Split and calculate string vb.net - vb.net

I have kind of difficult question.
I have a a string like
2021-09-24 00:52:27
2021-09-23 03:46:08
2021-09-22 04:13:03
2021-09-21 04:08:02
2021-09-20 02:13:27
2021-09-19 05:27:38
2021-09-18 03:43:32
2021-09-17 03:23:44
I need to count the timespan of a last week.
The thing the string not always will be the last 7 days
so i made a string to get the last 7 days and compare them and if a line isnat matching the date it will be 00:00:00,
before that i splited the string.
before that i declared X as a number of lines in the string
2021-09-24
2021-09-23
2021-09-22
2021-09-21
2021-09-20
2021-09-19
2021-09-18
2021-09-17
00:52:27
03:46:08
04:13:03
04:08:02
02:13:27
05:27:38
03:43:32
03:23:44
Dim x As String = RichTextBox4.Lines.Count ' The number of lines with date and hours together
Dim a1 As String = Date.Now.ToString("yyyy-MM") ' Creating dates for the last 7 days
Dim a2 As String = Date.Now.ToString("dd")
Dim b1 As String = Date.Now.ToString("yyyy-MM")
Dim b2 As String = Date.Now.ToString("dd") - 1
Dim c1 As String = Date.Now.ToString("yyyy-MM")
Dim c2 As String = Date.Now.ToString("dd") - 2
Dim dd1 As String = Date.Now.ToString("yyyy-MM")
Dim dd2 As String = Date.Now.ToString("dd") - 3
Dim e1 As String = Date.Now.ToString("yyyy-MM")
Dim e2 As String = Date.Now.ToString("dd") - 4
Dim f1 As String = Date.Now.ToString("yyyy-MM")
Dim f2 As String = Date.Now.ToString("dd") - 5
Dim g1 As String = Date.Now.ToString("yyyy-MM")
Dim g2 As String = Date.Now.ToString("dd") - 6
Dim d1 As String = a1 + "-" + a2
Dim d2 As String = b1 + "-" + b2
Dim d3 As String = c1 + "-" + c2
Dim d4 As String = dd1 + "-" + dd2
Dim d5 As String = e1 + "-" + e2
Dim d6 As String = f1 + "-" + f2
Dim d7 As String = g1 + "-" + g2
Dim lines11 = RichTextBox4.Lines
Dim modifiedLines11 = New List(Of String)()
For index11 As Integer = 0 To lines11.Length - 1
Dim url11 = lines11(index11).Substring(lines11(index11).LastIndexOf(" "c))
modifiedLines11.Insert(index11, lines11(index11).Replace(url11, String.Empty))
modifiedLines11.Add(url11)
RichTextBox4.Text = String.Join(Environment.NewLine, modifiedLines11)
Next
' after split to 2 lists in string
Dim o1 As String = RichTextBox4.Lines(0) ' The first lines of the string is the dates
Dim o2 As String = RichTextBox4.Lines(1)
Dim o3 As String = RichTextBox4.Lines(2)
Dim o4 As String = RichTextBox4.Lines(3)
Dim o5 As String = RichTextBox4.Lines(4)
Dim o6 As String = RichTextBox4.Lines(5)
Dim o7 As String = RichTextBox4.Lines(6)
Dim l1 As String ' This is the second list in the string those are the times
Dim l2 As String
Dim l3 As String
Dim l4 As String
Dim l5 As String
Dim l6 As String
Dim l7 As String
here im trying to compare it to the actual date and if isnt it will give me 00:00:00.
If o1 = d1 Then
l1 = RichTextBox4.Lines(x)
Else
l1 = "00:00:00"
If o2 = d2 Then
l2 = RichTextBox4.Lines(x + 1)
Else
l2 = "00:00:00"
If o3 = d3 Then
l3 = RichTextBox4.Lines(x + 2)
Else
l3 = "00:00:00"
If o4 = d4 Then
l4 = RichTextBox4.Lines(x + 3)
Else
l4 = "00:00:00"
If o5 = o5 Then
l5 = RichTextBox4.Lines(x + 4)
Else
l5 = "00:00:00"
If o6 = d6 Then
l6 = RichTextBox4.Lines(x + 5)
Else
l6 = "00:00:00"
If o7 = d7 Then
l7 = RichTextBox4.Lines(x + 6)
Else
l7 = "00:00:00"
End If
End If
End If
End If
End If
End If
End If
' here im trying to calculate the time.
Dim ts1 As TimeSpan = TimeSpan.Parse(l1)
Dim ts2 As TimeSpan = TimeSpan.Parse(l2)
Dim ts3 As TimeSpan = TimeSpan.Parse(l3)
Dim ts4 As TimeSpan = TimeSpan.Parse(l4)
Dim ts5 As TimeSpan = TimeSpan.Parse(l5)
Dim ts6 As TimeSpan = TimeSpan.Parse(l6)
Dim ts7 As TimeSpan = TimeSpan.Parse(l7)
Dim ttsum As TimeSpan = ts1 + ts2 + ts3 + ts4 + ts5 + ts6 + ts7
MsgBox(ttsum.ToString)
In my opinion the porblem with the code is or the method is bad or the if statements arent good with this method.

