No calls to throwing functions occur within 'try' expression - error-handling

Question

` enum outofBound: Error
{
case NegativeNumber
case OutOfLimit
}
func sqareRoot(Number: Int) throws -> String
{
if Number < 10
{
throw outofBound.NegativeNumber
}
if Number > 100
{
throw outofBound.OutOfLimit
}
else
{
let number1 = Double (Number / 4)
print(number1)
let number2 = Double (number1 / 2)
print(number2)
return "number2"
}
}
do
{
let Result = try sqareRoot(Number: 3600)
}
catch outofBound.NegativeNumber
{
print("Please provide positive number")
}
catch outofBound.OutOfLimit
{
print("please provide less than 1000 number")
}
catch
{
print("unkonw errors occured")
}
print(squareRoot(Number: 2500))
print(squareRoot(Number: 3600))
print(squareRoot(Number: 4))
`
it gives this suggestion I am not getting it please help me.
{
No calls to throwing functions occur within 'try' expression
'catch' block is unreachable because no errors are thrown in 'do' block
}

Answer 1

try something like this:
func test() {
do {
let result = try sqareRoot(Number: 3600)
print("result: \(result)")
}
catch (let error) {
switch error {
case outofBound.NegativeNumber:
print("Please provide >= 10 number")
case outofBound.OutOfLimit:
print("please provide <= 100 number")
default:
print("error: \(error)")
}
}
// test print
print(try? sqareRoot(Number: 25))
}
func sqareRoot(Number: Int) throws -> String {
if Number < 10 {
throw outofBound.NegativeNumber
}
if Number > 100 {
throw outofBound.OutOfLimit
}
else {
let number1 = Double (Number / 4)
print("number1 \(number1)")
let number2 = Double (number1 / 2)
print("number2 \(number2)")
return String(number2)
}
}