AID
BID
STATE
1
1
1
1
2
3
1
3
3
2
1
0
2
2
3
2
3
3
3
1
3
3
2
0
3
3
3
I am trying to find AID records which doesnt have any 0 state in this example AID = 1 (will be multiple records)
If you would like to find all the AID with no 0 state records you may use
SELECT
AID
FROM
mytable
GROUP BY
AID
HAVING
COUNT(
CASE WHEN STATE=0 THEN 1 END
)=0;
AID
1
or if you would like to find all AID records where the state is not 0 for any AID record you may use the following.
SELECT
*
FROM
mytable
WHERE AID NOT IN (
SELECT AID FROM mytable WHERE STATE=0
)
AID
BID
STATE
1
1
1
1
2
3
1
3
3
Let me know if this works for you.
Related
I have a table that looks something like this:
id name status
2 a 1
2 a 2
2 a 3
2 a 2
2 a 1
3 b 2
3 b 1
3 b 2
3 b 1
and the resultant i want is:
id name total count count(status3) count(status2) count(status1)
2 a 5 1 2 2
3 b 4 0 2 2
please help me get this result somehow, i can just get id, name or one of them at a time, don't know how to put a clause to get this table at once.
Here's a simple solution using group by and case when.
select id
,count(*) as 'total count'
,count(case status when 3 then 1 end) as 'count(status1)'
,count(case status when 2 then 1 end) as 'count(status3)'
,count(case status when 1 then 1 end) as 'count(status2)'
from t
group by id
id
total count
count(status3)
count(status2)
count(status1)
2
5
1
2
2
3
4
0
2
2
Fiddle
Here's a way to solve it using pivot.
select *
from (select status,id, count(*) over (partition by id) as "total count" from t) tmp
pivot (count(status) for status in ([1],[2],[3])) pvt
d
total count
1
2
3
3
4
2
2
0
2
5
2
2
1
Fiddle
I have such tables:
Group - combination of TypeId and ZoneId
ID TypeID ZoneID
-- -- --
1 1 1
2 1 2
3 2 1
4 2 2
5 2 3
6 3 3
Object
ID GroupId
-- --
1 1
2 1
3 2
4 3
5 3
6 3
I want to build a query for grouping all these tables by TypeId and ZoneId, with number of objects which have specific combination of these field:
ResultTable
TypeId ZoneId Number of objects
-- -- --
1 1 2
1 2 1
2 1 3
2 2 1
2 3 0
3 3 0
Query for this:
SELECT
group.TypeId,
group.ZoneId,
COUNT(obj.ID) as NumberOfObjects
FROM[Group] group
JOIN[Object] obj on obj.GroupID = group.ID
GROUP BY group.TypeId, group.ZoneId ORDER BY group.TypeId
But! I want to add summarize row after each group, and make it like:
ResultTableWithSummary
TypeId ZoneId Number of objects
-- -- --
1 1 2
1 2 1
Summary (empty field) 3
2 1 3
2 2 1
2 3 0
Summary (empty field) 4
3 3 0
Summary (empty field) 0
The problem is that I can use GROUP BY ROLLUP(group.TypeId, group.ZoneId):
TypeId ZoneId Number of objects
-- -- --
1 1 2
1 2 1
1 null 3
2 1 3
2 2 1
2 3 0
2 null 4
3 3 0
3 null 0
but I cannot or don't know how to change not-null group.TypeId in summary rows with "Summary".
How can I do this?
The simplest method is coalesce(), but you need to be sure the types match:
SELECT COALESCE(CONVERT(VARCHAR(255), group.TypeId, 'Summary') as TypeId,
. . .
This is not the most general method, because it does not handle real NULL values in the GROUP BY keys. That doesn't seem to be an issue in this case. If it were, you could use a CASE expression with GROUPING().
EDIT:
For your particular variant (which I find strange), you can use:
SELECT (CASE WHEN group.TypeId IS NULL OR group.ZoneID IS NULL
THEN 'Summary' ELSE CONVERT(VARCHAR(255), group.TypeId)
END) as TypeId,
. . .
In practice, I would use something similar to the COALESCE() in both columns, so I don't lose the information on what the summary is for.
I want to create a rank column using existing rank and binary columns. Suppose for example a table with ID, RISK, CONTACT, DATE. The existing rank is RISK, say 1,2,3,NULL, with 3 being the highest. The binary-valued is CONTACT with 0,1 or FAILURE/SUCESS. I want to create a new RANK that will order by RISK once a certain number of successful contacts has been exceeded.
For example, suppose the constraint is a minimum of 2 successful contacts. Then the rank should be created as follows in the two instances below:
Instance 1. Three ID, all have a min of two successful contacts. In that case the rank mirrors the risk:
ID risk contact date rank
1 3 S 1 3
1 3 S 2 3
1 3 F 3 3
1 3 F 4 3
2 2 S 1 2
2 2 S 2 2
2 2 F 3 2
2 2 F 4 2
3 1 S 1 1
3 1 S 2 1
3 1 S 3 1
Instance 2. Suppose ID=1 has only one successful contact. In that case it is relegated to the lowest rank, rank=1, while ID=2 gets the highest value, rank=3, and ID=3 maps to rank=2 because it satisfies the constraint but has a lower risk value than ID=2:
ID risk contact date rank
1 3 S 1 1
1 3 F 2 1
1 3 F 3 1
1 3 F 4 1
2 2 S 1 3
2 2 S 2 3
2 2 F 3 3
2 2 F 4 3
3 1 S 1 2
3 1 S 2 2
3 1 S 3 2
This is SQL, specifically Hive. Thanks in advance.
