I have 2 tables.
1st of them consists of working days for each month (year = 2020):
Month
Date from
Date to
January
01/01/2020
31/01/2020
February
01/02/2020
29/02/2020
March
01/03/2020
31/03/2020
2nd of them has a dates with public holidays for 2020 with the following format:
Date
Week day
Code
Working hours
01/01/2020
Wednesday
Holiday
0
08/03/2020
Sunday
Holiday
0
01/09/2020
Tuesday
Holiday
0
24/12/2020
Thursday
Holiday
0
I would like to create 1 table (with the format of 2nd table) which has data only working days excluding public holidays from 2nd table and weekends from calendar for 2020.
Thank you in advance for your help.
Regards,
You can create the table using:
CREATE TABLE working_days (
day DATE PRIMARY KEY,
week_day VARCHAR2(9)
GENERATED ALWAYS AS (CAST(RTRIM(TO_CHAR(day, 'FMDay')) AS VARCHAR2(9))),
code VARCHAR2(20),
working_hours NUMBER(4,2)
);
Then insert data using:
INSERT INTO working_days (day, code, working_hours)
WITH days (dt, date_to) AS (
SELECT TRUNC(date_from),
date_to
FROM working_day_ranges
UNION ALL
SELECT dt + INTERVAL '1' DAY,
date_to
FROM days
WHERE dt + INTERVAL '1' DAY <= date_to
)
SELECT dt, 'Working Day', 23
FROM days d
WHERE NOT EXISTS ( -- Not a holiday
SELECT 1
FROM holidays h
WHERE d.dt = h.dt
)
AND dt - TRUNC(dt, 'IW') < 5 -- Not a Saturday or Sunday;
ORDER BY dt;
(Alter the expected working hours, etc. as suits you.)
Which, assuming your tables:
CREATE TABLE working_day_ranges (Date_from, Date_to) AS
SELECT DATE '2020-01-01', DATE '2020-01-31' FROM DUAL UNION ALL
SELECT DATE '2020-02-01', DATE '2020-02-29' FROM DUAL UNION ALL
SELECT DATE '2020-03-01', DATE '2020-03-31' FROM DUAL;
ALTER TABLE working_day_ranges
ADD month VARCHAR2(8)
GENERATED ALWAYS AS (CAST(RTRIM(TO_CHAR(date_from, 'FMMonth')) AS VARCHAR2(8)));
CREATE TABLE holidays (dt, Code, Working_hours) AS
SELECT DATE '2020-01-01', 'Holiday', 0 FROM DUAL UNION ALL
SELECT DATE '2020-03-08', 'Holiday', 0 FROM DUAL UNION ALL
SELECT DATE '2020-09-01', 'Holiday', 0 FROM DUAL UNION ALL
SELECT DATE '2020-12-24', 'Holiday', 0 FROM DUAL;
ALTER TABLE holidays
ADD week_day VARCHAR2(9)
GENERATED ALWAYS AS (CAST(RTRIM(TO_CHAR(dt, 'FMDay')) AS VARCHAR2(9)));
Then:
SELECT * FROM working_days;
Outputs:
DAY
WEEK_DAY
CODE
WORKING_HOURS
02-JAN-20
Thursday
Working Day
23
03-JAN-20
Friday
Working Day
23
06-JAN-20
Monday
Working Day
23
07-JAN-20
Tuesday
Working Day
23
08-JAN-20
Wednesday
Working Day
23
09-JAN-20
Thursday
Working Day
23
10-JAN-20
Friday
Working Day
23
13-JAN-20
Monday
Working Day
23
14-JAN-20
Tuesday
Working Day
23
15-JAN-20
Wednesday
Working Day
23
16-JAN-20
Thursday
Working Day
23
17-JAN-20
Friday
Working Day
23
20-JAN-20
Monday
Working Day
23
21-JAN-20
Tuesday
Working Day
23
22-JAN-20
Wednesday
Working Day
23
23-JAN-20
Thursday
Working Day
23
24-JAN-20
Friday
Working Day
23
27-JAN-20
Monday
Working Day
23
28-JAN-20
Tuesday
Working Day
23
29-JAN-20
Wednesday
Working Day
23
30-JAN-20
Thursday
Working Day
23
31-JAN-20
Friday
Working Day
23
03-FEB-20
Monday
Working Day
23
04-FEB-20
Tuesday
Working Day
23
05-FEB-20
Wednesday
Working Day
23
06-FEB-20
Thursday
Working Day
23
07-FEB-20
