I have a string in the form of
<div>#FIRST#12345#</div>
How do I extract the number part from this string using T-SQL in SQL Server 2012? Note the number has variable length
Using just t-sql string functions you can try:
create table t(col varchar(50))
insert into t select '<div>#FIRST#12345#</div>'
insert into t select '<div>#THIRD#543#</div>'
insert into t select '<div>#SECOND#3690123#</div>'
select col,
case when p1.v=0 or p2.v <= p1.v then ''
else Substring(col, p1.v, p2.v-p1.v)
end ExtractedNumber
from t
cross apply(values(CharIndex('#',col,7) + 1))p1(v)
cross apply(values(CharIndex('#',col, p1.v + 1)))p2(v)
Output:
Caveat, this doesn't handle any "edge" cases and assumes data is as described.
Shooting from the hip due to a missing minimal reproducible example.
Assuming that it is XML data type column.
SQL
-- DDL and sample data population, start
DECLARE #tbl TABLE (ID INT IDENTITY PRIMARY KEY, xmldata XML);
INSERT INTO #tbl (xmldata) VALUES
('<div>#FIRST#12345#</div>'),
('<div>#FIRST#770770#</div>');
-- DDL and sample data population, end
SELECT t.*
, LEFT(x, CHARINDEX('#', x) - 1) AS Result
FROM #tbl t
CROSS APPLY xmldata.nodes('/div/text()') AS t1(c)
CROSS APPLY (SELECT REPLACE(c.value('.', 'VARCHAR(100)'), '#FIRST#' ,'')) AS t2(x);
Output
+----+---------------------------+--------+
| ID | xmldata | Result |
+----+---------------------------+--------+
| 1 | <div>#FIRST#12345#</div> | 12345 |
| 2 | <div>#FIRST#770770#</div> | 770770 |
+----+---------------------------+--------+
How can I replace 'a' to blank?
`Name` `ID`
----------------------------------
`b,c,d,e,abb,a` `1`
`b,c,d,a,e,abb` `2`
`a,b,c,d,a,e,abb` `3`
One way to do it would be to add a , to the beginning and end of each Name, then replace every occurence of ',a,' with ',', then trim the result of the ,:
update table_name
set Name = trim(',' from replace(concat(',', Name, ','), ',a,', ','));
Fiddle
Or if you just want to do a select without changing the rows:
select trim(',' from replace(concat(',', Name, ','), ',a,', ',')) as Name, ID
from table_name;
To address #Iptr's comment, if there can be consecutive a such as a, a, ..., you could use STRING_SPLIT to get rows from comma-separated values, then filter out where the value is a, then STRING_AGG and group by to get the comma separated values back:
select ID, STRING_AGG(u.Value, ',') as Name
from table_name
cross apply STRING_SPLIT (Name, ',') u
where Value <> 'a'
group by ID
Fiddle
Here is a solution based on tokenization via XML/XQuery.
It will work starting from SQL Server 2012 onwards.
Steps:
We are tokenizing a string of tokens via XML.
XQuery FLWOR expression is filtering out the 'a' token.
Reverting it back to a string of tokens.
SQL
-- DDL and sample data population, start
DECLARE #tbl TABLE (ID INT IDENTITY PRIMARY KEY, tokens VARCHAR(1000));
INSERT INTO #tbl (tokens) VALUES
('b,c,d,e,abb,a'),
('b,c,d,a,e,abb'),
('a,b,c,d,a,e,abb');
-- DDL and sample data population, end
DECLARE #separator CHAR(1) = ',';
SELECT t.*
, REPLACE(c.query('
for $x in /root/r/text()
return if ($x = "a") then ()
else data($x)
').value('.', 'VARCHAR(MAX)'), SPACE(1), #separator) AS Result
FROM #tbl AS t
CROSS APPLY (SELECT TRY_CAST('<root><r><![CDATA[' +
REPLACE(tokens, #separator, ']]></r><r><![CDATA[') +
']]></r></root>' AS XML)) AS t1(c);
Output
+----+-----------------+-------------+
| ID | tokens | Result |
+----+-----------------+-------------+
| 1 | b,c,d,e,abb,a | b,c,d,e,abb |
| 2 | b,c,d,a,e,abb | b,c,d,e,abb |
| 3 | a,b,c,d,a,e,abb | b,c,d,e,abb |
+----+-----------------+-------------+
Try as follow:
select Replace(name, N'a', N'') as RepName , ID from yourTable
Try this.