Edit - I think Gordon Linoff's code does it correctly. In the end, I used three interim tables. The code looks like that:
First,
--numerize risk, contact
select A.* ,
case when A.risk = 'H' then 3
when A.risk = 'M' then 2
when A.risk = 'L' then 1
when A.risk is NULL then NULL
when A.risk = 'NULL' then NULL
else -999 end as RISK_RANK,
case when A.contact = 'Successful' then 1
else NULL end as success
Second,
-- sum_successes_by_risk
select A.* ,
B.sum_successes_by_risk
from T as A
inner join
(select A.person, A.program, A.risk, sum(a.success) as sum_successes_by_risk
from T as A
group by A.person, A.program, A.risk
) as B
on A.program = B.program
and A.person = B.person
and A.risk = B.risk
Third,
--Create table that contains only max risk category
select A.* ,
B.max_risk_rank
from T as A
inner join
(select A.person, max(A.risk_rank) as max_risk_rank
from T as A
group by A.person
) as B
on A.person = B.person
and A.risk_rank = B.max_risk_rank
This is hard to follow, but I think you just want window functions:
select t.*,
(case when sum(case when contact = 'S' then 1 else 0 end) over (partition by id) >= 2
then risk
else 1
end) as new_risk
from t;
The simple question is how can you take a set of records with a PK and create exactly two records for each source with a slightly altered key for the duplicate? In other words, I take 4000 records and produce 8000 records where 4000 are identical and the other 4000 have a slightly altered key. I cannot do a union because this is essentially two selects (long story).
The rest gets complicated, but maybe necessary to provide examples.
This is my original set (it contains over 4000 records)
dateGroup areaGroup itemID editionID
1 1 1 1
1 1 1 2
1 2 1 1
1 2 2 1
2 1 1 1
2 1 1 2
2 2 1 1
2 2 1 2
For each record I need to create a duplicate record ganging the areaGroups together under '0', then create a comma separated list of original areaGroups as a separate field. (The "why" is some dumb programmer (me) made a mistake about 15 years ago.) I can renumber the editionIDs as necessary, but the original and duplicate record must have the same editionID (thus why a union wouldn't work). The PK remains the same as above (all fields)
dateGroup areaGroup itemID editionID aGroups
1 0 1 1 1
1 0 1 2 1
1 0 1 1 2 // Duplicate (EditionID)
1 0 2 1 2
2 0 1 1 1
2 0 1 2 1
2 0 1 1 2 // Duplicate (EditionID)
2 0 1 2 2
The end result would renumber the editionID as needed to make the record unique.
dateGroup areaGroup itemID editionID aGroups (EditionID is what is altered)
1 0 1 1 1
1 0 1 2 1
1 0 1 2 2 1 changed to 2 (one more than row 1)
1 0 2 1 2
2 0 1 1 1
2 0 1 2 1
2 0 1 2 2 1 changed to 2 (one more than row 1)
2 0 1 2 2
1 1 1 1
1 1 1 2
1 2 1 2 1 changed to 2 (editionID) to match
1 2 2 1
2 1 1 1
2 1 1 2
2 2 1 2 1 changed to 2 to match above
2 2 1 2
I know you could calculate the editionID like a row rank like so:
select row_number() over (
partition by dateGroup, itemID
order by dateGroup, itemID) as editionID
So all I need is to know how to duplicate the records from a single set
do a cross join on a derived table:
( select 1 as aGroups union all select 2 )
I'd create a temporary table with duplicates and their count.
Then I'd filter the original table to have only unique rows, and insert another row for each row in the temporary table, incrementing their editionID.
In MySQL, I'd use user #variables; not sure about MS SQL.
Did you try UNION ALL instead of just UNION
UDPATE perhaps I misunderstood the problem and I thought you were having a problem with the union loosing the duplicates.
If the problem is that you want to do a row_number over a union why don't you do somthing like
select row_number() over (
partition by dateGroup, itemID
order by dateGroup, itemID) as editionID
FROM
(
SELECT
dateGroup, itemID
FROM TableA
UNION ALL
SELECT
dateGroup, itemID
FROM TableB
) Data
I've got two tables.
I'm trying to calculating the SUM quantity of tbl1
tbl1.xid is the primary, while tbl2.xid is the foreign
tbl1
xid pub quantity
1 1 10
2 1 2
3 0 1
4 1 5
tbl2
id ttype fno xid qnty
1 A 0 1 0
2 A 1 1 3
3 B 1 1 4
4 A 1 2 1
5 A 1 3 2
6 A 1 4 3
7 A 1 4 1
8 A 0 1 0
We are calculating the sum of tbl1's quantity
1) Whos tbl1.pub is 1
Thus tbl1.xid 3 is removed form the list, for it's pub is 0
Results
tbl1
xid pub quantity
1 1 10
2 1 2
4 1 5
2) AND Who's tbl1 has at least one tbl2.xid who's tbl2.ttype is 'A' and who's tbl2.fno is '0'
Thus tbl1.xid 2 & 4 are removed form the list, because none of them have at least one tbl2.xid who's fno is '0' and who's tbl2.ttype is 'A'
Results
parent_tbl1
xid pub quantity
1 1 10
The final results should be 10
SELECT SUM(quantity) AS Total
FROM tbl1
WHERE pub=1
AND EXISTS
(SELECT *
FROM tbl2
WHERE tbl2.ttype = 'A'
AND tbl2.fno = 0
AND tbl1.xid = tbl2.xid
)