I have such table and need table 2 result. I am trying to select rows with max date grouped by project_id and ordered by id. And result table must have id column. Tried such request:
SELECT MAX(charges.id) as id,
"charges"."profile_id", MAX(failed_at) AS failed_at
FROM "charges"
GROUP BY "charges"."profile_id"
ORDER BY "charges"."id" ASC
And have error:
ERROR: column "charges.id" must appear in the GROUP BY clause or be used in an aggregate function)
Example table
id
profile_id
failed_at
1
1
01.01.2021
2
1
01.02.2021
3
1
01.03.2021
4
2
01.06.2021
5
2
01.05.2021
6
2
01.04.2021
Needed result
id
profile_id
failed_at
3
1
01.03.2021
4
2
01.06.2021
SELECT charges.*
FROM charges
INNER JOIN
(
SELECT
profile_id,
MAX(charges.failed_at) AS MaxFailed_at
FROM charges
GROUP BY profile_id
) AS xQ ON charges.profile_id = xQ.profile_id AND charges.failed_at = xQ.MaxFailed_at
Related
This is my parent table acc_detial -
ACC_DETIAL example -
acc_id
1
2
3
Now i have 3 tables:
ORDER
EMAIL
REPORT
Each table contains 100 rows and acc_id are ForeignKey from ACC_DETIAL.
In ORDER table I have a columns ACC_ID and QUANTITY. I want the count of ACC_ID and sum of QUANTITY.
ORDER table example:
acc_id
quantity
date
1
2
2022/01/22
2
5
2022/01/23
1
10
2022/01/25
3
1
2022/01/25
In EMAIL table I have a column name ACC_ID and I want count of ACC_ID.
EMAIL table example:
acc_id
mail
date
1
5
2022/01/22
2
10
2022/01/22
1
7
2022/01/23
1
7
2022/01/24
2
10
2022/01/25
In REPORT table I have a columns ACC_ID and TYPE and I want the count of ACC_ID and TYPE. Note that TYPE column has only two, possible values:
postive
negative
I want count of each, i.e. count of postive and count of negative in TYPE column.
REPORT table example:
acc_id
type
date
1
positive
2022/01/22
2
negative
2022/01/22
1
negative
2022/01/23
2
postitive
2022/01/26
2
postitive
2022/01/27
I need to take this in a single i need answer as raw query or sqlalchemy. Is it possible or not? Do I need to write separate query to get each table result ?
Result -
result based on above examplec -
acc_id
total_Order_acc_id
total_Order_quantity
total_Email_acc_id
total_Report_acc_id
total_postitive_report
total_negative_report
1
2
12
3
2
1
1
2
1
5
2
3
2
1
3
1
1
Null
Null
Null
Null
You need to aggregate then join as the following:
SELECT ADL.acc_id,
ORD.ord_cnt AS total_Order_acc_id,
ORD.tot_quantity AS total_Order_quantity,
EML.eml_cnt AS total_Email_acc_id,
RPT.rpt_cnt AS total_Report_acc_id,
RPT.pcnt AS total_postitive_report,
RPT.ncnt AS total_negative_report
FROM ACC_DETIAL ADL LEFT JOIN
(
SELECT acc_id,
SUM(quantity) AS tot_quantity,
COUNT(*) AS ord_cnt
FROM ORDERS
GROUP BY acc_id
) ORD
ON ADL.acc_id = ORD.acc_id
LEFT JOIN
(
SELECT acc_id, COUNT(*) AS eml_cnt
FROM EMAIL
GROUP BY acc_id
) EML
ON ADL.acc_id = EML.acc_id
LEFT JOIN
(
SELECT acc_id,
COUNT(*) AS rpt_cnt,
COUNT(*) FILTER (WHERE type='positive') AS pcnt,
COUNT(*) FILTER (WHERE type='negative') AS ncnt
FROM REPORT
GROUP BY acc_id
) RPT
ON ADL.acc_id = RPT.acc_id
See demo
Sample :
Select
`order`.`acc_id`,
report_email_select.`type`,
report_email_select.report_count,
report_email_select.email_count,
SUM(`quantity`) as quantity_sum
FROM
`order`
Left JOIN(
Select
report_select.`acc_id`,
report_select.`type`,
report_select.report_count,
COUNT(*) as email_count
from
(
SELECT
report.`acc_id`,
report.`type`,
COUNT(*) as report_count
FROM
`report`
WHERE
1
GROUP BY
report.`acc_id`,
report.`type`
) AS report_select
INNER JOIN email ON email.acc_id = report_select.acc_id
GROUP BY
report_select.`acc_id`,
report_select.`type`
) AS report_email_select ON `order`.acc_id = report_email_select.acc_id
GROUP BY
`order`.`acc_id`,
report_email_select.`type`;
I have a table where Employees can check assets and each of their checks is recorded in a table.
