Oracle recursive CTE for date with interval - sql

I'm trying to create a recursive CTE, which generates a date/time for every 10 minutes and stops at midnight but I am struggling with the syntax and can't seem to get it to work.
I would be very appreciative to anyone who can help me out. Thanks in advance to all who answer.
ALTER SESSION SET NLS_DATE_FORMAT = 'MMDDYYYY HH24:MI:SS';
with date_rows
(( SELECT TO_DATE('2021/08/20 18:30:25', 'YYYY/MM/DD HH24:MI:SS') as start_date FROM DUAL )
union all
select start_date+interval '10' minute
from date_rows
where start_date <
TRUNC(start_date) + INTERVAL '1' DAY)
select * from date_rows;

You can use:
WITH inputs ( value ) AS (
SELECT TO_DATE('2021/08/20 18:30:25', 'YYYY/MM/DD HH24:MI:SS')
FROM DUAL
),
date_rows ( start_date, end_date ) AS (
SELECT value,
TRUNC(value) + INTERVAL '1' DAY
FROM inputs
UNION ALL
SELECT start_date + INTERVAL '10' MINUTE,
end_date
FROM date_rows
WHERE start_date + INTERVAL '10' MINUTE < end_date
)
SELECT start_date
FROM date_rows;
or, if you want to duplicate the input value then you can use:
WITH date_rows ( start_date ) AS (
SELECT TO_DATE('2021/08/20 18:30:25', 'YYYY/MM/DD HH24:MI:SS')
FROM DUAL
UNION ALL
SELECT start_date + INTERVAL '10' MINUTE
FROM date_rows
WHERE start_date + INTERVAL '10' MINUTE
< TRUNC(TO_DATE('2021/08/20 18:30:25', 'YYYY/MM/DD HH24:MI:SS'))
+ INTERVAL '1' DAY
)
SELECT *
FROM date_rows;
Note: At each iteration of the recursive sub-query, start_date is the previous value so you need to check if start_date + INTERVAL '10' MINUTE is before midnight (rather than just start_date) otherwise you will have the final row after midnight.
db<>fiddle here
What was wrong with your code:
For a non-recursive sub-query factoring clause, the syntax is:
WITH query_alias AS (
or
WITH query_alias (column_alias) AS (
You were missing the AS keyword.
However, for a recursive sub-query factoring clause, you need to use the second version and specify the column aliases.
The () brackets around the first SELECT are redundant (but won't cause an error).
start_date < TRUNC(start_date) + INTERVAL '1' DAY) is always going to be true, even if the date goes past the midnight boundary; so the query will recurse infinitely.
db<>fiddle here

Something like this, I presume.
SQL> with date_rows (datum) as
2 (select cast (to_date('2021/08/20 18:30:25', 'YYYY/MM/DD HH24:MI:SS') as date)
3 from dual
4 union all
5 select cast (datum + interval '10' minute as date)
6 from date_rows
7 where datum < trunc(to_date('2021/08/20 18:30:25', 'YYYY/MM/DD HH24:MI:SS')) + interval '1' day
8 )
9 select * from date_rows;
DATUM
-----------------
08202021 18:30:25
08202021 18:40:25
08202021 18:50:25
08202021 19:00:25
08202021 19:10:25
08202021 19:20:25
08202021 19:30:25
08202021 19:40:25
08202021 19:50:25
08202021 20:00:25
08202021 20:10:25
<snip>
08202021 23:20:25
08202021 23:30:25
08202021 23:40:25
08202021 23:50:25
08212021 00:00:25
34 rows selected.
SQL>

