements.
Also you cannot nest window functions. If you logic requires this then these need to operate at different levels of the query (SELECT level). However, are you sure both of these need to window functions - MAX() OVER vs. MAX()? They are using the same OVER clause so I expect not.
Just guessing based on you query but does this give you what you want?
MAX(DECODE((b.issueorigin='completed') AND (b.changeto='In Progress') and (b.changefield='status')), true,
TO_DATE(SUBSTRING(b.changecreation,0,10),'YYYY-MM-DD')
) OVER (b.issueid,b.sprintid) as "lastinprogress"
Related
The following query errors with an invalid column name 'rowid'
SELECT row_number() over (partition by sales_rep order by timestamp desc) as rowid, *
FROM dbo.you_gettheidea
where rowid = 1
However, the following version works perfectly. I'm not sure why.
with t1 as (SELECT row_number() over (partition by sales_rep order by timestamp desc) as rowid, *
FROM dbo.you_gettheidea)
Select * from t1
Where rowid = 1
SQL Server 12.0.2000
Edit: It appears that this question is in line with the following answered question
You can't use column alias in where clause of same statement. It doesn't obey the execution order that's why CTE is needed. Please check Execution order
FROM and JOIN s. The FROM clause, and subsequent JOIN s are first executed to determine the total working set of data that is being
queried.
WHERE.
GROUP BY.
HAVING.
SELECT.
DISTINCT.
ORDER BY.
LIMIT / OFFSET / TOP
Late answer, but there is another option without a CTE or subquery ... WITH TIES
Select top 1 with ties *
From dbo.you_gettheidea
Order By row_number() over (partition by sales_rep order by timestamp desc)
I am trying to run this query in Snowflake, but I keep getting an error.
select x.*, (select z.status from TBLA z where z.number_id=x.number_id and z.country=x.country and z.datetime=x.datetime) status
from
(
select a.number_id, a.country, max(datetime) as datetime
from TBLA a
group by a.number_id, a.country
) x
This is the error I am getting:
SQL compilation error: Unsupported subquery type cannot be evaluated
Does anyone know how to fix this?
To get the status for the latest datetime per number_id/country windowed function could be used:
SELECT a.*,
(ARRAY_AGG(a.status) WITHIN GROUP(ORDER BY a.datetime DESC)
OVER(PARTITION BY a.number_id, a.country))[0] AS latest_status
FROM TBLA a;
Looks like you are trying to get the latest status by number_id and country. A simple query to do that in Snowflake using window function row_number() is
select * from TBLA
qualify row_number() over (partition by number_id, country order by datetime desc) = 1;
Only scalar subqueries are allowed in the SELECT. Your subquery is not inherently scalar.
https://docs.snowflake.com/en/user-guide/querying-subqueries.html
select a.pm_id, a.pm_name
from loc_table a
qualify row_number() over(partition by pm_id order by pm_name asc) =1;
Can we write it this way in Vertica, I tried it but the qualify keyword is not taken by Vertica and the from Clause has to be at the end.
Can anybody explain what the above query does and how can we achieve the same in Vertica.
Vertica does not have the QUALIFY clause.
What it does have, is the analytic limit clause
Re-write your query like below, and run an easy global search-replace if you need that often:
SELECT
a.pm_id
, a.pm_name
FROM loc_table a
LIMIT 1 OVER(PARTITION BY pm_id ORDER BY pm_name ASC);
I think you need a subquery in Vertica:
select pm_id, pm_name
from (select l.pm_id, l.pm_name,
row_number() over (partition by pm_id order by pm_name asc) as seqnum
from loc_table l
) l
where seqnum = 1;
This is pretty much exactly what qualify does. Just like having filters on aggregation columns, qualify filters on window functions.
I am trying to get the row number for the rank. Below is the query,
SELECT *
FROM (
SELECT DISTINCT TOP 100 PERCENT rank() OVER (
PARTITION BY o.panel_id
,o.combo_type_code ORDER BY row_number() OVER (
ORDER BY o.panel_id
)
) AS rank
,panel_code
FROM tbk_offer_head o
,tbk_combo_type ct
,tbk_panel p
WHERE o.panel_id = p.panel_id
AND o.combo_type_code = ct.combo_type_code
AND o.panel_id IN (
SELECT p.panel_id
FROM tbk_panel p
WHERE p.campaign_id = 7392
)
) A
WHERE A.rank = 1
ORDER BY panel_code
Getting the error, Windowed functions cannot be used in the context of another one. Please help how can i solve this problem.
I have no idea what you are really trying to do. But you should definitely learn to use proper, explicit JOIN syntax.
But there is no need to nest the functions. Your logic should be equivalent to:
row_number() over (partition by o.panel_id, o.combo_type_code
order by o.panel_id
) as rank
Why does this use row_number() instead of rank()? Your original order by used row_number() which never has duplicates. Hence, if rank() could use it, the values would all be distinct, and the rank() would be equivalent to row_number() -- even when panel_id is duplicated.
select * from
(
Select DISTINCT
DocManREPORT_View.DOCINPUTDATE,
DocManREPORT_View.REACTIVATEDATE,
DocManREPORT_View.TRACENO,
DocManREPORT_View.CLIENTNAME,
DocManREPORT_View.DOCUMENTID,DocManREPORT_View.BARCODEID,
DocManREPORT_View.INPUTMODE,
DocManREPORT_View.INPUTSOURCE,PI.start_time,
RANK() OVER (PARTITION BY process_instance_id
ORDER BY last_modified_date desc) rank,
PI.STATUS AS PROCESSSTATUS
FROM DocManREPORT_View
INNER JOIN PROCESS_INSTANCE PI ON
(pi.instance_id = DocManREPORT_View.process_instance_id)
)
where rank = 1;
I presume DISTINCT clause could screw up the performance. I would recommend you to get rid of it by including into partition by clause and have a look what have you got.
If you can, try to use the
RANK() OVER (PARTITION BY process_instance_id
ORDER BY last_modified_date desc) rank,
Inside the VIEW, since I tihnk the View has already every data to make this step inside.