I'm trying the following:
count(distinct concat(x.my_id,cast(date_trunc('day',DATETIME(x.my_datetime,'US/Central')) as string)))
But I get the error:
Found invalid date part argument function call syntax for DATETIME()
When I put DATETIME(x.my_datetime,'US/Central') on its own line, it has no errors. So how can I accomplish getting the day of a datetime cast to cdt and putting it in a concatenated string?
Two things:
date_trunc() should have the date/datetime/timestamp first, followed by the date part.
The date part should be the literal day instead of the string 'day'.
With that in mind, your expression should be
count(distinct concat(x.my_id,cast(date_trunc(DATETIME(x.my_datetime,'US/Central'), day) as string)))
Related
I'm trying to get the timestamp difference between two date fields in my table. I know both dates are on TIMESTAMP format, but when I tried using TIMESTAMP_DIFF function I get an error saying "No matching signature for function TIMESTAMP_DIFF for argument types: STRING, STRING, DATE_TIME_PART. Supported signature: TIMESTAMP_DIFF(TIMESTAMP, TIMESTAMP, DATE_TIME_PART) at [27:8]"
I also tried formatting them again in the query(as done on the example for FIRST_VALUE(): https://cloud.google.com/bigquery/docs/reference/standard-sql/functions-and-operators#datetime_diff , and then it showed the same error but for FORMAT_TIMESTAMP.
Any ideas what I could do to fix this or to get the time difference between two fields for each row?
use below (BigQuery Standard SQL)
#standardSQL
SELECT TIMESTAMP_DIFF(PARSE_TIMESTAMP('%Y-%m-%d %H:%M:%S', prev_time), PARSE_TIMESTAMP('%Y-%m-%d %H:%M:%S', event_datetime), MINUTE)
FROM `project.dataset.messages`
my table has a date column. its data type is date. I confirmed it by going to table name>>columns and it says MTH_END_DT [DATE, Not NULL]
I want to filter my data for a particular date. If I put a condition where MTH_END_DT = '6/1/2018' I get an error select failed [3535] A character string failed conversion to a numeric value.
I followed this page. I used where MTH_END_DT = date '6/1/2018' and i get an error syntax error invalid date literal
I tried where cast(timestamp_column as date) = date '2013-10-22'; something like this and it throws error too
How should i filter my data?
There's only one reliable way to write a date, using a date literal, date 'yyyy-mm-dd'
where MTH_END_DT = DATE '2018-06-01'
For a Timestamp it's
TIMESTAMP '2018-06-01 15:34:56'
and for Time
TIME '15:34:56'
In SQL Assistant it's recommended to switch to Standard SQL format YYYY-MM-DD in Tools-Options-Data Format-Display dates in this format
I did have the similar problem when I was filtering a particular date for my query with Teradata. First method I tried was putting 'DATE' term as the following:
WHERE saledate = DATE'04/08/01' but this did not solve the problem.
I then used an approach I stumbled upon when surfing, finally it worked.
WHERE extract(year from saledate)=2004 AND extract(MONTH from saledate)=8 AND extract(DAY from saledate)= 1 source
I think this really should not be this long, but it worked.
It seems to me it’s most likely you have input the date format incorrectly? Maybe it includes a time by default.
For example
where MTH_END_DT = ‘2013-10-22-00:00:00:00’
I have a question regarding SQL dates.
The table I am working with has a date field in the following format: "22-SEP-08". The field is a date column.
I am trying to figure out how to output records from 1/1/2000 to present day.
The code below is not filtering the date field:
Select distinct entity.lt_date
from feed.entitytable entity
where entity.lt_date >= '2000-01-01'
Any help regarding this issue is much appreciated. Thanks!
Edit: I am using Oracle SQL Developer to write my code.
DATEs do not have "a format". Any format you see is applied by the application displaying the date value.
You can either change the configuration of SQL Developer to display dates in a different format, or you can use to_char() to format the date the way you want.
The reason your statement does not work, is most probably because of the implicit data type conversion that you are relying on.
'2000-01-01' is a string value, not a date. And the string is converted using the NLS settings of your session. Given the fact that you see dates displayed as DD-MON-YY means that that is the format that is used by the evil implicit data type conversion. You should supply date values always as real date literals.
There are two ways of specifying a real date literal. The first is ANSI SQL and simple uses the keyword DATE in front of an ISO formatted string:
where entity.lt_date >= DATE '2000-01-01'
Note the DATE keyword in front of the string, wich makes it a real date literal not a string expression.
The other option is to use to_date() to convert a character value into a date:
where entity.lt_date >= to_date('2000-01-01', 'yyyy-mm-dd');
More details about specifying date literals can be found in the manual:
Date literals
to_date function
My guess is the data type isn't a Date. Just in case its a char type, try to convert it using the Oracle TO_DATE() function. The Oracle documentation below should help you with parameters.
http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions183.htm
An implicit datatype conversion bites once again.
You're right. The predicate is not doing the comparison you are expecting,
Oracle is performing an implicit datatype conversion, from DATE to VARCHAR, so that it can do a comparison to the string literal.