Related

Column based on time range in Oracle

I have a sales table with created datetime, my business hours are from 9 AM to 2 AM in the night on the following day. I am trying to convert the dates into my business date.
01/08/22 09:39:12.000000000 AM +04:00
Lets say I have a sale at 1 AM, this sale has to be considered in the previous day.
Any function that can help me solve this issue would be appreciated
It might be a bit of an overkill, but you could just use EXTRACT:
WITH dat AS
(
SELECT to_date('01/08/22 09:39:12','DD/MM/YY HH24:MI:SS') AS t_stmp FROM dual UNION ALL
SELECT to_date('02/08/22 01:03:15','DD/MM/YY HH24:MI:SS') FROM dual UNION ALL
SELECT to_date('02/08/22 08:27:33','DD/MM/YY HH24:MI:SS') FROM dual UNION ALL
SELECT to_date('02/08/22 14:11:51','DD/MM/YY HH24:MI:SS') FROM dual UNION ALL
SELECT to_date('02/08/22 02:01:15','DD/MM/YY HH24:MI:SS') FROM dual
)
SELECT CASE WHEN EXTRACT(HOUR FROM CAST(t_stmp AS TIMESTAMP)) BETWEEN 2 AND 8 THEN -1
ELSE 0
END + TRUNC(t_stmp,'DD') AS business_date
FROM dat;
business_date
01.08.2022
02.08.2022
01.08.2022
02.08.2022
01.08.2022
It looks like you just need to make a 2 hour shift to get your sales in the right date. You can add or substract hours from DATE/DATETIME/TIMESTAMP data type. If your column is TIMESTAMP then it would be like this:
-- when selecting data for date of sales
SELECT TRUNC(your_column_name - INTERVAL '2' HOUR, 'dd') "SALE_DATE"
-- And/Or
WHERE TRUNC(your_column_name - INTERVAL '2' HOUR, 'dd') = :DATE_OF_SALES
-- TRUNC function always returns DATE datatype
--
-- The opposite conversion would be
CAST(your_datetime_column + INTERVAL '2' HOUR as TIMESTAMP) ...
Here is the small sample with result:
SELECT
to_char(SYSDATE, 'dd.mm.yyyy hh24:mi:ss') "DATETIME",
to_char(SYSDATE - INTERVAL '2' HOUR, 'dd.mm.yyyy hh24:mi:ss') "DATETIME_MINUS_2H",
to_char(SYSDATE + INTERVAL '2' HOUR, 'dd.mm.yyyy hh24:mi:ss') "DATETIME_PLUS_2H",
to_char(SYSDATE - INTERVAL '10' HOUR, 'dd.mm.yyyy hh24:mi:ss') "DATETIME_MINUS_10H"
FROM
DUAL
--
-- R e s u l t
--
-- DATETIME DATETIME_MINUS_2H DATETIME_PLUS_2H DATETIME_MINUS_10H
-- ------------------- ------------------- ------------------- -------------------
-- 07.08.2022 09:58:38 07.08.2022 07:58:38 07.08.2022 11:58:38 06.08.2022 23:58:38
The last column now has the date from day before.

