Removing delimited block of code between patterns using bash (regex, sed) - awk

Question

I have a file with visibility declarations, spanning over one or more lines, that I want removed only if they are in a test block.
i.e. input.txt:
test(
srcs = [
"test1",
],
visibility = [
"common",
],
deps = [ "deps" ],
)
test(
srcs = [
"test2",
],
visibility = [ "common" ],
)
i.e. output:
test(
srcs = [
"test1",
],
deps = [ "deps" ],
)
test(
srcs = [
"test2",
],
)
The visibility lines could be inside other blocks i.e. etc(...), in which case they should not be removed. i.e.:
etc(
src = [
"etc",
],
# should not be removed because it's not inside a test(...) block
visibility = [
"common",
],
)
This is what I have tried, however, this only matches visibility blocks spanning over a single line:
#!/bin/bash
#remove_lines.sh
remove_visibility_lines () {
start_pattern="test"
end_pattern=")"
pattern_to_remove="visibility = \[.*\],"
sed "/${start_pattern}/,/${end_pattern}/{/${pattern_to_remove}/d}" "$1"
}
remove_visibility_lines $1
$ ./remove_lines.sh input.txt
I've tried several ways to get this to remove visibility spanning over multiple block, i.e. (.*?) and (\_.*), but I can't seem to get it to work.
Please help?
Question is similar to:
Using sed to delete all lines between two matching patterns , however, in my case I have patterns nested inside patterns. I.e.: you only look inside the test(...) block, and only inside those blocks you remove the visibility = [...], blocks.

Answer 1

With awk, assuming no nested () characters:
awk '/^test\(/{f=1} $0==")"{f=0}
f && /visibility = \[/{v=1} !v; /],/{v=0}' ip.txt
/^test\(/{f=1} set flag f if a line starts with test(
$0==")"{f=0} clear flag f if a line contains ) only
f && /visibility = \[/{v=1} set flag v if f is also set and a line contains visibility = [
!v; to print input lines only if flag v is not set
/],/{v=0} clear flag v if line contains ],
To pass start and end strings:
$ cat script.awk
index($0, start) == 1 { f = 1 }
$0 == end { f = 0 }
f && /visibility = \[/ { v = 1 }
! v { print }
/],/ { v = 0 }
$ awk -v start='test(' -v end=')' -f script.awk ip.txt