How are you? I guess there is no way to visually represent in the Netlogo Interface a system with a "many-to-many" relationship, where turtles belong to more than one patch, and of course patches host more than one turtle. Correct?
I have a model where Banks (my turtles) operate on more than one Country (my patches). So I think my only option is to have two breeds of turtles, i.e. Banks and Countries, and connect Banks to Countries with link agents. Correct?
(I will also need interbank links, so I will need to set up a different breed of links. Correct?)
Now: I need to identify countries by name (i.e. Italy, France, Spain, etc.). I am reading a CSV file with country names and feeding it into a Netlogo list, but I am not sure how to have a country agent "be" a name. I created a country breed-specific variable called "country-name", and I am trying to use "item" to sequentially access each next name in the list of country names and assign it to the country-name variable of the next country agent in the Countries breed. However, I cannot relate "item" to "who" here, because "who" is not breed-specific. So I am thinking of setting up a separate breed-specific numbered index, but something like this has been asked in a previous question (trying to create a sequential ID variable for breeds in netlogo) and it was strongly suggested NOT to do so. Any suggestions on how to proceed?
I agree with the comment by Matteo. That said,
You don't ever need to use "who". Identify your banks and your countries with a "name" field that the breed owns. For example
banks-own [ name ]
counties-own [ name ]
;; then somewhere in your loop as you read them in...
create-banks 1 [ set name "Chase" ... ]
create-countries 1 [ set name "England" ...]
Below I use 'one-of' but there will only be one hit.
This makes the syntax work converting a list item to a specific turtle.
You never should need to know or care about the "who" value of a bank
or country.
to make-branches
;; read this list in from a csv file, etc. or hard code it
set branchlist [[ "Lloyds" "England"] ["Lloyds" "France"] [ "Chase" "USA"]["Chase" "France" ]]
;; then work the list. Again, you never need "who".
foreach branchlist [
z -> ask one-of banks with [name = item 0 z ]
[ create-link-with one-of countries with [ name = item 1 z ]]
]
end
Related
Imagine I have a report, a letter actually, which I need to translate to several languages. I have created a greeting field in the form which is filled programatically by an onchange event method.
if self.partner_id.gender == 'female':
self.letter_greeting = _('Dear %s %s,') % ( # the translation should be "Estimada"
self.repr_recipient_id.title.shorcut, surname
)
elif self.partner_id.gender == 'male':
self.letter_greeting = _('Dear %s %s,') % ( # translation "Estimado"
self.repr_recipient_id.title.shorcut, surname
)
else:
self.letter_greeting = _('Dear %s %s,') % ( # translation: "Estimado/a"
self.partner_id.title.shorcut, surname
)
In that case the word Dear should be translated to different Spanish translations depending on which option is used, this is because we use different termination depending on the gender. Exporting the po file I found that all the options are altogether, that make sense because almost all the cases the translations will be the same, but not in this case:
#. module: custom_module
#: code:addons/custom_module/models/sale_order.py:334
#: code:addons/custom_module/models/sale_order.py:338
#: code:addons/custom_module/models/sale_order.py:342
#, python-format
msgid "Dear %s %s,"
msgstr "Dear %s %s,"
Solutions I can apply directly
Put all the terms in different entries to avoid the same translation manually every time I need to update the po file. This can be cumbersome if you have many different words with that problem. If I do it and I open the file with poedit, this error appears: duplicate message definition
Put all the possible combinations with slashes, this is done y some other parts of Odoo. For both gender would be:
#. module: stock
#: model:res.company,msg:stock.res_company
msgid "Dear"
msgstr "Estimado/a"
This is just an example. I can think of many words that look the same in English, but they use different spelling or meanings in other languages depending on the context.
Possible best solutions
I don't know if Odoo know anything aboutu the context of a word to know if it was already translated or not. Adding a context manually could solve the problem, at least for words with different meanings.
The nicest solution would be to have a parameter to the translation module to make sure that the word is exported as an isolated entry for that especific translation.
Do you think that I am giving to it too much importance haha? Do you know if there is any better solution? Why is poedit not taking into account that problem at all?
I propose an extension of models res.partner.title and res.partner.
res.partner.title should get a translateable field for saving salutation prefixes like 'Dear' or 'Sehr geehrter' (German). Maybe it's worth to get something about genders, too, but i won't get into detail here about that.
