SQL Select Query Giving me duplicate columns - sql

I am trying to write a query to display information, but when I use INNER JOIN I am getting duplicate ID fields. My tables and query are below. I am getting duplicate columns for wrestlerID. could it be my PK constraints?
CREATE TABLE WRESTLER
(
WrestlerID CHAR(6) NOT NULL,
WrestlerFirst VARCHAR2(15) NOT NULL,
WrestlerLast VARCHAR2(25) NOT NULL,
WrestlerStyle CHAR(2) NOT NULL,
WrestleKilos NUMERIC(3,0) NOT NULL,
WrestleMeters NUMERIC(3,2),
WrestleCity VARCHAR2(40) NOT NULL,
WrestlerState CHAR(2) NOT NULL,
WrestlerBirthdate Date,
CONSTRAINT WRESTLER_PK PRIMARY KEY (WrestlerID)
);
CREATE TABLE CLUB
(
ClubID CHAR(5) NOT NULL,
Club VARCHAR2(35) NOT NULL,
WrestlerID CHAR(6) NOT NULL,
CONSTRAINT CLUB_PK PRIMARY KEY (ClubID, WrestlerID),
CONSTRAINT CLUB_FK
FOREIGN KEY (WrestlerID) REFERENCES WRESTLER(WrestlerID)
);
CREATE TABLE SCHOOL
(
SchoolID VARCHAR2(10) NOT NULL,
School VARCHAR2(35) NOT NULL,
WrestlerID CHAR(6) NOT NULL,
CONSTRAINT SCHOOL_PK PRIMARY KEY (SchoolID, WrestlerID),
CONSTRAINT SCHOOL_FK
FOREIGN KEY (WrestlerID) REFERENCES WRESTLER(WrestlerID)
);
CREATE TABLE MEDAL
(
WrestlerID CHAR(6) NOT NULL,
WorldMedal NUMERIC(4,0),
CONSTRAINT MEDAL_PK PRIMARY KEY (WrestlerID, WorldMedal),
CONSTRAINT MEDAL_FK
FOREIGN KEY (WrestlerID) REFERENCES WRESTLER(WrestlerID)
);
SELECT
t1.WrestlerID, t1.WrestlerFirst, t1.WrestlerLast,
t2.WrestlerID, t2.School,
t2.WrestlerID, t3.Club
FROM
WRESTLER t1
INNER JOIN
SCHOOL t2 ON t1.WrestlerID = t2.WrestlerID
INNER JOIN
CLUB t3 ON t1.WrestlerID = t3.WrestlerID;

Fixing my query worked
SELECT
t1.WrestlerID, t1.WrestlerFirst, t1.WrestlerLast,
t2.School,
t3.Club FROM
WRESTLER t1 INNER JOIN
SCHOOL t2 on t1.WrestlerID = t2.WrestlerID INNER JOIN
CLUB t3 on t1.WrestlerID = t3.WrestlerID;

