I am trying to reorder a column of names that is in the form lastname, firstname to firstname lastname. The original column is NAME_BAT and I have confirmed there are no leading or trailing spaces. Here is my SQL code:
SELECT TOP (100) NAME_BAT
, LTRIM(RIGHT(NAME_BAT, CHARINDEX(', ', NAME_BAT) - 1)) AS FIRST_NAME
, RTRIM(LEFT(NAME_BAT, CHARINDEX(', ', NAME_BAT) - 1)) AS LAST_NAME
, LTRIM(RIGHT(NAME_BAT, CHARINDEX(', ', NAME_BAT) - 1)) + ' ' + RTRIM(LEFT(NAME_BAT, CHARINDEX(', ', NAME_BAT) - 1)) AS NAME_FULL
FROM pitch_aggregate
;
and here is a screenshot of the output:
Output from SQL query
Why are the first four rows perfect, then row 5 includes a leading comma and space before the name, and in row 8 the first name has the first two letter cut off?
Take
LTRIM(RIGHT(NAME_BAT, CHARINDEX(', ', NAME_BAT) - 1)) AS FIRST_NAME
Presume data like Casanova, Bob
CHARINDEX(', ', NAME_BAT) returns 9
RIGHT(NAME_BAT, CHARINDEX(', ', NAME_BAT) - 1) is the rightmost 9-1 = 8 characters, which is nova, Bob
(All your sample/testing firs and last names are nearly the same length.) I'm guessing this is not what you really want?
Now, something like
SUBSTRING(NAME_BAT, CHARINDEX(', ', NAME_BAT) + 2, 100)
might be what you're looking for. Me, I see it as a prime example of why SQL is a poor place to implement string manipulations.
I have tested your query and you do indeed have some formatting issues.
Rather than pick it apart, here is a simpler working alternative you can try. By using cross apply and a values construct you can abstract out the string splitting to leave a more easy to use select list of columns.
select name_bat, f.name FirstName, l.name LastName, Concat_ws(' ',f.name,l.name) Name_full
from t
cross apply (values( Left(name_bat,CharIndex(',',name_bat)-1 )))l(name)
cross apply (values( Replace(name_bat,Concat(l.name,', '),'') ))f(name)
See original and new version example
Related
I want to return name of customers and order them, but their titles must be excluded in ordering.
SELECT name
FROM customers
WHERE name LIKE ...
ORDER BY name
I mean by 'their titles' is such as Dr., Sn., Lady, Sir, Mr., and Mrs.
Possible solution to your problem.
In Oracle:
regexp_replace(user_name, '^(MISS|MS\.|MS|MRS\.|MRS|MR\.|MR)\s*', '') as user_name
Also you can use REPLACE () function like:
REPLACE (user_name, 'MISS', '') as user_name
If you have a column structure like (mr | mrs | other) / space / username you can try this:
with users(user_name) as
(select 'mr user name1' from dual union all
select 'miss username2 ' from dual union all
select 'other username 3' from dual )
select substr(user_name,instr(user_name,' ')+1) real_username from users
Output:
REAL_USERNAME
----------------
username 1
username 2
username 3
In MSSQL:
DECLARE #str VARCHAR(500)='Mr Sam'
SELECT Title,
first_name,
Substring(NAME, CASE
WHEN Charindex(' ', NAME) = 0 THEN 1
ELSE Charindex(' ', NAME)
END, Len(NAME)) last_name
FROM (SELECT CASE
WHEN LEFT(#str, Charindex(' ', #str)) IN( 'Mr', 'Mrs', 'Miss' ) THEN LEFT(#str, Charindex(' ', #str))
ELSE ''
END AS Title,
CASE
WHEN LEFT(#str, Charindex(' ', #str)) IN ( 'Mr', 'Mrs', 'Miss' ) THEN LEFT(Stuff(#str, 1, Charindex(' ', #str), ''), Charindex(' ', Stuff(#str, 1, Charindex(' ', #str), '')))
ELSE LEFT(#str, Charindex(' ', #str))
END AS first_name,
CASE
WHEN LEFT(#str, Charindex(' ', #str)) IN ( 'Mr', 'Mrs', 'Miss' ) THEN Stuff(#str, 1, Charindex(' ', #str), '')
ELSE #str
END NAME) a
Technically using a % before their name will allow any prefix, which would get you the desired result (ex. WHERE name LIKE ('%' + #name). However, this is not the recommended approach on larger data sets as you will see significant performance issues with this approach.
