when using picker the dropdown is not working for me - react-native

This is a simplification of the code but I have several pickers and they don't work correctly for me, I don't know what I'm doing wrong.
import { Picker } from '#react-native-picker/picker';
export default function ProfileScreen() {
const [ province, setProvince ] = useState("madrid")
return (
<>
<View style={styles.picker_and_inputs}>
<Picker
selectedValue={province}
onValueChange={(value, itemIndex) => setProvince({value})}
mode="dropdown"
>
<Picker.Item label="Madrid" value="madrid" />
<Picker.Item label="Barcelona" value="barcelona" />
<Picker.Item label="Cataluña" value="cataluña" />
</Picker>
</View>
</>
);
}

I consoled logged what onValueChange was returning
onValueChange={(value, itemIndex) => console.log(value)}
and got a string
madrid
Thus all you need to do is change from this
onValueChange={(value, itemIndex) => setProvince({value})}
to this.
onValueChange={(value, itemIndex) => setProvince(value)}
Everything works fine now just remove those brackets.Full Example here (https://snack.expo.dev/#heytony01/insane-pretzel)

Related

How can I make a picker in react native required

I have created a signup form in react native with formik and yup.According to the documentation I have added the react native picker.
<Formik
initialValues={{ password: '', first_name: '', email: '', passwordConfirmation: '' }}
onSubmit={values => handleSubmit(values)}
validationSchema={registerSchema}
>
{({ handleChange, handleBlur, handleSubmit, values, touched, errors }) => (
<View>
<TextInput
style={styles.textInputTop}
onChangeText={handleChange('first_name')}
onBlur={handleBlur('first_name')}
value={values.first_name}
label="First Name"
mode="outlined"
/>
<Text style={styles.errorMsg}>{touched.first_name && errors.first_name}</Text>
//Other Fields I have not mentioned in the code
<View style={styles.pickerContainer}>
<Text style={styles.depText}>Department</Text>
<Picker
style={{ height: 50, width: 150 }}
onValueChange={(itemValue, itemIndex) => setdepartment(itemValue)}
mode={"dropdown"}
>
<Picker.Item label="Management" value="Management" />
<Picker.Item label="HR" value="HR" />
<Picker.Item label="Accounting" value="Accounting" />
<Picker.Item label="Sales" value="Sales" />
</Picker>
</View>
<Button style={styles.btn} mode="contained" onPress={handleSubmit}>
<Text style={{ color: "white" }}>Sign Up</Text>
</Button>
</View>
)}
</Formik>
I need to add formik and yup to the picker to make it a required field. How do I do it?
If it is not possible with formik and yup, then how I can make the picker required.
on the registerSchema make:
department: Yup.string().required('this field is required')
department will hold the selected value from the picker, you may change the type from string to array depending on the selected value.

Formik handleChange - use hooks

before installing Formik, my input looked like so:
const [search, setSearch] = useState('');
....
<View style={styles.profileEditContainer__top}>
<TextInput
style={styles.profileEditContainer__form}
autoCapitalize="none"
placeholder="Enter what you want to create.."
placeholderTextColor={Colors.formPlaceHolderDefault}
name="search"
type="search"
value={search}
onChangeText={(e) => setSearch(e)}
autoCorrect={false}
defaultValue={search}
/>
<Button
disabled={!search}
title="Create"
onPress={(e) => {
createNewCar(e);
}}
/>
</View>
in onChangeText, I would set every character I typed to a state prop called search. With every key that I typed, an API called would be made to get some data from the db.
for example:
if I typed h into the input, the db would return 2 cars honda, hyundai
I read that Formik can simplify a lot of the form setup in React, so I downloaded it, however, the handleChange prop from Formik wants to keep track of values.search
<Formik
initialValues={{
search,
}}
onSubmit={(values) => {
console.log('values', values);
}}>
{({ handleChange, handleSubmit, values }) => (
<View style={styles.profileEditContainer__top}>
<TextInput
style={styles.profileEditContainer__form}
autoCapitalize="none"
placeholder="Enter what you want to create.."
placeholderTextColor={Colors.formPlaceHolderDefault}
autoCorrect={false}
value={values.search}
onChangeText={(e) => {
handleChange(values.search);
setSearch(e);
}}
/>
<Button
disabled={!search}
title="Create"
onPress={handleSubmit}
/>
</View>
)}
</Formik>
Now I can't type into the form because value is pointing at values.search instead of search like it did originally.
Question
How do I fire setSearch in onChangeText but also add search into the formik values prop?
you can make use of setFieldValue('search', e.target.value) instead of handleChange() change the code to the following:
<Formik
initialValues={{
search,
}}
onSubmit={(values) => {
console.log('values', values);
}}>
{({ handleChange, handleSubmit, values, setFieldValue }) => (
<View style={styles.profileEditContainer__top}>
<TextInput
style={styles.profileEditContainer__form}
autoCapitalize="none"
placeholder="Enter what you want to create.."
placeholderTextColor={Colors.formPlaceHolderDefault}
autoCorrect={false}
value={values.search}
onChangeText={(e) => {
//handleChange(values.search);
setFieldValue('search', e.target.value)
setSearch(e);
}}
/>
<Button
disabled={!search}
title="Create"
onPress={handleSubmit}
/>
</View>
)}
</Formik>