Now I want to extract the 5 last checked Asset_Ids for a given employee. He might have checked the same asset more than once, each check is recorded in a table -EmployeeLog-
Basically my table has 3 columns :
Employee_ID
DateChecked
Asset_ID
1
06/10/2021 10:56:22
1
1
06/10/2021 14:58:25
1
1
02/10/2021 13:56:22
2
1
06/10/2021 08:56:22
1
1
04/10/2021 03:56:22
1
1
06/10/2021 02:56:22
3
1
06/10/2021 15:56:22
2
1
03/10/2021 03:56:22
5
1
06/10/2021 03:56:22
5
I have below query which lists Asset_IDs by check date, but I have to apply distinct and top 5 to this list which I couldn't, any help appreciated.
SELECT Asset_ID
FROM EmployeeLog
WHERE EmployeeID = #Emp_ID AND Asset_ID != '00000000-0000-0000-0000-000000000000'
ORDER BY EmployeeLog.DateChecked Desc
You can do a GROUP BY, and order by first (or last) date.
SELECT Asset_ID
FROM EmployeeLog
WHERE EmployeeID = #Emp_ID AND Asset_ID != '00000000-0000-0000-0000-000000000000'
GROUP BY Asset_ID
ORDER BY MIN(EmployeeLog.DateChecked) Desc
To get the first 5 rows only, do SELECT TOP 5 Asset_ID etc.
I want to achieve these two requirements using a single query. Currently I'm using 2 queries in the program and use C# to do the process part something like this.
Pseudocode
select top 1 id from table where type=b
if result.row.count > 0 {var typeBid = row["id"]}
select * from table where id >= {typeBid}
else
select * from table
Req1: If there is records exist with type=b, Result should be latest row with type=b and all other rows added after.
Table
--------------------
id type date
--------------------
1 b 2021-10-15
2 a 2021-11-16
3 b 2021-11-19
4 a 2021-12-02
5 c 2021-12-12
6 a 2021-12-16
Result
--------------------
id type date
--------------------
3 b 2021-11-19
4 a 2021-12-02
5 c 2021-12-12
6 a 2021-12-16
Req2: There is NO record exist with type=b. Query should select all the records in the table
Table
---------------------
id type date
---------------------
1 a 2021-10-15
2 a 2021-11-16
3 a 2021-11-19
4 a 2021-12-02
5 c 2021-12-12
6 a 2021-12-16
Result
--------------------
id type date
--------------------
1 a 2021-10-15
2 a 2021-11-16
3 a 2021-11-19
4 a 2021-12-02
5 c 2021-12-12
6 a 2021-12-16
with max_b_date as (select max(date) as date
from table1 where type = 'b')
select t1.*
from table1 t1
cross join max_b_date
where t1.date >= max_b_date.date
or max_b_date.date is null
(table is a SQL reserved word, https://en.wikipedia.org/wiki/SQL_reserved_words, so I used table1 as table name instead.)
https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=bd05543a9712e27f01528708f10b209f
Please try this(It's somewhat deep but might you exact looking for)
select ab.* from
((select top 1 id, type, date from test where type = 'b' order by id desc)
union
select * from test where type != 'b') as ab
where ab.id >= (select COALESCE((select top 1 id from test where type = 'b' order by id desc), 0))
order by ab.id;
https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=739eb6bfee787e5079e616bbf4e933b1
Looks Like you can use an OR condition here
SELECT
*
FROM
(
SELECT
*,
BCount = COUNT(CASE type WHEN 'B' THEN 1 ELSE NULL END)-- to get the Count of Records with Type b.
FROM Table
)Q
WHERE
(
BCount > 0 AND id >= (select top 1 id from table where type=b)-- if there are Row's with Type b then select Req#1
)
OR
(
BCount = 0 -- if THere are no rows with Type B select All
)
Table Structure First
users table
id
1
2
3
sites table
id
1
2
site_memberships table
site_id
user_id
created_on
1
1
1
1
1
2
1
1
3
2
1
1
2
1
2
1
2
2
1
2
3
Assuming higher the created_on number, latest the record
Expected Output
site_id
user_id
created_on
1
1
3
2
1
2
1
2
3
Expected output: I need latest record for each user for each site membership.
Tried the following query, but this does not seem to work.
select * from users inner join
(
SELECT ROW_NUMBER () OVER (
PARTITION BY sm.user_id,
sm.created_on
), sm.*
from site_memberships sm
inner join sites s on sm.site_id=s.id
) site_memberships
ON site_memberships.user_id = users.user_id where row_number=1```
I think you have overcomplicated the problem you want to solve.
You seem to want aggregation:
select site_id, user_id, max(created_on)
from site_memberships sm
group by site_id, user_id;
If you had additional columns that you wanted, you could use distinct on instead:
select distinct on (site_id, user_id) sm.*
from site_memberships sm
order by site_id, user_id, created_on desc;
I have 2 tables A and B. The columns names are similar in both the tables. The columns are
1. fees
2. user_id
I want to get the sum of fees from both tables where user_id = 1
For eg:
Table A:
id user_id fees
1 1 10
2 2 11
3 1 5
Table B:
id user_id fees
1 1 15
2 2 10
3 1 20
I need the result as below:
user_id fees
1 50
2 21
Please help me with the query
Try this:
select user_id, sum(fees) from (
select user_id, fees from Table_A
union all
select user_id, fees from Table_B
) as A
group by user_id