Hi I was needing help with the syntax to add a condition where the current date is retrieved if today is after the 5th of each month but if its between the 1st to the 5th then it should retrieve the month before this month. Is it something you can help with please? Below is how my query is structured.
Select *
FROM table1
left join table2
on e.ENTITY_NBR = d.entity_nbr
and cast(getdate() as date) between MONTH_BEGIN_DATE and MONTH_END_DATE
Select *,
CASE WHEN day(GETDATE()) > 5 THEN GETDATE()
ELSE DATEADD(month,-1,getdate()) END as date
FROM table1
left join table2
on e.ENTITY_NBR = d.entity_nbr
and cast(getdate() as date) between MONTH_BEGIN_DATE and MONTH_END_DATE
Based on a vague description of your problem this is the best I can write.
If you simply want to include todays date (or the same date from last month if it's currently the 5th or earlier in the current month), then this can be done in your SELECT clause:
select
case
when datepart(day,getdate()) <= 5
then dateadd(month,-1,getdate())
else getdate()
end
If you want to actually use this date to compare to some field in your dataset, then you can include this same case expression in your WHERE clause.
where the current date is retrieved if today is after the 5th of each month but if its between the 1st to the 5th then it should retrieve the month before this month.
Based on this description, you want something like this:
select *
from table1 e left join
table2 d
on e.ENTITY_NBR = d.entity_nbr and
(day(getdate() > 5 and datediff(month, d.date_col, getdate()) = 0 or
day(getdate() <= 5 and datediff(month, d.date_col, getdate()) = 1)
)
Related
I need to get end of each month for the past 3 yrs from the current date excluding statutory holidays and weekends using table1 and table2. Table1 has all the dates ranging from year 2025-2017. Table2 has all the statutory holidays for the years ranging from 2025-2017.
How to create SQL script for to attain this result? Any suggestions could help. Expected result would be list of date last 3yrs of endofmonth excluding statutory holidays and weekends.
Table 1 has 2 columns, DateId and FullDate column
DateID Fulldate
1010392 2019-12-1
1010393 2019-12-2
1010394 2019-12-3
1010395 2019-12-4
.
.
101086 2019-12-31
Table 2 has 2 columns, DateId and Statutory_Holidays
Date ID Stat_Holidays
101085 2019-12-25
101086 2019-12-26
And the returned results should look like
WeekDay_FullDate_Past3yrs
2019-12-31
2020-1-31
2020-2-28
2020-3-31
Tried the below:
select * from
( select a.Date from Table1 a where a.Date <=
'20221215' and a.Date >= DATEADD (YEAR, -3, getdate()) ) as t1
join
( select EOMONTH(a.Date) as Date from Table1 a where a.Date <= '20221215' and a.Date >= DATEADD (YEAR, -3, getdate()) ) as t2 on t1.Date = t2.Date
tried the solution from the below link it dosen't solve my issue. I'm looking to get list of last workday of a month(excluding weekends and holiday) for the past 3yrs
SQL Server - Get Last Business Data excluding holidays and Weekends
You can group by month and year and take the max date (excluding holidays and weekends):
SET DATEFIRST 1;
DECLARE #CurrentDate DATE = '20221215';
WITH cte
AS
(
SELECT MAX(Date ) as EOMDate
FROM Table1
WHERE DATEPART(weekday,Date) NOT IN (6,7)
AND Date NOT IN (SELECT Date FROM Table2)
GROUP BY YEAR(Date),MONTH(Date)
)
SELECT *
FROM cte
WHERE cte.EOMDate BETWEEN DATEADD(YEAR,-3,#CurrentDate) AND #CurrentDate;
This should work and give you the last working day for each month in your main table. Just filter by the desired time period:
SELECT TOP 1 WITH TIES FullDate
FROM Table1
WHERE FullDate NOT IN (SELECT Stat_Holidays FROM Table2) -- not holiday
AND DATEPART(weekday, FullDate) NOT IN (7, 1) -- not saturday and sunday
ORDER BY DENSE_RANK() OVER(PARTITION BY YEAR(FullDate), MONTH(FullDate) ORDER BY FullDate DESC)
Check this with your table name and column names.
select year(dates) _Year ,month(dates) _Month,EOMONTH(dates) endofMOnth from tabledate1 where DATENAME(DW, dates) not in ('Saturday','Sunday')
and EOMONTH(dates) not in (select holidaydate from tableholidays)
Group by year(dates),month(dates),EOMONTH(dates)
order by year(dates) ,month(dates)
My table creates a new record with timestamp daily when an integration is successful. I am trying to create a query that would check (preferably automated) the number of days in a month vs number of records in the table within a time frame.
