Pivot data T-SQL - sql

I have the following table:
I want to pivot it to the following table:
I tried to work with the following example:
https://www.sqlshack.com/dynamic-pivot-tables-in-sql-server/
But in this case a SUM operator is mandatory.
I don't want to use the SUM operator for my data.
What would be the best approach to go.
Eventually I want to use the data again, I want to prevent that I need to make a lot of "left join" statements like the following:
select table_a.Cat,one.number as number1, one.namevalue as Name1, two.number as number2, two.namevalue as name2
from table_a
left outer join (
select *
from #temp
where numbercat = 'number1'
) as one on table_a.cat = one.cat
left outer join (
select *
from #temp
where numbercat = 'number2'
) as two on table_a.cat = two.cat
I am able to unpivot the numbercat & number with the following code:
select *
from
(
select cat, numbercat, number
from #input
) src
pivot
(
min(number)
for numbercat in ([1], [2], [3])
) piv;
What should I do to also incorporate the Namecat & namevalue data?

I find that conditional aggregation is usually simpler and more versatile than pivot:
select cat,
max(case when numbercat = 'number1' then number end) as number1,
max(case when numbercat = 'number2' then number end) as number2,
max(case when namecat = 'name1' then name end) as name1,
max(case when namecat = 'name2' then name end) as name2
from #temp
group by cat;

Related

sql transformation - rows to column

i have been trying to solve this one image
my initial idea is like this
select name,
CASE
when count(name) = 1 then get first distinct value
when count(name) = 2 then get first distinct value
else get first distinct value
END as val1,
CASE
when count(name) = 1 then null
when count(name) = 2 then get second distinct value
else get second distinct value
END as val2,
CASE
when count(name) = 1 then null
when count(name) = 2 then null
else get third distinct value
END as val3
into desired_table
from source_table
group by name
is my attempt feasible? if so, how do i access the first, second and third distinct values?
use pivot . Your output table was incorrect. The correct form is available in db<>fiddle.
select name,x as value1,y as value2,z as value3
from
(
select *
from t1
) as SourceTable
pivot
(
max(value) for value in(x,y,z)
) as PivotTable
demo in db<>fiddle
You can use conditional aggregation along with row_number():
select name,
max(case when seqnum = 1 then value end) as value_1,
max(case when seqnum = 2 then value end) as value_2,
max(case when seqnum = 3 then value end) as value_3
into desired_table
from (select s.*,
row_number() over (partition by name order by value) as seqnum
from source_table s
) s
group by name;

Conditional Selection of Rows Using TSQL SQL Server (2008 R2)

