I recently started working on sparql to generate query for getting the age of a specific person (say, Donald Trump)
The only thing I could understand is that it would be an instance of Person class.
Can someone help me with what else needs to be done to get that specific information.
SELECT ?item WHERE {
?item wdt:P31 wd:Q5.
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],en". }
}
Related
How do I get the instance type(s) (i.e., property=P31 and associated labels) for multiple Wikidata IDs in a single query? Ideally, I want to output a list with the columns: Wikidata ID | P31 ID | P31 Label, with multiple rows used if a Wikidata ID has more than one P31 attached.
I am using the web query service, which works well in part, but I am struggling to understand the syntax. I have so far managed to work out how to process a list of items, and return each one as a row (simple I know!), but I can't work out how to generate a new column that gives the P31 item:
SELECT ?item
WHERE {
VALUES ?item { wd:Q1347065 wd:Q731635 wd:Q105492052 }
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
I have found the following from a previusly answered question here, which returns multiple rows per an item of interest, but this requires specifying the P31 type at the outset, which is what I am looking to generate.
Any help would be appreciated as I am really stuck understanding the syntax.
Update:
I have now worked out how to return P31s for a single ID. I need to expand this query to receive a list of IDs, and include the ID as a column:
SELECT ?item ?itemLabel
WHERE
{
wd:Q18656 wdt:P31 ?item.
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE]". }
}
If I correctly understood your problem, you can use the following query:
SELECT ?item ?class ?classLabel
WHERE {
VALUES ?item { wd:Q1347065 wd:Q731635 wd:Q105492052 }
?item wdt:P31 ?class .
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
Here, first you fix the possible values for ?item, then you say that ?item is instance of a certain ?class and contestually you also retrieve the label for such ?class.
I have a list of wikidata items I wish to extract the "instance of" property from. For example, looking up Q1339 I can see that it has a single instance type (P:31) labelled "human" (Q5). I have tried to write a simple query that would extract that but I am not getting any records returned. I am v. new to SPARQL so it's very likely I'm missing something obvious.
SELECT ?item ?itemLabel
WHERE
{
?item wdt:P31 wd:Q1339.
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE]". }
}
Based on wikidata I want to make a list of all members of the European Parliament and I want some metadata about their membership like start date and the party they represent.
As a start I run the following query:
SELECT ?human ?humanLabel ?positionheldLabel
WHERE
{
# human position_held MembEuroParl
?human wdt:P39 wd:Q27169;
wdt:P39 ?positionheld.
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE]". }
}
This returns a list of people who once were member of european parliament and the positions they held. However also if those positions were not Member of parliament. See image.
So I change the query to the following adding a line that the positionheld sould be member of parliament:
SELECT ?human ?humanLabel ?positionheld
WHERE
{
# ?human position_held MEP
?human wdt:P39 wd:Q27169;
wdt:P39 ?positionheld.
?positionheld wdt:P31 wd:Q27169.
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE]". }
}
However, this last query does not return any results. Besides, it feels repetitive
My question how can I select only those rows where positionheld is member of parliament.
The answer is probably trivial, yet currently I am left clueless. Something I wanted to take 1 minutes is taking an hour.
This is probably pretty simple but I can't figure out how to do it. I have a query that selects all information about a rockband. I want to select just some of the attributes, for example the name of the band. Any help is appriciated.
And I also want the information to be in english only.
SELECT * WHERE {
wd:Q856941 ?p ?o.
#?o wdt:P571 ?inception.
#?o wdt:P154 ?logo
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],en". }
}
I have a set of DBpedia concepts and would like to get the corresponding wikidata IDs of them. For example, consider word2vec. The wikidata ID of word2vec is wd:Q22673982.
Currently, I am doing it as follows.
SELECT * {
VALUES ?searchTerm { "word2vec" "fasttext" "natural language processing" "deep learning" "support vector machine" }
SERVICE wikibase:mwapi {
bd:serviceParam wikibase:api "EntitySearch".
bd:serviceParam wikibase:endpoint "www.wikidata.org".
bd:serviceParam wikibase:limit 10 .
bd:serviceParam mwapi:search ?searchTerm.
bd:serviceParam mwapi:language "en".
?item wikibase:apiOutputItem mwapi:item.
?num wikibase:apiOrdinal true.
}
?item (wdt:P279|wdt:P31) ?type
}
ORDER BY ?searchTerm ?num
However, I noted that when I do it this way, most of my terms do not get a wikidata ID.
Therefore, I would like to know;
Are all DBpedia concepts associated with its relevent wikidata ID?
How to get the wikidata ID associated with DBpedia using sparql?
I am happy to provide more details if needed.
I used the following SPARQL query to solve my issue:
SELECT distinct ?wikidata_concept
WHERE {dbr:Word2vec owl:sameAs ?wikidata_concept}
LIMIT 100