For example, January has 31 days, so i would like to know how many days in january my process was not successful. If the number of records is less than 31, than i know the job failed 31 - x times.
I tried the following but was not getting very far:
SELECT COUNT (DISTINCT CompleteDate)
FROM table
WHERE CompleteDate BETWEEN '01/01/2015' AND '01/31/2015'
Every 7 days the system executes the job twice, so i get two records on the same day, but i am trying to determine the number of days that nothing happened (failures), so i assume some truncation of the date field is needed?!
One way to do this is to use a calendar/date table as the main source of dates in the range and left join with that and count the number of null values.
In absence of a proper date table you can generate a range of dates using a number sequence like the one found in the master..spt_values table:
select count(*) failed
from (
select dateadd(day, number, '2015-01-01') date
from master..spt_values where type='P' and number < 365
) a
left join your_table b on a.date = b.CompleteDate
where b.CompleteDate is null
and a.date BETWEEN '01/01/2015' AND '01/31/2015'
Sample SQL Fiddle (with count grouped by month)
Assuming you have an Integers table*. This query will pull all dates where no record is found in the target table:
declare #StartDate datetime = '01/01/2013',
#EndDate datetime = '12/31/2013'
;with d as (
select *, date = dateadd(d, i - 1 , #StartDate)
from dbo.Integers
where i <= datediff(d, #StartDate, #EndDate) + 1
)
select d.date
from d
where not exists (
select 1 from <target> t
where DATEADD(dd, DATEDIFF(dd, 0, t.<timestamp>), 0) = DATEADD(dd, DATEDIFF(dd, 0, d.date), 0)
)
Between is not safe here
SELECT 31 - count(distinct(convert(date, CompleteDate)))
FROM table
WHERE CompleteDate >= '01/01/2015' AND CompleteDate < '02/01/2015'
You can use the following query:
SELECT DATEDIFF(day, t.d, dateadd(month, 1, t.d)) - COUNT(DISTINCT CompleteDate)
FROM mytable
CROSS APPLY (SELECT CAST(YEAR(CompleteDate) AS VARCHAR(4)) +
RIGHT('0' + CAST(MONTH(CompleteDate) AS VARCHAR(2)), 2) +
'01') t(d)
GROUP BY t.d
SQL Fiddle Demo
Explanation:
The value CROSS APPLY-ied, i.e. t.d, is the ANSI string of the first day of the month of CompleteDate, e.g. '20150101' for 12/01/2015, or 18/01/2015.
DATEDIFF uses the above mentioned value, i.e. t.d, in order to calculate the number of days of the month that CompleteDate belongs to.
GROUP BY essentially groups by (Year, Month), hence COUNT(DISTINCT CompleteDate) returns the number of distinct records per month.
The values returned by the query are the differences of [2] - 1, i.e. the number of failures per month, for each (Year, Month) of your initial data.
If you want to query a specific Year, Month then just simply add a WHERE clause to the above:
WHERE YEAR(CompleteDate) = 2015 AND MONTH(CompleteDate) = 1
The below query returns accurate info, I just haven't had any luck trying to make this:
1) More dynamic so I'm not repeating the same line of code every month
2) Formatted differently, so just 2 columns of month + year are needed to view pending counts by field1 + field2
Example code (basically, sum when (OPEN date is before/on the last day of the month) and (CLOSE date comes after the month OR it's still opened)
SELECT
SUM(CAST(case when OPENDATE <= '2014-11-30 23:59:59'
and ((CLOSED >= '2014-12-01')
or (CLOSED is null)) then '1' else '0' end as int)) Nov14
,SUM(CAST(case when OPENDATE <= '2014-12-31 23:59:59'
and ((CLOSED >= '2015-01-01')
or (CLOSED is null)) then '1' else '0' end as int)) Dec14
,SUM(CAST(case when OPENDATE <= '2015-01-30 23:59:59'
and ((CLOSED >= '2015-02-01')
or (CLOSED is null)) then '1' else '0' end as int)) Jan15
,FIELD1,FIELD2
FROM T
GROUP BY FIELD1,FIELD2
Results:
FIELD1 FIELD2 NOV14 DEC14 JAN15
A A 2 5 7
A B 6 8 4
C A 5 6 5
…
Instead of:
COUNT FIELD1 FIELD2 MO YR
14 A A 12 2014
18 A B 12 2014
16 C A 1 2015
...