I've been staring at this for hours and hours and can't come up with an "elegant" set-based way of getting the result set I need...
Here's my sample data (my real data could be 1,000,000+ rows)...
DECLARE #t AS TABLE (ID int,ID1 nvarchar(15),[DATE] date,PERIOD int,[TYPE] nchar(1));
INSERT INTO #t (ID,ID1,[DATE],PERIOD,[TYPE])
VALUES
(1,N'NUM1','2016-01-01',1,N'B'),
(2,N'NUM1','2016-01-01',2,N'A'),
(3,N'NUM1','2016-01-01',3,N'A'),
(4,N'NUM1','2016-01-01',4,N'B'),
(5,N'NUM1','2016-01-01',4,N'A'),
(6,N'NUM1','2016-01-01',5,N'A'),
(7,N'NUM1','2016-01-02',1,N'A'),
(8,N'NUM1','2016-01-02',2,N'A'),
(9,N'NUM1','2016-01-02',3,N'A'),
(10,N'NUM1','2016-01-02',4,N'A'),
(11,N'NUM1','2016-01-02',5,N'A'),
(12,N'NUM2','2016-01-01',1,N'A'),
(13,N'NUM2','2016-01-01',1,N'B'),
(14,N'NUM2','2016-01-01',2,N'A'),
(15,N'NUM2','2016-01-01',3,N'A'),
(16,N'NUM2','2016-01-01',4,N'B'),
(17,N'NUM2','2016-01-01',4,N'A'),
(18,N'NUM2','2016-01-01',5,N'A'),
(19,N'NUM2','2016-01-02',1,N'A'),
(20,N'NUM2','2016-01-02',2,N'B'),
(21,N'NUM2','2016-01-02',3,N'A'),
(22,N'NUM2','2016-01-02',4,N'A'),
(23,N'NUM2','2016-01-02',4,N'B'),
(24,N'NUM2','2016-01-02',5,N'A');
Here is the result set I'm trying to get...
1,'NUM1','2016-01-01',1,'B'
2,'NUM1','2016-01-01',2,'A'
3,'NUM1','2016-01-01',3,'A'
5,'NUM1','2016-01-01',4,'A'
6,'NUM1','2016-01-01',5,'A'
7,'NUM1','2016-01-02',1,'A'
8,'NUM1','2016-01-02',2,'A'
9,'NUM1','2016-01-02',3,'A'
10,'NUM1','2016-01-02',4,'A'
11,'NUM1','2016-01-02',5,'A'
12,'NUM2','2016-01-01',1,'A'
14,'NUM2','2016-01-01',2,'A'
15,'NUM2','2016-01-01',3,'A'
17,'NUM2','2016-01-01',4,'A'
18,'NUM2','2016-01-01',5,'A'
19,'NUM2','2016-01-02',1,'A'
20,'NUM2','2016-01-02',2,'B'
21,'NUM2','2016-01-02',3,'A'
22,'NUM2','2016-01-02',4,'A'
24,'NUM2','2016-01-02',5,'A'
Simply put, each day has 5 periods. They can be of type A or B. I need to get the A types. but if there are no A types, I need to get the B types... (Sounds so simple when I write it out.., but my brain will not come up with something suitable)
Pleeeeeease put me out of my misery..
You can use ROW_NUMBER for this:
SELECT ID, ID1, [DATE], PERIOD, [TYPE]
FROM (
SELECT ID, ID1, [DATE], PERIOD, [TYPE],
ROW_NUMBER() OVER (PARTITION BY ID1, [DATE], PERIOD
ORDER BY [TYPE]) AS rn
FROM #t) AS t
WHERE t.rn = 1
Using ORDER BY [TYPE] in the OVER clause of ROW_NUMBER places 'A' records on top of 'B' records. If there are no 'A' records for a given ID1, [DATE], PERIOD then B records are assigned rn = 1.
Your desired outpout contradicts the statement that "I need to get the A types. but if there are no A types, I need to get the B types... ". Every date in the data has one or more 'A' types. By the statement, the output should include only the 'A' types. But if the statement is correct, then this should work:
Select d.[DATE], t.Id, t.ID1, t.PERIOD, t.[TYPE]
from (select distinct [date] from #t) d
left join #t t
on t.[date] = d.[date]
and t.type = case when exists
(select * from #t
where [date] = d.[Date]
and type = 'A') then 'A'
else 'B' End
I've just come up with
SELECT * FROM #t WHERE [TYPE]='A'
UNION ALL
SELECT * FROM #t t1 WHERE [TYPE]='B' AND NOT EXISTS (SELECT ID FROM #t WHERE ID1=t1.ID1 AND [TYPE]='A' AND [DATE]=t1.[DATE] AND Period=t1.Period)
ORDER BY ID;
which give's me what I need...