Friday
Working Day
23
10-FEB-20
Monday
Working Day
23
11-FEB-20
Tuesday
Working Day
23
12-FEB-20
Wednesday
Working Day
23
13-FEB-20
Thursday
Working Day
23
14-FEB-20
Friday
Working Day
23
17-FEB-20
Monday
Working Day
23
18-FEB-20
Tuesday
Working Day
23
19-FEB-20
Wednesday
Working Day
23
20-FEB-20
Thursday
Working Day
23
21-FEB-20
Friday
Working Day
23
24-FEB-20
Monday
Working Day
23
25-FEB-20
Tuesday
Working Day
23
26-FEB-20
Wednesday
Working Day
23
27-FEB-20
Thursday
Working Day
23
28-FEB-20
Friday
Working Day
23
02-MAR-20
Monday
Working Day
23
03-MAR-20
Tuesday
Working Day
23
04-MAR-20
Wednesday
Working Day
23
05-MAR-20
Thursday
Working Day
23
06-MAR-20
Friday
Working Day
23
09-MAR-20
Monday
Working Day
23
10-MAR-20
Tuesday
Working Day
23
11-MAR-20
Wednesday
Working Day
23
12-MAR-20
Thursday
Working Day
23
13-MAR-20
Friday
Working Day
23
16-MAR-20
Monday
Working Day
23
17-MAR-20
Tuesday
Working Day
23
18-MAR-20
Wednesday
Working Day
23
19-MAR-20
Thursday
Working Day
23
20-MAR-20
Friday
Working Day
23
23-MAR-20
Monday
Working Day
23
24-MAR-20
Tuesday
Working Day
23
25-MAR-20
Wednesday
Working Day
23
26-MAR-20
Thursday
Working Day
23
27-MAR-20
Friday
Working Day
23
30-MAR-20
Monday
Working Day
23
31-MAR-20
Tuesday
Working Day
23
db<>fiddle here
Related
I want to calculate the Fiscal Week of the Year with the following rules:
The fiscal year always starts on June/01
The week always starts on Sunday
Samples are provided for 2019 but ideally it should work for any year
A few samples of correct values are provided with the screenshot attached
I tried to do something like TO_NUMBER(TO_CHAR(TO_DATE(DATE_ID + 1,'DD-Mon-YY'),'IW')) -21 but towards the end of the Calendar year I start to get negatives
SELECT
DATE_ID
, WEEK_OF_YEAR
FROM DATE_DIM
WHERE
DATE_ID IN
(
20190601
, 20190602
, 20190915
, 20191228
, 20191229
, 20200101
, 20200601
, 20200606
, 20200607
)
ORDER BY DATE_ID ASC
;
SELECT TO_CHAR(ADD_MONTHS(SYSDATE,+7),'IW')
FROM dual
Or in your case,
SELECT date_id,TO_CHAR(ADD_MONTHS(TO_DATE(date_id,'YYYYMMDD'),+7),'IW') week_of_year
FROM date_dim
If you don't like the ISO dating where week 1 is the week beginning Sunday during which the 1st of the year falls, you can try offsetting it by moving it back to the previous sunday (TRUNC(..,'D'), then advance a week, then add the 7 months. See if this works for you:
SELECT date_id, TO_CHAR(ADD_MONTHS(TRUNC(date_id,'D') + 7,7),'IW') week_of_year
FROM date_dim
You got confused with your date formats ('yyyymmdd' vs. 'DD-Mon-YY'), so I am using a real date (mydate) in my answer. Convert your string or number to a proper date and you are there :-)
The important thing is to check whether your date is >= June 1. Once this is done you can subtract that year's June 1 or the previous year's one. Well, more or less :-)
select
mydate,
to_char(mydate, 'DY') as tag,
trunc
(
case when to_char(mydate, 'mmdd') >= '0601' then
trunc(mydate + 1, 'iw') + 6 - to_date(to_char(mydate, 'yyyy') || '0601', 'yyyymmdd')
else
trunc(mydate + 1, 'iw') + 6 - to_date(to_char(extract(year from mydate) - 1) || '0601', 'yyyymmdd')
end / 7
) + 1 as fiscal_week
from ...
