"no matching unique or primary key for this column-list" Error in SQL - sql

Question

Was creating some tables in SQL and got stuck when I had to design the following tables:
As you can see it is impossible to create Room details and services details Table without customer receipt table as they contain Receipt_no as the primary key.
Similarly, it is impossible to create a Customer Receipt table without Room_charges and Service_charges attributes without first creating the two details tables.
Hence, I first created a customer receipt table but without FK constraints on Room_Charges and Service_charges and then I created Services Details and Room Details tables.
Later, using ALTER command I tried to add FK Constraints on Customer Receipt table but it gives me this error
ORA-02270: no matching unique or primary key for this column-list
Now, after researching a bit about it on StackOverflow, there might be three possible cases as mentioned in the approved answer (# Oracle (ORA-02270) : no matching unique or primary key for this column-list error )
I think my case is number 3 as I have ensured the first two cases to be implemented.
Can anyone help me resolve it?
I am attaching SQL Code as a reference:
CREATE TABLE Customer_Receipt
(
Receipt_no VARCHAR2(12) PRIMARY KEY,
Booking_no NUMBER NOT NULL,
Total_charges NUMBER(12,2),
CONSTRAINT bookingnocustrec
FOREIGN KEY(Booking_no) REFERENCES Room_booking (Booking_no)
);
CREATE TABLE Services_Details
(
Receipt_no VARCHAR2(12) NOT NULL,
Service_offered VARCHAR2(8) NOT NULL,
Service_charges NUMBER(12,2),
PRIMARY KEY(Receipt_no, Service_offered),
CONSTRAINT recno
FOREIGN KEY(Receipt_no) REFERENCES Customer_receipt (Receipt_no)
);
ALTER TABLE Services_Details
MODIFY Service_charges NOT NULL;
CREATE TABLE Room_Details
(
Receipt_no VARCHAR2(12) NOT NULL,
Category_name VARCHAR2(9) NOT NULL,
Days_stayed INT,
Room_charges NUMBER(12,2),
PRIMARY KEY(Receipt_no, Category_name),
CONSTRAINT recno1
FOREIGN KEY(Receipt_no) REFERENCES Customer_receipt (Receipt_no),
CONSTRAINT catname1
FOREIGN KEY(Category_name) REFERENCES Room_category (Category_name)
);
ALTER TABLE Customer_receipt
ADD Room_charges NUMBER(12,2) NOT NULL;
ALTER TABLE Customer_receipt
ADD CONSTRAINT FK_RC
FOREIGN KEY (Room_charges) REFERENCES Room_Details (Room_charges);

Answer 1

As a frame challenge.
Can anyone help me resolve it?
Yes, do not violate Third Normal Form and do not duplicate data by storing Total_Charges, Service_Charges or Room_Charges in the Customer_Receipt table when the data is already stored in the Service_Details and Room_Details tables.
If you are storing the same data in two locations then you are likely get into the situation where the data is inconsistent between those two location; just store each piece of data in a single location so there is a single source of truth in your database.
CREATE TABLE Customer_Receipt
(
Receipt_no VARCHAR2(12)
CONSTRAINT custreceipt__recno__pk PRIMARY KEY,
Booking_no CONSTRAINT custreceipt__bookingno__fk REFERENCES Room_booking
NOT NULL
);
CREATE TABLE Services_Details
(
Receipt_no CONSTRAINT servicedetails__recno__fk REFERENCES Customer_receipt
NOT NULL,
Service_offered VARCHAR2(8)
NOT NULL,
Service_charges NUMBER(12,2),
CONSTRAINT servicedetails__recno_servoff__pk PRIMARY KEY(Receipt_no, Service_offered)
);
CREATE TABLE Room_Details
(
Receipt_no CONSTRAINT roomdetails__recno__fk REFERENCES Customer_receipt
NOT NULL,
Category_name CONSTRAINT roomdetails__catname__fk REFERENCES Room_category
NOT NULL,
Days_stayed INT,
Room_charges NUMBER(12,2),
CONSTRAINT roomdetails__recno_catname__pk PRIMARY KEY(Receipt_no, Category_name)
);
If you want to display the Total_Charges, Service_Charges and Room_Charges then use a JOIN and get the data from the related tables. Something like:
SELECT cr.*,
COALESCE(s.service_charges, 0) AS service_charges,
COALESCE(r.room_charges, 0) AS room_charges,
COALESCE(s.service_charges, 0) + COALESCE(r.room_charges, 0)
AS total_charges
FROM customer_receipt cr
LEFT OUTER JOIN (
SELECT receipt_no,
SUM(service_charges) AS service_charges
FROM services_details
GROUP BY receipt_no
) s
ON cr.receipt_no = s.receipt_no
LEFT OUTER JOIN (
SELECT receipt_no,
SUM(days_stayed * room_charges) AS room_charges
FROM room_details
GROUP BY receipt_no
) r
ON cr.receipt_no = r.receipt_no;
Or create a view (or a materialized view).