Is there a way to get this in one shot? Sorry if this is a repeat topic, I've looked at some boards and they've helped me get closing counts.. but using a range between two date fields, I haven't had any luck.
Thanks in advance
One way to do it is to use a table of numbers or calendar table.
In the code below the table Numbers has a column Number, which contains integer numbers starting from 1. There are many ways to generate such table.
You can do it on the fly, or have the actual table. I personally have such table in the database with 100,000 rows.
The first CROSS APPLY effectively creates a column CurrentMonth, so that I don't have to repeat the call to DATEADD many times later.
Second CROSS APPLY is your query that you want to run for each month. It can be as complicated as needed, it can return more than one row if needed.
-- Start and end dates should be the first day of the month
DECLARE #StartDate date = '20141201';
DECLARE #EndDate date = '20150201';
SELECT
CurrentMonth
,FIELD1
,FIELD2
,Counts
FROM
Numbers
CROSS APPLY
(
SELECT DATEADD(month, Numbers.Number-1, #StartDate) AS CurrentMonth
) AS CA_Month
CROSS APPLY
(
SELECT
FIELD1
,FIELD2
,COUNT(*) AS Counts
FROM T
WHERE
OPENDATE < CurrentMonth
AND (CLOSED >= CurrentMonth OR CLOSED IS NULL)
GROUP BY
FIELD1
,FIELD2
) AS CA
WHERE
Numbers.Number < DATEDIFF(month, #StartDate, #EndDate) + 1
;
If you provide a table with sample data and expected output, I could verify that the query produces correct results.
The solution is written in SQL Server 2008.
Like this:
SELECT
FIELD1,FIELD2,datepart(month, OPENDATE), datepart(year, OPENDATE), sum(1)
FROM T
GROUP BY FIELD1,FIELD2, datepart(month, OPENDATE), datepart(year, OPENDATE)
But this of course is just based on OPENDATE, if you need to have the same thing calculated into several months, that's going to be more difficult, and you'll probably need a calendar "table" that you'll have to cross apply with this data.
I have a Postgres table that I'm trying to analyze based on some date columns.
I'm basically trying to count the number of rows in my table that fulfill this requirement, and then group them by month and year. Instead of my query looking like this:
SELECT * FROM $TABLE WHERE date1::date <= '2012-05-31'
and date2::date > '2012-05-31';
it should be able to display this for the months available in my data so that I don't have to change the months manually every time I add new data, and so I can get everything with one query.
In the case above I'd like it to group the sum of rows which fit the criteria into the year 2012 and month 05. Similarly, if my WHERE clause looked like this:
date1::date <= '2012-06-31' and date2::date > '2012-06-31'
I'd like it to group this sum into the year 2012 and month 06.
This isn't entirely clear to me:
I'd like it to group the sum of rows
I'll interpret it this way: you want to list all rows "per month" matching the criteria:
WITH x AS (
SELECT date_trunc('month', min(date1)) AS start
,date_trunc('month', max(date2)) + interval '1 month' AS stop
FROM tbl
)
SELECT to_char(y.mon, 'YYYY-MM') AS mon, t.*
FROM (
SELECT generate_series(x.start, x.stop, '1 month') AS mon
FROM x
) y
LEFT JOIN tbl t ON t.date1::date <= y.mon
AND t.date2::date > y.mon -- why the explicit cast to date?
ORDER BY y.mon, t.date1, t.date2;
Assuming date2 >= date1.
Compute lower and upper border of time period and truncate to month (adding 1 to upper border to include the last row, too.
Use generate_series() to create the set of months in question
LEFT JOIN rows from your table with the declared criteria and sort by month.
You could also GROUP BY at this stage to calculate aggregates ..
