Imagine this data.
Id
Type
1
A
1
B
1
B
2
A
3
B
I want to select table and ad two columns turning it to this. How can i do it? (In teradata)
Id
Type
Id with both A+B
Id with only A
1
A
1
0
1
B
1
0
1
B
1
0
2
A
0
1
3
B
0
0
I'm not familiar with teradata but in standard SQL next query should be working:
SELECT
T.*,
CASE WHEN Cnt = 2 THEN 1 ELSE 0 END AS BOTH_TYPES_PRESENT,
CASE WHEN Cnt = 1 AND Type = 'A' THEN 1 ELSE 0 END AS ONLY_A_PRESENT
FROM T
LEFT JOIN (
SELECT Id, COUNT(DISTINCT Type) Cnt FROM T WHERE Type IN ('A', 'B') GROUP BY Id
) CNT ON T.Id = CNT.Id;
SQL online editor
I have a table as shown below:
group item rank
1 A 1
1 B 2
1 C 3
2 A 2
2 B 1
3 A 1
3 C 2
I want those groups data only, where item A has rank 1 as shown below:
group item rank
1 A 1
1 B 2
1 C 3
3 A 1
3 C 2
In group 2, A has rank 2, therefore not a part of output.
One way is using an IN clause
select *
from yourTable
where id in (select id from yourtable where item='A' and rank = 1)
you could use a subquery for get the involved id and the join
select * from my_table m
inner join (
select distinct id
from my_table
where item = 'A'
and rank = 1
) t on t.id = m.id
Here's the example:
ID | value
1 51
2 25
3 11
4 27
5 21
I need to get first three parameters and place them into variables e.g. out_x, out_y, out_z.
Is it possible to do it without multiple selects?
You can do something like this:
select max(case when id = 1 then value end),
max(case when id = 2 then value end),
max(case when id = 3 then value end)
into out_x, out_y, out_z
from t
where id in (1, 2, 3);
However, I think three queries of the form:
select value into out_x
from t
where id = 1;
is a cleaner approach.
You can use a PIVOT:
SELECT x, y, z
INTO out_x, out_y, out_z
FROM your_table
PIVOT ( MAX( value ) FOR id IN ( 1 AS x, 2 AS y, 3 AS z ) )
Or, if you do not know which IDs you need (but just want the first 3) then:
SELECT x, y, z
INTO out_x, out_y, out_z
FROM (
SELECT value, ROWNUM AS rn
FROM ( SELECT value FROM your_table ORDER BY id )
WHERE ROWNUM <= 3
)
PIVOT ( MAX( value ) FOR rn IN ( 1 AS x, 2 AS y, 3 AS z ) )
I realise this maybe similar to other questions, but I am stuck!
I am having trouble organising some data into an appropriate format to export to another tool. Basically I have an ID column and then 2 response columns. I would like to separate the ID and then list the responses under each. See the example below for clarification.
I have played around with Pivot and UnPivot but can't get it quite right.
Here is how the data looks now.
ID X1 X2
1 2 Y
1 5 Y
1 3 N
1 7 N
1 6 Y
2 5 N
2 4 Y
2 8 Y
2 3 N
3 5 Y
3 1 N
3 9 N
Here is how I would like the data to look
ID1_X1 ID1_X2 ID2_X1 ID2_X2 ID3_X1 ID3_X2
2 Y 5 N 5 Y
5 Y 4 Y 1 N
3 N 8 Y 9 N
7 N 3 N null null
6 Y null null null null
Here is the code to create/populate the table.
create table #test (ID int, X1 int, X2 varchar(1))
insert into #test values
('1','2','Y'),('1','5','Y'),('1','3','N'),('1','7','N'),
('1','6','Y'),('2','5','N'),('2','4','Y'),('2','8','Y'),
('2','3','N'),('3','5','Y'),('3','1','N'),('3','9','N')
You can do this using aggregation and row_number() . . . assuming you know the ids in advance:
select max(case when id = 1 then x1 end) as x1_1,
max(case when id = 1 then x2 end) as x2_1,
max(case when id = 2 then x1 end) as x1_2,
max(case when id = 2 then x2 end) as x2_2,
max(case when id = 3 then x1 end) as x1_3,
max(case when id = 3 then x2 end) as x2_3
from (select t.*,
row_number() over (partition by id order by (select null)) a seqnum
from #test t
) t
group by seqnum;
I should note that SQL tables represent unordered sets. Your original data doesn't have an indication of the ordering, so this is not guaranteed to put the values in the same order as the original data (actually, there is no such order that that statement is a tautology). If you have another column with the ordering, then you can use that.
Here is a alternative approach to Gordan's good answer using OUTER JOIN's
Considering that there is a Identity column in your table to define the order of X1 in each ID and fixed number of ID's
;WITH FST
AS (SELECT ROW_NUMBER()OVER(ORDER BY IDENTITY_COL) RN,X1 AS ID1_X1,X2 AS ID1_X2
FROM #TEST A
WHERE ID = 1),
SCD
AS (SELECT ROW_NUMBER()OVER(ORDER BY IDENTITY_COL) RN,X1 AS ID2_X1,X2 AS ID2_X2
FROM #TEST A
WHERE ID = 2),
TRD
AS (SELECT ROW_NUMBER()OVER(ORDER BY IDENTITY_COL) RN,X1 AS ID3_X1,X2 AS ID3_X2
FROM #TEST A
WHERE ID = 3)
SELECT ID1_X1,ID1_X2,ID2_X1,ID2_X2,ID3_X1,ID3_X2
FROM FST A
FULL OUTER JOIN SCD B
ON A.RN = B.RN
FULL OUTER JOIN TRD C
ON C.RN = COALESCE(B.RN, A.RN)
Have the following Data in the table
Example Table
ID Value
1 a
1 b
1 c
2 a
2 b
2 c
3 a
3 b
I need to retrieve records having ID with only two values a and b.
So i am expecting only the Record with ID 3 .
Can anyone help me with the query
I guess you could do something like
select
ID,
sum(case when value = 'a' then 1
when value = 'b' then 1
else 3 end)
from
table1
group by id
having
sum (case when value = 'a' then 1
when value = 'b' then 1
else 3 end) =2
SQL Fiddle
That will work:
select x.id from
(
select id from mytable where value = 'a'
union all
select id from mytable where value = 'b'
) x
group by x.id
having COUNT(*) = 2
and not exists (select * from mytable t where t.id = x.id and value <> 'a' and value <> 'b')