order by mydate;
Demo: https://dbfiddle.uk/N5pX_5cV
UPDATED ANSWER
You can try this - provide the date like 31-MAY-19 to start your calendar from 01-JUN-19 and define how many days you want. There is a shift of 5 months as the code was taken from my regular calendar and adjusted the start of week to sunday...Tested OK for periods up to 2 years per run. So if you want 6 years you'll have to run this 3 times...
WITH
base_calendar AS
(
SELECT CurrDate AS Day_ID,
TO_CHAR(CurrDate,'Day') AS Week_Day_Full,
TO_CHAR(CurrDate,'DY') AS Week_Day_Short,
TO_NUMBER(TRIM(leading '0' FROM TO_CHAR(CurrDate,'D'))) AS Day_Num_of_Week,
--
MAX(CASE WHEN To_Char(CurrDate, 'ddmm') = '2902' THEN EXTRACT(YEAR From CurrDate) END) OVER(Order By CurrDate Rows Between Unbounded Preceding And Current Row) AS last_leap_year,
Count(CASE WHEN ( TO_CHAR(CurrDate,'DY') = 'SUN' And
CurrDate Between To_date('01.06.' || To_Char(EXTRACT(YEAR From CurrDate)), 'dd.mm.yyyy') And To_date('31.05.' || To_Char(EXTRACT(YEAR From CurrDate) + 1), 'dd.mm.yyyy') )
OR
( TO_CHAR(CurrDate,'DY') = 'SUN' And
CurrDate Between To_date('01.06.' || To_Char(EXTRACT(YEAR From CurrDate) - 1), 'dd.mm.yyyy') And To_date('31.05.' || To_Char(EXTRACT(YEAR From CurrDate) ), 'dd.mm.yyyy') )
THEN 1
END) OVER(Order By CurrDate Rows Between Unbounded Preceding And Current Row) AS cnt_sundays
FROM
(
SELECT level n,
-- Calendar starts at the day after this date
TO_DATE('31/05/2019','DD/MM/YYYY') + NUMTODSINTERVAL(level,'DAY') CurrDate
FROM dual
-- Change for the number of days to be added to the table.
CONNECT BY level <= 731
)
)
SELECT DISTINCT
day_id,
CASE WHEN (cnt_sundays + 1 ) - ( (EXTRACT(YEAR From Add_Months(Day_id, - 5)) -EXTRACT(YEAR From MIN(Day_id) OVER()) ) * 53) >= 54 THEN 1
WHEN EXTRACT(YEAR From day_id) <> last_leap_year And day_id > = To_Date('01.06.' || To_Char(EXTRACT(YEAR From day_id)), 'dd.mm.yyyy' )
THEN (cnt_sundays + 1) - ( (EXTRACT(YEAR From Add_Months(Day_id, - 5)) -EXTRACT(YEAR From MIN(Day_id) OVER()) ) * 53) + 1
ELSE (cnt_sundays + 1) - ( (EXTRACT(YEAR From Add_Months(Day_id, - 5)) -EXTRACT(YEAR From MIN(Day_id) OVER()) ) * 53)
END week_of_year,
--
week_day_full,
week_day_short,
CASE week_day_short
WHEN 'SUN' THEN 1
WHEN 'MON' THEN 2
WHEN 'TUE' THEN 3
WHEN 'WED' THEN 4
WHEN 'THU' THEN 5
WHEN 'FRI' THEN 6
WHEN 'SAT' THEN 7
END AS day_num_of_week
FROM base_calendar
ORDER BY day_id
R E S U L T S :
DAY_ID WEEK_OF_YEAR WEEK_DAY_FULL WEEK_DAY_SHORT DAY_NUM_OF_WEEK
--------- ------------ ------------- -------------- ---------------
01-JUN-19 1 Saturday SAT 7
02-JUN-19 2 Sunday SUN 1
03-JUN-19 2 Monday MON 2
04-JUN-19 2 Tuesday TUE 3
05-JUN-19 2 Wednesday WED 4
... ...