Since I don't see any AM/PM data, I am assuming the data in the rich text box is in 24 hour format.
Your code is so complicated because you are manipulate strings instead of dealing with dates. If you want to compare dates and manipulate dates, the first thing you need to do is turn your strings into dates. Since we do not know how many items we are dealing with we will use List(Of T).
Private Function GetListOfDates() As List(Of Date)
Dim lst As New List(Of Date)
Dim provider As CultureInfo = CultureInfo.InvariantCulture
For Each line In RichTextBox1.Lines
' 2021-09-17 03:23:44
lst.Add(Date.ParseExact(line, "yyyy-MM-dd hh:mm:ss", provider))
Next
Return lst
End Function
Next you need to filter the list for last week. For your purposes, a day starts as 00:00:00 and ends at 23:59:59
Private Function FilterListForLastWeek(lst As List(Of Date)) As List(Of Date)
Dim DatesInWeek As New List(Of Date)
'I hardcoded the following date to work with your sample data
Dim LastDayOfWeek = New Date(2021, 9, 24, 23, 59, 59)
'You would use the following code in the real version
'Dim LastDayOfWeek = New Date(Date.Now.Year, Date.Now.Month, Date.Now.Day, 23, 59, 59)
Debug.Print(LastDayOfWeek.ToString)
Dim FirstDayOfWeek = LastDayOfWeek.AddDays(-6)
FirstDayOfWeek = New Date(FirstDayOfWeek.Year, FirstDayOfWeek.Month, FirstDayOfWeek.Day, 0, 0, 0)
Debug.Print(FirstDayOfWeek.ToString)
For Each d In lst
If d >= FirstDayOfWeek AndAlso d <= LastDayOfWeek Then
DatesInWeek.Add(d)
End If
Next
Return DatesInWeek
End Function
It looks like you are considering the hour, minute, second portion of the date as a time span. To add TimeSpan you use the Add method. The last date in the data from the rich text box (the 17th) is excluded since it is not in the week (days 18-24 inclusive is 7 days). The message box displays 1:00:24:17 which is 1 day, zero hours, 24 minutes, and 17 seconds. You can also display as TotalHours, TotalMinutes, etc..
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim AllDates = GetListOfDates()
Dim DatesInWeek = FilterListForLastWeek(AllDates)
Dim TimeSpanSum As TimeSpan
For Each d In DatesInWeek
TimeSpanSum = TimeSpanSum.Add(New TimeSpan(d.Hour, d.Minute, d.Second))
Next
MessageBox.Show(TimeSpanSum.ToString)
End Sub

Related

I have problem that says System.Security.Cryptography.CryptographicException: 'Bad Data. ' in vb.net when trying to import RSA parameters

