In my query I want total file count and total closed files in the same table.
My first query:
select hi.eksper_id,ef.ad, count(hi.eksper_id) as total_files
from hasar_ihbar as hi
left outer join eksper_firma ef on ef.id=hi.eksper_id
group by hi.eksper_id,ef.ad
My second query:
select ef.id as eksper_id,ef.ad,count(ef.id) closed_files
from hasar_ihbar_rapor hir
left outer join hasar_ihbar hi on hi.id = hir.hasar_ihbar_id
left outer join eksper_firma ef on ef.id = hi.eksper_id
where hir.rapor_tipi = 3 group by ef.id,ef.ad
I want both combined and this is my code:
select ef.id as eksper_id,ef.ad,count(ef.id) closed_files, count(hi.id) AS total_files
from hasar_ihbar_rapor hir
left outer join hasar_ihbar hi on hi.id = hir.hasar_ihbar_id
left outer join eksper_firma ef on ef.id = hi.eksper_id
where hir.rapor_tipi = 3 group by ef.id,ef.ad
I don't know what I did wrong. Thanks for your help.
The double joins effect your counts since there are more rows.
A better way to combine both counts is to create a query that has two subqueries for each count.
SELECT id,
(SELECT COUNT(*)...) total_files,
(SELECT COUNT(*)...) closed_files
FROM ...
Related
Im trying to show all columns from my t1_elem table and join 2 columns in which I use COUNT.
I used query:
SELECT p.*,COUNT(t4_id) as ile_publikacji, COUNT(t7_id) as ile_fitow
FROM t1_elem p
LEFT OUTER JOIN t4_autorzy ON p.t1_id=t4_autorzy.t4_t1_id
LEFT JOIN t7_pliki ON p.t1_id=t7_pliki.t7_t1_id
GROUP BY t1_id
But the results are bad. What I'm doing wrong?
Probably you have multiple matches. As stated, the two counts will be the same. The simplest solution is probably to use distinct:
SELECT p.*, COUNT(DISTINCT t4_id) as ile_publikacji, COUNT(DISTINCT t7_id) as ile_fitow
FROM t1_elem p LEFT JOIn
t4_autorzy
ON p.t1_id = t4_autorzy.t4_t1_id LEFT JOIN
t7_pliki
ON p.t1_id=t7_pliki.t7_t1_id
GROUP BY t1_id
I want to join two tables and then I want to join this result with another table
but it doesn't work
select * from
(
(select SeId,FLName,Company from Sellers) s
inner join
(select SeId,BIId from BuyInvoices) b
on s.SeId=b.SeId
) Y
inner join
(select * from BuyPayments) X
on Y.BIId=X.BIId
thanks
In most databases, your syntax isn't going to work. Although parentheses are allowed in the FROM clause, they don't get their own table aliases.
You can simplify the JOIN. This is a simpler way to write the logic:
select s.SeId, s.FLName, s.Company, bp.*
from Sellers s inner join
BuyInvoices b
on s.SeId = b.SeId inner join
BuyPayments bp
on bp.BIId = b.BIId;
I have the following query:
SELECT MS.idReg, MS.dsMotivo, A.contrato FROM MS
INNER JOIN S
ON S.motivoSiniestro = MS.idReg
INNER JOIN C
ON C.n__contrat = S.n__contrat
INNER JOIN A
ON A.n__article = C.n__article
Table MS has only 12 records, the ones I need and others have many more entries.
My problem is that I only want the 12 records from MS and their contrato column but I'm getting much more that that. Have tried many combinations of INNER, OUTER, LEFT and RIGHT joins. Any help?
You get too many records because there are several A.contrato values for each row in the MS table. Sql server does not know which one of all the A.contrato values to take so it returns all of them. First you need to decide which one you want.
If any will do you can simply write your query like this:
SELECT MS.idReg, MS.dsMotivo, MAX(A.contrato)
FROM MS
INNER JOIN S
ON S.motivoSiniestro = MS.idReg
INNER JOIN C
ON C.n__contrat = S.n__contrat
INNER JOIN A
ON A.n__article = C.n__article
GROUP BY MS.idReg, MS.dsMotivo
Try this one -
SELECT MS.idReg, MS.dsMotivo, A.contrato
FROM dbo.MS
OUTER APPLY (
SELECT TOP 1 A.contrato
FROM dbo.S
JOIN dbo.C ON C.n__contrat = S.n__contrat
JOIN dbo.A ON A.n__article = C.n__article
WHERE S.motivoSiniestro = MS.idReg
) s
I wrote a query. this query sum fields from 2 different table. And grouped by main table id field. But second left outer join is not grouped and giving me different results.
SELECT s.*,
f.firma_adi,
sum(sd.fiyat) AS konak,
sum(ss.fiyat) AS sponsor
FROM fuar_sozlesme1 s
INNER JOIN fuar_firma_2012 f
ON ( s.cari = f.cari )
LEFT OUTER JOIN fuar_sozlesme1_detay sd
ON ( sd.sozlesme_id = s.id )
LEFT OUTER JOIN fuar_sozlesme1_sponsor ss
ON ( ss.sozlesme_id = s.id )
GROUP BY s.id
ORDER BY s.id DESC
I know, it is really complicated but I'm stucking on this issue.