picker in android with dynamic data. but it giving me a error " cannot read property of null"

i am trying to render a picker with dynamic data from api. but it is giving error
<Picker style={styles.pickerStyleClass}
enabled={true} mode="dropdown"
selectedValue={(this.state.selectedWeight) || "Status"} prompt="Transaction Type"
onValueChange={(itemValue, itemIndex) => this.PickerDataSelection(itemIndex, itemValue)}
itemStyle={{ color: Colors.textColor }}>
{stockQty.map((data) => { <Picker.Item label={data} value={data} /> })}
</Picker>
let stockQty = ["Test1","Test2"];
The only thing missing here that causes this error is return so replace the Picker.Item line to
{stockQty.map((data) => { return <Picker.Item label={data} value={data} /> })}
as nothing was being returned from the function and Picker is made in a way that you can't return anything other than Picker.Item with the required props. Even the following line gives the same error.
{ this.state.someCheck && <Picker.Item label='some' value='value' /> }
and key should also be added as prop in Picker.Item.

"Undefined is not an object (evaluating 'child.props.value') " error with Picker component in react-native

I have come across this error when I used Picker component as follows,
<Picker
style={{ flex: 1 }}>
selectedValue={this.props.shift}
onValueChange={value => this.props.employeeFormAction({
prop:'shift', value })}
>
<Picker.Item label='Monday' value='Monday' />
<Picker.Item label='Tuesday' value='Tuesday' />
<Picker.Item label='Wednesday' value='Wednesday' />
<Picker.Item label='Thursday' value='Thursday' />
<Picker.Item label='Friday' value='Friday' />
<Picker.Item label='Saturday' value='Saturday' />
<Picker.Item label='Sunday' value='Sunday' />
</Picker>
I have tired this solution from same community
react-native - Picker - undefined is not an object (evaluating 'this.props.children[position].props)
But it didn't work for me. Could any body suggest solution for this issue.
Try to not hardcode the values. This way is cleaner:
// inside your component (supposing is not a functional component)
_renderShifts = () => {
const shifts = ['Monday', 'Tuesday', 'Wednesday','Thursday',
'Friday','Saturday', 'Sunday'];
return shifts.map((shift) => {
<Picker.Item key={"shift_"+i} label={shift} value={shift} />
});
}
// now your picker should render this way
_renderPicker = () => {
<Picker
style={{ flex: 1 }}>
selectedValue={this.props.shift}
onValueChange={value => this.props.employeeFormAction({prop:'shift', value })}
>
{this._renderShifts()}
</Picker>
}
This error is also returned when the Picker is imported without the corresponding object destructuring.
Incorrect
import Picker from '#react-native-community/picker'
Correct
import { Picker } from '#react-native-community/picker'

how to set inital value of React-Native Picker to empty

Do you know how to set the inital value of React-Native Picker component to empty. I mean it should not show any item selected.
I solved this problem by setting fake unselectable item with value={-1}. Then when user picks valid item,fake item with value={-1} disappear.
// this.state.selectedIndex initially setted to -1
<Picker
selectedValue={this.state.selectedIndex}
onValueChange={(value, index) => { this.setState({selectedIndex: index})
}}
>
// first fake item
if(Platform.OS === 'android' && this.state.selectedIndex === -1) {
<Picker.Item label={'CANCEL'} value={-1} />
}
<Picker.Item label={'First'} value={1} />
<Picker.Item label={'Second'} value={2} />
<Picker.Item label={'Third'} value={3} />
</Picker>
I think the part you need is enabled={false}.
https://github.com/react-native-picker/picker#enabled-1
<Picker
selectedValue={selected}
onValueChange={(itemValue, itemIndex) => setSelected(itemValue)}>
<Picker.Item key='' label='-- Select a Item --' value={null} enabled={false} />
{items.map(i => <Picker.Item key={i.key} label={i.label} value={i.value} />)}
</Picker>
you can do it this way
<Picker
selectedValue={selected}
onValueChange={itemValue => setSelected(itemValue)}
>
{items &&
items.map((element, index) => {
if (index === 0) {
return (
<Picker.Item
key={element.value}
label={element.label}
value={element.value}
enabled={false}
/>
);
}
return (
<Picker.Item
key={element.value}
label={element.label}
value={element.value}
/>
);
})}
</Picker>