SELECT ID,Name, REPLACE(Name, 'a', ' ')
FROM tableName;
I have a string that I want to replace a group of numbers.
The string contains groupings of numbers (and a few letters). 'A12 456 1 65 7944'
I want to replace the group of 3 numbers with 'xxx', and the group of 4 numbers with 'zzzz'
I thought something like REPLACE(#str, '%[0-9][0-9][0-9]%', 'xxx') would work, but it doesn't. I can't even get '%[0-9]%' to replace anything.
If REPLACE is not suitable, how can I replace groups of numbers?
Please try the following solution based on XML and XQuery.
Notable points:
We are tokenizing input string as XML in the CROSS APPLY clause.
XQuery's FLWOR expression is checking for numeric integer values with
a particular length, and substitutes then with a replacement string.
XQuery .value() method outputs back a final result.
SQL
-- DDL and sample data population, start
DECLARE #tbl TABLE (ID INT IDENTITY PRIMARY KEY, tokens VARCHAR(MAX));
INSERT INTO #tbl (tokens) VALUES
('A12 456 1 65 7944');
-- DDL and sample data population, end
DECLARE #separator CHAR(1) = SPACE(1);
SELECT t.*
, c.query('
for $x in /root/r/text()
return if (xs:int($x) instance of xs:int and string-length($x)=3) then "xxx"
else if (xs:int($x) instance of xs:int and string-length($x)=4) then "zzzz"
else data($x)
').value('.', 'VARCHAR(MAX)') AS Result
FROM #tbl AS t
CROSS APPLY (SELECT TRY_CAST('<root><r><![CDATA[' +
REPLACE(tokens, #separator, ']]></r><r><![CDATA[') +
']]></r></root>' AS XML)) AS t1(c);
Output
+----+-------------------+-------------------+
| ID | tokens | Result |
+----+-------------------+-------------------+
| 1 | A12 456 1 65 7944 | A12 xxx 1 65 zzzz |
+----+-------------------+-------------------+
I have column with different pattern of string for each records let's call it [Description]. Here's the sample of records
[Description]
-qwetw MANN/1234556/DATE/030621/B/C/ACC/DIFF+AA11000532
-qwerty 123456789/06/29/2021/ACC./DONE/CLOSED+06+AA11001234
-qwert 123456789101213/-/BACK/300621/Rekening/Tutup+06+ZZZ21001123A
I want only pick the last number order - so the output would be:
[Description]
-11000532
-11001234
-21001123
Is there any function how to get it?
Thanks
Please try the following solutions.
First solution is for SQL Server 2017 onwards.
It is working by implementing the following steps:
It is tokenizing column value as XML.
Last token is our goal, i.e. (/root/r[last()]/text())[1]
TRIM() removes unwanted chars.
Second solution is for SQL Server 2012. It is much more involving.
SQL 2017
-- DDL and sample data population, start
DECLARE #tbl TABLE (ID INT IDENTITY PRIMARY KEY, Tokens VARCHAR(4000));
INSERT INTO #tbl VALUES
('-qwetw MANN/1234556/DATE/030621/B/C/ACC/DIFF+AA11000532'),
('-qwert 123456789101213/-/BACK/300621/Rekening/Tutup+06+ZZZ21001123A'),
('-qwerty 123456789/06/29/2021/ACC./DONE/CLOSED+06+AA11001234');
-- DDL and sample data population, end
DECLARE #separator CHAR(1) = '+'
, #CharsToRemove VARCHAR(100) = 'AZ';
SELECT ID, tokens
, TRIM(#CharsToRemove FROM token) AS Result
FROM #tbl
CROSS APPLY (VALUES (TRY_CAST('<root><r><![CDATA[' +
REPLACE(tokens, #separator, ']]></r><r><![CDATA[') +
']]></r></root>' AS XML))) AS t(c)
CROSS APPLY (VALUES (c.value('(/root/r[last()]/text())[1]', 'VARCHAR(256)'))) AS t2(token);
SQL 2012
SELECT ID, tokens
, (
SELECT SUBSTRING(token, number, 1)
FROM #tbl AS c
CROSS APPLY (
SELECT DISTINCT number
FROM master..spt_values
WHERE number BETWEEN 1 AND LEN(token)
) V
WHERE c.ID = p.ID
FOR XML PATH('r'), TYPE, ROOT('root')
)
.query('for $x in /root/r
return if (xs:int($x) instance of xs:int) then $x
else ()')
.query('/r/text()').value('.', 'BIGINT') AS Result
FROM #tbl AS p
CROSS APPLY (VALUES (TRY_CAST('<root><r><![CDATA[' +
REPLACE(tokens, #separator, ']]></r><r><![CDATA[') +
']]></r></root>' AS XML))) AS t(c)
CROSS APPLY (VALUES (c.value('(/root/r[last()]/text())[1]', 'VARCHAR(256)'))) AS t2(token);
Output
+----+---------------------------------------------------------------------+----------+
| ID | tokens | Result |
+----+---------------------------------------------------------------------+----------+
| 1 | -qwetw MANN/1234556/DATE/030621/B/C/ACC/DIFF+AA11000532 | 11000532 |
| 2 | -qwert 123456789101213/-/BACK/300621/Rekening/Tutup+06+ZZZ21001123A | 21001123 |
| 3 | -qwerty 123456789/06/29/2021/ACC./DONE/CLOSED+06+AA11001234 | 11001234 |
+----+---------------------------------------------------------------------+----------+
Your example is tricky, as it is having alphabets also as part of the order number.