... ...
13-SEP-19 16 Friday FRI 6
14-SEP-19 16 Saturday SAT 7
15-SEP-19 17 Sunday SUN 1
16-SEP-19 17 Monday MON 2
... ...
30-DEC-19 32 Monday MON 2
31-DEC-19 32 Tuesday TUE 3
01-JAN-20 32 Wednesday WED 4
02-JAN-20 32 Thursday THU 5
...
27-FEB-20 40 Thursday THU 5
28-FEB-20 40 Friday FRI 6
29-FEB-20 40 Saturday SAT 7
01-MAR-20 41 Sunday SUN 1
02-MAR-20 41 Monday MON 2
...
29-MAY-20 53 Friday FRI 6
30-MAY-20 53 Saturday SAT 7
31-MAY-20 1 Sunday SUN 1
01-JUN-20 1 Monday MON 2
02-JUN-20 1 Tuesday TUE 3
03-JUN-20 1 Wednesday WED 4
04-JUN-20 1 Thursday THU 5
05-JUN-20 1 Friday FRI 6
06-JUN-20 1 Saturday SAT 7
07-JUN-20 2 Sunday SUN 1
... ...
... ...
22-MAY-21 51 Saturday SAT 7
23-MAY-21 52 Sunday SUN 1
24-MAY-21 52 Monday MON 2
25-MAY-21 52 Tuesday TUE 3
26-MAY-21 52 Wednesday WED 4
27-MAY-21 52 Thursday THU 5
28-MAY-21 52 Friday FRI 6
29-MAY-21 52 Saturday SAT 7
30-MAY-21 53 Sunday SUN 1
31-MAY-21 53 Monday MON 2
731 rows selected
... with year 2025 - part of the result mentioned in comments above ...
... ...
29-MAY-25 53 Thursday THU 5
30-MAY-25 53 Friday FRI 6
31-MAY-25 53 Saturday SAT 7
01-JUN-25 1 Sunday SUN 1
02-JUN-25 1 Monday MON 2
03-JUN-25 1 Tuesday TUE 3
04-JUN-25 1 Wednesday WED 4
05-JUN-25 1 Thursday THU 5
06-JUN-25 1 Friday FRI 6
07-JUN-25 1 Saturday SAT 7
08-JUN-25 2 Sunday SUN 1
... ...
I have a table with just one column and about 3000 rows that follows the same pattern. I want to include the days of the week at the beginning of the string for each TIME inside the same string in the row.
Original table :
DATA_TIME_COMBINATION
Monday 3 am HM, 5 am HC, 10 pm HX
Saturday AB 6 am, WE 5 pm
Sunday Friday AN 50 TU,FG 55 RE, DC 56 JJ
Tuesday 10 am, 5 am, 1 am
Wednesday 12 pm-9 pm- 1 am
Results needed :
DATA_TIME_COMBINATION
Monday 3 am HM, Monday 5 am HC, Monday 10 pm HX
Saturday AB 6 am, Saturday WE 5 pm
Sunday Friday AN 50 TU, Sunday Friday FG 55 RE, Sunday Friday DC 56 JJ
Tuesday 10 am, Tuesday 5 am, Tuesday 1 am
Wednesday 12 pm- Wednesday 9 pm- Wednesday 1 am
Thanks in advance!
seems you want replace the comma with a comma and the first word at beginning of the string
select replace(DATA_TIME_COMBINATION, ',',
concat(',', substr(DATA_TIME_COMBINATION,1,charindex(' ', DATA_TIME_COMBINATION)-1)))
from my_table
Once you know the character and days.