You need to be more specific. First of all: Which SQL "flavor" are you using? Postgres? Oracle? MySql? This is very important because each engine has different functions. Every time you ask an SQL question in SO, be sure to include at the very least a tag mentioning which DBMS you're using.
Now, what do you mean by "I shouldn't return them". Do you mean you should not return records which have a prefix, or do you mean you need to return the records but without the prefix? (So if you have Dr. Henry Gutierrez, do you exclude him from the result? Or have it output as Henry Gutierrez?)
This is also a good place for another tip: Always write an expected output in your questions. "If X is Y then I expect the output to be this:"
If you need to exclude them entirely, you can use a REGEXP match (Once again, I cannot list a specific function because I have no idea which type of SQL you're using) Something like WHERE REGEXP(UPPER(COL)) NOT ('^(MS|MR)\s+.*$')
If it's the 2nd case, that's going to be much harder because you'd need to get a substring which excludes the prefix, but the prefixes all have different sizes so you can't just write a "one size fits all"
In general, it's a bad normalization practice to have prefixes in your SQL database. You should have a column called PREFIX and another column for the name itself.
EDIT: Based on your answer. This is the closest you can get to achieving what you want.
SELECT NAME
FROM (SELECT NAME,
CASE WHEN NAME LIKE 'MR %' THEN SUBSTRING(NAME, 4)
WHEN NAME LIKE 'MRS %' THEN SUBSTRING(NAME, 5)
ELSE NAME AS NAME2
FROM YOUR_TABLE ORDER BY NAME2) AS SUBQ
I am 99% sure this will not return the results ordered though, because the select order might be ignored outside of the subquery, so you can also just try whats in the subquery in a main query instead, but this will output 2 columns.
***My reply is in pseudocode. It is not exactly MySql syntax, you will need to check MySql documentation for the actual substring function implementation it has and for the CASE syntax.
I am trying to get First name from employee table, in employee table full_name is like this: Dow, Mike P.
I tried with to get first name using below syntax but it comes with Middle initial - how to remove middle initial from first name if any. because not all name contain middle initial value.
-- query--
select Employee_First_Name as full_name,
SUBSTRING(
Employee_First_Name,
CHARINDEX(',', Employee_First_Name) + 1,
len(Employee_First_Name)) AS FirstName
---> remove middle initial from right side from employee
-- result
Full_name Firstname Dow,Mike P. Mike P.
--few example for Full_name data---
smith,joe j. --->joe (need result as)
smith,alan ---->alan (need result as)
Instead of specifying the len you need to use charindex again, but specify that you want the second occurrence of a space.
select Employee_First_Name as full_name,
SUBSTRING(
Employee_First_Name,
CHARINDEX(',', Employee_First_Name) + 1,
CHARINDEX(' ', Employee_First_Name, 2)) AS FirstName
One thing to note, the second charindex can return 0 if there is no second occurence. In that case, you would want to use something like the following:
select Employee_First_Name as full_name,
SUBSTRING(
Employee_First_Name,
CHARINDEX(',', Employee_First_Name) + 1,
IIF(CHARINDEX(' ', Employee_First_Name, 2) = 0, Len(Employee_First_name), CHARINDEX(' ', Employee_First_Name, 2))) AS FirstName
This removes the portion before the comma.. then uses that string and removes everything after space.