Here's the code I am not sure if there's any hidden error but on runtime when trying to import the rsa parameters it pops up that error
Imports System.Security.Cryptography
Imports System.Security
Imports System.Text
Imports System.IO
Public Class RSA_Test_Form
Public FactorList As New List(Of Integer)
Public FindFactor As Long
Public PString, QString, ModulusString, ExponentString, DString, DPString,
DQString, InverseQString As String
Function ModInverse(ByVal a As Long, ByVal b As Long) As Long
Dim b0 As Long = b
Dim t As Long
Dim q As Long
Dim x0 As Long = 0
Dim x1 As Long = 1
If b = 1 Then Return 1
While a > 1
q = a \ b
t = b
b = a Mod b
a = t
t = x0
x0 = x1 - q * x0
x1 = t
End While
If x1 < 0 Then x1 += b0
Return x1
End Function
Function gcd(ByVal n1 As Long, ByVal n2 As Long) As Long
Dim i As Integer
Dim minimum As Integer
If n1 < n2 Then
minimum = n1
Else
minimum = n2
End If
For i = minimum To 1 Step -1
If n1 Mod i = 0 And n2 Mod i = 0 Then
Return i
End If
Next
Return gcd
End Function
Sub FindFactorFunction()
Dim x As Long
For x = 2 To FindFactor - 1
If FindFactor Mod x = 0 Then
FactorList.Add(x)
End If
Next
End Sub
Private Sub GenerateBTN_Click(sender As Object, e As EventArgs) Handles GenerateBTN.Click
Dim Result As Long = 0
Dim Result2 As Long = 0
Dim Result3 As Long = 0
Dim Random1, Random2 As New Random()
Dim P, Q, Modulus As Long
Dim Exponent, D, DP, DQ As New Nullable(Of Long)
Dim InverseQ As New Nullable(Of ULong)
Dim Modulus1 As Long = 0
Dim LoopCount As Integer = 0
Dim ls, ls2 As New List(Of Long)
Dim PrimeString As String
PrimeString = ""
Using MyNewStreamReader As StreamReader = New StreamReader("AllPrimes.txt")
PrimeString = MyNewStreamReader.ReadLine().ToString
MessageBox.Show(PrimeString)
While PrimeString <> "" And LoopCount <= 1249
ls.Add(Long.Parse(PrimeString))
LoopCount += 1
PrimeString = ""
PrimeString = MyNewStreamReader.ReadLine
End While
End Using
Using MyNewStreamReader2 As StreamReader = New StreamReader("AllPrimes.txt")
PrimeString = ""
PrimeString = MyNewStreamReader2.ReadLine().ToString
LoopCount = 0
MessageBox.Show(PrimeString)
While PrimeString <> ""
If LoopCount >= 1250 And LoopCount <= 2499 Then
ls2.Add(Long.Parse(PrimeString))
End If
LoopCount += 1
PrimeString = ""
PrimeString = MyNewStreamReader2.ReadLine
End While
End Using
Dim rand = Random1.Next(0, ls.Count)
Dim rand2 = Random2.Next(0, ls2.Count)
P = ls(rand)
Q = ls2(rand2)
Result3 = gcd(P, Q)
While Result3 <> 1
rand = Random1.Next(0, ls.Count)
rand2 = Random2.Next(0, ls2.Count)
P = ls(rand)
Q = ls2(rand2)
Result3 = gcd(P, Q)
End While
MessageBox.Show("P= " & P & "Q= " & Q)
Modulus = (P - 1) * (Q - 1)
Modulus1 = Modulus + 1
FindFactor = Modulus1
FindFactorFunction()
Dim Count As Integer = 0
Dim Count2 As Integer = 0
For A As Integer = 0 To FactorList.Count - 1
Result = gcd(FactorList.ElementAt(A), Modulus)
If Result = 1 Then
Count += 1
End If
Next
Dim PositionArray(Count) As Integer
Count = 0
For A As Integer = 0 To FactorList.Count - 1
Result = gcd(FactorList.ElementAt(A), Modulus)
If Result = 1 Then
PositionArray(Count) = FactorList.ElementAt(A)
Count += 1
End If
Next
Dim Number1, Number2 As Long
Dim GetResult As Boolean = False
Count = 0
If PositionArray.Count = 2 Then
Exponent = PositionArray(0)
D = PositionArray(1)
Else
While GetResult = False And Count <> PositionArray.Count
For Count = 0 To PositionArray.Count - 1
For Count2 = Count + 1 To PositionArray.Count - 1
Number1 = PositionArray(Count)
Number2 = PositionArray(Count2)
Result2 = Number1 * Number2 Mod Modulus
If Result2 = 1 Then
GetResult = True
End If
If GetResult = True Then
Exit While
End If
Next
Next
End While
End If
Dim Selection As Integer = MessageBox.Show(Number1 & "=E And D= " & Number2, "Information", MessageBoxButtons.OKCancel, MessageBoxIcon.Information)
If Selection = DialogResult.OK Then
Exponent = Number1
D = Number2
DP = D * P
DQ = D * Q
InverseQ = ModInverse(Q, P)
MessageBox.Show("DP= " & DP)
MessageBox.Show("DQ= " & DQ)
MessageBox.Show("InverseQ= " & InverseQ)
In here when generating RSA numbers, I can not always get the correct numbers so i am using this website to check that i have get the correct RSA numbers and the D and Exponent was not = 0
Exponent=e