You probably want to show the configuring user an example like "Dear Mr. Name" or something like that. A computed field should work.
On res.partner you should just implement either a computed field or just a method to get a full salutation for a partner record.
To some degree this is a linguistics problem. I believe the best solution would be to use a different "Source Language", one made up of keys, and then have English as another Translation. The word "Dear" in English does not have a gender context (and typically, much of English doesn't), while the word "Estimado" in Spanish does. The translation from that Spanish word to English is more appropriately "Masculine Dear." Therefore, using keys as your source language, you would have this:
SourceText (EnglishDescription) -> Translation (English) -> Translation (Spanish)
DearMasculine -> Dear -> Estimado
DearFeminine -> Dear -> Estimada
DearNuetral -> Dear -> Estimado/a
i am trying to model the following hierarchical structur in Netlogo:
Imagine a typical company or a a brach of public administration. There is one boss (turtle) on top and a number of employees (turtles) below him/her. There are two variables: span-of-control soc (how many employees can one Boss overwatch) and depth-of-control doc (how many hierarchical levels do exist in the structure). The total number of employees equals soc^doc. The total number of turtles equals 1+soc^doc (1 is the boss).
There are two Choosers in the Netlogo-Interface: soc and doc (ranging from 1 to 4).
What I imagine to code: Depending on the Variables chosen, the structure should arrange itself automatically by the following rule: Create as many links to employees as there have been employees on the higher hierarchical level until the doc is reached.
Example: doc:3 soc:3 1 Boss (always 1 so it can be used like an anchor)
1. Level: 3 links (1*3)
2. Level: 9 Links (3*3)
3. Level: 27 Links (9*3)
4. Level: Over as doc is reached
To realise this, I need to make the turtles kind of read the doc and soc variables and make them create links accordingly but I dont know how.
Here is my code so far:
globals [
information
]
undirected-link-breed [ Informationflows Informationflow ]
breed [ Employees Employee ]
breed [ tasks task ]
breed [ Bosses Boss ]
;#########SETUP########
to setup
clear-all
create-Bosses 1 [ set color red
set size 2 ]
set-default-shape Bosses "person"
ask Bosses [ setxy 0 15 ]
ask patches [ set pcolor white ]
set-default-shape Employees "person"
create-Employees ( span-of-control ^ depth-of-control) [set color blue
set size 2 ] ; absolute Number of Employees
;ask Boss 0 [ create-Informationflow-with random Employee 8] ; IDEA
;ask Employees [ create-Informationflow-with one-of other Employees] ; IDEA
;ask Employees [ create-Informationflow-with Boss 0 ] ; IDEA
repeat 100 [ layout ]
ask Employees [
setxy 0.95 * xcor 0.95 * ycor ]
end
to-report value-of-span-of-control? ; Just an idea
report span-of-control
end
;##########LAYOUT##########
to layout
; layout-radial Employees Informationflows (Boss 0) ;Problem: Boss is fixed in the Center
layout-spring Employees Informationflows 0 10 2
end
If anybody could hint me in the right direction, I would be very thankful.
Kind regards,
Jon
Okay, general coding advice first - do ONE thing, test it and fix it before moving on to the next thing.
Your question about how to 'read' the doc and soc variables makes me think you are very new to NetLogo. If so, please go and do the tutorials that are at the NetLogo site. Creating a chooser with the name 'XYZ' creates a global variable named 'XYZ', there is no additional step to read it. Since you are choosing numbers, you might want to use a slider instead of a chooser.
Try replacing your commented out ask Boss line with this:
ask one-of Boss [ create-Informationflow-with n-of soc Employees ]
It's generally bad practice to use who numbers because turtles can die or be generated in a different order because you change some code and then the who numbers are different. So I used one-of to randomly select any boss (of which there is only one anyway). I similarly used n-of to select Employees to create links with and specified the number n in the n-of to be the value from the soc variable.
I'm trying to train my Wit.ai bot in order to recognize the first name of someone. I'm not very sure if I well understand how the NLP works so I'll give you an example.
I defined a lot of expressions like "My name is XXXX", "Everybody calls me XXXX"
In the "Understanding" table I added an entity named "contact_name" and I add almost 50 keywords like "Michel, John, Mary...".
I put the trait as "free-text" and "keywords".
I'm not sure if this process is correctly. So, I ask you:
does it matter the context like "My name is..." for the NLP? I mean...will it help the bot to predict that after this expression probably a fist name will come on?
is that right to add like 50 values to an entity or it's completly wrong?
what do you suggest as a training process in order to get the first name of someone?
