Showing only none in output instead of changing numeric value to capitilized alphabets - python-3.8

Question

def convert_digits(input_string, start_position, end_position):
# The ending index was required as it was not returning the whole sentence
new_string = input_string[:end_position]
newstring = " "
# return new_string
digit_mapping = {
'0': 'ZERO',
'1': 'ONE',
'2': 'TWO',
'3': 'THREE',
'4': 'FOUR',
'5': 'FIVE',
'6': 'SIX',
'7': 'SEVEN',
'8': 'EIGHT',
'9': 'NINE'
}
if start_position >= 1:
if end_position <= len(new_string):
if start_position < end_position:
for index in range(start_position - 1, end_position):
if input_string[index].isdigit():
mapped = digit_mapping[input_string[index]]
newstring += " " + mapped + " "
else:
newstring += input_string[index]
else:
return "INVALID"
else:
return "INVALID"
else:
return "INVALID"
return newstring
if name == 'main':
print(convert_digits("you are a 4king 5shole", 1, 21))

Answer 1

Use this code.
Your problem was in line 39, you add 2 tabs place 1.
def convert_digits(input_string, start_position, end_position):
# The ending index was required as it was not returning the whole sentence
new_string = input_string[:end_position]
newstring = " "
# return new_string
digit_mapping = {
'0': 'ZERO',
'1': 'ONE',
'2': 'TWO',
'3': 'THREE',
'4': 'FOUR',
'5': 'FIVE',
'6': 'SIX',
'7': 'SEVEN',
'8': 'EIGHT',
'9': 'NINE'
}
if start_position >= 1:
if end_position <= len(new_string):
if start_position < end_position:
for index in range(start_position - 1, end_position):
if input_string[index].isdigit():
mapped = digit_mapping[input_string[index]]
newstring += " " + mapped + " "
else:
newstring += input_string[index]
else:
return "INVALID"
else:
return "INVALID"
else:
return "INVALID"
return newstring
if __name__ == '__main__':
print(convert_digits("you are a 4king 5shole", 1, 21))