I'm trying to achieve a result where only one result for each TEAM and each PLACE is returned.
The twist is that the highest result should from each place should have priority.
My table currently looks something like this:
ENTRY_ID TEAM_ID DATE PLACE SCORE
1 1 2021-10-12 Ireland 64
2 2 2021-10-12 Ireland 31
3 3 2021-10-12 France 137
4 2 2021-10-12 France 61
5 5 2021-10-12 France 38
6 1 2021-10-12 France 66
7 2 2021-10-12 Italy 17
8 3 2021-10-12 Italy 61
9 1 2021-10-12 Italy 74
The competition is held at three different places at the same time, with technically all teams being able to have people playing in all of them at the same time.
Each team however can only win one point so, in the example, it's possible to see that Team 1 would win both in Italy and Ireland, but it should be awarded only one point for the highest score, so only Italy. The point in Ireland should go to the second place.
I've tried over 30 queries I've found in several correlated questions, but none of them seems to be applicable to my situation.
Basically:
"Return the highest score on each PLACE, but only calls each TEAM once.
If that certain TEAM was already called, ignore it, get the second place."
So I could retrieve all three winners with no further processing. The results I'm trying to achieve should repeat neither the TEAM_ID nor PLACE, in this particular example it should output:
3 FRANCE (Since it has the highest score in France at 137)
1 ITALY (For the highest score in Italy at 74)
2 IRELAND (For the second-highest score in Ireland, since Team 1 already won in Italy)
The production model of this table has far more entries so it's unlikely there would be any clashes with too many second-places.
How can I achieve that?
Related
I want to list the person's name and beside how many times this person got a 10.
Is there any command like this?
marcus gold 25
julia silver 34
jason platinium 12
sarah bronze 45
I'm ranking race data for series of cycling events. Racers win various amounts of points for their position in races. I want to retain the discrete event scoring, but also rank the racer in the series. For example, considering a sub-query that returns this:
License #
Rider Name
Total Points
Race Points
Race ID
123
Joe
25
5
567
123
Joe
25
12
234
123
Joe
25
8
987
456
Ahmed
20
12
567
456
Ahmed
20
8
234
You can see Joe has 25 points, as he won 5, 12, and 8 points in three races. Ahmed has 20 points, as he won 12 and 8 points in two races.
Now for the ranking, what I'd like is:
Place
License #
Rider Name
Total Points
Race Points
Race ID
1
123
Joe
25
5
567
1
123
Joe
25
12
234
1
123
Joe
25
8
987
2
456
Ahmed
20
12
567
2
456
Ahmed
20
8
234
But if I use rank() and order by "Total Points", I get:
Place
License #
Rider Name
Total Points
Race Points
Race ID
1
123
Joe
25
5
567
1
123
Joe
25
12
234
1
123
Joe
25
8
987
4
456
Ahmed
20
12
567
4
456
Ahmed
20
8
234
Which makes sense, since there are three "ties" at 25 points.
dense_rank() solves this problem, but if there are legitimate ties across different racers, I want there to be gaps in the rank (e.g if Joe and Ahmed both had 25 points, the next racer would be in third place, not second).
The easiest way to solve this I think would be to issue two queries, one with the "duplicate" racers eliminated, and then a second one where I can retain the individual race data, which I need for the points break down display.
I can also probably, given enough effort, think of a way to do this in a single query, but I'm wondering if I'm not just missing something really obvious that could accomplish this in a single, relatively simple query.
Any suggestions?
You have to break this into steps to get what you want, but that can be done in a single query with common table expressions:
with riders as ( -- get individual riders
select distinct license, rider, total_points
from racists
), places as ( -- calculate non-dense rankings
select license, rider, rank() over (order by total_points desc) as place
from riders
)
select p.place, r.* -- join rankings into main table
from places p
join racists r on (r.license, r.rider) = (p.license, p.rider);
db<>fiddle here
I am working on a problem where I have the following table:
+----------+ | +------+ | +------------+
company_id | country | total revenue
1 Russia 1200
2 Croatia 1200
2 Italy 1200
3 USA 1200
3 UK 1200
3 Italy 1200
There are 3 companies in this table, but company '2' and company '3' have offices in 2 and 3 countries respectively. All companies pay 1200 per month, and because company 2 has 2 offices it shows as if they paid 1200 per month 2 times, and because company 3 has 3 offices it shows as if it paid 1200 per month 3 times. Instead, I would like revenue to be equally distributed based on how many times company_id appears in the table. company_id will only appear more than once for every additional country in which a company is based.