Related

SQL Missing left/right parenthesis

I keep getting a missing right or left parenthesis error when I try to create my tables with a foreign key, but when I remove the foreign key my code has no problem creating the tables. I need the code to run with the foreign keys.
--deletes respective tables previously created
drop table DEPARTMENT;
drop table POSITION;
drop table EMPLOYEE;
drop table COMPANY;
drop table DEGREE;
drop table GRAD_INFO;
drop table STUDENT;
CREATE TABLE Department
(
Dept_Name varchar(255) PRIMARY KEY, --primary key
Dept_Phone_Num numeric(35) not null
);
CREATE TABLE Position
(
Position_Name varchar(255) NOT NULL PRIMARY KEY, --primary key
Position_Salary decimal(10, 2) not null,
Employee_num numeric(35) not null,
CONSTRAINT fk_Dept_Name
FOREIGN KEY Dept_Name REFERENCES Department (Dept_Name) --foreign key
);
CREATE TABLE Employee
(
EmployeeID INT NOT NULL PRIMARY KEY, --primary key
Employee_Salary DECIMAL(10,2) DEFAULT NULL,
Employee_FName VARCHAR(30) DEFAULT NULL,
Employee_LName VARCHAR(30) NOT NULL,
Employee_Address VARCHAR(30) DEFAULT NULL,
Employee_Phone_Num INT(10) DEFAULT NULL,
Employee_Email VARCHAR(30) NOT NULL,
Employee_Status VARCHAR(10) NOT NULL,
CONSTRAINT Position_Name
FOREIGN KEY Position_Name REFERENCES Position(Position_Name), --foreign key
CONSTRAINT fk_Dept_Name
FOREIGN KEY Dept_Name REFERENCES Department(Dept_Name) --foreign key
);
CREATE TABLE Company
(
Comp_Name VARCHAR(20) NOT NULL PRIMARY KEY, --primary key
Position_Offer VARCHAR(30) NOT NULL,
Salary_Offer DECIMAL(10,2) NOT NULL,
Signing_Bonus DECIMAL(10,2) DEFAULT NULL,
Comp_Phone_Num INT(10) NOT NULL,
Comp_Address VARCHAR(30) NOT NULL,
CONSTRAINT fk_Employee_ID
FOREIGN KEY Employee_ID REFERENCES Employee (Employee_ID), --foreign key
CONSTRAINT fk_Dept_Name
FOREIGN KEY Dept_Name REFERENCES Department (Dept_Name) --foreign key
);
CREATE TABLE Degree
(
Degree_Type varchar(255) PRIMARY KEY, --primary key
Academic_Status varchar(255) not null,
Academic_Level varchar(255) not null,
Major varchar(255) not null,
Minor varchar(255) default null
);
CREATE TABLE Gead_Info
(
Grad_Status VARCHAR(255) NOT NULL PRIMARY KEY, --primary key
College_Name VARCHAR(255) NOT NULL,
Num_Of_Degrees NUMERIC(10) NOT NULL,
Grad_Date NUMERIC(6) NOT NULL,
CONSTRAINT fk_Degree_Type
FOREIGN KEY Degree_Type REFERENCES Degree(Degree_Type) --foreign key
);
CREATE TABLE Student
(
Student_ID NUMERIC(10) NOT NULL PRIMARY KEY, --primary key
Student_FName VARCHAR(20) NOT NULL,
Student_LName VARCHAR(20) NOT NULL,
Student_Address VARCHAR(20) NOT NULL,
Student_Email VARCHAR(20) NOT NULL,
Student_Phone_Num VARCHAR(10) NOT NULL,
CONSTRAINT fk_Comp_Name
FOREIGN KEY Comp_Name REFERENCES Company(Comp_Name), --foreign key
CONSTRAINT fk_Grad_Status
FOREIGN KEY Grad_Status REFERENCES Gead_Info(Grad_Status) --foreign key
);
The degree table is the only table where I don't get an error.
Should I use an alter table instead after I create all the tables or is there another way to solve my problem?
edit: updated code
I think your most immediate issue is with the Department table not having a comma between the two CONSTRAINT clauses. You might also run into issues with your Position table's CONSTRAINT clause referencing the Position table instead of the Employee table, although honestly I don't think you need that relationship defined at all since the Employee table already has a foreign key constraint with Position. And like what was stated earlier, your table definitions aren't in the right order so you have some tables referencing other tables before those others are created.
Give this a shot to see if the syntax works. I've added the column definition for the foreign key in Position, put parentheses around the foreign key column name in the CONSTRAINT clause, and removed the space between Department and the left paren in the CONSTRAINT clause. If this script works, make the same changes to your other table defs.
CREATE TABLE Department(
Dept_Name varchar(255) Primary Key, --primary key
Dept_Phone_Num numeric(35) not null
);
CREATE TABLE Position(
Position_Name varchar(255) not null Primary Key, --primary key
Position_Salary decimal(10, 2) not null,
Employee_num numeric(35) not null,
Dept_Name varchar(255) not null,
CONSTRAINT fk_Dept_Name FOREIGN KEY (Dept_Name) REFERENCES Department(Dept_Name) --foreign key
);