You have done it right by keeping the entity's search strategy as "free-text" and "Keywords". But Adding keywords examples to the entity doesn't make any sense because a person's name is not a keyword.
So, I would recommend a training strategy which is as follows:
Create various templates of the message like, "My name is XYZ", "I am XYZ", "This is XYZ" etc. (all possible introduction messages you could think of)
Remove all keywords and expressions for the entity you created and add these two keywords:
"a b c d e f g h i j k l m n o p q r s t u v w x y z"
"XYZ" (can give any name but maintain this name same for validating the templates)
In the 'Understanding' tab enter the messages and extract the name into the entity ("contact_name" in your case) and validate them
Similarly, validate all message templates keeping the name as "XYZ"
After you have done this for all templates your bot will be able to recognise any name in a given template of the message
The logic behind this is your entity is a free-text and keyword which means it first tries to match the keyword if not matched it tries to find the word in the same position of the templates. Keeping the name same for validations helps to train the bot with the templates and learn the position where the name will be usually found.
Hope this works. I have tried this and worked for me. I am not sure how bot trains in background. I recommend you to start a new app and do this exercise.
Comment if there is any problem.
wit.ai has a pre-trained entity extraction method called wit/contact, which
Captures free text that's either the name or a clear reference to a
person, like "Paul", "Paul Smith", "my husband", "the dentist".
It works good even without any training data.
To read about the method refer to duckling.
I still feel like a SPARQL newbie, so I may be way off base about what SPARQL GROUP BY does, but here's my questions.
Suppose I wanted to request all resources in graph database called Categories, and I wanted to get all the items associated with these categories, along with the names of the items and their price.
Right now my SPARQL queries are giving me back something like the following table:
**Categories Item ItemName ItemPrice**
Tools HammerID Hammer $12
Tools SawID Saw $13
Tools WrenchID Wrench $10
Food AppleID Apple $5
Food CornID Corn $1
I wanted to use GROUP BY to group the items under a single category, so that when I start processing it, I can look through each unique category and then display the items that belong in that category.
Right now if I loop through the above results, I will be iterating over 5 entries instead of 2.
The other way I can describe the results I want are by imaging what the corresponding json data would look like. I want something like:
[
tools: [
{id: hammerId
title: hammer
price: $12},
{id: sawId
title: saw
price: $13},
{id: wrenchId
title: wrench
price: $10}
],
food: [
{id: appleId
title: apple
price: $5},
{id: cornId
title: corn
price: $1}
]
]
With the results, like this I can directly loop over the top level items, and then display the results for each.
Can I use GROUP BY to tell SPARQL to give me results like this?
No, you can't. A SPARQL SELECT query-result is defined as a sequence of solutions, with each solution being a set of variable-value pairs (with a value being defined as an IRI, BNode, or literal value). Basically it's a simple table. There is no provision for 'nested' solutions like you'd need for your JSON-like structure.
However the difference is purely syntactic. If you group, you know the result will deliver all solutions belonging to the same group together (one after the other) - so in processing the result you can simply treat the grouped variable as a marker. And of course if you really want, you can easily rewrite the query result into this kind of syntactic structure yourself - it's just a different way of writing down the exact same information, after all.
I have a relation called conversations_grouped made up of bags of tuples of varying sizes, like so:
DUMP conversations_grouped:
...
({(L194),(L195),(L196),(L197)})
({(L198),(L199)})
({(L200),(L201),(L202),(L203)})
({(L204),(L205),(L206)})
({(L207),(L208)})
({(L271),(L272),(L273),(L274),(L275)})
({(L276),(L277)})
({(L280),(L281)})
({(L363),(L364)})
({(L365),(L366)})
({(L666256),(L666257)})
({(L666369),(L666370),(L666371),(L666372)})
({(L666520),(L666521),(L666522)})
Each L[0-9]+ is a tag corresponding to a string. For example, L194 might be "Hello, how are you doing?" and L195 might be "fine, how are you?". This correspondence is maintained by a map called line_map. Here's a sample:
DUMP line_map;
...
([L666324#Do you think she might be interested in someone?])
([L666264#Well that's typical of Her Majesty's army. Appoint an engineer to do a soldier's work.])
([L666263#Um. There are rumours that my Lord Chelmsford intends to make Durnford Second in Command.])