Assuming each company always pays 1,200 per month, my desired output is:
+----------+ | +------+ | +------------+
company_id | country | total revenue
1 Russia 1200
2 Croatia 600
2 Italy 600
3 USA 400
3 UK 400
3 Italy 400
Being new to SQL, I was thinking this can maybe be done through CASE WHEN statement, but I only learned to use CASE WHEN when I want to output a string depending on a condition. Here, I am trying to assign equal revenue weight to each company's country, depending on in how many countries a company is based in.
Thank you in advance for you help!
Below is for BigQuery Standard SQL
#standardSQL
SELECT company_id, country,
total_revenue / (COUNT(1) OVER(PARTITION BY company_id)) AS total_revenue
FROM `project.dataset.table`
If to apply to sample data from your question - output is
Row company_id country total_revenue
1 1 Russia 1200.0
2 2 Croatia 600.0
3 2 Italy 600.0
4 3 USA 400.0
5 3 UK 400.0
6 3 Italy 400.0
I have a subset summation problem I cannot find the answer to. I am trying to write something in VBA for access that will take all combinations of summations within a certain criteria and place them in a table so I can match a different table to it. Right now I am more concerned with creating the table of combinations. First time I have asked a question sorry if I mess something up.
Example:
Access Table: ImpTable
Fields: ID, Year-Month, Name, Country, Quantity
I need to make every combination of summations where the country and Year-Month are the same. Yet keep track of what was included in the formula. If the new table was created and kept track of which ID's were included in the combination I can reference the original table for the name.
Expected Ending Table Results:
NewID, Year-Month, Country, SumQuantity, ComboName (ID's from original table)
Any help is appreciated.
Raw Data:
ID Year-Month Name Country Quantity
1 2016-06 Person1 US 10
2 2016-06 Person2 US 12
3 2016-10 Person3 US 4
4 2016-06 Person4 UK 5
5 2016-06 Person5 UK 6
6 2016-06 Person6 US 3
Desired Results:
NewID Year-Month Country SumQuantity ComboName
1 2016-06 US 22 1,2
2 2016-06 US 13 1,6
3 2016-06 US 25 1,2,6
4 2016-06 US 15 2,6
5 2016-06 UK 11 4,5
6 2016-10 US 4 3
DBpedia just released their data as tables, suitable to import into a relational database. How can I query this data online using SQL?
Dataset:
http://wiki.dbpedia.org/DBpediaAsTables
I took the raw data, uploaded it to BigQuery, and made it public. So far I've done it with the 'person' and the 'place' table. Check them at https://bigquery.cloud.google.com/table/fh-bigquery:dbpedia.person.
Now is easy to know what are the most popular alma maters, for example:
SELECT COUNT(*), almaMater_label
FROM [fh-bigquery:dbpedia.person]
WHERE almaMater_label != 'NULL'
GROUP BY 2
ORDER BY 1 DESC
It's a little more complicated than that, as some people have more than one alma mater - and the particular way DBpedia encodes that. I left the complete query at http://www.reddit.com/r/bigquery/comments/1rjee7/query_wikipedia_in_bigquery_the_dbpedia_dataset/.
Btw, the top alma maters are:
494 Harvard University
320 University of Cambridge
314 University of Michigan
267 Yale University
216 Trinity College Cambridge
You can also do joins between tables.
For example, for each building (from the place table) that has an architect: What year was that architect born? How many buildings with an architect born that year are listed in DBpedia?
SELECT COUNT(*), LEFT(b.birthDate, 4) birthYear
FROM [fh-bigquery:dbpedia.place] a
JOIN EACH [fh-bigquery:dbpedia.person] b
ON a.architect = b.URI
WHERE a.architect != 'NULL'
AND birthDate != 'NULL'
GROUP BY 2
ORDER BY 2
Results:
...
8 1934
13 1935
9 1937
7 1938
17 1939
7 1941
1 1943
15 1944
10 1945
12 1946
7 1947
9 1950
20 1951
1 1952
...
(Google BigQuery has a free monthly quota to query, up to a 100GB each month)
(DBpedia data from version 3.4 on is licensed under the terms of the Creative Commons Attribution-ShareAlike 3.0 license and the GNU Free Documentation License. http://dbpedia.org/Datasets#h338-24)