Restricting values in a table used in a FULL OUTER JOIN

This concerns Oracle SQL.
Considering the following 3 tables:
TRIP_SEGMENT:
CREATE TABLE TRIP_SEGMENT(
SEG_ID NUMBER(6) NOT NULL,
DIRECTION VARCHAR(8) NOT NULL,
DEPARTURE_LOCATION VARCHAR(50) NOT NULL,
DESTINATION VARCHAR(50) NOT NULL,
SEGMENT_PRICE NUMBER(5,2) NULL,
TRIP_ID NUMBER(6) NOT NULL,
CONSTRAINT chk_SEG_DIRECTION CHECK (DIRECTION IN ('Outbound','Inbound')),
CONSTRAINT pk_SEGMENT PRIMARY KEY (SEG_ID),
CONSTRAINT fk_TRIP_ID FOREIGN KEY (TRIP_ID) REFERENCES TRIP(TRIP_ID)
);
TRANSPORTATION:
CREATE TABLE TRANSPORTATION(
TRANSP_BOOK_ID NUMBER(6) NOT NULL,
TRANSP_PRICE NUMBER(5,2) NULL,
DEPARTURE_DATE DATE NULL,
ARRIVAL_DATE DATE NULL,
EXT_BOOK_ID NUMBER(6) NULL,
SEG_ID NUMBER(6) NOT NULL,
SERV_TYPE_ID NUMBER(3) NOT NULL,
PARTNER_ID NUMBER(3) NULL,
CONSTRAINT pk_TRANSP_BOOK_ID PRIMARY KEY (TRANSP_BOOK_ID),
CONSTRAINT fk_TRANSP_SEG_ID FOREIGN KEY (SEG_ID) REFERENCES TRIP_SEGMENT(SEG_ID),
CONSTRAINT fk_TRANSP_SERV_ID FOREIGN KEY (SERV_TYPE_ID) REFERENCES SERVICE_TYPE(SERV_TYPE_ID),
CONSTRAINT fk_TRANSP_PARTNER_ID FOREIGN KEY (PARTNER_ID) REFERENCES PARTNER(PARTNER_ID)
);
PARTNER:
CREATE TABLE PARTNER(
PARTNER_ID NUMBER(3) NOT NULL,
PARTNER_NAME VARCHAR(50) NOT NULL,
CONTACT_FNAME VARCHAR(20) NOT NULL,
CONTACT_LNAME VARCHAR(20) NOT NULL,
ADDRESS VARCHAR(100) NULL,
PHONE_NO NUMBER(20) NOT NULL,
EMAIL VARCHAR(50) NULL,
SERV_TYPE_ID NUMBER(3) NOT NULL,
CONSTRAINT pk_PARTNER_ID PRIMARY KEY (PARTNER_ID),
CONSTRAINT fk_PART_SERV_ID FOREIGN KEY (SERV_TYPE_ID) REFERENCES SERVICE_TYPE(SERV_TYPE_ID)
);
I wanted to create a FULL OUTER JOIN like this:
SELECT TS.SEG_ID, TS.DEPARTURE_LOCATION, TS.DESTINATION, P.PARTNER_NAME
FROM TRIP_SEGMENT TS
FULL OUTER JOIN TRANSPORTATION T
ON TS.SEG_ID = T.SEG_ID
FULL OUTER JOIN PARTNER P
ON T.PARTNER_ID = P.PARTNER_ID;
...but have it restricted to PARTNER.PARTNER_ID < 6. If I just add a WHERE clause at the end of the JOIN, this will restrict all the values to those where there is an association with PARTNER.PARTNER_ID < 6, therefore defeating the purpose of the FULL OUTER JOIN.
So far, I've come up with this solution:
First, create a table that only contains PARTNER.PARTNER_ID < 6 :
CREATE TABLE TRANSPORTATION_PARTNER AS SELECT * FROM PARTNER WHERE PARTNER_ID < 6;
Then, use that table in the FULL OUTER JOIN instead:
SELECT TS.SEG_ID, TS.DEPARTURE_LOCATION, TS.DESTINATION, TP.PARTNER_NAME
FROM TRIP_SEGMENT TS
FULL OUTER JOIN TRANSPORTATION T
ON TS.SEG_ID = T.SEG_ID
FULL OUTER JOIN TRANSPORTATION_PARTNER TP
ON T.PARTNER_ID = TP.PARTNER_ID;
This works fine and it demonstrates what I'm trying to achieve, however I was wondering if there is a way of doing in one single query AND using a subquery.
Thank you!
YES, just do something like :
SELECT TS.SEG_ID, TS.DEPARTURE_LOCATION, TS.DESTINATION, P.PARTNER_NAME
FROM TRIP_SEGMENT TS
FULL OUTER JOIN TRANSPORTATION T
ON TS.SEG_ID = T.SEG_ID
FULL OUTER JOIN (SELECT *
FROM PARTNER
WHERE PARTNER.PARTNER_ID < 6) P
ON T.PARTNER_ID = P.PARTNER_ID;
You are placing restrictions on the rows to be selected so you can use LEFT JOIN instead of the FULL OUTER JOIN. Try something like
SELECT TS.SEG_ID, TS.DEPARTURE_LOCATION, TS.DESTINATION, P.PARTNER_NAME
FROM TRIP_SEGMENT TS
FULL OUTER JOIN TRANSPORTATION T
ON TS.SEG_ID = T.SEG_ID
LEFT OUTER JOIN PARTNER P
ON T.PARTNER_ID = P.PARTNER_ID AND P.Partner_ID = 6;