Everytime I get Exponent and D, I will always use this website to check P,Q,Exponent and D to make sure it's correct
https://www.cs.drexel.edu/~jpopyack/IntroCS/HW/RSAWorksheet.html
End If
If Exponent.HasValue And D.HasValue Then
PString = P.ToString
QString = Q.ToString
ModulusString = Modulus.ToString
ExponentString = Exponent.ToString
DString = D.ToString
DPString = DP.ToString
DQString = DQ.ToString
InverseQString = InverseQ.ToString
In here all D,P,Q,DP,DQ,Exponent,Modulus,InverseQ value has been calculated and checked
End If
End Sub
Private Sub Number2ByteConverterBTN_Click(sender As Object, e As EventArgs) Handles Number2ByteConverterBTN.Click
If it's possible try check the coding here, perhaps this place was the place that i do it wrongly
I initially thought of using BitCoverter.GetBytes() to convert the long and Ulong datatype value
But in the end, the bitconverter.getbytes() doesn't work for me so i have to first convert all those long and ulong data type values into string then use BYTE.PARSE() to convert the string into byte value
That's how i do it
If let's any experts here confirmed that the coding above worked and all the values are correct then try to check is there any potential error here
Dim PByte, QByte, ModulusByte, ExponentByte, DByte, DPByte, DQByte, InverseQByte As Byte()
ReDim PByte(PString.Count)
ReDim QByte(QString.Count)
ReDim ModulusByte(ModulusString.Count)
ReDim ExponentByte(ExponentString.Count)
ReDim DByte(DString.Count)
ReDim DPByte(DPString.Count)
ReDim DQByte(DQString.Count)
ReDim InverseQByte(InverseQString.Count)
Dim TempPByte, TempQByte, TempModulusByte, TempExponentByte, TempDByte As New Byte
Dim StringBuilder As New StringBuilder
Dim StringBuilder2 As New StringBuilder
Dim StringBuilder3 As New StringBuilder
Dim StringBuilder4 As New StringBuilder
Dim StringBuilder5 As New StringBuilder
Dim StringBuilder6 As New StringBuilder
Dim StringBuilder7 As New StringBuilder
Dim StringBuilder8 As New StringBuilder
For i As Integer = 0 To PString.Length - 1
PByte(i) = Byte.Parse(PString.ElementAt(i))
StringBuilder.Append(PByte(i).ToString)
Next
For i As Integer = 0 To QString.Length - 1
QByte(i) = Byte.Parse(QString.ElementAt(i))
StringBuilder2.Append(QByte(i).ToString)
Next
For i As Integer = 0 To ModulusString.Length - 1
ModulusByte(i) = Byte.Parse(ModulusString.ElementAt(i))
StringBuilder3.Append(ModulusByte(i).ToString)
Next
For i As Integer = 0 To ExponentString.Length - 1
ExponentByte(i) = Byte.Parse(ExponentString.ElementAt(i))
StringBuilder4.Append(ExponentByte(i).ToString)
Next
For i As Integer = 0 To DString.Length - 1
DByte(i) = Byte.Parse(DString.ElementAt(i))
StringBuilder5.Append(DByte(i).ToString)
Next
For i As Integer = 0 To DPString.Length - 1
DPByte(i) = Byte.Parse(DPString.ElementAt(i))
StringBuilder6.Append(DPByte(i).ToString)
Next
For i As Integer = 0 To DQString.Length - 1
DQByte(i) = Byte.Parse(DQString.ElementAt(i))
StringBuilder7.Append(DQByte(i).ToString)
Next
For i As Integer = 0 To InverseQString.Length - 1
InverseQByte(i) = Byte.Parse(InverseQString.ElementAt(i))
StringBuilder8.Append(InverseQByte(i).ToString)
Next
Dim MyRSAParams As New RSAParameters
MyRSAParams.P = PByte
MyRSAParams.Q = QByte
MyRSAParams.Exponent = ExponentByte
MyRSAParams.Modulus = ModulusByte
MyRSAParams.D = DByte
MyRSAParams.DP = DPByte
MyRSAParams.DQ = DQByte
MyRSAParams.InverseQ = InverseQByte
Dim MyRSA As RSA
MyRSA = RSA.Create()
MyRSA.ImportParameters(MyRSAParams)
End Sub
Private Sub RSA_Test_Form_Load(sender As Object, e As EventArgs) Handles MyBase.Load
Dim temp, temp2 As Integer
temp = gcd(1, 2)
temp2 = gcd(2, 3)
FindFactor = 0
End Sub
End Class
What I am trying to do in the generate button was to create the suitable parameters for RSA.
The parameters I was actually able to generate them but in either ULong or Long data type.
When i first convert them into array of Bytes I have considered to use BitConverter but it doesn't work at least in my case.
The only way i am only able to make them into array of Bytes was by making the ULong or Long data type variable into string.
Then convert those string into Byte then put them into ByteArray
I hope it was correct but it is out of my reach for now.
Any ideas on how can i make the parameter data to be accepted as rsa parameter?