([L666262#Lighting COGHILL' 5 cigar: Our good Colonel Dumford scored quite a coup with the Sikali Horse.])
([L666522#So far only their scouts. But we have had reports of a small Impi farther north, over there. ])
([L666521#And I assure you, you do not In fact I'd be obliged for your best advice. What have your scouts seen?])
([L666520#Well I assure you, Sir, I have no desire to create difficulties. 45])
([L666372#I think Chelmsford wants a good man on the border Why he fears a flanking attack and requires a steady Commander in reserve.])
([L666371#Lord Chelmsford seems to want me to stay back with my Basutos.])
([L666370#I'm to take the Sikali with the main column to the river])
([L666369#Your orders, Mr Vereker?])
([L666257#Good ones, yes, Mr Vereker. Gentlemen who can ride and shoot])
([L666256#Colonel Durnford... William Vereker. I hear you 've been seeking Officers?])
What I'm trying to do now is parse through each line and replace the L[0-9]+ tags with their corresponding text from line_map. Is it possible to make references to line_map from within a Pig FOREACH statement, or is there something else I have to do?
The first issue with this is that in a map the key must be a quoted string. So you can't use a schema value to access the map. E.G. This will not work.
C: {foo: chararray, M: [value:chararray]}
D = FOREACH C GENERATE M#foo ;
The solution that comes to mind is to FLATTEN conversations_grouped. Then do a join between conversations_grouped and line_map on the L[0-9]+ tag. You'll probably want to project out some of the extra fields (like the L[0-9]+ tag after the join) to make the next step faster. After that you'll have to regroup the data, and massage it into the correct format.
This won't work unless each bag has it's own unique ID for the regrouping, but if each of the L[0-9]+ tags appear in only one bag (conversation) you can use this to create a unique id.
-- A is dumped conversations_grouped
B = FOREACH A {
-- Pulls out an element from the bag to use as the id
id = LIMIT tags 1 ;
-- Flattens B into id, tag form. Each group of tags will have the same id.
GENERATE FLATTEN(id), FLATTEN(tags) ;
}
The schema and output for B is:
B: {id: chararray,tags::tag: chararray}
(L194,L194)
(L194,L195)
(L194,L196)
(L194,L197)
(L198,L198)
(L198,L199)
(L200,L200)
(L200,L201)
(L200,L202)
(L200,L203)
(L204,L204)
(L204,L205)
(L204,L206)
(L207,L207)
(L207,L208)
(L271,L271)
(L271,L272)
(L271,L273)
(L271,L274)
(L271,L275)
(L276,L276)
(L276,L277)
(L280,L280)
(L280,L281)
(L363,L363)
(L363,L364)
(L365,L365)
(L365,L366)
(L666256,L666256)
(L666256,L666257)
(L666369,L666369)
(L666369,L666370)
(L666369,L666371)
(L666369,L666372)
(L666520,L666520)
(L666520,L666521)
(L666520,L666522)
Assuming that the tags are unique, the rest is done like:
-- A2 is line_map, loaded in tag/message pairs instead of a map
-- Joins conversations_grouped and line_map on tag
C = FOREACH (JOIN B by tags::tag, A2 by tag)
-- This generate removes the tag
GENERATE id, message ;
-- Regroups C on the id created in B
D = FOREACH (GROUP C BY id)
-- This step limits the output to just messages
GENERATE C.(message) AS messages ;
Schema and output from D:
D: {messages: {(A2::message: chararray)}}
({(Colonel Durnford... William Vereker. I hear you 've been seeking Officers?),(Good ones, yes, Mr Vereker. Gentlemen who can ride and shoot)})
({(Your orders, Mr Vereker?),(I'm to take the Sikali with the main column to the river),(Lord Chelmsford seems to want me to stay back with my Basutos.),(I think Chelmsford wants a good man on the border Why he fears a flanking attack and requires a steady Commander in reserve.)})
({(Well I assure you, Sir, I have no desire to create difficulties. 45),(And I assure you, you do not In fact I'd be obliged for your best advice. What have your scouts seen?),(So far only their scouts. But we have had reports of a small Impi farther north, over there. )})
NOTE: If at worst, (the L[0-9]+ tags aren't unique) you can give each line of the input file(s) a sequential, integer id before you load it into pig.
UPDATE: If you are using pig 0.11, then you can also use the RANK operator.