WITH cte AS (
SELECT *
FROM (VALUES('smith,joe j.'),('smith,alan'),('joe smith')) t(fullname)
)
SELECT
SUBSTRING(
LTRIM(SUBSTRING(fullname,CHARINDEX(',',fullname) + 1,LEN(fullname))),
0,
COALESCE(NULLIF(CHARINDEX(' ',LTRIM(SUBSTRING(fullname,CHARINDEX(',',fullname) + 1,LEN(fullname)))),0),LEN(fullname)))
FROM cte
output
------
joe
alan
joe
To be honest, this is most easily expressed using multiple levels of logic. One way is using outer apply:
select ttt.firstname
from t outer apply
(select substring(t.full_name, charindex(', ', t.full_name) + 2, len(t.full_name) as firstmi
) tt outer apply
(select (case when tt.firstmi like '% %'
then left(tt.firstmi, charindex(' ', tt.firstmi)
else tt.firstmi
end) as firstname
) as ttt
If you want to put this all in one complicated statement, I would suggest a computed column:
alter table t
add firstname as (stuff((case when full_name like '%, % %.',
then left(full_name,
charindex(' ', full_name, charindex(', ', full_name) + 2)
)
else full_name
end),
1,
charindex(', ', full_name) + 2,
'')
If format of this full_name field is the same for all rows, you may utilize power of SQL FTS word breaker for this task:
SELECT N'Dow, Mike P.' AS full_name INTO #t
SELECT display_term FROM #t
CROSS APPLY sys.dm_fts_parser(N'"' + full_name + N'"', 1033, NULL, 1) p
WHERE occurrence = 2
DROP TABLE #t
I have a need to retrieve a hierarchy of managers and the column which stores the manager names for a given person are formatted like this Smith, Mr. William (Bill). I want this output to simply be William Smith. So far I have put this together:
SELECT DISTINCT RIGHT(u.manager, LEN(u.manager)-(1+CHARINDEX(', ', u.manager))) + ' ' +
LEFT(u.manager, CHARINDEX(', ', u.manager) - 1) as ManagerName
FROM Users u
The current result from that query using my example above is Mr. William (Bill) Smith. This CHARINDEX and SUBSTRING stuff always gives me a lot of trouble so I am not really sure what the easiest way to do this is. This is also a one-off, so I am not sure a function would be useful here.
DEMO
SELECT
SUBSTRING(manager,0,CHARINDEX(',', manager)) as surname,
SUBSTRING(manager,CHARINDEX('. ', manager)+2, LEN(manager)-CHARINDEX(' (', manager)+1) as name,
CONCAT(SUBSTRING(manager,CHARINDEX('. ', manager)+2, LEN(manager)-CHARINDEX(' (', manager)+1),
' ',
SUBSTRING(manager,0,CHARINDEX(',', manager))) as 'name surname'
FROM
Users
Result:
+-------------+-----------+--------------+
| surname | name | name surname |
+-------------+-----------+--------------+
Smith William William Smith
I took your query and modified a little bit:
SELECT
---this is the tricky part: inner part finds the first instance of '(' parenthesis
--and substract it from the length of the first name and get only the left part of the first name by subtracting it
CONCAT (
LEFT(t.FirstName, LEN(t.FirstName) - (LEN(t.FirstName) - CHARINDEX('(', t.FirstName) + 1))
,t.LastName
)
FROM (
--basically separating your above syntax to two columns
SELECT RIGHT('Smith, Mr. William (Bill)', LEN('Smith, Mr. William (Bill)') - CHARINDEX('.', 'Smith, Mr. William (Bill)') - 1) AS FirstName
,LEFT('Smith, Mr. William (Bill)', CHARINDEX(', ', 'Smith, Mr. William (Bill)') - 1) AS LastName
) t
Here is the query that should work with your table name and column:
SELECT
---Use case when statement to determine if there are any instances of '(' in the first name
CONCAT (
CASE
WHEN CHARINDEX('(', t.FirstName) > 0
THEN LEFT(t.FirstName, LEN(t.FirstName) - (LEN(t.FirstName) - CHARINDEX('(', t.FirstName) + 1))
ELSE t.FirstName + ' '
END
,t.LastName
)
FROM (
SELECT
RIGHT(u.manager, LEN(u.manager) - CHARINDEX('.', u.manager) - 1) AS FirstName
,LEFT(u.manager, CHARINDEX(', ', u.manager) - 1) AS LastName from Users u
) t
SELECT RIGHT(NameStripped, LEN(NameStripped) - (1 + CHARINDEX(', ', NameStripped))) + ' ' + LEFT(NameStripped, CHARINDEX(', ', NameStripped) - 1) AS ManagerName --Your original code
FROM (
SELECT replace(replace(
LEFT(u.manager, CHARINDEX('(', u.manager) - 2) --Get rid of nickname
, 'Mr. ', ''), 'Ms.', '') AS NameStripped --Get rid of Mr/Ms
from MyTable u) a
This should work - I used the code you posted, but added a subquery to remove the nicknames and prefixes.