Then it'll become a simple replace.
One cross apply for the weekdays.
A second for a character in place.
SELECT
REPLACE(REPLACE([DATA_TIME_COMBINATION], chr, chr+' '+days+' '),' ',' ') as DATA_TIME_COMBINATION
FROM mytable AS t
CROSS APPLY (
SELECT STRING_AGG(value, ' ') days
FROM STRING_SPLIT(
LEFT([DATA_TIME_COMBINATION], PATINDEX('%[a-z] [0-9]%', [DATA_TIME_COMBINATION])), ' ') spl
WHERE value LIKE '%day'
) ca1
CROSS APPLY (
SELECT
chr = SUBSTRING([DATA_TIME_COMBINATION], PATINDEX('%[^A-Za-z0-9 ]%', [DATA_TIME_COMBINATION]), 1)
) ca2;
DATA_TIME_COMBINATION
Monday 3 am HM, Monday 5 am HC, Monday 10 pm HX
Saturday AB 6 am, Saturday WE 5 pm
Sunday Friday AN 50 TU, Sunday Friday FG 55 RE, Sunday Friday DC 56 JJ
Tuesday 10 am, Tuesday 5 am, Tuesday 1 am
Wednesday 12 pm- Wednesday 9 pm- Wednesday 1am
Test on db<>fiddle here
Using CONCAT(TO_CHAR(T.order_create_date,'yyyy')," ",WEEKOFYEAR(T.order_create_date)) returns 2018-12-31 as 2018-1.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
SELECT(DATEPART(dy,DATEADD(dd,DATEDIFF(dd,'17530101',#SomeDate)/7*7,'17530104'))+6)/7;
I am attempting to change the start of the week of a data set from Monday to the previous Friday. The overall data will be aggregated to a week level to look like this.
Week 1
Friday,
Saturday,
Sunday,
Monday,
Tuesday,
Wednesday,
Thursday
The best I have come up with to do this is a case statement which sets Friday, Saturday and Sunday to next week's First day of the week (the system first day is Monday and last day is Sunday).
SELECT TRANSACTIONDATE,
CASE
WHEN TO_CHAR(TRANSACTIONDATE, 'DAY') IN ('FRIDAY', 'SATURDAY',
'SUNDAY') THEN (TRUNC(TRANSACTIONDATE, 'IW')+7)
ELSE TRUNC(TRANSACTIONDATE, 'IW')
END AS TEST
FROM TRANSACTIONS
My logic for this code is: if Fri, Sat or Sun then find the first day of the week and add 7 returning next week's first day of the week.
The problem is that the statement "TRUNC(TRANSACTIONDATE, 'IW')+7" is not adding 7 days to the week start.
When I query
select "TRUNC(TRANSACTIONDATE, 'IW')+7" from transactions
I get the next weeks week start which is correct.
This way all the days from Friday to Thursday are under the same week number.
Any ideas what's going wrong or if theres a better way to accomplish what I'm after?
Thanks,
Tom
Edit**
The first data set is what I would like at achieve,
Date Day Week
4/1/2018 Monday 1
4/2/2018 Tuesday 1
4/3/2018 Wednesday 1
4/4/2018 Thursday 1
4/5/2018 Friday 2
4/6/2018 Saturday 2
4/7/2018 Sunday 2
4/8/2018 Monday 2
4/9/2018 Tuesday 2
4/10/2018 Wednesday 2
4/11/2018 Thursday 2
So above you can see I want Firday/Saturday/Sunday to fall into the next week.