How to convert Julian date ignoring the year to Julian Day

How do i convert day/Month to Julian Day in visual basic?
Formula for converting in other languages are also appreciated.
For e.g
Julian Day for 1 Feb=032
https://landweb.modaps.eosdis.nasa.gov/browse/calendar.html
From research in the web ,most resolutions are converting the date with yyyy-mm-dd to julian date.
As the example above, i need to get value 032
The .Net JulianCalendar Class exposes all methods needed to achieve your goal. It is also COM visible, so you can reference it in a VBA project after adding a project reference to "mscorlib.dll".
In VB.Net the code would be:
Dim jc As New System.Globalization.JulianCalendar
' create a gregorian equivalent of the julian date: 1 Feb 2018
Dim gregoriaDateEquivalent As DateTime = jc.ToDateTime(2018, 2, 1, 0, 0, 0, 0)
' = #2/14/2018 12:00:00 AM#
Dim dayOfYear As Int32 = jc.GetDayOfYear(gregoriaDateEquivalent)
' = 32
In VBA the code would be:
Dim jc As mscorlib.JulianCalendar
Set jc = New mscorlib.JulianCalendar
' create a gregorian equivalent of the julian date: 1 Feb 2018
Dim gregoriaDateEquivalent As Date
gregoriaDateEquivalent = jc.ToDateTime(2018, 2, 1, 0, 0, 0, 0)
' = #2/14/2018
Dim dayOfYear As Long
dayOfYear = jc.GetDayOfYear(gregoriaDateEquivalent)
' = 32
First you have to add reference to mscorlib library
Under VB6,Project-References->Tick the mscorlib checkbox
Create this function method in the object that you ahve or otherwise create a sub procedure
Public Function JulianConverter() As String
'MsgBox Fix(5.2), vbExclamation, App.Title
'MsgBox Fix(5.6)
Dim y As String
Dim m As String
Dim d As String
Dim strDate As String
Dim dateArray() As String
strDate = Format(Now, "dd/MMM/yyyy")
dateArray = Split(strDate, "/")
d = dateArray(0)
m = dateArray(1)
y = dateArray(2)
'Debug
'MsgBox strDate
'Convert to Integer
y = Val(y)
m = Val(m)
d = Val(d)
If m <= 2 Then
y = y - 1
m = m + 12
End If
'Dim A As Double
' Dim B As Double
'Dim JD As Double
' A = CDbl(Fix(y / 100#))
'B = 2 - A + Fix(A / 4)
'JD = Fix(365.25 * (y + 4716)) + Fix(30.6001 * (m + 1)) + d + B - 1524.5
'JulianConverter = CStr(JD) 'Convert to string
Dim jc As mscorlib.JulianCalendar
Set jc = New mscorlib.JulianCalendar
' create a gregorian equivalent of the julian date: 1 Feb 2018
Dim gregoriaDateEquivalent As Date
gregoriaDateEquivalent = jc.ToDateTime(2018, m, d, 0, 0, 0, 0)
' = #2/14/2018
Dim dayOfYear As Long
Dim dayOfYearS As String
Dim digitLength As Integer
Dim Counter As Integer
dayOfYear = jc.GetDayOfYear(gregoriaDateEquivalent)
'Have to ensure 3 digits values
dayOfYearS = CStr(dayOfYear)
'Count number of Digits of string
digitLength = Len(dayOfYearS)
MsgBox "DigitLength" & digitLength, vbExclamation, App.Title
'If Digits length smaller than 3,add one 0 in front
If (digitLength < 3) Then
dayOfYearS = "0" & dayOfYearS
End If
JulianConverter = dayOfYearS
End Function
This will ensure the julian day will be 3 digits in value based on the current system date