Oracle SQL time difference in HH:MM:SS

I am trying to get time difference in Oracle database. The time difference for all the rows is okay except for one row. Here is the query
SELECT MAX(REGEXP_SUBSTR (CAST(TO_DATE(call_end, 'YYYY/MM/DD HH24:MI:SS') AS TIMESTAMP) - CAST(TO_DATE(call_start, 'YYYY/MM/DD HH24:MI:SS') AS TIMESTAMP), '\d{2}:\d{2}:\d{2}')) AS call_time
FROM calls
The time difference occurs with the following row:
call_end: '2020-02-20 13:00:20'
call_start: '2020-02-20 12:56:03'
The returned result is '11:55:43' which is wrong. As the correct answer should be '00:04:17'
It looks like your table already stores the call start/end times as dates, and you're doing an implicit conversion from date to string, then converting back to a date. You can see that result if you have HH instead of HH24 in your NLS_DATE_FORMAT setting:
alter session set nls_date_format = 'YYYY-MM-DD HH:MI:SS';
with calls (call_end, call_start) as (
select cast(timestamp '2020-02-20 13:00:20' as date), cast(timestamp '2020-02-20 12:56:03' as date) from dual
)
SELECT MAX(REGEXP_SUBSTR (CAST(TO_DATE(call_end, 'YYYY/MM/DD HH24:MI:SS') AS TIMESTAMP) - CAST(TO_DATE(call_start, 'YYYY/MM/DD HH24:MI:SS') AS TIMESTAMP), '\d{2}:\d{2}:\d{2}')) AS call_time
FROM calls;
CALL_TIME
---------------------------
11:55:43
When you do
TO_DATE(call_end, 'YYYY/MM/DD HH24:MI:SS')
because it's already a date you're really doing:
TO_DATE(TO_CHAR(call_end, <NLS_DATE_FORMAT>), 'YYYY/MM/DD HH24:MI:SS')
so with my setting (and yours must be similar, maybe with slashes instead of dashes) that is:
TO_DATE(TO_CHAR(call_end, 'YYYY-MM-DD HH:MI:SS'), 'YYYY/MM/DD HH24:MI:SS')
and the mismatch between HH and HH24 becomes more obvious. So, you're actually converting the strings 2020-02-20 01:00:20 and 2020-02-20 12:56:03 back to dates, and the time difference between 01:00:20 and 12:56:03 is 11:55:43. Well - actually, it is minus 11 hours:
SELECT CAST(TO_DATE(call_end, 'YYYY/MM/DD HH24:MI:SS') AS TIMESTAMP) - CAST(TO_DATE(call_start, 'YYYY/MM/DD HH24:MI:SS') AS TIMESTAMP)
FROM calls;
CAST(TO_DATE(CALL_E
-------------------
-00 11:55:43.000000
but your regex isn't picking that up.
As they are dates skip that part of the conversion completely, and just cast directly to timestamps if you want intervals to work from:
SELECT MAX(REGEXP_SUBSTR (CAST(call_end AS TIMESTAMP) - CAST(call_start AS TIMESTAMP), '\d{2}:\d{2}:\d{2}')) AS call_time
FROM calls;
CALL_TIME
---------------------------
00:04:17
or use a substring instead of a regex, as #MTO showed.
You could also leave them as dates, get the difference as a fraction of a day, add that back to any nominal date at midnight, and then convert the resulting date to a string:
SELECT TO_CHAR(date '2000-01-01' + MAX(call_end - call_start), 'HH24:MI:SS') AS call_time
FROM calls;
CALL_TIM
--------
00:04:17
This won't work properly for a call that lasts more than 24 hours (used to see that a lot with modem calls, but can still happen); but neither will your interval approach. Both ignore any full days and just show the remainder. There are ways to handle that of course, but you'd need to decide how you want to display it - with separate day count (like interval does anyway), or with the 'hours' number allowed to go above 24... but then you may go above 99 hours...
Your question shows the call end time as 2020-02-20 13:00:20, which suggests that's how your client is displaying it when you query the table. Some clients (I think PL/SQL Developer, but not sure, it's been a while) use their own preferences/settings instead of honouring the session's NLS settings. But that has no effect on how Oracle behaves internally when it has to do implicit conversions.
I'm not sure if you want the result as an interval or timestamp, but this should do what you want:
select t.*, call_end - call_start,
substr(to_char(call_end - call_start, 'HH24:MI:SS'), 12, 8) as str from (select timestamp '2020-02-20 13:00:20.000' as call_end,
timestamp '2020-02-20 12:56:03.000' as call_start
from dual) t
Here is a db<>fiddle.
Assuming your data types are strings (you really should store them as DATE data types), you can use:
SELECT SUBSTR(
MAX(
( TO_DATE( call_end, 'YYYY-MM-DD HH24:MI:SS' )
- TO_DATE( call_start, 'YYYY-MM-DD HH24:MI:SS' )
) DAY(1) TO SECOND
),
4,
8
) AS call_time
FROM calls
If they are already DATE data types then, in the MAX aggregation, just use:
( call_end - call_start ) DAY(1) TO SECOND
So for your data:
CREATE TABLE calls ( call_end, call_start ) AS
SELECT '2020-02-20 13:00:20', '2020-02-20 12:56:03' FROM DUAL
This outputs:
| CALL_TIME |
| :-------- |
| 00:04:17 |
db<>fiddle here
Mr Gyl, You can as well do: db <> fiddle :This solution will also consider when the call has lapsed over days by adding those hours together:
WITH da AS (
SELECT
NUMTODSINTERVAL(TO_DATE('2020-02-20 13:00:20', 'yyyy-mm-dd hh24:mi:ss') - TO_DATE('2020-02-20 12:56:03', 'yyyy-mm-dd hh24:mi:ss'), 'DAY') AS call_diff
FROM
dual ) SELECT
EXTRACT( DAY FROM call_diff )*24 + EXTRACT( HOUR FROM call_diff )|| ':' || EXTRACT( MINUTE FROM call_diff ) || ':' || EXTRACT( SECOND FROM call_diff ) DIFFERENCE
FROM
da
DIFFERENCE|
----------|
0:4:17 |
So you can implement as
WITH da AS (
SELECT
NUMTODSINTERVAL(TO_DATE(call_end, 'yyyy-mm-dd hh24:mi:ss') - TO_DATE(call_start, 'yyyy-mm-dd hh24:mi:ss'), 'DAY') AS call_diff
FROM
calls
) SELECT
EXTRACT( DAY FROM call_diff )*24 + EXTRACT( HOUR FROM call_diff )|| ':' || EXTRACT( MINUTE FROM call_diff ) || ':' || EXTRACT( SECOND FROM call_diff ) TIMESTAMP
FROM
da
Please see below response but this will only work within 24hrs and returns both '00'
WITH sample_lt AS(
SELECT '2020-02-20 12:56:03' START_TIME, '2020-02-20 13:00:20' END_TIME FROM dual
)
SELECT start_time,
end_time,
TO_CHAR (TRUNC (SYSDATE) + (to_date(end_time, 'yyyy-mm-dd HH24:MI:SS') -
to_date(start_time, 'yyyy-mm-dd HH24:MI:SS')
) , 'hh24:mi:ss' ) duration
FROM sample_lt ;