If lt_date column is DATE datatype, then Oracle is seeing your where clause:
where entity.lt_date >= '2000-01-01'
Oracle is actually seeing it as if it's written like this:
where TO_CHAR(entity.lt_date) >= '2000-01-01'
And that's where the "format" problem comes in. The column itself does not have a "format". Because the second argument to the TO_CHAR function is not supplied, Oracle is using the value of the NLS_DATE_FORMAT parameter (from your session). And that's probably set to DD-MON-YY. Which is why that's the "format" you're seeing when you a run a SELECT statement in SQL*Plus. Because the DATE value is (again) being run through a TO_CHAR function to get a string that can be displayed.
To get the "filtering" you want, don't do a comparison to a string literal. Instead, do the comparison to an expression that has DATE datatype.
You can use the Oracle TO_DATE function. And you don't want to rely on setting of NLS_DATE_FORMAT, explicitly specify the format model as the second argument to the function. For example:
DO THIS
where entity.lt_date >= TO_DATE('2000-01-01','YYYY-MM-DD')
DON'T DO THIS
It's also possible to specify the format model as the second argument to the TO_CHAR function.
where TO_CHAR(entity.lt_date,'YYYY-MM-DD') >= '2001-01-01'
But you don't want to do that because that's going to force Oracle to evaluate that expression on the left side for every flipping row in the table, so it has a string value to do the comparison. (That's true unless someone created a function-based index for you.) If you do the comparison on the bare column, using the TO_DATE on the literal side, Oracle can make effective use of an appropriate index (with lt_date as the leading column) to satisfy the predicate.
I'm trying to calculate the difference between two days using DATEDIFF (). I use following code for this:
=DATEDIFF(DAY,CDate(Fields!Eingang_Kundenanfrage.Value),CDate(Fields!Ausgang_Angebot.Value))
Every time I try to save the report, I get this error message:
[BC30455] Argument not specified for parameter 'DateValue' of 'Public Function Day(DateValue As Date) As Integer'.
The DataSource is a SharePoint List and the Date is given in the following format: 23.05.2014 00:00:00 (DD.MM.YYYY HH:MM:SS).
I've googled for a working solution for a long time now, but I had no success.
Is there someone who can help me?
Before enter your date value convert it to date datatype.
select datediff(day,convert(date,'2014-05-28 16:07:54.647'),convert(date,'2014-05-29 16:07:54.647')) as DiffDay
I'm sure this is quite simple, but I've been stuck on it for some time. How can I convert a varchar field (YYYYMM) to a date (MM/01/YY) in SQL?
Thanks.
Edit: I'm using Open Office Base (HSQL), not MySQL; sorry for the confusion.
Try the str_to_date and date_format functions. Something like:
select date_format( str_to_date( my_column, '%Y%c' ), '%c/01/%y' ) from my_table
try :
SELECT STR_TO_DATE(CONCAT(myDate,'01'),'%Y%m%d')
FROM myTable
Use STR_TO_DATE:
From mysql.com:
STR_TO_DATE(str,format)
This is the inverse of the DATE_FORMAT() function. It takes a string str and a format string format. STR_TO_DATE() returns a DATETIME value if the format string contains both date and time parts, or a DATE or TIME value if the string contains only date or time parts.
The date, time, or datetime values contained in str should be given in the format indicated by format. For the specifiers that can be used in format, see the DATE_FORMAT() function description. If str contains an illegal date, time, or datetime value, STR_TO_DATE() returns NULL. Starting from MySQL 5.0.3, an illegal value also produces a warning.
Range checking on the parts of date values is as described in Section 11.3.1, “The DATETIME, DATE, and TIMESTAMP Types”. This means, for example, that “zero” dates or dates with part values of 0 are allowed unless the SQL mode is set to disallow such values.
mysql> SELECT STR_TO_DATE('00/00/0000', '%m/%d/%Y');
-> '0000-00-00'
mysql> SELECT STR_TO_DATE('04/31/2004', '%m/%d/%Y');
-> '2004-04-31'
Get the year:
SUBSTRING(field FROM 2 FOR 2)
Get the month:
SUBSTRING(field FROM -2 FOR 2)
Compose the date:
CONCAT(SUBSTRING(field FROM -2 FOR 2), '/01/', SUBSTRING(field FROM 2 FOR 2))
This will convert from YYYYMM to MM/01/YY.
To be clear: if you're looking for method to convert some value of type Varchar/Text to value of type Date than solutions are:
using CAST function
CAST(LEFT('201205',4)||'-'||SUBSTRING('201205' FROM 5 FOR 6)||'-01' AS DATE)
starting from OpenOffice 3.4 (HSQLDB 2.x) new Oracle-like function TO_DATE supposed to be available
TO_DATE('201205','YYYYMM')
in addition to the written i can mention that you also can construct a string with ANSI/ISO 'YYYY-MM-DD' formatted representation of the date,- Base will acknowledge that and succesfully convert it to the Date type if necessary (e.g. INSERTing in Date typed column etc.)
Here is doc's on HyperSQL and highly recommended OO Base guide by Andrew Pitonyak