What is different between Microsoft.VisualBasic.VBMath.Rnd and the old VB Rnd() function?

I am trying to convert some old VB code to .Net but am having a problem with the Rnd function.
Old Code
Private Function Decode() As String
Dim r As Integer
Dim x As Integer
Dim c As Integer
Dom Code As String = "m[n-Msr0Xn*ca8qiGeIL""7'&;,_*EV{M;[{2bEmg8u!^s*+O37!692{-Y4IS"
x = Int(Rnd(-7))
For r = 1 To Len(Code)
x = Int(Rnd() * 96)
c = Asc(Mid(Code, r, 1))
c = c + x
If c >= 126 Then c = c - 126 + 32
Decode = Decode & Chr$(c)
Next
End Function
The decoded text is "Bet you needed more than a pencil and paper to get this one!"
This is what I have done:
Private Function Decode() As String
Dim r As Integer
Dim x As Integer
Dim c As Integer
Dim Answer As String
Dim Code As String = "m[n-Msr0Xn*ca8qiGeIL""7'&;,_*EV{M;[{2bEmg8u!^s*+O37!692{-Y4IS"
x = CType(Microsoft.VisualBasic.VBMath.Rnd(-7), Integer)
For r = 0 To sList.Length - 1
x = CType(Microsoft.VisualBasic.VBMath.Rnd() * 96 - 0.5, Integer)
c = Asc(sList.Substring(r, 1))
c = c + x
If c >= 126 Then c = c - 126 + 32
Answer &= Chr(c)
Next
Return Answer
End Function
but this is what I get "Bet you needed morB th(n a pencil and paper to get this one!"
I suspect its how I am castng to an int but I can't figure out how.
When I run your "Old Code" (after correcting the typos) under Office VBA (which should have the same Rnd implementation as VB6), I get the same result as you say you get from VB.Net. Therefore, there must be an error in the string assigned to Code.
Public Function Decode() As String
Dim r As Integer
Dim x As Integer
Dim c As Integer
Dim Code As String
Code = "m[n-Msr0Xn*ca8qiGeIL""7'&;,_*EV{M;[{2bEmg8u!^s*+O37!692{-Y4IS"
x = Int(Rnd(-7))
For r = 1 To Len(Code)
x = Int(Rnd() * 96)
c = Asc(Mid(Code, r, 1))
c = c + x
If c >= 126 Then c = c - 126 + 32
Decode = Decode & Chr$(c)
Next
End Function
Thanks to TnTinMan for leading me to the solution. The problem was created when I copied the string. I used a I instead of an l. The font that was used has these two characters looking identical. I also mistook ' for `.
so basically all I had to do was subtract .5