Closest Date to a given date - SQL Oracle

Oracle (SQL) - I have 3 available dates in a month (1st, 10th and 25th). I need a query to find out the closest among the 3 dates based on the date of executing my query. For e.g, when i run the query on 4th, i should get 10th as my result, when i run on 12th, the result should be 25th and when i run on 27th, the result should be the 01st of next month.
I am struggling with the logic. Please help..
with
inputs ( dt ) as (
select to_date( '03/24/2015 11:30:00', 'mm/dd/yyyy hh24:mi:ss') from dual union all
select to_date( '08/03/2016 07:15:00', 'mm/dd/yyyy hh24:mi:ss') from dual union all
select to_date( '02/29/2016 22:30:00', 'mm/dd/yyyy hh24:mi:ss') from dual
)
-- End of simulated inputs (for testing only, not part of the solution).
-- SQL query begins BELOW THIS LINE. Use your actual table and column names.
select dt,
case when extract(day from dt) < 10 then trunc(dt, 'mm') + interval '9' day
when extract(day from dt) < 25 then trunc(dt, 'mm') + interval '24' day
else add_months(trunc(dt, 'mm'), 1)
end as next_std_dt
from inputs;
DT NEXT_STD_DT
------------------- -------------------
03/24/2015 11:30:00 03/25/2015 00:00:00
08/03/2016 07:15:00 08/10/2016 00:00:00
02/29/2016 22:30:00 03/01/2016 00:00:00
I believe this is much more efficient and simpler than the other solutions.
WITH
possible_dates
AS
-- generate the three available dates for the current month
(SELECT TRUNC (SYSDATE, 'MM') available_date
FROM DUAL
UNION ALL
SELECT TRUNC (SYSDATE, 'MM') + 9
FROM DUAL
UNION ALL
SELECT TRUNC (SYSDATE, 'MM') + 24
FROM DUAL
UNION ALL
SELECT ADD_MONTHS (TRUNC (SYSDATE, 'MM'), 1)
FROM DUAL),
delta
AS
-- calculate the distance of those available dates
(SELECT (available_date - SYSDATE) diff, available_date
FROM possible_dates)
SELECT *
FROM delta
WHERE diff = (SELECT MIN (diff)
FROM delta
WHERE diff >= 0);
If using PL SQL is an option, then use the query as following:
`DECLARE
curr_month CHAR(2);
curr_year CHAR(4);
future_date DATE;
BEGIN
select to_char(sysdate, 'MM') INTO curr_month from dual;
select to_char(sysdate, 'YYYY') INTO curr_year from dual;
future_date := TO_DATE('12' || curr_month || curr_year, 'DD/MM/YYYY');
IF (SYSDATE > future_date) THEN
{..whatever you want to do...}
ELSIF (SYSDATE > future_date2) THEN
{..whatever you want to do...}
END IF;
END;`
WITH mytable(dt) AS
(SELECT '01'
FROM dual
UNION ALL SELECT '10'
FROM dual
UNION ALL SELECT '25'
FROM dual),
given_dates AS
(SELECT Trunc (To_date (dt || To_char(sysdate, 'MMYYYY'), 'DDMMYYYY')) dt,
Trunc(sysdate) cdate
FROM mytable),
comp AS
(SELECT cdate,
CASE
WHEN ABS (cdate - dt) < ABS (cdate - Add_months (dt, 1)) THEN dt
ELSE Add_months (dt, 1)
END dt_comp
FROM given_dates)
SELECT dt_comp closest_date
FROM
(SELECT dt_comp,
rank() OVER (
ORDER BY ABS (cdate - dt_comp)) rn
FROM comp)
WHERE rn = 1;

Increment Oracle time in varchar field by a certain amount?