SQL Server 2008 Reporting: Sum of Max of group

I have a table like this in the report designer:
Category: 1 2 3 4 Total
Max Amount: x y z c ?
I need to get the total of Max Amount, but expressions will not let me take Sum(Max(amount)), and the add total is disabled for this cell.
The max amount row is an expression that takes the max of each category. The source data has repeated values, so I just take the max. For example:
Category Amount
1 4.6
1 4.6
1 4.6
2 5
3 4
Other columns in the table are different, but amount will be the same so I cannot only select distinct values.
Maybe something like this:
SELECT
SUM(t1.maxAmout)
FROM
(
SELECT
MAX(t.Amout) AS maxAmout,
t.Category
FROM
yourTable AS t
GROUP BY
t.Category
) AS t1
You can also do it like this. If you are using sql server 2005+:
SELECT
pvt.[1],
pvt.[2],
pvt.[3],
(
pvt.[1]+
pvt.[2]+
pvt.[3]
) AS Total
FROM
(
SELECT
t.Category,
t.Amout
FROM
yourTable AS t
) AS SourceTable
PIVOT
(
MAX(Amout)
FOR Category IN([1],[2],[3])
) AS pvt
EDIT
If you have a 1000 categories. Then a dynamic pivot would be the best solution. So like this:
Test data
CREATE TABLE #T
(
Category INT,
Amout FLOAT
)
INSERT INTO #T
VALUES
(1,4.6),
(1,4.6),
(1,4.6),
(2,5),
(3,4)
Unique column names
DECLARE #cols VARCHAR(MAX)
DECLARE #colsTotal VARCHAR(MAX)
;WITH CTE
AS
(
SELECT
ROW_NUMBER() OVER(PARTITION BY t.Category ORDER BY t.Amout) AS RowNbr,
t.*
FROM
#T AS t
)
SELECT #cols = COALESCE(#cols + ','+QUOTENAME(Category),
QUOTENAME(Category)),
#colsTotal=COALESCE(#colsTotal + '+ISNULL('+QUOTENAME(Category)+',0)',
'ISNULL('+QUOTENAME(Category)+',0)')
FROM
CTE
WHERE
CTE.RowNbr=1
ORDER BY
Category
Dynamic pivot
DECLARE #query NVARCHAR(4000)=
N'SELECT
'+#cols+',
(
'+#colsTotal+'
) AS Total
FROM
(
SELECT
t.Category,
t.Amout
FROM
#T AS t
) AS SourceTable
PIVOT
(
MAX(Amout)
FOR Category IN('+#cols+')
) AS pvt'
EXECUTE(#query)
WITH
aggregate
AS
(
SELECT
category,
MAX(amount) AS max_amount
FROM
yourTable
GROUP BY
category
)
SELECT
MAX(CASE WHEN category = 1 THEN max_amount ELSE NULL END) AS [1],
MAX(CASE WHEN category = 2 THEN max_amount ELSE NULL END) AS [2],
MAX(CASE WHEN category = 3 THEN max_amount ELSE NULL END) AS [3],
MAX(CASE WHEN category = 4 THEN max_amount ELSE NULL END) AS [4],
SUM(max_amount) AS [total]
FROM
aggregate
The following returns a single value:
SELECT DISTINCT SUM(MAX(Amount)) OVER ()
FROM atable
GROUP BY Category
You could use this as a subquery calculating the value of the Total column.
Alternatively, TOP (1) could be used instead of DISTINCT (don't know why I couldn't think of it before):
SELECT TOP (1) SUM(MAX(Amount)) OVER ()
FROM atable
GROUP BY Category

How do i convert rows into columns?

i know this can be done with pivot but dont know how to put this in query..heres my table..
Id Date Code
1 1-2-2011 Code1
2 2-2-2011 Code2
Desired table:
Id 1-2-2011 2-2-2011
1 Code1 Null
2 Null Code2
Heres something i am trying but i want to know if there is any different way..
SELECT [Id], '1-2-2011','2-2-2011'
FROM ( SELECT [Id]
, Code
FROM #r
) p PIVOT ( Code
FOR [date] IN ('1-2-2011','2-2-2011')
) AS pvt
ORDER BY [Id]
The correct PIVOT query would be something like this
declare #r table (Mobile int, Calldate datetime, Dispo varchar(10))
insert #r select
1, '2011-02-21', 'Code1' union all select
2, '2011-02-22', 'Code2'
SELECT ID, [2011-02-21], [2011-02-22]
-- SELECT * << or just use this, which includes all columns
FROM (
SELECT Id, Date, Code
FROM #r) p
PIVOT (MAX(Code) FOR Date IN ([2011-02-21], [2011-02-22])) AS pvt
ORDER BY ID
Your query used
SELECT [Id], '1-2-2011','2-2-2011'
Which includes two FIXED-VALUE strings, which means the DATA is the string '1-2-2011', not a column name. You also needed MAX(Code) or some aggregate function to use when pivoting.
Pivoting in SQL Server requires you to know the columns in advances, which you need to list out in the FOR () bit. Otherwise, you will need to look at dynamic pivoting. This is true whether you use the PIVOT operator or the MAX(CASE pattern to pivot.
The MAX(CASE) pattern
select id,
MAX(case when date = '2011-02-21' then Code end) "2011-02-21",
MAX(case when date = '2011-02-22' then Code end) "2011-02-22"
from #r
group by id

Optimizing sql, existing query using two full table scans CTE's

I am looking for an improvement to the below query, any input gratefully received
with cteA as (
select name, count(1) as "A"
from mytable
where y="A"
group by name
),
cteB as (
select name, count(1) as "B"
from mytable
where y="B"
group by name
)
SELECT cteA.name as 'name',
cteA.A as 'count x when A',
isnull(cteB.B as 'count x when B',0)
FROM
cteOne
LEFT OUTER JOIN
cteTwo
on cteA.Name = cteB.Name
order by 1
select name,
sum(case when y='A' then 1 else 0 end) as [count x when A],
sum(case when y='B' then 1 else 0 end) as [count x when B]
from mytable
where y in ('A','B')
group by name
order by name
The simplest answer is:
select name, y, count(*)
from mytable
where y in ('A','B')
group by name, y
You can use a PIVOT to move Y row values into columns, if you need them in columns.