Converting RGB value into integers

I'm making an app with a color dropper tool on it using g.CopyFromScreen(screenpoint, Point.Empty, Bmp2.Size) (the dropper tool works currently), once I have the dropper values I want to convert the RBG values into individual integers.
The values that i'm converting are in this format
Color [A=255, R=240, G=240, B=240]
which needs to be in four different integers
My code is giving me odd results and I'm lost now
My code:
Dim text1Conv As String
text1Conv = TextBox1.Text
Dim myChars() As Char = text1Conv.ToCharArray()
For Each ch As Char In myChars
If Char.IsDigit(ch) And Not ch = " " And Not ch = "," And Not count > 2 Then
color1Conv = color1Conv + ch
TextBox2.Text = TextBox2.Text + color1Conv 'test result
count = count + 1
ElseIf Char.IsDigit(ch) And Not ch = " " And Not ch = "," And count < 2 And Not count > 5 Then
color2Conv = color2Conv + ch
TextBox2.Text = TextBox2.Text + color2Conv 'test result
count = count + 1
ElseIf Char.IsDigit(ch) And Not ch = " " And Not ch = "," And count < 5 And Not count > 8 Then
color3Conv = color3Conv + ch
TextBox2.Text = TextBox2.Text + color3Conv 'test result
count = count + 1
ElseIf Char.IsDigit(ch) And Not ch = " " And Not ch = "," And count < 8 And Not count > 11 Then
color4Conv = color4Conv + ch
TextBox2.Text = TextBox2.Text + color4Conv 'test result
count = count + 1
End If
Next
results: 225 255 118 112 122
results: 225 255 116 772 721
probably an easy one but I can't see it
Using regular expressions:
I used "[A=255, R=241, G=24, B=2]" as a test string and split it into four integers.
Dim a as Integer, r as Integer, g as Integer, b as Integer
Dim s as String = "[A=255, R=241, G=24, B=2]"
Dim mc as MatchCollection = System.Text.RegularExpressions.Regex.Matches( s, "(\d+)\D+(\d+)\D+(\d+)\D+(\d+)\D+", RegexOptions.None )
Integer.TryParse( mc(0).Groups(1).Value, a )
Integer.TryParse( mc(0).Groups(2).Value, r )
Integer.TryParse( mc(0).Groups(3).Value, g )
Integer.TryParse( mc(0).Groups(4).Value, b )
NOTE: it will have no problems with numbers being 1, 2, or any number of digits long.
You can use regular expressions:
Imports System.Text.RegularExpressions
Dim input As String = "Color [A=255, R=240, G=240, B=240]"
Dim re As New Regex("Color \[A=(\d+), R=(\d+), G=(\d+), B=(\d+)\]")
Dim m As Match = re.Match(input)
Dim integer1 As Integer = Convert.ToInt32(m.Groups(1).Value) '255
Dim integer2 As Integer = Convert.ToInt32(m.Groups(2).Value) '240
Dim integer3 As Integer = Convert.ToInt32(m.Groups(3).Value) '240
Dim integer4 As Integer = Convert.ToInt32(m.Groups(4).Value) '240

Using math for negative minus negative

this gives me 0 instead of -10. how can I fix it?
Dim aa As String = "-5"
Dim bb As String = "-5"
Debug.Print(Val(aa) - Val(bb))
Actually Its correct
Dim aa As String = "-5"
Dim bb As String = "-5"
Debug.Print(Val(aa) - Val(bb))
If you want -10 then you need to add
Dim aa As String = "-5"
Dim bb As String = "-5"
Debug.Print(Val(aa) + Val(bb))
because (-5) - (-5) becomes -5 + 5 so its 0
it is the right answer.
-5 - -5 = 0
if you want to get -10 just do
Dim aa = -5
Dim bb = -5
Debug.Print(aa + bb)