This is the current system dates/weeks does,
Date Day Week
4/1/2018 Monday 1
4/2/2018 Tuesday 1
4/3/2018 Wednesday 1
4/4/2018 Thursday 1
4/5/2018 Friday 1
4/6/2018 Saturday 1
4/7/2018 Sunday 1
4/8/2018 Monday 2
4/9/2018 Tuesday 2
The problem is TO_CHAR(TRANSACTIONDATE, 'DAY')
When you use 'DAY' then the weekday name is padded with space characters. Try SELECT '<'||TO_CHAR(DATE '2018-05-07', 'DAY')||'>' from dual; to see the effect.
Function TO_CHAR(..., 'DAY') returns the weekday name according to current user session NLS_DATE_LANGUAGE settings. This might be english or not.
Change your expression for example to
TO_CHAR(TRANSACTIONDATE, 'fmDAY', 'NLS_DATE_LANGUAGE=american') IN ('FRIDAY', 'SATURDAY', 'SUNDAY')
2012
January
2/1/2012
9/1/2012
16/1/2012
23/1/2012
30/1/2012
February
6/2/2012
.
.
.
.
and so on till decemeber.
the dates mentioned are mondays..How do i get the output in this format?? please help
One option
SQL> ed
Wrote file afiedt.buf
1 select next_day(trunc(sysdate,'YYYY') + 7*(level-1), 'MON' )
2 from dual
3* connect by level <= 53
SQL> /
NEXT_DAY(
---------
02-JAN-12
09-JAN-12
16-JAN-12
23-JAN-12
30-JAN-12
06-FEB-12
13-FEB-12
20-FEB-12
27-FEB-12
05-MAR-12
12-MAR-12
<<snip>>
03-DEC-12
10-DEC-12
17-DEC-12
24-DEC-12
31-DEC-12
53 rows selected.
Query:
select distinct next_day(to_date('01-01-2012','mm-dd-yyyy')-1+level,'Monday') All_MON from dual
connect by level <= floor(to_date('12-31-2011','mm-dd-yyyy') - to_date('01-01-2011','mm-dd-yyyy'))
order by All_MON;
Output:
01/02/2012 MONDAY
01/09/2012 MONDAY
01/16/2012 MONDAY
01/23/2012 MONDAY
01/30/2012 MONDAY
02/06/2012 MONDAY
02/13/2012 MONDAY
02/20/2012 MONDAY
02/27/2012 MONDAY
03/05/2012 MONDAY
03/12/2012 MONDAY
03/19/2012 MONDAY
03/26/2012 MONDAY
04/02/2012 MONDAY
04/09/2012 MONDAY
04/16/2012 MONDAY
04/23/2012 MONDAY
04/30/2012 MONDAY
05/07/2012 MONDAY
05/14/2012 MONDAY
05/21/2012 MONDAY
05/28/2012 MONDAY
06/04/2012 MONDAY
06/11/2012 MONDAY
06/18/2012 MONDAY
06/25/2012 MONDAY
07/02/2012 MONDAY
07/09/2012 MONDAY
07/16/2012 MONDAY
07/23/2012 MONDAY
07/30/2012 MONDAY
08/06/2012 MONDAY
08/13/2012 MONDAY
08/20/2012 MONDAY
08/27/2012 MONDAY
09/03/2012 MONDAY
09/10/2012 MONDAY
09/17/2012 MONDAY
09/24/2012 MONDAY
10/01/2012 MONDAY
10/08/2012 MONDAY
10/15/2012 MONDAY
10/22/2012 MONDAY
10/29/2012 MONDAY
11/05/2012 MONDAY
11/12/2012 MONDAY
11/19/2012 MONDAY
11/26/2012 MONDAY
12/03/2012 MONDAY
12/10/2012 MONDAY
12/17/2012 MONDAY
12/24/2012 MONDAY
12/31/2012 MONDAY