KeyError:'1,2' running Postgresql regexp_match() in Jupyter Notebook - sql

Question

I am using Jupyter notebook to run postgresql. Python, postgres, pips and Jupyter are all up to date. I have been able to load sql with
%load_ext sql
and connected to the postgres database with
%sqlpostgresql://postgres:postgres#localhost/analysis
Table was created and loaded a csv loaded successfully with
%%sql
CREATE TABLE crime_reports (
crime_id bigserial PRIMARY KEY,
date_1 timestamp with time zone,
date_2 timestamp with time zone,
street varchar(250),
city varchar(100),
crime_type varchar(100),
description text,
case_number varchar(50),
original_text text NOT NULL
);
COPY crime_reports (original_text)
FROM 'C:\YourDirectory\crime_reports.csv'
WITH (FORMAT CSV, HEADER OFF, QUOTE '"');
However, this code
%%sql
SELECT crime_id,
regexp_match(original_text, '\d{1,2}\/\d{1,2}\/\d{2}')
FROM crime_reports;
runs successfully in pgAdmin, returning dates but in the Jupyter notebook I get this error instead:
KeyError Traceback (most recent call last)
~\AppData\Local\Temp/ipykernel_10976/608277809.py in <module>
----> 1 get_ipython().run_cell_magic('sql', '', "SELECT crime_id,\n regexp_match(original_text, '\\d{1,2}\\/\\d{1,2}\\/\\d{2}')\nFROM crime_reports;\n")
~\AppData\Local\Programs\Python\Python310\lib\site-packages\IPython\core\interactiveshell.py in run_cell_magic(self, magic_name, line, cell)
2417 with self.builtin_trap:
2418 args = (magic_arg_s, cell)
-> 2419 result = fn(*args, **kwargs)
2420 return result
2421
~\AppData\Local\Programs\Python\Python310\lib\site-packages\decorator.py in fun(*args, **kw)
230 if not kwsyntax:
231 args, kw = fix(args, kw, sig)
--> 232 return caller(func, *(extras + args), **kw)
233 fun.__name__ = func.__name__
234 fun.__doc__ = func.__doc__
~\AppData\Local\Programs\Python\Python310\lib\site-packages\IPython\core\magic.py in <lambda>(f, *a, **k)
185 # but it's overkill for just that one bit of state.
186 def magic_deco(arg):
--> 187 call = lambda f, *a, **k: f(*a, **k)
188
189 if callable(arg):
~\AppData\Local\Programs\Python\Python310\lib\site-packages\decorator.py in fun(*args, **kw)
230 if not kwsyntax:
231 args, kw = fix(args, kw, sig)
--> 232 return caller(func, *(extras + args), **kw)
233 fun.__name__ = func.__name__
234 fun.__doc__ = func.__doc__
~\AppData\Local\Programs\Python\Python310\lib\site-packages\IPython\core\magic.py in <lambda>(f, *a, **k)
185 # but it's overkill for just that one bit of state.
186 def magic_deco(arg):
--> 187 call = lambda f, *a, **k: f(*a, **k)
188
189 if callable(arg):
~\AppData\Local\Programs\Python\Python310\lib\site-packages\sql\magic.py in execute(self, line, cell, local_ns)
149 cell_params = {}
150 for variable in cell_variables:
--> 151 cell_params[variable] = local_ns[variable]
152 cell = cell.format(**cell_params)
153
KeyError: '1,2'
I have tried trusting the Notebook and still getting same error.

Answer 1

Try to replace this:
regexp_match(original_text, '\d{1,2}\/\d{1,2}\/\d{2}')
with this:
regexp_match(original_text, '\d{{1,2}}\/\d{{1,2}}\/\d{{2}}')
Probably it's python formatting and you need to escape your {}s.