Retrieve Data from Different Tables (SQL Server)

I have 4 tables in a SQL Server database with following schema:
Attendance
CREATE TABLE [dbo].[Attendance] (
[AttendanceId] UNIQUEIDENTIFIER DEFAULT (newid()) NOT NULL,
[CourseId] UNIQUEIDENTIFIER NOT NULL,
[StudentId] UNIQUEIDENTIFIER NOT NULL,
[SubjectId] UNIQUEIDENTIFIER NOT NULL,
[Semester] INT NOT NULL,
[Month] NVARCHAR (50) NOT NULL,
[Count] INT NOT NULL,
CONSTRAINT [PK_Attendance] PRIMARY KEY NONCLUSTERED ([AttendanceId] ASC),
CONSTRAINT [FK_Attendance_Student] FOREIGN KEY ([StudentId]) REFERENCES [dbo].[Student] ([StudentId]) );
Course
CREATE TABLE [dbo].[Course] (
[CourseId] UNIQUEIDENTIFIER DEFAULT (newid()) NOT NULL,
[Name] NVARCHAR (50) NOT NULL,
CONSTRAINT [PK_Course] PRIMARY KEY NONCLUSTERED ([CourseId] ASC)
);
Student
CREATE TABLE [dbo].[Student] (
[StudentId] UNIQUEIDENTIFIER DEFAULT (newid()) NOT NULL,
[CourseId] UNIQUEIDENTIFIER NOT NULL,
[Name] NVARCHAR (100) NOT NULL,
[RollNo] INT NOT NULL,
[Semester] INT NOT NULL,
CONSTRAINT [PK_Student] PRIMARY KEY NONCLUSTERED ([StudentId] ASC),
CONSTRAINT [FK_Student_Course] FOREIGN KEY ([CourseId]) REFERENCES [dbo].[Course] ([CourseId])
);
Subject
CREATE TABLE [dbo].[Subject] (
[SubjectId] UNIQUEIDENTIFIER DEFAULT (newid()) NOT NULL,
[CourseId] UNIQUEIDENTIFIER NOT NULL,
[Name] NVARCHAR (100) NOT NULL,
[Semester] INT NOT NULL,
CONSTRAINT [PK_Subject] PRIMARY KEY NONCLUSTERED ([SubjectId] ASC),
CONSTRAINT [FK_Subject_Course] FOREIGN KEY ([CourseId]) REFERENCES [dbo].[Course] ([CourseId])
);
I need to create a attendance report in the following format:
Course Name | Student Name | Subject Name | Semester | Month | Count
Please tell me what SQL Query I need to use and if there's any change in schema required then suggest the same.
I'm looking forward to have your replies.
Thanks,
You need to use a JOIN in your query so that it only returns rows which match a [StudentId] from the Attendance table.
e.g.
SELECT c.CourseName, s.StudentName, u.SubjectName, u.Semester, a.Month, a.Count
FROM Student s
JOIN Attendance a ON s.StudentId = a.StudentId
JOIN Course c ON a.CourseId = c.CourseId
JOIN Subject u ON c.CourseId = u.CourseId
Something along these lines will only return rows which specifically match