We have times stored in an Oracle varchar(5) field.
Times stored using HH24:MI (ie: 22:30, 10:15).
How can we run a query that will increase or decrease these times by a certain amount? Ie: increase by one hour or decrease by 45 minutes.
you could use the built-in date (and interval -- thanks Alex for the link) calculation:
to_char(to_date(:x, 'hh24:mi') + INTERVAL :y MINUTE,'hh24:mi')
for instance:
SQL> WITH my_data AS (
2 SELECT '12:15' t FROM dual
3 UNION ALL SELECT '10:30' FROM dual
4 )
5 SELECT t,
6 to_char(to_date(t, 'hh24:mi') + INTERVAL '15' MINUTE,'hh24:mi')"t+15"
7 FROM my_data;
T t+15
----- -----
12:15 12:30
10:30 10:45
The functions to convert from/to date and char are TO_DATE() and TO_CHAR():
SELECT
TO_DATE('31/12/2001 23:55:00', 'DD/MM/YYYY HH24:MI:SS') AS "DATE",
TO_CHAR(CURRENT_TIMESTAMP, 'DD/MM/YYYY HH24:MI:SS') AS "CHAR"
FROM DUAL
So you can do:
SELECT
TO_DATE('23:45', 'HH24:MI'),
TO_DATE('23:45', 'HH24:MI') + INTERVAL '45' MINUTE,
TO_CHAR(TO_DATE('23:45', 'HH24:MI') + interval '45' MINUTE, 'HH24:MI')
FROM DUAL
There're possibly other better ways to do it (I'm not sure this will work as expected if ran when DST is about to start) but I'm still learning :)