Here is the reasoning. First, create a list of all possible dates. Then get the cumulative number of date1 up to a given date. Then get the cumulative number of date2 after the date and subtract the results. The following query does this using correlated subqueries (not my favorite construct, but handy in this case):
select thedate,
(select count(*) from t where date1::date <= d.thedate) -
(select count(*) from t where date2::date > d.thedate)
from (select distinct thedate
from ((select date1::date as thedate from t) union all
(select date2::date as thedate from t)
) d
) d
This is assuming that date2 occurs after date1. My model is start and stop dates of customers. If this isn't the case, the query might not work.
It sounds like you could benefit from the DATEPART T-SQL method. If I understand you correctly, you could do something like this:
SELECT DATEPART(year, date1) Year, DATEPART(month, date1) Month, SUM(value_col)
FROM $Table
-- WHERE CLAUSE ?
GROUP BY DATEPART(year, date1),
DATEPART(month, date1)
I have a table that contains multiple records for each day of the month, over a number of years. Can someone help me out in writing a query that will only return the last day of each month.
SQL Server (other DBMS will work the same or very similarly):
SELECT
*
FROM
YourTable
WHERE
DateField IN (
SELECT MAX(DateField)
FROM YourTable
GROUP BY MONTH(DateField), YEAR(DateField)
)
An index on DateField is helpful here.
PS: If your DateField contains time values, the above will give you the very last record of every month, not the last day's worth of records. In this case use a method to reduce a datetime to its date value before doing the comparison, for example this one.
The easiest way I could find to identify if a date field in the table is the end of the month, is simply adding one day and checking if that day is 1.
where DAY(DATEADD(day, 1, AsOfDate)) = 1
If you use that as your condition (assuming AsOfDate is the date field you are looking for), then it will only returns records where AsOfDate is the last day of the month.
Use the EOMONTH() function if it's available to you (E.g. SQL Server). It returns the last date in a month given a date.
select distinct
Date
from DateTable
Where Date = EOMONTH(Date)
Or, you can use some date math.
select distinct
Date
from DateTable
where Date = DATEADD(MONTH, DATEDIFF(MONTH, -1, Date)-1, -1)
In SQL Server, this is how I usually get to the last day of the month relative to an arbitrary point in time:
select dateadd(day,-day(dateadd(month,1,current_timestamp)) , dateadd(month,1,current_timestamp) )
In a nutshell:
From your reference point-in-time,
Add 1 month,
Then, from the resulting value, subtract its day-of-the-month in days.
Voila! You've the the last day of the month containing your reference point in time.
Getting the 1st day of the month is simpler:
select dateadd(day,-(day(current_timestamp)-1),current_timestamp)
From your reference point-in-time,
subtract (in days), 1 less than the current day-of-the-month component.
Stripping off/normalizing the extraneous time component is left as an exercise for the reader.
A simple way to get the last day of month is to get the first day of the next month and subtract 1.
This should work on Oracle DB
select distinct last_day(trunc(sysdate - rownum)) dt
from dual
connect by rownum < 430
order by 1
I did the following and it worked out great. I also wanted the Maximum Date for the Current Month. Here is what I my output is. Notice the last date for July which is 24th. I pulled it on 7/24/2017, hence the result
Year Month KPI_Date
2017 4 2017-04-28
2017 5 2017-05-31
2017 6 2017-06-30
2017 7 2017-07-24
SELECT B.Year ,
B.Month ,
MAX(DateField) KPI_Date
FROM Table A
INNER JOIN ( SELECT DISTINCT
YEAR(EOMONTH(DateField)) year ,
MONTH(EOMONTH(DateField)) month
FROM Table
) B ON YEAR(A.DateField) = B.year
AND MONTH(A.DateField) = B.Month
GROUP BY B.Year ,
B.Month
SELECT * FROM YourTableName WHERE anyfilter
AND "DATE" IN (SELECT MAX(NameofDATE_Column) FROM YourTableName WHERE
anyfilter GROUP BY
TO_CHAR(NameofDATE_Column,'MONTH'),TO_CHAR(NameofDATE_Column,'YYYY'));
Note: this answer does apply for Oracle DB
Here's how I just solved this. day_date is the date field, calendar is the table that holds the dates.
SELECT cast(datepart(year, day_date) AS VARCHAR)
+ '-'
+ cast(datepart(month, day_date) AS VARCHAR)
+ '-'
+ cast(max(DATEPART(day, day_date)) AS VARCHAR) 'DATE'
FROM calendar
GROUP BY datepart(year, day_date)
,datepart(month, day_date)
ORDER BY 1