Need help in the query (oracle 11 g)

First of all, these are my create_table statements.
/*--- Base tables ---*/
CREATE TABLE CUSTOMER (
CUST_ID VARCHAR(10) NOT NULL,
CUST_FNAME VARCHAR(15),
CUST_LNAME VARCHAR(15),
CUST_HP NUMBER(10),
CUST_EMAIL VARCHAR(40),
primary key (CUST_ID)
);
CREATE TABLE STAFF(
STAFF_ID NUMBER(12) NOT NULL,
STAFF_FNAME VARCHAR(15),
STAFF_LNAME VARCHAR(15),
STAFF_DOB Date,
STAFF_AGE NUMBER(2),
STAFF_ADDRESS VARCHAR(70),
STAFF_HP NUMBER(10),
STAFF_SALARY NUMBER(6,2),
primary key (STAFF_ID)
);
CREATE TABLE SUPPLIER(
SUPP_ID VARCHAR(10) NOT NULL,
SUPP_NAME VARCHAR(30),
SUPP_TEL NUMBER(10),
SUPP_EMAIL VARCHAR(25),
SUPP_ADDRESS VARCHAR(80),
SUPP_CITY VARCHAR(20),
SUPP_STATE VARCHAR(10),
SUPP_ZIP NUMBER(5),
primary key (SUPP_ID)
);
CREATE TABLE PRODUCT(
PROD_ID VARCHAR(10) NOT NULL,
PROD_NAME VARCHAR(30),
PROD_DESC VARCHAR(70),
R_UNIT_PRICE NUMBER(3,2) DEFAULT 4.50,
L_UNIT_PRICE NUMBER(3,2) DEFAULT 5.00,
primary key (PROD_ID)
);
CREATE TABLE INGREDIENT(
ING_ID VARCHAR(10) NOT NULL,
ING_NAME VARCHAR(20),
ING_DESC VARCHAR(60),
primary key (ING_ID)
);
CREATE TABLE TOPPING(
TOP_ID VARCHAR(10) NOT NULL,
TOP_NAME VARCHAR(20),
TOP_DESC VARCHAR(40),
TOP_PRICE NUMBER(2,2),
primary key (TOP_ID)
);
/*--- Child tables ---*/
CREATE TABLE ORDERS(
ORDERS_ID VARCHAR(10) NOT NULL,
CUST_ID VARCHAR(10) NOT NULL,
STAFF_ID NUMBER(12) NOT NULL,
TOTAL_PRICE NUMBER(5,2),
ORDERS_DATE DATE,
primary key (ORDERS_ID),
foreign key (CUST_ID) references CUSTOMER(CUST_ID),
foreign key (STAFF_ID) references STAFF(STAFF_ID)
);
CREATE TABLE ORD_DETAIL(
SK1_ID NUMBER(4) NOT NULL,
ORDERS_ID VARCHAR(10) NOT NULL,
PROD_ID VARCHAR(10) NOT NULL,
TOP_ID VARCHAR(10) NOT NULL,
TEATYPE VARCHAR(8),
CUPSIZE CHAR(1),
QTY NUMBER(2),
CONSTRAINT CHK_CUPSIZE CHECK (CUPSIZE = 'R' OR CUPSIZE = 'L'),
CONSTRAINT CHK_TEATYPE CHECK (TEATYPE = 'Oolong' OR TEATYPE = 'Jasmine'),
primary key (SK1_ID),
foreign key (ORDERS_ID) references ORDERS(ORDERS_ID),
foreign key (PROD_ID) references PRODUCT(PROD_ID),
foreign key (TOP_ID) references TOPPING(TOP_ID)
);
CREATE TABLE PROD_ING(
PROD_ID VARCHAR(10) NOT NULL,
ING_ID VARCHAR(10) NOT NULL,
primary key (PROD_ID , ING_ID),
foreign key (PROD_ID) references PRODUCT(PROD_ID),
foreign key (ING_ID) references INGREDIENT(ING_ID)
);
CREATE TABLE ING_SUPP(
ING_ID VARCHAR(10) NOT NULL,
SUPP_ID VARCHAR(10) NOT NULL,
SUPP_PRICE NUMBER(6,2),