My question is: why second left outer join is not correctly sum of field . If I remove second left outer join or first, everything is normal.
The problem is that you have multiple dimensions on your data, and the number of rows is multiplying beyond what you expect. I would suggest that you run the query for one id, without the group by, to see what rows the join is producing.
One way to fix this is by using correlated subqueries:
select s.*, f.firma_adi,
(select SUM(sd.fiyat)
from fuar_sozlesme1_detay fd
where sd.sozlesme_id = s.id
) as konak,
(select SUM(ss.fiyat)
from fuar_sozlesme1_sponsor ss
where (ss.sozlesme_id = s.id)
) as sponsor
from fuar_sozlesme1 s inner join
fuar_firma_2012 f
on (s.cari = f.cari)
order by s.id DESC
By the way, you appear to by using MySQL (because your query is not parsable in any other dialect). You should tag your questions with the version of the database you are using.
I have 2 tables AP and INV where both have the columns [PROJECT] and [Value].
I want a query to return something like this :
PROJECT | SUM_AP | SUM_INV
I came up with the code below but it's returning the wrong results ( sum is wrong ).
SELECT AP.[PROJECT],
SUM(AP.Value) AS SUM_AP,
SUM(INV.Value) AS SUM_INV
FROM AP INNER JOIN INV ON (AP.[PROJECT] =INV.[PROJECT])
WHERE AP.[PROJECT] = 'XXXXX'
GROUP BY AP.[PROJECT]
The results from your query are wrong because the values you are trying to summarize are being grouped, which causes duplicate values to be included in the SUM.
You could solve it with a couple of sub-selects:
SELECT
AP1.[PROJECT],
(SELECT SUM(AP2.Value) FROM AP AS AP2 WHERE AP2.PROJECT = AP1.PROJECT) AS SUM_AP,
(SELECT SUM(INV2.Value) FROM INV AS INV2 WHERE INV2.PROJECT = AP1.PROJECT) AS SUM_INV
FROM AP AS AP1
INNER JOIN INV AS INV1
ON (AP1.[PROJECT] =INV1.[PROJECT])
WHERE AP1.[PROJECT] = 'XXXXX'
GROUP BY AP1.[PROJECT]
If you have N rows in AP with a given project ID, and M rows in INV with that ID, then the join between the two tables on the project ID will have a total of N*M rows for that project, because the same row in AP will be repeated for every row in INV that has that project ID, and vice versa. Hence why your counts are most likely off (because it's counting the same row in a given table multiple times due to repetition from the join).
Instead, you might want to try doing a join between the results of two subqueries, one which groups the first table by project ID and does that its sum, and the second which groups the other table by project ID and does that sum - then joining once you only have 1 row with sum for each project ID.
If PROJECT is the parent table, you should select FROM the project table, and do a left outer join on the two child tables:
SELECT PROJECT.PROJECT_ID, SUM(AP.Value) AS SUM_AP, SUM(INV.Value) AS SUM_INV
FROM PROJECT
LEFT OUTER JOIN AP ON (AP.[PROJECT] = PROJECT.[PROJECT_ID])
LEFT OUTER JOIN INV ON (INV.[PROJECT] = PROJECT.[PROJECT_ID])
WHERE PROJECT.[PROJECT_ID] = 'XXXXX'
GROUP BY PROJECT.[PROJECT_ID]
You could separate the two sum calculations. One way I can think of is to move the inventory calculation to a subquery, like:
SELECT
AP.[PROJECT]
, SUM(AP.Value) AS SUM_AP
, SummedInv as SUM_INV
FROM AP
LEFT JOIN (
SELECT PROJECT, SUM(Value) AS SUM_INV
FROM INV
GROUP BY PROJECT
) SummedInv ON SummedInv.Project = AP.Project
GROUP BY AP.PROJECT, SummedInv.SUM_INV
Because the SummedInv subquery is grouped on project, it's safe to group on SummedInv.SUM_INV in the outer query as well.
how about this query :
select SUM(gpCutBody.actualQty) as cutQty , SUM(gpSewBody.quantity) as sewQty
from jobOrder
inner join gpCutHead on gpCutHead.joNum = jobOrder.joNum
inner join gpSewHead on gpSewHead.joNum = jobOrder.joNum
inner join gpCutBody on gpCutBody.gpCutID = gpCutHead.gpCutID
inner join gpSewBody on gpSewBody.gpSewID = gpSewHead.gpSewID
where jobOrder.joNum = '36'
here is the link to the ERD: http://dl.dropbox.com/u/18794525/AUG%207%20DUMP%20STAN.png
Try:
SELECT AP.[PROJECT] AS PROJECT, SUM(AP.[Value]) AS SUM_AP, SUM(INV.[Value]) AS SUM_INV
FROM AP, INV
WHERE AP.[PROJECT] = INV.[PROJECT]
AND AP.[PROJECT] = 'XXXXX'
GROUP BY AP.[PROJECT]