ADD_MONTHS function does not return the correct date in Oracle

See the results of below queries:
>> SELECT ADD_MONTHS(TO_DATE('30-MAR-11','DD-MON-RR'),-4) FROM DUAL;
30-NOV-10
>> SELECT ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR'),4) FROM DUAL;
31-MAR-11
How can I get '30-MAR-11' when adding 4 months to some date?
Please help.
There is another question here about Oracle and Java
It states that
From the Oracle reference on add_months http://download-west.oracle.com/docs/cd/B19306_01/server.102/b14200/functions004.htm
If date is the last day of the month or if the resulting month has fewer days than the day component of date, then the result is the last day of the resulting month. Otherwise, the result has the same day component as date.
So I guess you have to manually check stating day and ending day to change the behaviour of the function. Or maybe by adding days instead of months. (But I didn't find a add_day function in the ref)
As a workaround, I might possibly use this algorithm:
Calculate the target date TargetDate1 using ADD_MONTHS.
Alternatively calculate the target date TargetDate2 like this:
1) apply ADD_MONTHS to the first of the source date's month;
2) add the difference of days between the source date and the beginning of the same month.
Select the LEAST between the TargetDate1 and TargetDate2.
So in the end, the target date will contain a different day component if the source date's day component is greater than the number of day in the target month. In this case the target date will be the last day of the corresponding month.
I'm not really sure about my knowledge of Oracle's SQL syntax, but basically the implementation might look like this:
SELECT
LEAST(
ADD_MONTHS(SourceDate, Months),
ADD_MONTHS(TRUNC(SourceDate, 'MONTH'), Months)
+ (SourceDate - TRUNC(SourceDate, 'MONTH'))
) AS TargetDate
FROM (
SELECT
TO_DATE('30-NOV-10', 'DD-MON-RR') AS SourceDate,
4 AS Months
FROM DUAL
)
Here is a detailed illustration of how the method works:
SourceDate = '30-NOV-10'
Months = 4
TargetDate1 = ADD_MONTHS('30-NOV-10', 4) = '31-MAR-11' /* unacceptable */
TargetDate2 = ADD_MONTHS('01-NOV-10', 4) + (30 - 1)
= '01-MAR-11' + 29 = '30-MAR-11' /* acceptable */
TargetDate = LEAST('31-MAR-11', '30-MAR-11') = '30-MAR-11'
And here are some more examples to show different cases:
SourceDate | Months | TargetDate1 | TargetDate2 | TargetDate
-----------+--------+-------------+-------------+-----------
29-NOV-10 | 4 | 29-MAR-11 | 29-MAR-11 | 29-MAR-11
30-MAR-11 | -4 | 30-NOV-10 | 30-NOV-10 | 30-NOV-10
31-MAR-11 | -4 | 30-NOV-10 | 01-DEC-10 | 30-NOV-10
30-NOV-10 | 3 | 28-FEB-11 | 02-MAR-11 | 28-FEB-11
You can use interval arithmetic to get the result you want
SQL> select date '2011-03-30' - interval '4' month
2 from dual;
DATE'2011
---------
30-NOV-10
SQL> ed
Wrote file afiedt.buf
1 select date '2010-11-30' + interval '4' month
2* from dual
SQL> /
DATE'2010
---------
30-MAR-11
Be aware, however, that there are pitfalls to interval arithmetic if you're working with days that don't exist in every month
SQL> ed
Wrote file afiedt.buf
1 select date '2011-03-31' + interval '1' month
2* from dual
SQL> /
select date '2011-03-31' + interval '1' month
*
ERROR at line 1:
ORA-01839: date not valid for month specified
How about something like this:
SELECT
LEAST(
ADD_MONTHS(TO_DATE('30-MAR-11','DD-MON-RR'),-4),
ADD_MONTHS(TO_DATE('30-MAR-11','DD-MON-RR')-1,-4)+1
)
FROM
DUAL
;
Result: 30-NOV-10
SELECT
LEAST(
ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR'),4),
ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR')-1,4)+1
)
FROM
DUAL
;
Result: 30-MAR-11
the add_months function returns a date plus n months.
Since 30th November is the last date of the month, adding 4 months will result in a date that's the end of 4 months. This is expected behavior. If the dates are not bound to change, a workaround is to subtract a day after the new date has been returned
SQL> SELECT ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR'),4) -1 from dual;
ADD_MONTH
---------
30-MAR-11
SELECT TO_DATE('30-NOV-10','DD-MON-RR') +
(
