Find all possible combinations column value in ORACLE SQL - sql

Question

Could you please help me to solve this Below Query:
I have below table of data.
EmpNo
Name
City
1
John
US
2
Miranda
US
3
Pete
US
4
Jack
US
5
Kathy
UK
6
Tanni
UK
7
Sally
UAE
I want output as like below:
City
Name1
Name2
US
John
Miranda
US
John
Pete
US
John
Jack
US
Miranda
Pete
US
Miranda
Jack
US
Pete
Jack
UK
Kathy
Tanni
PLSQL we can write block to get this output. But is it possible to get output using SQL code alone?

Answer 1

Looks like a self join.
SQL> with temp (empno, name, city) as
2 (select 1, 'John' , 'US' from dual union all
3 select 2, 'Miranda', 'US' from dual union all
4 select 3, 'Pete' , 'US' from dual union all
5 select 4, 'Jack' , 'US' from dual union all
6 select 5, 'Kathy' , 'UK' from dual union all
7 select 6, 'Tanni' , 'UK' from dual union all
8 select 7, 'Sally' , 'UAE' from dual
9 )
10 select a.city, a.name, b.name
11 from temp a join temp b on a.city = b.city and a.name < b.name
12 order by a.city, a.name;
CIT NAME NAME
--- ------- -------
UK Kathy Tanni
US Jack Miranda
US Jack John
US Jack Pete
US John Pete
US John Miranda
US Miranda Pete
7 rows selected.
SQL>

Answer 2

with
input_table (empno, name, city) as (
select 1, 'John' , 'US' from dual union all
select 2, 'Miranda', 'US' from dual union all
select 3, 'Pete' , 'US' from dual union all
select 4, 'Jack' , 'US' from dual union all
select 5, 'Kathy' , 'UK' from dual union all
select 6, 'Tanni' , 'UK' from dual union all
select 7, 'Sally' , 'UAE' from dual
)
-- end of sample data (for testing only, not part of the query)
-- remove WITH clause and use your actual table name below
select t1.city, t1.name as name1, t2.name as name2
from input_table t1 inner join input_table t2
on t1.city = t2.city and t1.empno < t2.empno
order by t1.empno, t2.empno -- if needed
;
CITY NAME1 NAME2
----- -------- --------
US John Miranda
US John Pete
US John Jack
US Miranda Pete
US Miranda Jack
US Pete Jack
UK Kathy Tanni