Note that you may need to adjust this if a) you have more prefix options than this (in which case you could add additional replaces) and/or b) not everyone in your database has a nickname (in which case you'll want to wrap that part in a case statement, most likely).
I have a column as FullName containg FirstName, MiddleName, LastName in it.
For example:
FullName: Marilyn Kean Kirkland
I want to have 3 separate columns for FirstName, MiddleName and LastName from the FullName by taking a substring from it.
I am pulling the FirstName by using the code:
substring(c.LegalName, 1, CHARINDEX(' ', c.LegalName)) as 'First Name'
I am wondering how can I pull just the middle name which comes after first space and before second space?
Also, I want to pull the last name which comes after the second space?
SQL Server doesn't have very good string manipulation functions. This is easier with subqueries:
select firstname,
stuff(reverse(stuff(reverse(legalname), 1, len(lastname) + 1, '')),
1, len(firstname) + 1, '')
from (select legalname,
left(legalname, charindex(' ', legalname) - 1) as firstname,
right(legalname, charindex(' ', reverse(legalname)) - 1) as lastname
. . .
) c
However, I would be very careful, because not all people have three part names. And others have suffixes (JR, SR) and other complications.
You can try something like this.
;WITH c AS
(
SELECT 'Marilyn Kean Kirkland' AS legalname
UNION ALL SELECT 'J Smith' AS legalname
)
SELECT
SUBSTRING(legalname,1,space1) firstname,
SUBSTRING(legalname,space1,space2 - space1 + 1) middlename,
SUBSTRING(legalname,space2 + 1,totallength - space2) lastname
FROM
(
SELECT
legalname,
CHARINDEX(' ',legalname) space1,
LEN(legalname) - CHARINDEX(' ',REVERSE(legalname)) space2,
LEN(legalname) as totallength
FROM c
)c
GO
As noted above by other users as well,these scripts will work with user that only have 3 part or 2 part names.
Running sql server 2008 The title says it, but in my select statement I have this
COALESCE( ca.AttributeList.value('(/AttributeList/IRName)[1]','varchar(max)')
,ca2.AttributeList.value('(/AttributeList/IRName)[1]','varchar(max)'))
AS IR_Name
and it returns lastName, FirstName
This becomes a problem when exporting to a csv as it creates two separate columns and what not.
I somehow have to figure out how to have the string be firstName lastName, no commas, and putting the firstName first.
SELECT PARSENAME(REPLACE('John , Doe', ',', '.'), 1) + ' ' + PARSENAME(REPLACE('John , Doe', ',', '.'), 2)
this will switch 'John , Doe' to 'Doe John'. Now, you just need replace the 'John, Doe" with the
COALESCE(ca.AttributeList.value('(/AttributeList/IRName)[1]','varchar(max)'),ca2.AttributeList.value('(/AttributeList/IRName)[1]','varchar(max)')) AS IR_Name
Another way to do this is by using string functions:
select (case when IR_Name like '%,%'
then (ltrim(rtrim(substring(IR_NAME, charindex(',', IR_NAME)+1, 1000))) + ' ' +
ltrim(rtrim(left(IR_Name, charindex(',', IR_NAME) - 1)))
)
else IR_NAME
end) t
from (select COALESCE( ca.AttributeList.value('(/AttributeList/IRName)[1]','varchar(max)')
,ca2.AttributeList.value('(/AttributeList/IRName)[1]','varchar(max)'))
AS IR_Name
. . .
) t
The trimming functions are to remove extra spaces.
The parsename solution is clever. But, it looks strange since parsename is designed for multipart naming conventions, with up to four parts separated by periods.