I am assuming your datatype is VARCHAR(4000) and accordingly, I have applied substring in the end with 4000, to make it simpler in the end.
DECLARE #table table(Description varchar(4000))
insert into #table values
('-qwetw MANN/1234556/DATE/030621/B/C/ACC/DIFF+AA11000532')
,('-qwert 123456789101213/-/BACK/300621/Rekening/Tutup+06+ZZZ21001123A')
,('-qwerty 123456789/06/29/2021/ACC./DONE/CLOSED+06+AA11001234');
SELECT SUBSTRING(REVERSE(SUBSTRING(REVERSE(Description),1,CHARINDEX('+',REVERSE(Description)))),PATINDEX('%[1-9]%',REVERSE(SUBSTRING(REVERSE(Description),1,CHARINDEX('+',REVERSE(Description))))),4000) as ordernumber FROM #table
ordernumber
11000532
21001123A
11001234
I have a column named 'path' which has some URLs and I need to extract the date that is coming after the word News
Example -
ex1-/News/2010/May/03/Ribbon-cut-on-new-HQ/
ex2-/India-Team-Cricket/News/2012/July/26/This-cricket/
There can be many dates in the URL. But the requirement is to extract the 1st occurrence of date which is coming after '/News/'
Output - a new column that has dates as below
2010/May/03
2012/July/26
Please try the following solution.
It is for SQL Server 2008 onwards.
SQL
-- DDL and data population, start
DECLARE #tbl Table (ID INT IDENTITY PRIMARY KEY, Tokens VARCHAR(MAX));
INSERT INTO #tbl (Tokens) VALUES
('ex1-/News/2010/May/03/Ribbon-cut-on-new-HQ/'),
('ex2-/India-Team-Cricket/News/2012/July/26/This-cricket/');
-- DDL and data population, end
DECLARE #separator CHAR(1) = '/';
SELECT ID, tokens, pos -- position of the News token/element
, c.value('(/root/r[sql:column("pos") + 1]/text())[1]','CHAR(4)') + #separator +
c.value('(/root/r[sql:column("pos") + 2]/text())[1]','VARCHAR(20)') + #separator +
c.value('(/root/r[sql:column("pos") + 3]/text())[1]','CHAR(2)') AS Result
FROM #tbl
CROSS APPLY (SELECT TRY_CAST('<root><r><![CDATA[' +
REPLACE(tokens, #separator, ']]></r><r><![CDATA[') +
']]></r></root>' AS XML)) AS t1(c)
CROSS APPLY (SELECT c.query('for $r in /root/r[./text()="News"]
let $pos := count(root/r[. << $r]) + 1
return $pos').value('text()[1]','INT')) AS t2(pos);
Output
+----+---------------------------------------------------------+--------------+
| ID | tokens | Result |
+----+---------------------------------------------------------+--------------+
| 1 | ex1-/News/2010/May/03/Ribbon-cut-on-new-HQ/ | 2010/May/03 |
| 2 | ex2-/India-Team-Cricket/News/2012/July/26/This-cricket/ | 2012/July/26 |
+----+---------------------------------------------------------+--------------+
https://regex101.com/r/kpViwY/1
The regex I used: News/(\d{4}/.+/\d{2})