ADD_MONTHS(TRUNC(TO_DATE('30-NOV-10','DD-MON-RR'),'MM'),4) -
TRUNC(TO_DATE('30-NOV-10','DD-MON-RR'),'MM')
) RESULT
FROM DUAL;
This section in paranthesis:
ADD_MONTHS(TRUNC(TO_DATE('30-NOV-10','DD-MON-RR'),'MM'),4) - TRUNC(TO_DATE('30-NOV-10','DD-MON-RR'),'MM')
gives you number of days between the date you entered and 4 months later. So, adding this number of days to the date you given gives the exact date after 4 months.
Ref: http://www.dba-oracle.com/t_test_data_date_generation_sql.htm
Simple solution:
ADD_MONTHS(date - 1, x) + 1
Here is the trick:
select add_months(to_date('20160228', 'YYYYMMDD')-1, 1)+1 from dual;
Enjoy!
We have come to simpler (in our understanding) solution to this problem - take the least day number from original and add_month result dates, as this:
TRUNC(ADD_MONTHS(input_date,1),'MM') + LEAST(TO_CHAR(input_date, 'DD'), TO_CHAR(ADD_MONTHS(input_date,1), 'DD')) - 1
Some other examples here do not work on every date, below our test results:
WITH DATES as (
SELECT TO_DATE('2020-01-31', 'YYYY-MM-DD HH24:MI:SS') as input_date,
'2020-02-29' as expected_date
FROM dual
UNION ALL
SELECT TO_DATE('2020-02-28', 'YYYY-MM-DD HH24:MI:SS'),
'2020-03-28'
FROM dual
UNION ALL
SELECT TO_DATE('2020-09-30', 'YYYY-MM-DD HH24:MI:SS'),
'2020-10-30'
FROM dual
UNION ALL
SELECT TO_DATE('2020-09-01', 'YYYY-MM-DD HH24:MI:SS'),
'2020-10-01'
FROM dual
UNION ALL
SELECT TO_DATE('2019-01-30', 'YYYY-MM-DD HH24:MI:SS'),
'2019-02-28'
FROM dual
UNION ALL
SELECT TO_DATE('2020-02-29', 'YYYY-MM-DD HH24:MI:SS'),
'2020-03-29'
FROM dual
UNION ALL
SELECT TO_DATE('2020-09-29', 'YYYY-MM-DD HH24:MI:SS'),
'2020-10-29'
FROM dual
UNION ALL
SELECT TO_DATE('2020-03-01', 'YYYY-MM-DD HH24:MI:SS'),
'2020-04-01'
FROM dual
),
methods as (
SELECT
input_date,
expected_date,
ADD_MONTHS(input_date,1) as standard_way,
add_months(input_date-1, 1)+1 as wrong_way,
TO_DATE(LEAST(TO_CHAR(input_date, 'DD'), TO_CHAR(ADD_MONTHS(input_date,1), 'DD')) || '-' || TO_CHAR(ADD_MONTHS(input_date,1), 'MM-YYYY'), 'DD-MM-YYYY') as good_way,
TRUNC(ADD_MONTHS(input_date,1),'MM') + LEAST(TO_CHAR(input_date, 'DD'), TO_CHAR(ADD_MONTHS(input_date,1), 'DD')) - 1 as better_way
FROM
DATES
)
SELECT
input_date,
expected_date,
standard_way,
CASE WHEN TO_CHAR(standard_way,'YYYY-MM-DD') = expected_date THEN 'OK' ELSE 'NOK' END as standard_way_ok,
wrong_way,
CASE WHEN TO_CHAR(wrong_way,'YYYY-MM-DD') = expected_date THEN 'OK' ELSE 'NOK' END as wrong_way_ok,
good_way,
CASE WHEN TO_CHAR(good_way,'YYYY-MM-DD') = expected_date THEN 'OK' ELSE 'NOK' END as good_way_ok,
better_way,
CASE WHEN TO_CHAR(better_way,'YYYY-MM-DD') = expected_date THEN 'OK' ELSE 'NOK' END as better_way_ok
FROM
methods
;
CREATE OR REPLACE FUNCTION My_Add_Month(
STARTDATE DATE,
MONTHS_TO_ADD NUMBER
)
RETURN DATE
IS
MY_ADD_MONTH_RESULT DATE;
BEGIN
SELECT ORACLES_ADD_MONTH_RESULT + NET_DAYS_TO_ADJUST INTO MY_ADD_MONTH_RESULT FROM
(
SELECT T.*,CASE WHEN SUBSTRACT_DAYS > ADD_DAYS THEN ADD_DAYS - SUBSTRACT_DAYS ELSE 0 END AS NET_DAYS_TO_ADJUST FROM
(
SELECT T.*,EXTRACT(DAY FROM ORACLES_ADD_MONTH_RESULT) AS SUBSTRACT_DAYS FROM
(
SELECT ADD_MONTHS(STARTDATE,MONTHS_TO_ADD) AS ORACLES_ADD_MONTH_RESULT,EXTRACT(DAY FROM STARTDATE) AS ADD_DAYS FROM DUAL
)T
)T
)T;
RETURN TRUNC(MY_ADD_MONTH_RESULT);
END My_Add_Month;
/
--test & verification of logic & function both
SELECT T.*,ORACLES_ADD_MONTH_RESULT + NET_DAYS_TO_ADJUST AS MY_ADD_MONTH_RESULT,
My_Add_Month(STARTDATE,MONTHS_TO_ADD) MY_ADD_MONTH_FUNCTION_RESULT
FROM
(
SELECT T.*,CASE WHEN SUBSTRACT_DAYS > ADD_DAYS THEN ADD_DAYS - SUBSTRACT_DAYS ELSE 0 END AS NET_DAYS_TO_ADJUST FROM
(
SELECT T.*,EXTRACT(DAY FROM ORACLES_ADD_MONTH_RESULT) AS SUBSTRACT_DAYS FROM
(
SELECT T.*,ADD_MONTHS(STARTDATE,MONTHS_TO_ADD) AS ORACLES_ADD_MONTH_RESULT,EXTRACT(DAY FROM STARTDATE) AS ADD_DAYS FROM
(
SELECT TO_DATE('28/02/2014','DD/MM/YYYY') AS STARTDATE, 1 AS MONTHS_TO_ADD FROM DUAL
)T
)T
)T
)T;
Query-result
STARTDATE 2/28/2014
MONTHS_TO_ADD 1
ORACLES_ADD_MONTH_RESULT 3/31/2014
ADD_DAYS 28
SUBSTRACT_DAYS 31
NET_DAYS_TO_ADJUST -3
MY_ADD_MONTH_RESULT 3/28/2014
MY_ADD_MONTH_FUNCTION_RESULT 3/28/2014