Pivot Sql with no aggregate - sql

Question

I learned I can't pivot text without aggregation max() & min().
I am trying to figure out a workaround but the answers to similar questions are sailing over my head. would anyone have tips to workaround that?
data table:
pax
codex
mis
dog1
hair
10
dog1
face
10
dog1
eye
5
dog1
smell
7
dog1
yellow
7
dog1
green
8
dog1
blue
9
dog1
tan
10
desired output:
pax
10
10
5
7
7
8
9
10
dog1
hair
face
eye
smell
yellow
green
blue
tan
actual outcome:
pax
10
5
7
8
9
dog1
hair
eye
smell
green
blue
I used this code:
DECLARE #cols AS NVARCHAR(MAX)='';
DECLARE #query AS NVARCHAR(MAX)='';
SELECT #cols = #cols + QUOTENAME(mis) + ',' FROM (select distinct mis from #dd) as tmp
select #cols = substring(#cols, 0, len(#cols)) --trim "," at end
set #query =
'SELECT * from
(
select pax,codex,mis from #dd
) src
pivot
(
max(codex) for mis in (' + #cols + ')
) piv'
execute(#query)

Answer 1

Try this
Select
pax,
concat(mis, '-', rn) as mis_new,
codex
from (
Select
pax,
mis,
row_number() over (partition by pax, mis
order by mis ) rn
from table
) t
pivot (
max(codex) for (
mis_new in ('10-1','10-2', '5-1','7-1','7-2','8-1','9-1','10-3')
) pvt

Answer 2

It looks like standard conditional aggregation over a row-number would serve better:
DECLARE #cols AS NVARCHAR(MAX) =
(
SELECT CONCAT(',MIN(CASE WHEN mis = ', QUOTENAME(mis, ''''), ' AND rn = ', rn, ' THEN codex END) ', QUOTENAME(mis))
FROM (
SELECT *,
ROW_NUMBER() OVER (PARTITION BY pax ORDER BY mis) rn
FROM dd
) as tmp
GROUP BY mis, rn
FOR XML PATH(''), TYPE
).value('text()[1]','nvarchar(max)');
DECLARE #query AS NVARCHAR(MAX) = '
SELECT
pax' + #cols + '
FROM (
SELECT *,
ROW_NUMBER() OVER (PARTITION BY pax ORDER BY mis) rn
FROM dd
) dd
GROUP BY pax;
';
PRINT #query; --for testing
EXEC sp_executesql
#query;
db<>fiddle
Note the use of FOR XML to aggregate. Variable coalescing should not be used, due to unpredictability.