primary key (ING_ID, SUPP_ID),
foreign key (ING_ID) references INGREDIENT(ING_ID),
foreign key (SUPP_ID) references SUPPLIER(SUPP_ID)
);
And my query is this:Which employee served the most number of customers?
But when I executed these statements:
SELECT MAX (COUNT (O.CUST_ID)) AS "Served customer"
FROM STAFF S, ORDERS O
WHERE (S.STAFF_ID = O.STAFF_ID)
GROUP BY O.STAFF_ID
HAVING COUNT (O.CUST_ID) > 0;
What I got was there was a column named "Served customer" with the maximum number only.
So, now my question is how to display the employee's ID, first name and last name along with
"Served customer" column.
The question is: "Which employee served the most number of customers? " Your query does not even return information about the employee, only about the number of customers.
The following aggregation returns for each staff member, the number of customers who were served:
SELECT O.STAFF_ID, COUNT(O.CUST_ID) AS "Served customer"
FROM STAFF SS JOIN
ORDERS O
ON S.STAFF_ID = O.STAFF_ID
GROUP BY O.STAFF_ID;
To get the maximum number we just need to order this by the count and take the first row. In Oracle, this uses a subquery:
SELECT so.*
FROM (SELECT O.STAFF_ID, COUNT(O.CUST_ID) AS "Served customer"
FROM STAFF SS JOIN
ORDERS O
ON S.STAFF_ID = O.STAFF_ID
GROUP BY O.STAFF_ID
ORDER BY COUNT(O.CUST_ID) DESC
) so
WHERE rownum = 1;

sqlplus using of sub query

I have 3 tables, and have to find out the applicant number, name and total number of position each applicant applied for.
CREATE TABLE APP (
appNum varchar2(10) not null,
appName varchar2(70),
constraint applicant_Pkey primary key (appNum)
);
CREATE TABLE POS (
posNum varchar2(10) not null,
posStartOfferDt date not null,
constraint pos_Pkey primary key (posNum, posStartOfferDt)
);
CREATE TABLE APPLICATION (
appcnPosNum varchar2(10) not null,
appcnPosStOffrDt date not null,
appcnAppNum varchar2(10) not null,
appcnDt date,
constraint application_Pkey primary key (appcnPosNum, appcnPosStOffrDt, appcnAppNum),
constraint application_Fkey1 foreign key (appcnPosNum, appcnPosStOffrDt) references POSITION(posNum, posStartOfferDt),
constraint application_Fkey2 foreign key (appcnAppNum) references APPLICANT(appNum)
);
I have tried using sub query, natural join but all not working out for me.
SELECT appNum, appName, COUNT(*)
FROM applicant
JOIN application ON applicant.appNum = application.appcnAppNum
GROUP BY appNum, appName